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P-Q=2j-2k is the right answer

we have to find that vector, which on adding to A = i-j+k , gives one as magnitude

so the best answer is option b => i-j+k +(j-k) = i-j+k+j+k = i, and |i| = 1

Answer of the question is option (3)

3 is tje Best or correct option

3 is the correct answer

3) is the right answer of the following

3) is the right answer of the following

4) is the correct answer

2 ) is the correct answer

3) is the right answer of the following

option 3 is the correct answer of the given question

These are threeeventsplease share the feedback and like the solution 👍 ✔️

1) absorption of light energy2) conversion of light energy into chemical energy and splitting up of water molecules into hydrogen and oxygen.3) reduction of carbon dioxide into carbohydrates

Downward force = upward force see attachment, here it is clear that , down ward force is weight = mg and upward force is magnetic force = Bil

Hence, magnetic force per unit length = weight per unit distance So, μI₁I₂/2πr /meter length = mg/meter length Here, μ = 4π × 10^-7 , r is the require distance between wires mg/meter length = 0.05N/m , I₁ = 100A , I₂ = 200A

⇒ 4π × 10⁻⁷ × 100A × 200A/2πr = 0.05 ⇒ 2 × 2 × 10⁻³ = 5 × 10⁻²r r = 0.4/5 m = 0.08 m or 8 cm

Hence, require distance between wires is 8 cm

thanks

It is totally arbitrary wether we say that the apple falls onto the earth or the earth falls onto the apple. Both scenarios are completely equivalent, since both (apple and earth) just fall towards each other and collide and it is entirely up to us to choose areference framein respect to which we describe the process.

A reference frame is basically just the perspective from which we ‘view’ the physical world. In the case of the falling apple, we're usually standing on the earth itself,so we naturally assume the rest frame of the earth as our frame of reference. In this frame, the apple appears to fall onto the earth, while the earth appears to be at rest. Were you very small and standing on the apple, well then you would consider the apple at rest (along with yourself) and the earth as falling towards you

This can be easily explained by the equation of Newton's second law of motion F = m.a .

Earth and any body pull each other towards themselves , the force applied on both of them remaining the same , but the changes in position of an object is determined by its velocity and acceleration . This is where the answer lies . Assume the mass of earth to be M and that of the arbitrary body to be m. Now the force on both these objects is GMm/ r^2. r being the separation between these objects . Now acceleration of these bodies

Earth - Gm / r^2

Body b - GM /r^2

If you try putting in values(as G is very small) , earth's acceleration remains a very minute ,ignorable quantity until the mass of b becomes significantly large , comparable to planetary masses . On the other hand acceleration of b is considerably high and hence we are able to observe if it's position changes w.r.t. time . If b was something as heavy as sun you would have been able to see change in earth's position as we experience earth revolving .

Our body possess many white blood cells which are part of our immunity and they help in fighting of diseases. Every disease has a particular incubation period. If within that time, W.B.C fights off the microbe, the disease does not develop.Sometimes, there exist some diseases that damage body internally but don't show any changes which are noticeable e.g. diabetes.

moment = F×ds

and here ds = (-2-1)i+(3-2)j+(4-3)k = -3i+j+k

so, M = -[ (i+j+k)×(-3i+j+k)]=> M = -[i(0) -j(1+3) +k(1+3)]= +4j-4k = 4(j-k)

Here dr vector is = (-2-1)i+(3-2)j+(4-3)k = -3i+j+k

also, moment = F×dr = (i+j+k) = (-3i+j+k)

M = i(0) +j(1+3) +k(1+3) = 4(j-k)

option 2

The net horizontal forces must be balanced, since tendency of motion is in horizontal direction. Assume the tension in string to be T1. Then T1 = Wsin30= W/2. Now the horizontal component of this force must be equal to tension T. Therefore, T1cos30=T. Hence, T = root3 /4 mg

Ans:- Arainbowis a meteorological phenomenon that iscausedby reflection, refraction and dispersion of light in water droplets resulting in a spectrum of light appearing in the sky. It takes theformof a multicoloured circular arc.Rainbows causedby sunlight always appear in the section of sky directly opposite the sun.

thee rain is over and then with few seconds the sun is bright this process cause rainbow

Expressionfor K.E -KINETIC ENERGY-

K.E = 1/2 mv2.

"Energyposses by a body by virtue of its motion is referred to as 'Kinetic Energy'".Kinetic energydepends upon the mass and velocity of body.

Consider a body of mass "m" starts moving from rest.

this is correct answer

KE=1/2 mv²is the right answerhope this will help youLike my answer

The Ganga action plan was, launched byShri Rajeev Gandhi, the then Prime Minister of India on 14 Jan. 1986 with the main objective of pollution abatement, to improve the water quality by Interception, Diversion and treatment of domestic sewage and present toxic and industrial chemical wastes from identified grossly polluting units entering in to the river. The other objectives of the Ganga Action Plan are as under.

Control of non-point pollution from agricultural run off, human defecation, cattle wallowing and throwing of unburnt and half burnt bodies into the river.

Research and Development to conserve the biotic, diversity of the river to augment its productivity.

New technology of sewage treatment like Up-flow Anaerobic Sludge Blanket (UASB) and sewage treatment through afforestation has been successfully developed.

Rehabilitation of soft-shelled turtles for pollution abatement of river have been demonstrated and found useful.

Resource recovery options like production of methane for energy generation and use of aquaculture for revenue generation have been demonstrated.

To act as trend setter for taking up similar action plans in other grossly polluted stretches in other rivers.

The ultimate objective of the GAP is to have an approach of integrated river basin management considering the various dynamic inter-actions between abiotic and biotic eco-system.

In physics, thekinetic energyof an object is theenergythat it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained thisenergyduring its acceleration, the body maintains thiskinetic energyunless its speed changes.

Kinetic energy is the energy possessed by an object by virtue of its motion.K.E=1/2 mV²

Derivation:Let us consider an object of m which is at rest lying on a table.Let A force F acts on the object which moves the object through a distance S.

The workdone=FxS

W=Fnet XS-------(1)

Let the workdone on the object causes a change in its velocity from u to V and let a be the acceleration.

From Third equation of motion:V²-u²=2ass=V²-u²/2a----------(2)

By Newton's Second law:F=ma------(3)From equation (1), (2) and (3)

W=ma*(V²-u²/2a)\=(1/2)m(V²-u²)

As we assumed object at rest, u=0W=(1/2)mV²we know that the kinetic energy of a body moving with certain velocity is equal to workdone on the object to acquire that velocity from rest.∴K.E=1/2 mV²

A force is a push or pulls acting upon an object as a result of its interaction with another object.

Basically, there are two types of forces, contact forces, and non-contact forces. Gravitational force, electric force, magnetic force, nuclear force, frictional force are some examples of force.

Hence, option (c) is correct.

Horizontal range is given by R=u^2sin2A/gsin(180-2A)=sin2Asin2(90-A)=sin2Asin2B=sin2A...where B=90-ANow,R=u^2sin2A/g and R=u^2sin2B/gSince sin2A=sin2Bhencesame for A and B=90-A

A projectile is an object that is given an initial velocity, and is acted on by gravity. The horizontal range of a projectile is the distance along the horizontal plane it would travel, before reaching the same vertical position as it started from. The horizontal range depends on the initial velocity v0, the launch angle θ, and the acceleration due to gravity. The unit of horizontal range is meters (m).

R = horizontal range (m)

v0 = initial velocity (m/s)

g = acceleration due to gravity (9.80 m/s2)

θ = angle of the initial velocity from the horizontal plane (radians or degrees)

A projectile is an object that is given an initial velocity, and is acted on by gravity. The horizontal range of a projectile is the distance along the horizontal plane it would travel, before reaching the same vertical position as it started from. The horizontal range depends on the initial velocity v0, the launch angle θ, and the acceleration due to gravity. The unit of horizontal range is meters (m).

R = horizontal range (m)

v0 = initial velocity (m/s)

g = acceleration due to gravity (9.80 m/s2)

θ = angle of the initial velocity from the horizontal plane (radians or degrees)

H = (R/4) Tanθ

Given that R = 2H

H = (H/2) TanθTanθ = 2

If Tanθ = 2 thenSinθ = 2 / √5Cosθ = 1 / √5

R = 2u² sinθ cosθ / g= (2u² × 2 / 5) / g= 4u² / (5 g)

Range of projectile is 4u² / (5g)

Ans :- •Rock - you can hear echos (reflections) in a natural canyon or cave.

concrete

steel

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some data is missing.. the final Velocity. post full question.

But they given answer as opt 4

ok.. sorry , but the question is not clear.. aft it strikes the ground with , which Velocity ?

Ok

their is some mistake in your options