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the answer could be option b

b is the correct answer.

F = ( Centripetal Force ) v is the Tangential Velocity r is the Radius of circler = 50cm = 0.5 mv = 1m s⁻¹F = ma = mv² r ⁻¹a = v² r⁻¹

Therefore, Centripetal Acceleration = ( 1 )² / ( 0.5 ) = 2m s⁻²

(b) is correct option

The focal length of the lens is

(2) 100is a correct answer

Option 3 is the right answer.....

The measure of the ability of a conductor to store charges is known as capacitance or capacity.qαVqαVorq=CVq=CVIf V = 1 volt, then C = qCapacitance of a conductor is defined as the charge required to raise itspotentialthrough one unit.SI Unit of capacitance isfarad

no.it can niether be created nor b destroyed

Magnesium chloride a ionic compound is formed by the transferring of electrons.magnesium having 2 valence electron and chlorine having 1 valence electron are interchanged with each other so the resultant compound is the MgCl2.

Also in order of being an ionic compound and the due the presence of free electrons it conducts electricity

Some liquids such as oil or alcohol do not form ions and do not conduct electricity.Vinegaris mostlywater with a small amount of acetic acid in it. The acetic acid separates into ions on so that the solution conducts electricity.Tap watermay or may not conduct electricity depending on its hardness.

this question is in options

A. lemon juiceB. sugar solutionC. distilled waterD. dilute hydrochloric acid

Mechanism ofphototherapy: Blue-greenlightin therangeof 460-490 nm is most effective forphototherapy.

The force exerted on a body in circular motion is known as Centripetal Force. It is directed towards the center of the circular path.

Ans doesnot match

= Moment of force is given by= Force * Distance through which the force has been applied = 4 * 1.5 = 6 Nm.

force=ma=3×8/2=3×4=12N

Young’s double slit experiment uses two coherent sources of light placed at a small distance apart, usually, only a few orders of magnitude greater than thewavelength of lightis used. A screen or photodetector is placed at a large distance ’D’ away from the slits as shown.The original Young’s double slit experiment used diffracted light from a single source passed into two more slits to be used as coherent sources. Lasers are commonly used ascoherent sourcesin the modern-day experiments.Each source can be considered as a source of coherentlight waves. At any point on the screen at a distance ‘y’ from the centre, the waves travel distancesl1andl2to create a path difference of Δl at the point in question. The point approximately subtends an angle of θ at the sources (since the distance D is large there is only a very small difference of the angles subtended at sources).

angular fringe width

(1) using relation v = u + at v = final velocity u = initial velocity a = acceleration t = time taken

v = 0 + 2*5 = 10 Therefore, velocity after 5 seconds is 10 m/s

(2) using relation s = ut + 1/2at^2 s = 0*5 + 1/2*2*(5)^2 s = 0 + 25 = 25 Therefore, distance covered is 25 m

The formula is

Sn= u+a/2(2n-1)

For t=n=3

S3= 0+10/2(5)S3= 50/2 m

Similarly,

S4= 0+10/2(7)

S4= 70/2m

S3/S4= 50/2×2/50

S3:S4= 5:7

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option B is correct

why

If we assume constant acceleration then s=ut+0.5at^2

where s is distance, u is initial velocity and t is time.

In this instance I will call distance at 5 seconds s5, and at 6 seconds s6.

We know that s6-s5= 1.2m (using metres to be consistent throughout)

s5=ut+0.5at^2 , t=5, u=0 so…

s5=0.5*a*25=12.5a

and

s6=ut+0.5at^2, t=6, u=0

s6=18a

so now we know that s6=18a, s5=12.5a and s6-s5=1.2

from this we can work out that 5.5a=1.2 and therefore a=1.2/5.5

Acceleration is 0.218 ms^-2

Weight : Quantity of matter contained by it, giving rise to a downward force.

i.e; W = mg

As mentioned m = 5 kg, and also we know the acceleration due to gravity on earth is g = 9.81 m/s^2 .

Hence we can get Weight W = 49.05 N.

Weight: Quantity of matter contained by it, giving rise to a downwardforce.Asyou've mentioned m =5 kg, and also we know the acceleration due to gravity on earth is g = 9.81 m/s^2 . Hence we can getWeightW = 49.05 N.Ifabodyofmass1 kg has aweightof 10 N at a certain place, what will be theweightof 100 g?

Weight: Quantity of matter contained by it, giving rise to a downwardforce.Asyou've mentioned m =5 kg, and also we know the acceleration due to gravity on earth is g = 9.81 m/s^2 . Hence we can getWeightW = 49.05 N.Ifabodyofmass1 kg has aweightof 10 N at a certain place, what will be theweight

49.05 is right answer of this question

Mass = 200g = 0.2kginitial velocity (u)= 10 m/s^2final Velocity (v)= 5 m/s^2

Now to Find change in momentum:

Change in momentum(p)= m(v-u) = 0.2(10-5) = 0.2 x 5 = 1 kg m/sec✓ the change in momentum occured in the motion of the hockey ball by the force applied by the hockey stick is 1 kg m/s

thanx v much

2 ) is the correct answer

2) is the right answer of the following

(1) is right answer