InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 12701. |
BSHORT-ANSWER QUESTIONS :Answer1. State the laws of reflection. |
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Answer» Thelaw of reflection statesthat the incident ray, thereflectedray, and the normal to the surface of the mirror all lie in the same plane. Furthermore, the angle ofreflectionis equal to the angle of incidence . Both angles are measured with respect to the normal to the mirror. |
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| 12702. |
- In which of the following ma-terials, resistance decreaseswith increasing temperature ?(1). Pure Silicon(2) Copper(3) Nichrome(4) Platinum |
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Answer» copper okkkkkkkkk write copper . copper it's right answer OK... copper is the right answer. copper is the right answer copper is correct answer of following question copper is correct answer (2) copper is right ans copper is the correct answer 2) copper is the correct answer |
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| 12703. |
Long. (2) What Urterom below the anLong Answer Type Question20. (a) What is meant by "electric power" ? Write the formula for electric power in terms of potential diffeand current.(b) The diagram below shows a circuit containing a lamp L, a voltmeter and an ammeter. The volreading is 3 V and the ammeter reading is 0.5 A.(i) What is the resistance of the lamp ?(in) What is the power of the lamp ?(c) Define kilowatt-hour. How many joules are there in one kilowatt-hour ? 3(d) Calculate the cost of operating a heater of 500 W for 20 hours at the rate of 3.90 per uni- 20 hours at the top 3.6667 |
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| 12704. |
1. A boat which has a speed of 5 km/h in still water crosses ariver of width 1 km along the shortest possible path in15 min. The velocity of the river water in km/h is(1989 n |
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Answer» speed of the river water is 4km/h let the velocity of the river be x. the velocity of the river will be in the horizontal direction velocity of boat in still water is 5km/hr. As the width of the river is 1 km and time taken by the boat to cross the river along the shortest path is 15 min therefore the velocity of the boat is= 1*60/15= 4km/hr according to the figure the velocity of the river is along AB . By applying triangle law of vector addition the value of AB comes to be 3km/hr |
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| 12705. |
A boat which has a speed of 5 km/h in still water crossesa river of width 1 km along the shortest possible path in15min. The velocity of the river water in km/h is |
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| 12706. |
(Merits of Mendeleev's Periodic Table) |
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Answer» Advantage of Mendeleev Periodic Table : 1.He left blank places which help scientist to discover new element 2.When Noble gasses was discovered Hel could add it to periodic table without any major change 3.He predicted the property of new element |
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| 12707. |
20.3 The position x of particle moving along x-axis varieswith time t as x-Asin (dot) where A and ω arepositive constants. The acceleration a of particlevaries with its position (x) as(1) a=Ax(3) a = A ωχ(2) a _ω3x(4) a 02 x A |
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Answer» After double differentiating the given equation we get the acceleration ,i.e d²x/dt²=A(w²)×-sin(wt) =-(w²)×Asin(wt)But we know that Asin(wt) =x,Therefore, answer is a=-w²x |
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| 12708. |
(11.The-displacement in meter of a particle moving along x-axis is given byX = 18t + 5t2Calculate(i) The instantaneous velocity att 2s(ii) Average velocity between t 2s and t- 3s(iii) Instantaneous acceleration. |
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Answer» given x = 5t2+ 18t we know that v = dx/dt = d/dt[5t2+ 18t] or v = 10t + 18 now, the instantaneous velocity at t = 2s is given as v = 10x2 + 18 or v = 38 m/s now, at t = 2s x1= 5(2)2+ 18(2) = 56m and at t = 3s x2= 5(3)2+ 18(3) =99m so, total distance travelled dx = (x2- x1) total time taken dt = 1s so, average velocity vav= dx/dt = (99 - 56) / 1 thus, vav=43 m/s dv / dt = 10a = 10 m/ s |
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| 12709. |
15.The rate of doing work by force acting on a particlemoving along x-axis depends on position x ofparticle and is equal to 2x. The velocity of particleis given by expression3x2(1) 3x271a3x2 71/32m(3) (29)121/22mx(4)3 |
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| 12710. |
9. What is ecosystem?o. What is mean of 'One man one Tree?"hort answer tyne questi |
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Answer» 9)An ecosystem is a community made up of living organisms and nonliving components such as air, water, and mineral soil. |
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| 12711. |
EXERCISE-ill (Analytical Questions)Position of a particle moving along x-axis is given 9,by x 2+ 8particle from t 0 to t 2 ise distance travelled by the(2) 8(3) 12(4) 16 |
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Answer» v= dx/dt= 8-8*t at t=1 you get v=0 and the particle stops and reverses direction split the integral of v into two region 0<=t<=1 and 1<t<=2 and later add them together and get the solution x1= 8*t-4*t^2 ....8*1-4*1^2= 4 m x2 = [0-(8-4)] = 4 m x=x1+x2 = 8 m why we did integration of v |
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| 12712. |
1. A mirror forms a virtual image of a real object.(a) It must be a convex mirror.(b) It must be a concave mirror.(c) It must be a plane mirror.(d) It may be any of the mirrors mentioned above. |
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Answer» A concave mirror forms a virtual image of a real object. (b) is correct option the answer is( b) it must be aconcave mirror C Is the correct answer A convex mirror always forms virtual image. A concave mirror produces virtual image when it is placed too closely to it.A plane mirror always forms virtual image.Therefore option (c)is the correct answer |
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| 12713. |
Two particles A and B which are initially atrest move towards each other under themutual force of attraction. At the instant whenthe speed of A is v and the speed of B is 2vThe speed of the centre of mass of thesystem is(A) v1(B) 1.5v(D) zero(C) 3v |
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Answer» At initial position both A and B are at rest, hence momentum is zero. It is given that no external force is acting on them .So, momentum remains zero. Since mass cannot be zero, therefore velocity is zero |
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| 12714. |
Dew the graph of each of the following linear equations and answer the following questinyarii)y=2xii)y=-2xiv)y=3xy-ax |
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Answer» vui8y8y8you8uu9uoyiyiyu7 hyyyyyyyyyyyyyyyyyggggggg udits8teigw8eisigeogs uwvjysceycwvycwyrcaujsurjwcyya jya 6 wu3u I don't know please like |
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| 12715. |
()35sThe light reflected by a plane mirror may form a real image(a) If the rays incident on the mirror are diverging(c) If the object is placed very close to the mirror6) If the rays incident on the mirror are convergir(d) Under no circumstances |
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Answer» option B can be correct . Although plane mirror always forms virtual image of real object. image can help you.. that when the incident ray is comvergent in nature.. then real image can be formed. |
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| 12716. |
. Two particles A and B initially at rest movetowards each other under mutual force ofattraction. At the instant when the speed of Ais V and the speed of B is 2V, the speed ofthe centre of mass of the system is(B) V(D) zero(C) 1.5V |
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Answer» Initially both A and B were at rest. So momentum of centre of mass is 0. And it is given that there is no external force. Hence no change in momentum of centre of mass. And it will remain 0. As momentum(product of mass and velocity) is zero ans mass is not zero, velocity must be 0. |
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| 12717. |
Three particles P, Q and R are situated at pointA on the circular path of radius 10 m. All threeparticles move along different paths andreach pointB as shown in figure. Then the ratio of distancetraversed by particles P and Q is: |
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Answer» u know the perimeter of circle is 2pi r.here r is radius ________________________ now Point A all P,Q,R particle present , now point B is present on opposite side of A ________________________________P particle goes from A to B anticlockwise , so it travel 2pi*10/2=10pi_________________________________Q particle goes clockwise , similarly to P is also be 2pi*10/2=10pi_____________________ and R particle goes through the centre that why the distance travel by the R is 10+10=20(because 10 is the radius of circle) __________________________________ now ratio of P/Q=10pi/10pi=1 P/R=Q/R=10pi/20=pi/2 |
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| 12718. |
m 1.235 Aand 1kø osre henyes eRecate tthe centretht |
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| 12719. |
I. A photon in X region is more energetic than in thevisible region; X isa. IR raysc. Microwavesb. UV raysd. Radiowaves |
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Answer» yes, option a is the correct answer but correct answer should be option B otherwise all the options a,c, d should be correct they also come below the visible range |
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| 12720. |
rest. Calculate the magnitude of average velbeily r the piucie dTwo particles move in concentric circles of radi ry and ra such that they maintain a straight line trouthe centre. Find the ratio of their angular velocities. |
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| 12721. |
Suppose that the electric field part of an electromagnetic wave invacuum is E = {(3.1 N/C) cos [(1.8 rad/m) y + (5.4 x 106 rad/stli(a) What is the direction of propagation?(b) What is the wavelength λ ?(c) What is the frequency v?(d) What is the amplitude of the magnetic field part of the wave?uitte an ernression for the magnetic field part of the wave. |
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| 12722. |
An object of mass 100 kg is accelerated uniformly from a velocityof 5 m s1 to 8 m s1 in 6 s. Calculate the initial and finalmomentum of the object. Also, find the magnitude of the forceexerted on the object. |
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| 12723. |
_ 90рел 000 USA-0 |
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Answer» The total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux through an area isdefinedas the electric field multiplied by the area of the surface projected in a plane perpendicular to the field. |
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| 12724. |
minutes. Find its acceleration.A body start from rest and attains a velocity of 12 mps is in 30 second if the final velocity becon8 mps, What will the de-acceleration after 5 seconds?15ahanges from the following: |
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Answer» Given,Initial velocity, u=12m/sFinal velocity, v=8m/stime,. t= 5 slet deceleration be aWe know, the first equation of motion is v=u+at =>8=12+a*5 =>-4=5a =>a=-4/5 m/s^2= -0.8 m/s^2So deceleration is 0.8m/s^2 |
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| 12725. |
GP1.33e minimum wave-length of a spectral line inThthe Balmer series when the Rydberg's constant(R) 1097 x 10 m1(a) 36.44A(c) 1097 A(b) 36.46 x 10- m(d) 1097 x 104 m |
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Answer» λ = 4/1097 × 10^4 = 0.003646 × 10^-4 = 3.646 × 10^-7 m |
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| 12726. |
9. A constant force is applied on an object of 5 kg for 2s. Ifthe velocty of the object increases from 3ms-1 to 7 msthen find the magnitude of force applied. What would bethe final velocity of this object if the force is applied for5 5? |
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Answer» Let the force be F,Mass is M,time for which it is accelerated = 2svelocity is increased from 3m/s to 7m/sso, acceleration is , a = (7-3)/2 = 2m/s²The force applied is, F = ma = (5)(2) = 10 NNow, the force is applied for 5s, the velocity after 5s will be,v=u+at=> v =3+(2)(5)=>v=13m/s , this is final velocity. |
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| 12727. |
8. The ground state energy of hydrogen atom is13-6 eV. If an electron makes a transition froman energy level -0-85 eV to 3.4 eV, calculatethe wavelength of spectral line emitted. To whichseries of hydrogen spectrum does this wavelengthbelong |
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| 12728. |
A train starts from rest and accelerates uniformlyat a rate of 2 m s2 for 10 s. It then maintains aconstant speed for 200 s. The brakes are thenapplied and the train is uniformly retarded andcomes to rest in 50 s. Find: (i) the maximumvelocity reached, (ii) the retardation in the last50 s, (iii) the total distance travelled, and(iv) the average velocity of the train.15. |
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Answer» In this Journey, the train has accelerated and decelerated motion. For accelerated motion :Initial velocity=u=0m/sacceleration=a=2m/s2time=t=half minute=30 secFinal velocity =V=?From first equation of motion , v=u+atv=0+2x30=60m/sSo train has travelled 60m/s before brakes are appplied. Hence the maximum speed attained by train 60m/s. Distance travelled : From second equation of motion : S=ut+1/2at²S=0x30+1/2 x 2x 30²s=900m/ss=900/1000 =0.9km c) The position of train at half the maximum speed [30m/s]:=Let s be the position of train at half the maximum speedv²-u²=2ass=v²-u²/2as=30²-0²/2x2s=900/4=225m For decelerated motion :Final Velocity=V=o m/sinitial velocity=u=60m/stime=60secFrom first equation of motion : v=u+at0=60+ax60a=-60/60=-1m/s2 Distance travelled during this part is :s=ut+1/2at²=60x60+1/2 (-1x60²)=3600-1800=1800m=1.8km Hence total distance travelled by train=0.9km+1.8km=2.7km - |
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| 12729. |
Power applied to a particle varies, with time aso P (3t -2t + 1) watt, where t is in second.The change in its kinetic energy between time t =2 sand t= 4 s is(1) 32J(3) 61 J(2) 46 J(4) 102 J |
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Answer» dw=(3t²-2t+1)dt=>w=[t³-t²+t](2s to 4s)so W=56-12+2=46 J.It is the kinetic energy |
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| 12730. |
Example 5. A bus starts from rest accelerating uniformlywith 4 ms. A2At t -10 s,a stone is dropped out of a windowof the bus 2 m high. What are the (i) magnitude of velocityand (ii) acceleration of the stone at 10.2 s? Take g-10 ms |
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| 12731. |
The magnitude of image distance of a bus as seenby the driver of an ambulance in rear view mirror offocal length 10 cm is about (Assume bus issituated 10 m from the rear view mirror](1) 0.40 m(2) 0.20 m(3) 0.30 m(4) 0.10 m |
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Answer» 3 is the right answer |
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| 12732. |
How much energy will be necessary for making a body of 500 kg escape fromg 9.8 m/s, radius of earth 6.4 x 10 m)(1) About 9.8x 10° J (2) About 6.4x 100 J (3) About 3.1 1010 J (4) About 2the earth1010 J (4) About 27.4 x 101Jenituuhen it escapes |
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| 12733. |
A liquid soap film in shape of a plane loop has an initial area 0.05 m2. If its area is slowly doubled then theincrease in its surface potential energy from its initial value will be (Surface tension of liquid 0.2 N/m)(A) 5 x 10- J(B) 2 x 102 J(C) 3 x 10-2 J(D) of these |
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Answer» dE = TdsT = surface tension , ds change in area =(0.05)2(0.2) = 2*10-3joules |
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| 12734. |
Example 15.2 A message signal of frequency 10 kHz and peak voltageof 10 volts is used to modulate a carrier of frequency 1 MHz and peakvoltage of 20 volts. Determine (a) modulation index. (b) the side bandsproduced. |
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| 12735. |
A ball is dropped from a height of 10 m. If energy of the ballreduces by 40% after striking the ground, how high can the ballbounce back? (g 10 ms-) |
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Answer» The potential energy at height of 10m =mgh =m×10×10 =100m(jule) On sticking the ground,the potential energy get converted into kinetic energy Kinetic energy=100J Energy is reduced by 40% so the remaining energy=60%×100 =60J The height upto which the ball can bounce back is given by 'h' such that mgh=60m×10×h=60×mh=60/10h=6m thanks |
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| 12736. |
17.The capacitance of a variable capacitor connected la 10 Venergy-change.attery is changed from 7 to 3 HE ComputeAns. 2 x 1o4 J energy will be transferredto the battery. |
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| 12737. |
energy supplied by the battery.38. Rach capacitor in figure (31-P21) has a capacitance of10 uF. The emf of the battery is 100 V. Find the energystored in each of the four capacitors, |
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| 12738. |
2 AA plane electromagnetic wave of frequency 25 MHz travels in free spacealong the x-direction. At a particular point in space and time, EWhat is B at this point?6.3 Vm.63 T. 2 lx 10 T2 I 10 T6.3 k T |
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| 12739. |
- ENTRANCEModel Solved PPart Phys9.1. The least distance of distinct vision for a young adultwith normal vision is about(a) 25 m(b) 25 cm(c) 25 cm(d) 2.5 cm10. |
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Answer» 25 cm is the least distance |
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| 12740. |
5. State and prove the work-energy theorernocity vThe blades of a windmill sweep out a circle of area A. If the wind flows with a velperpendicular to the circle derive expression theala) Mass of air passing through the circle and the kinetic energy transferred by wind to theblades of windmill in time t'electric energy and A- 30m2 , v 36 km/h and density of air is 1.2 kgm3(b) Find the electric power produced that the windmill converts 25% of wind energy into |
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Answer» this is not the answer |
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| 12741. |
ing energies per nucleon fordeuterium and helium are 1.1 MeV and 7.0MeV respectively. The energy in joules wilbe liberated when 10 deuterons take part inthe reaction1) 18.88x103 J3) 18.88×10-7J2) 18.88x10"4) 18.88x1010 J |
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| 12742. |
State two advantages of an electromagnet overa permanent magnet. |
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Answer» Control of Magnet Strength One of the most important features of an electromagnet is the ability to change its magnetic force. When no electric current flows through the magnet’s wires, it has no magnetic force. Put a little current in the magnet, and it has a small force. A large current gives the magnet a bigger force, able to lift or pull heavier objects. The ability to turn magnetic force on and off has many important uses, ranging from simple household gadgets to giant industrial machines. Greater Magnet Power The pulling power of a permanent magnet is limited to the type of metal from which it’s made. Currently, the strongest permanent magnets are made of a combination of iron and a metal called neodymium. Although these permanent magnets are strong, the best electromagnets are more than 20 times stronger. |
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| 12743. |
Air is filled in a motortubeat27Candatapressure of 8 atmospheres. The tube suddenlybursts, then temperature of air is [Given Îł ofair 1.5] |
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| 12744. |
The human heart forces 4000 cm3 of blood per minutethrough the arteries under a pressure of 130 mm. Thedensity of blood is 1.03 g em3, What is the horse power ofthe heart?Ans. 1.2x10-4hpl |
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Answer» Work done by the heart will be given by, W = P.∆ VHere, P is the pressure and ∆ V is the volume of blood being pumped.Now, pressure P = hρgWhere, h = height of mercury column = 130 mm = 0.13 mρ = density of mercury = 13.6 g/cm3 = 13.6 × 103 kg/m3And, g = acceleration due to gravity = 9.8 m/s2Also, ∆ V = 4000 l = 4 × 10–3 m3Where, t = 60 sUsing these values in the equation of power, we get P = 1.15 WThus, the power of heart is 1.15 watt ~ 1.2watt 1 watt= 0.00134 british horsepower why is the colour of the blood red |
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| 12745. |
20. The weight of a body in water is one third of its weight in air. The density of the body is(1) 0.5 g/cm3(3) 2.5 g/cm3(2) 1.5 g/cm(4) 3.5 g/cm3 |
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Answer» the volume of the body =v cm³andthedensityof the body = d gcm⁻³. Theweight of the body in air,Wair= vdgdyne, where g is the acceleration due to gravity. The buoyant force on the body when it is completely immersed is the weight of displaced water,Wbouyant =v x 1 x gdyne. The weight of the body in water, Wwater = Wair - Wbuoyant = vg(d−1)dyne According to the question, Wwater =1/3Wair ⇒vg(d−1) =1/3vdg ⇒d−1 =1/3d ⇒d−d/3= 1 ⇒2d/3= 1 ⇒d=3/2= 1.5 gcm⁻³. |
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| 12746. |
14) Explain any two advantages of friction.15) What are elastic & inelastic collision? |
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Answer» 14)A moving object will never stop if there is nofriction. Actually it isimportantbecause it basically allows us to do everyday things: driving a car, picking up objects etc. Without it everything would just slip and slide, with nothing to grip onto. ...Friction"pushes" the wheels in a circular motion. Helpful frictionPeople often usefrictionto slow things down. These brake blocks usefrictionto slow the bike wheels. When the skydiver opens the parachute, air resistance slows him down. ...Frictionalso wears engine parts, so they need replacing. 15)Elastic collision is a collision where the colliding objects bounce back without undergoing any deformation or heat generation. Inelastic collision is a collision where the colliding objects are distorted and heat is generated.2. In elastic collision, the momentum and total kinetic energy before and after collision is the same.3. In inelastic collision, the energy changes into other energies such as sound energy or thermal energy.4. The forces during elastic collision are conservative and the mechanical energy is not transformed into some other form of energy such as sound energy or thermal energy.5. The Forces during inelastic collision are non-conservative and mechanical energy is transformed into some other form of energy such as sound energy or thermal energy.6. An example of elastic collision is the movement of the swinging balls. An example of inelastic collision is an automobile collision. hit like if you find it useful |
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| 12747. |
The binding energy per nucleon for a gC12 nucleus is(Nuclear mass of C12Mass of hydrogen nucleus 1.007825 a.m.uMass of neutron- 12.00000 a.m.u1.008665 a.m.u) |
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Answer» It is found that the stable nuclei have binding energy per nucleon between 8 and8.8 MeV |
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| 12748. |
23. If an inflated tyre bursts, the air issuing out is cooled, why? |
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Answer» Theairinside a tire which is about toburstis at very high temperature and pressure. Now,whenthe tirebursts airrushesoutand there is a sudden decrease inairpressure and temperature. This is what causes theairto become cooler as the pressure is reduced which causes temperature of theairto reduce as well. |
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| 12749. |
ulilol mproves our living standards. Thisnergy cannot be fulfilled by using traditional sources of energy, whichexhaustible and cause pollution. So, we are looking at alternate sources of energy3. How has the traditional use of wind and water energy been modified for ourconvenience?(i) wind has h |
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Answer» The kinetic energy of wind was traditionally used to do mechanical work like pulling water from a well or lifting. Nowadays, we can generate electricity using windmills.The potential energy of stored water at a height and the kinetic energy of flowing water were traditionally used to do mechanical energy. Nowadays, hydroelectric power stations are built to make use of the energy of water to generate electricity. |
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| 12750. |
. Find the distance between two stones each of mass 2 kg so that the gravitational force between them is 1 NAns. 1-63 x 10-5 m] |
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