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The molecules in a gas are the most energetic. Due to weak intermolecular forces, the particles of a gas are free and possess most kinetic energy. A solid is rigid. Due to srong intermolecular forces of attraction, the particles of a solid are held tightly together and have the least kinetic energy.

The statement is false. Light year is used to measure large distances in space.

Rails have gap at specific distance because in summer season the heat of Sun may cause the rails to expand and if they do not have gap they will try to overlap each other and this may cause real accident

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apparent change in weight = pseudo force = 60*2.45 = 147N

weight is equal to reaction force

Mg cost(option 2). as normal is the weight of the body so which acts perpendicular to the plane which is shown in fig.

Mg cost(option 2). as normal is the weight of the body so which acts perpendicular to the plane which is shown in fig.

As normal = mgcosx so weight registered will be mgcosx

Let man sits at position x from centreso 20 ×2 = 40 ×xx =1m away from centre

Displacement = Shortest Distance between initial and final position.

When it travels a semicircular path then it’s displacement is equal to diameter of circle i.e 2r

Therefore displacement = 2 x 1 m = 2 m

Average velocity = Displacement / Time= 2 /1 = 2 m/s

Average velocity of particle is 2 m/s

Volume of water displaced = 300cm*400cm*1cm = 60000cm^3We know that density of water is 1gm/cmAgain Mass = Density*Volume = 60000*1 gmMass of displaced liquid = 60000gm = 60 kgUsing Archimedes Principal we know weight of displaced liquid = weight of floating body.

Ft

Mass of the person = 80 kgit is same on the Earth as well as on the Moon.

weight (force ) of the person on Earth = 80 kg wt = 80 kg * ge = 784 Newtons

weight of the person on the Moon = 80 kg * gm = 130.4 Newtons

Weight of the person on earth is 784 Nweight on moon is 130.67 NHis mass remains the same on Earth and Moon.

for equilibirium, mω²r = mgcosAwhere,ω is angular velocity , m is the mass of bob , r is the radius of circular motion and A is theangle of inclination of bob with vertical. we know, ω = 2π/T , here T is time periodso, m{2π/T}²r = mgcosA⇒ T = 2π√{r/gcosA} now, put r = 0.5m , T = 2π secso, 2π = 2π√{0.5/10cosA}⇒1 = 1/20cosA⇒ cosA = 1/20so, A = cos⁻¹(1/20)hence, angle of inclination = cos⁻¹(1/20)

Let the initial velocity of the object = u

Let the object is moving with uniform acceleration, a.

Let object reaches at point B after time, t and its final velocity becomes, v

Draw a line parallel to x-axis DA from point, D from where object starts moving.

Draw another line BA from point B parallel to y-axis which meets at E at y-axis.

Let OE = time, t

Now, from the graph,

BE = AB + AE

⇒ v = DC + OD (Since, AB = DC and AE = OD)

⇒ v = DC + u (Since, OD = u)

⇒ v = DC + u ------------------- (i)

Now, Acceleration (a)=Change in velocityTime taken=Change in velocityTime taken

⇒a=v−ut

⇒a=OC−ODt=DCt

⇒at=DC⇒

By substituting the value of DC from (ii) in (i) we get

v=at+u

⇒v=u+at

Above equation is the relation among initial vlocity (u), final velocity (v), acceleration (a) and time (t). It is called first equation of motion.

Equation for distance –time relation

Distance covered by the object in the given time ‘t’ is given by the area of the trapezium ABDOE

Let in the given time, t the distance covered by the moving object = s

The area of trapezium, ABDOE

Equation for Distance Velocity Relation: Third equation of Motion:

The distance covered by the object moving with uniform acceleration is given by the area of trapezium ABDO

Therefore, Area of trapezium ABDOE

Weight = 350 NHeight = height of one step x no. of steps = 0.2 x 30 = 6 mWork done = P.E = mghWork done = 350 x 6 = 2100 JPower = Work done/Time = 2100/60 [ 1 min = 60 sec.] = 35 W

Parallax is a displacement or difference in the apparent position of an object viewed along two different lines of sight, and is measured by the angle or semi-angle of inclination between those two lines

Theparallax angleis theanglebetween the Earth at one time of year, and the Earth six months later, as measured from a nearby star. Astronomers use thisangleto find the distance from the Earth to that star..

Items made of plastic or paper generally float.Metal items sink.I hope this is what you are looking for.

It is the unit of distance. Parallactic second is nothing but what we call “Parsec” .1ps =3.08567758x10^16 metres

1/2 kx2= 1/2 mv2

1/2 X 100 X x2= 1/2 X 16 X (4)2

50 X x2= 256/2

x2= 128/50

x2= 2.56

x = 1.6

so, the spring is compressed 1.6 m

i am not clear with your answer sorry please sent again

(1) The force must not cause displacement in its own direction. (2) The force must act at right angle to direction of displacement.

Given: speed = 60km/hrTime (t1)= 1hr , time(t2)=30min= 30/60= 1/2 hr

Distance travelled by a car in East direction(s1)= speed× t1 = 60× 1= 60km

Distance travelled by a car in south direction(s2)= speed× t1 = 60×1/2= 30 km

Displacement from intial position(s)= √(s1)²+(s²)²= √ (60)²+(30)²= √3600+900= √900(4+1)= 30√5 Displacement= 30√5km_____________________________The displacement of car from initial position is 30√5km

Dewforms when the radiational cooling of objects near or on the ground also cools the shallow layer of air that comes in contact with them, causing the condensation of some water vapor.

Dew forms when the radiational cooling of objects near or on the ground also cools the shallow layer of air that comes in contact with them, causing the condensation of some water vapor. The atmosphere supplies most of the water vapor, but some also can diffuse up through the soil and condense on the ground. The temperature at which condensation begins is termed the dew point. The best conditions for dew formation are high humidity in the lowest layers of air and the absence of a strong wind, which would create a larger, more homogeneous layer ofair.

Forceis the rate of change in momentum. Hence theunit of forceis theunitof rate of change in momentum. In SI system ofunits,unit of forceis kg.m/s^2.(unitof rate of change of momentum).

4×10^-10 N

Any diagram provided?

No

what is the answer sandip

can u please explain me once again

thank u i understood

Let us take that the pendulum is at rest initially and after the collision the velocity of the system is V .Now from the conservation of momentum we have ,Initial Momentum = Final Momentum⇒mv+m×0=⎛⎝⎜m+m⎞⎠⎟×V⇒mv=2mV⇒V=v/2Nowletustakethattheblockrisestomaximumheighth.So,P.Eofthecombination=K.Eofthecombination⇒(m+m)gh=1/2(m+m)V2⇒2mgh=mV2⇒h=V2/2g⇒h=(v/2)2/2g=v2/8g

T = F×r = { i×j } = +k

and +k denotes +Z axis

so, option 1