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physics, the angular velocity of a particle is the rate at which it rotates around a chosen center point: that is, the time rate of change of its angular displacement relative to the origin. It is measured in angle per unit time, radians per second in SI units, and is usually represented by the symbol omega

Angular momentum -the quantity of rotation of a body, which is the product of its moment of inertia and its angular velocity

Angular acceleration is the rate of change of angular velocity. In three dimensions, it is a pseudovector. In SI units, it is measured in radians per second squared, and is usually denoted by the Greek letter alpha

Begin witha diagram of the system, anddefinition of directions. Vertically upand clockwise rotations arepositive. It must be recalled that in SHM force is proportional to displacement from equqilibrium.The key assumptions to make are:

the string is taught throughout the motion of the pendulum,

the string doesn't break thtroughout the motion of the pendulum,

the initial angle of displacement from vertical is small,

there is no drag.

Take theangular displacement from veritcal to bex, and look at the forces on the particle. Assumptions 1) and 2)implythat there is no motion parrallel to the string, and hence the tension in the string must be equal magnitude to the weight of the mass parallel to the string. Hence the resultant force must act perpendicular to the direction of the string. Using trigonometry, this force (F)is: -mgsin(x). where g is the acceleration due to gravity. Now, in the small angle limit sin(x) ~ xso F=-mgsin(x) becomes F~-mgx. Since x is displacement from equilibrium, the system undergoesSHM.

Consider the Work done by this force in moving the body a distance 4m along the z axis, since the question provided doesn't provide sufficient details.

Angular displacement of a body is the angle in radians through which a point revolves around a centre or line has been rotated in a specified sense about a specified axis.

The rate of change of angular displacement of a rotating body.

Angular acceleration is the rate of change of angular velocity. In three dimensions, it is a pseudovector. In SI units, it is measured in radians per second squared, and is usually denoted by the Greek letter alpha.

Angular displacement of a body is the angle in radians through which a point revolves around a centre or line has been rotated in a specified sense about a specified axis.

Vector angular velocity. For an object rotating about an axis, every point on the object has the same angular velocity. The tangential velocity of any point is proportional to its distance from the axis of rotation. Angular velocity has the units rad/s.

Angular acceleration is the rate of change of angular velocity. In three dimensions, it is a pseudovector. In SI units, it is measured in radians per second squared, and is usually denoted by the Greek letter alpha.

angular velocity is d∅/dt = 3t²+2t+1 at t = 2sec , d∅/dt = 3*(2)²+2*(2)+1 = 12+4+1 = 17 rad-¹

The hour hand would move 1/12 of 360 degrees or 30 degrees in 1 hour, and would move 20/60 or 1/3 in 20 minutes.

Therefore, in 20 minutes angular displacement of minute hand = 1/3 * 30= 10 degrees

3 answer has greater for block B

The correct answer is option (3) Greater for block B.

3 answer has greater for block B

option s is the correct answer

option 3, is the right answer

option 3 is correct answer

option 3. is the correct answer

answer is greater of block b

greater for block A is the correct answer

From the string constant acceleration of string should be a1

so acceleration of block b along the string is a2cos∅ , that should be equal to a1

=> a1 = a2cos∅.

Please post the figure

let initially the COM is at x= 0

so, when COM is at x = 1cm and 10kg is at 7cm

the the expression becomes

Xcm = (m1x1 +m2x2)/(m1+m2)

=> 1= 10*7+30*(x2)/(10+30)=> 40 = 70 +30(x2)=> x2 = (40-70)/30 = -1cm...

30 kg mass should be moved 1cm away.

sahi hai

Acceleration = change in velocity / change in time= (v - vo) / (t - to)

Average Velocity= Change in displacement/ Total time= 300/10 = 30 m/s

Acceleration = (30 - 0)/(10 - 0) = 3 m/s^2

Force acting on truck= mass*acceleration = 8000*3 = 24000 N

S = (v^2 - u^2) / (2a)

If Length of train is L thenL = ((3u)^2 - u^2) / (2a)L = 4u^2 / a —-(1)

Midpoint is at Distance L/2S = (v^2 - u^2) / (2a)L/2 = (v^2 - u^2) / (2a)From equation (1)2u^2 / a = (v^2 - u^2) / (2a)4u^2 = v^2 - u^2v^2 = 5u^2v = u√5

option(c)

ty

Thelarge brakeon abicycle wheelismore effectivethan a small one. It is because thelargerone covers lots of surface area of awheelwhen compared with the smallerbrakes. It is the main reason why thelarge brakeis highlyeffectivethan the smaller ones.

wrong

18 kmph=5 m/s

-v(x)=15+5=20{velocity along x before collision}

-v(y)=-15{velocity along y before collision is same as u(y) with opposite sign}

-now tan(Q)=v(y)/v(x)=15/20=3/4

so answer is 37°

We know 360°= 2π rad

=>1°= (π/180) rad = 0.01745 rad

1`= (1/60)0= π/(60 × 180) = 0.00029 rad

1``= (1/3600)0= π/(3600 × 180) = 0.0000048 rad

not understood

n3 is the answer?????

how u calculated can u plz tell

option B

Loss in weight when iron casting weighed in water=6000-4000 =2000 N

According to Archimedes principle,

Loss in wt in water = wt of equal volume of water

volume of displaced water= V =weight/ (density*g)

volume of displaced water= V =2000/1000*g

volume of displaced water= V = 2 /g m^3

Actual volume of iron in casting = Vi = weight / (density of iron*g)

Vi=6000/7870*g=0.7624 /g

volume of cavity = vol. of displaced water - vol. of iron

volume of cavity=2/g -0.7624/g=1.2376 /g

volume of cavity =0.012628 m^3 =12628 cc

the total volume of all the cavities in the casting is 0.012628 m^3 or 12628 cc

f=510Hztime required for 250 vibrations=250/510velocity of sound is 340m/sdistance travelled=340×250/510=166.7m

1.Human larynx-vibration in vocal cords2.Loudspeakers- vibration of screen3.Jal-tarang-vibration in metal arms4.Tuning fork-vibration in air column5.Sitar-vibration in strings