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1501.

4ln the process PV- constant, pressure (P) versus denisty (p )raph of an ideal gas is

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1502.

The isothermal Bulk modulus of an ideal gasat pressure P is

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The value ofisothermal bulk modulusofgasat oneatmospheric pressureis equal toatmospheric pressure.

1503.

12 The viscous force acting between liquids layers ofeasurednAarea A is given by F-(where dv is changedxin speed and dx is change in column length)The dimension of η is(1) IMLT](2) [ML T-1](3) [MLT-2](4) [ML T-2ameas

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dimension of Force = MLT-²

so dimension of n = dim(F*l/A*v) = ML²T-²/(L²*L/T) = ML-¹T-¹..

option 2

1504.

hA AlTlo determine the Young's modulus of a wire, the formula isY=, where L=length,A - area of cross- section of the wire, AL- Change in length of the wire when stretchedwith a force F. The conversion factor to change it from CGS to MKS system isa) 1b) 10c) 0.1d) 0.01

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1505.

Newton's second law of motionconnects(a) momentum and acceleration(b) change of momentum and velocity(c)yTate of change of momentum andexternal force(d) rate of change of force andmomentum

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(c) rate of change of momentum and external force

Newton's second law of motion provides an explanation for the behaviour of objects when forces are applied to the objects. The law states that external forces cause objects to accelerate, and the amount of acceleration is directly proportional to the net force and inversely proportional to the mass of the object.

1506.

In symbols, pressure is equal to -(a) A/F, where A is area and F is force(c) d/F, where d is distance and F is force(b) F/A, where A is area and F is force(d) F/d, where d is distance and F is force

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Pressure =F/A, where A is area and F is force.

1507.

7.A student measured the length of a rod and wroteit as 3.50 cm. Which instrument did he use tomeasure it?(1) A meter scale with least count 0.1 cm(2) A vernier calliper where the 10 divisions in vemierscale matches with 9 divisions in main scale andmain scale has 10 divisions in 1 cm(3) A screw gauge having 100 divisions in thecircular scale and pitch as 1 mm(4) A screw gauge having 50 divisions in thecircular scale and pitch as 1 mmuchod off to

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Option number 2 is correct answer

1508.

U. Suive these numericals.In a pair of Vernier live main erale divisions coincide with 20 Vernier scale divisions. If the main scaleU divisions in a centimetre, calculate the least count of the Vernier callipers. (Ans. Least count * 0.0025

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1 Division of Main Scale is coinciding with 1/20 cm. = 0.05 cm

Least Count of vernier = 1/n (Main scale's 1 division)

Where n is no. Of Divisions in V.S.

L.S.= (1/20) * 0.05

=0.0025cm.

Divide the 1/20 cm.=0.05L.S.=(1/20)*0.050.0025cm.

1509.

wo vectors P and Q have magnitudes 3 units anunits respectively. R' is the resultant of P and Qind the magnitude and direction of R when thgle θ between P and Q is 30°

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please post the complete question.

1510.

A sphere of diameter r is cut from a solid sphereof radius r such that the centre of mass of remainingpart be at maximum distance from orginal centre then this distance is :1)r/22)r/33)r/14(4) none of these

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1

Secondary School

Physics

5 points

A sphere of diameter r is cut from a sphere of radius r such that the center of mass of the remaining mass be at maximum distance from original center then the distance is

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byGazala216.04.2017

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kvnmurty

See diagram.

Let x = distance between COM from the original center of the sphere, after the small sphere is cut off from it.

Let the density of the sphere be = dMass of big sphere (full) = 4/3 * π r³* dMass of the small sphere cut off from it = 4/3 *π (r/2)³ * dMass of the remaining object = 7/6 π r³ * d

Position of the COM of the complete sphere = 0=>- x * 7/6 π r³ d + r/2 * 4/3π (r/2)³ * d = 0=> x = r / 14

1511.

capacitanceandinductancewhičhFind the voltage across the various elements, i.e., resistance,are in series and having values 1000 ΩΊμF and 2.0 henry respectivelyGiven emf as, ε 100-2 sin 1000 t volt

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1512.

A given piece of wire of length l radius r andresistance R is stretched uniformly to a wire ofradius r / 2. The new resistance is(A) 16 R(B)4 R(C) R/4(D) R/16

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1513.

7.1f From a uniform disk of radius R, a circular hole of radius R/2 is cut out. The centreof the hole is at R/2 from the centre of the original disc. Locate the centre of gravity.of the resulting flat body.

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1514.

rample 4. From a unform dise of radius R, a circularat R/2 from the centre of the original disc., Locate the centre of mass of the resulting flat bodyholeofradiusR/2iscutout.Thecentreoftheho

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1515.

The electric field intensity outside the charged conducting sphereof radius 'R', placed in a medium of permittivity at a distancer' from the centre of the sphere in terms of surface chargedensity σ is2-2σ(RE R2E r

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what's the correct answer ?

please reply me

Option (d) is the correct answer

1516.

12.A body is projected vertically upwards with a speedGMR (M is mass and R is radius of earth). Thebody will attain a height of(2) R2R43R4) 2(3)

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1517.

9.The change in surface energy when a drop of radiusR splits into 8 droplets, each of radius r is (surfacetension is 7)(1) 21RT(2) 4R2T 10(3) SRT(47 TERET

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V=8v

R³=n*r³

Work done =change in surface energy

ΔU=T * Δ Α

= T * 4 π ( n r² - R²)

= T* 4π n ( R² * n^ (-2/3) - R²)

= T 4π R² ( n^{1/3} - 1 )Here,n=8

ΔU=4π R²T

∴Option 2 is correct.

1518.

vessel is filled only with oil. (Assume atmospnelle piesjuon (B) : Archemedies principle and force of buoyancyA cube of wood supporting a 200 gm mass just frises by 2 cm at equilibrium. Find side of the cube.oats in water. When the mass is removed the cubefroahr under gravity from a height of 19.6 m and then

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1519.

A cube of wood supporting a mass of 200 g justfloats in water. When the mass is removed, thecube rises by 2 cm. What is the size of the cube?(a) 6 cm (b) 8 cm (c) 10 cm (d) 12 cm

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Let the edge of cube be ℓ. When mass is on the cube of wood

200 g + ℓ3d wood g = ℓ3dwaterg

⇒ ℓ3dwood= ℓ3dwater– 200 … (i)

When the mass is removed

ℓ3dwood= (ℓ - 2 ) ℓ2dwater… (ii)

From (i) and (ii)

ℓ3dwater- 200 = (ℓ- 2) ℓ2dwater

But dwater= 1

∴ ℓ3- 200 = ℓ2(ℓ - 2)

⇒ ℓ = 10 cm

1520.

SET-C [11] A distance 2 m separates two points charges of +5 x 10-19Cand - 15 x 10-19 C. Find the point on the line joining them, at whichelectric field intensity is zero.(Marks 2)(Hint: Apply Formula No. 2] (Ans. F = 4.73 m from -15x10-1°C]

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x=4.73 is the correct answer

1521.

definition of electronic enginee

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Electronic engineering is an electrical engineering discipline which utilizes nonlinear and active electrical components to design electronic circuits, devices, VLSI devices and their systems. The discipline typically also designs passive electrical components, usually based on printed circuit boards.

Electronic engineering(also calledelectronicsand communicationsengineering) is anelectrical engineeringdiscipline which utilizes nonlinear and activeelectricalcomponents (such as semiconductor devices, especially transistors, diodes and integrated circuits) to designelectroniccircuits, devices, VLSI devices ...

Electronic engineering(also calledelectronicsand communicationsengineering) is anelectrical engineeringdiscipline which utilizes nonlinear and activeelectricalcomponents (such as semiconductor devices, especially transistors, diodes and integrated circuits) to designelectroniccircuits, devices, VLSI devices

1522.

What is rigidity

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Rigidity is the ability of a solid to withstand deformation when it undergoes mechanical stress. It is mainly dependent on the geometry of the part and the elasticity moduli of the material.

1523.

6. What happens to the force between two objects, If(1) the mass of one object is doubled?(ll) the distance between the objects is doubled and tripled?(iii) the masses of both objects are doubled?

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1524.

6. What happens to the force between two objects, if(i) the mass of one object is doubled?(ii) the distance between the objects is doubled and tripled?(iii) the masses of both objects are doubled?

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1525.

14. What happens to the force between twoobjects, if(i) the mass of one object is doubled?(ii) the distance between the objects isdoubled and tripled?(iii) the masses of both the objects aredoubled?

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1526.

What happens to the force between two objects, if(i) the mass of one object is doubled?(ii) the distance between the objects is doubled and tripie(ii) the masses of both objects are doubled?6.ofuniversal law of gravitation

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1527.

1. Two spherical balls of mass 10 kg each are placed 10 cmapart. Find the gravitational force of attraction betweenthem.

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1528.

12 marks each ]6. What are Jovian planets? State their general characteristics.

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The Jovian planets are Jupiter, Saturn, Uranus, and Neptune. They orbit far from the sun. These planets have no solid surfaces and are essentially large balls of gas composed primarily of hydrogen and helium. They are much larger than the terrestrial planets (Earth, Mercury, Venus, and Mars).

In our solar system, the Jovian planets share two main characters: they are comprised of gaseous matter, rather than solid rock, and are very large relative to the other, terrestrial planets. The four Jovian plants in the solar system--Jupiter, Saturn, Uranus, and Neptune--are all classified as "gas giants," meaning that they are made out of gases, rather than the solid materials that comprise the "terrestrial" planets (such as Earth). The gas giants are also much larger than the four terrestrial planets. In fact, the mass of the planet Jupiter can hold about 1,300 Earth-sized planets. The term "Jovian" comes from the planet Jupiter (as "Jove" is an alternate name for the Roman god Jupiter), which is the largest planet in our solar system.

1529.

what is cell wall

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a rigid layer of polysaccharides lying outside the plasma membrane of the cells of plants, fungi, and bacteria. In the algae and higher plants it consists mainly of cellulose

1530.

OrGive the simple structure of an u-p-n transistor. Show the biasing of an n-p-n transistorand explain the transistor action.

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As the connection between emitter and base is forward biased the depletion layer at E-B junction shrinks. If the voltage supplied crosses the cutting voltage, depletion layer will demolish.

Resistance in the circuit between emitter and base is decreased hence, current in circuit is increased.

This results in the flow of current.

The connection between base and collector is reverse biased the depletion layer at C-B junction gets wider.

Resistance in the circuit between collector and base is increased hence, current in circuit is decreased.

As a result, the current carried by majority charge carrier is stopped but reverse current will continue to flow.

it is not correct answer please reply my answer

1531.

9. Explain the working of an n-p-n transistor

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the emitter-base junction is forward biased and the collector-base junction is reversed biased.

Forward biased causes the electron in the n-type emitter to flow toward the base. This constitutes the emitter current Ie. As these electrons flow through the p-type base, these electrons tend to combine with the holes. As the base is lightly doped and very thin,therefore,only few electrons (less than 5%) combine with holes to constitute the base current Ib. The remainder(more than 95) cross over into the collector region to constitute collector current Ic. In this way, almost the entire current fows in the collector circuit. it is clear that emitter current is the sum of the collector current and base currents. i.e.Ie=Ib+Ic

1532.

explain the zener diode is fabricated by heavily doped both p and n side of Junction

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Heavy doping makes the depletion region very thin. This makes the electric field of the junction very high, even for a small reverse bias voltage. This in turn helps the Zener diode to act as a ‘voltage regulator

1533.

A barometer kept in a stationary elevator reads 76 cm. If the elevator starts accelerating upreading will be(A) Zero54.9.(B) Equal to 76 cm(C) More than 76 cm(D) Less than 76 cm(B) 76 cm亩軻-C) 76 cm 긁 af(D) 76 cm

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The answer to this question is option c because a pseudo force will act in the barometer which will increase the pressure reading.

1534.

A barometer kept in an elevator reads 76 cm when it is atrest. If the elevator goes up with increasing speed, thenreading will be(a) zero(c)>76 cm(b) 76 cm(d) < 76 cm

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1535.

A barometer kept in an elevator reads 76 cm when itis at rest. If the elevator goes up with someacceleration, the reading will be(1) 76 cm(2) > 76 cm(3) < 76 crm(4) Zero

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1536.

A barometer kept in an elevator reads 76 cm when the elevator is accelerating upwards. The most likelypressure inside the elevator (in cm of Hg) is(1) 74(3) 76(2) 75(4) 77

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1537.

Whad is Lenz Law?

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Lenz's law states that the current induced in a circuit due to a change or a motion in a magnetic field is so directed as to oppose the change in flux and to exert a mechanical force opposing the motion.

1538.

what is lenz law explain

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Lenz's law states that the current induced in a circuit due to a change or a motion in a magnetic field is so directed as to oppose the change in flux and to exert a mechanical force opposing the motion.

1539.

what is lenz law by conservation of energy

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According to Lenz’s law:-The polarity of the induced emf is such that it tends to produce induced current in such a direction that it opposes the change in magnetic flux that produced it.

The (-) ive sign in given equatione= (-)(dΦ/dt)tells about the direction.

According to Faraday’s law whenever there is change in the magnetic flux, emf is induced, as aresult there will be induced current.

According to Lenz’s law the direction of the induced current will be such that it opposes the change in the magnetic flux.

For example:-

Consider a circuit where the magnetic flux is increasing, as a result flux will change and which induces the emf in the circuit, and as a result current will be induced in the circuit.

The direction of the induced current will be such that it will oppose the cause which induced it.

The induced current will be in such a direction that it decreases the magnetic flux.

Note: - The induced current will try to oppose the change which is producing it.

how this related to conservation of energy

1540.

6. A stoneof 1 kg is thrown with a velocity of20ms1acrossthe frozen surface of a lake and comes to rest after travellinga distance of 50 m. What is the force of friction between thestone and the ice?

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1541.

A stone of 1 kg is thrown with a velocity of 20 m s^-1 acrossthe frozen surface of a lake and comes to rest after travellinga distance of 50 m. What is the force of friction between thestone and the ice?

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m = 1kgu = 20m/s. v = 0m/s. s(distance travelled) = 50m

Using third equation of motionv²=u²+2as0² = (20)²+2(a)(50)-400 = 100aa = -400/100 = -4m/s² (retardation)

F = m×aF = 1×(-4) = -4N. (negative sign indicates the opposing force which is Friction)

1542.

what is newton's first,second and third law of motion ?

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Newton'sFirstLawstates that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. It may be seen as a statement about inertia, that objects will remain in their state of motion unless a force acts to change the motion.

Newton's Second Law as stated below applies to a wide range of physical phenomena, but it is not a fundamental principle like theConservation Laws. It is applicable only if theforceis the net external force. It does not apply directly to situations where the mass is changing, either from loss or gain of material, or because the object is traveling close to the speed of light where relativistic effects must be included. It does not apply directly on the very small scale of the atom where quantum mechanics must be used.

First Law of motion :- This states the body remains at the state of rest or motion unless is has been acted by an external force ! If there was no friction the ball would keep rolling on the floor !

Second Law of motion :- This brings about a relation between Force , mass and acceleration given by F=ma , and is the source of whole mechanics studies

Third Law Of Motion :- Every action has an equal and opposite reaction. !

Third law every reaction has equal and opposite reaction

1543.

give two ex of first law second law and third law of motion

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Newton's First Law Examples

When the bus starts moving forward, the person that is standing is thrown off balance and then falls backward.

Newton's Second Law Examples

If you push on the cart, it begins to move, The harder you push, the faster the cart accelerates.

Newton's Third Law Examples

As you walk, your feet push against the floor. At the same time, the floor pushes with an equal but opposite force against your feet.

1544.

10. State Newton's second law of motion. Prove that second law is the real law of motion.

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Newton's second law of motion pertains to the behavior of objects for which all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

1545.

Q.2. State Lenz's law. Show that Lenz'slaw is in accordance with the law ofconservation of energy.

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Lenz’s Law states that the direction of the induced current is such that it opposes the change that has induced it. Inother words, it is defined as “Effect Opposes the Cause”.

1546.

A particle in S H.M is described by the displacement function x(t)-Acos(at + θ) If the initial (t 0) position of the particleis 1 cm and its initial velocity is π cm/s The angular frequency of the particle is π s-1 , then it's amplitude is(A) 。,1 cm2 cm(C) 2 cmm(D) 25 cm

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can u tell me how fives value came 3pie/4 and 7pie/4

1547.

By sucking through a straw, a boy can reduce the pressure in his lungs to 750 mm of Hg(density 13.6 g/cm3). Using a straw, he can drink water from a maximum depth of(1) 13.6 cm(3) 0.136 cm(2) 1.36 cm(4) 10 cmm

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1548.

e 1.11 The electric field components in Fig. 1.27 areE, E 0, in which Îą-800N/Cm1/2. Calculate (a) theough the cube, and (b) the charge within the cube. AssumeExamr/2a 0.1 m.alninqalal

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hit like if you find it useful

1549.

5. In figure (14-E1) the upper wire is made of steel andthe lower of copper. The wires have equal cross section.Find the ratio of the longitudinal strains developed inthe two wires.SteelCopperFigure 14-E1

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1550.

10. Pigure (32-E1) shows a conductor of length I havingacircular cross section. The radius of cross section varieslinearly from a to b. The resistivity of the material is p.Assuming that b-a<l, find the resistance of theconductor.Figure 32-E1

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