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electric field intensity due to infinite long wire is given by E = λ/2π∈₀r , where r is distance between wire and observation point.

So, electric field due to 1st wire at P , E₁ = λ₁/2π∈₀x electric field due to 2nd wire at P, E₂ = λ₂/2π∈₀y So, Enet = √{E₁² + E₂²} = 1/2π∈₀ [λ₁²/x² + λ₂²/y²]½

Hence, answer is Enet = 1/2π∈₀ [λ₁²/x² + λ₂²/y²]½

(d) is the answer that you are looking for

D is the right answer of this question

λ= h/mv [de-Broglie wavelength]

From E = hv [Plank's equation]

h = E/v

Write the dimension of each quantity in the above relation

λ = wavelength = [L] ,

h = Energy / frequency = Energy x time = [ML2T-2][T] = [ML2T-1]

mv = mass x velocity = momentum = [MLT-1]

--

LHS = [L]

RHS = [ML2T-1] / [MLT-1] = [L]

We see that dimensions of both sides are equal to [L]

The given relation is correct.

λ= h/mv [de-Broglie wavelength]

From E = hv [Plank's equation]

h = E/v

Write the dimension of each quantity in the above relation

λ = wavelength = [L] ,

h = Energy / frequency = Energy x time = [ML2T-2][T] = [ML2T-1]

mv = mass x velocity = momentum = [MLT-1]

--

LHS = [L]

RHS = [ML2T-1] / [MLT-1] = [L]

We see that dimensions of both sides are equal to [L]

The given relation is correct.

v=vsin53=3v/4 (1) is correct answer

gff37_+684+/46$-&775+68

3v/4 is correct answer for this

3v/4 options (1) is the right answer of the following

3v/4 is the correct answer

chfvligbhtofvmy 5uib68hv

abe pagal he kya

option (c) is correct.

The horizontal component of falling rain is 40km/hrnow convert km/hr into m/s

40*5/18=11.11m/s

vertical component of falling the rain is 20 m/s

Q=tan^-1(horizontal/vertical)

Q=tan^-1(11.11/20)

how you got 100/9 ?

the horizontal component of falling rain is 40km/hrnow convert km/hr into m/s

40*5/18=11.11m/s

vertical component of falling the rain is 20 m/s

Q=tan^-1(horizontal/vertical)

Q=tan^-1(11.11/20)

Suppose horizontal direction is represented byiunit vector.

Suppose vertical direction is represented byjunit vector.

Vc = Velocity of car with respect to earth is 40ikm/hr.

Vr = Velocity of rain with respect to earth is 20jm/s = 72jkm/hr.

Suppose the angle required is taken to be Q.

tan Q = Vc / Vr = 5/9.

hence, option (a) is correct.

Let Two bodies m₁ and m₂ moves with speed v₁ and v₂ , collide after some interval of time and new bodies of mass (m₁ + m₂) form and it moves with v velocity as shown in figure.

now, There is no external force act on Bodies so, linear momentum of bodies are conserved . so, initial momentum = final momentum m₁v₁ + m₂v₂ = (m₁ + m₂)v ----(1)

Now, change in kinetic energy = final kinetic energy - intial kinetic energy = 1/2(m₁ + m₂)v² - 1/2m₁v₁² - 1/2m₂v₂² Putting equation (1)= 1/2(m₁ + m₂)[(m₁v₁ + m₂v₂)/(m₁ + m₂)]² - 1/2m₁v₁² - 1/2m₂v₂² = 1/2[m₁v₁ + m₂v₂]²/(m₁ + m₂) - 1/2m₁v₁² - 1/2m₂v₂² = 1/2[ (m₁²v₁² + m₂²v₂² + 2m₁m₂v₁v₂ - m₁²v₁² - m₁m₂v₁² - m₂²v₂² - m₁m₂v₂²)]/(m₁+m₂)= 1/2[2m₁m₂v₁v₂ - m₁m₂v₁² - m₁m₂v₂² ]/(m₁ + m₂) = -1/2{m₁m₂/(m₁+m₂)}(v₁²+v₂²-2v₁v₂) = -1/2μ (v₁ - v₂)²

where μ = m₁m₂/(m₁ + m₂) here negative sign shows that kinetic energy is lost .

Ty😘

Momentum is conserved in both types of collisions, but kinetic energy is "conserved" in only elastic collisions. This means that if you tally the kinetic energies of both object just before the interaction starts and just after it ends, you'g get the same amount only in elastic collisions. This assumes that nothing else acts on the objects to increase or decrease kinetic energies.

Almost any collision you observe on a human scale will be inelastic. Examples include, tackles in football, a bat hitting a baseball, two cars colliding and even a superball bouncing on a hard surface. The most inelastic collisions are ones in which the two objects end up at rest relative to one another. A bullet shot into a tree would be one case. The final kinetic energy is nearly zero.

Most collisions between air molecules are perfectly elastic. Otherwise considering how fast and how close together these molecules are, there would be so many collisions losing little bits of energy that in only minutes to hours our atmosphere would cool into a liquid or even a solid state.

The "field collisions" (objects interacting with gravitational or electric fields) known with the name of the slingshot effect are just about perfectly elastic.

To contrive an elastic collision on a human scale suspend two magnets as pendulums in such a way that when they are allowed to swing toward each other, magnet repulsive forces cause them to bounce away from each other without touching.

A perfectly elastic collision is defined as one in which there is no loss of kinetic energy in the collision.

A perfectly elastic collision is defined as one in which there is no loss of kinetic energy in the collision.

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is same in both cases

1. Car crash : the car crashing against the tree is the example of inelastic collision as the kinetic energy is not conserved here. The car stops.

2.The collision between two objects such that after the collision both stick to each other and hence move with the same velocity.3. The bullet hitting wood is also an example of inelastic collision. The kinetic energy is not conserved in this case also.

4. Seat belt tied to a person and the sudden application of breaks is also an example of inelastic collision.

Collisions come in two main types ‘“ elastic and inelastic collisions. An elastic collision is a collision where the colliding objects bounce back without undergoing any deformation or heat generation. An inelastic collision is a collision where the colliding objects are distorted and heat is generated.

In an elastic collision, the momentum and total kinetic energy before and after the collision is the same. In other words, it can be said that the total kinetic energy and momentum are conserved during the elastic collision. So there is no wasting of energy in an elastic collision. An example of an elastic collision is the movement of the swinging balls.

In an inelastic collision, the energy changes into other energies such as sound energy or thermal energy. In an inelastic collision, the energy is not conserved. An example of an inelastic collision is an automobile collision.

Some of the characteristics of elastic collisions are as follows: kinetic energy is conserved, linear momentum is conserved, and total energy is conserved. The forces during an elastic collision are conservative, and the mechanical energy is not transformed into some other form of energy such as sound energy or thermal energy.

Some of the characteristics of inelastic collisions are as follows: kinetic energy is not conserved, linear momentum is conserved, and total energy is conserved. The forces during inelastic collisions are non-conservative, and the mechanical energy is transformed into some other form of energy such as sound energy or thermal energy.

B) the correct answer

our School bag... is the answer

Ans :- It isdifficult to hold a school bag havinga strap made of a thin and strong string because the area under the strap is small. Due to the large pressure, the strap tends to cut the skin and hence pain is caused.

this is because, pressure is inversely proportional to areatherefore ,thin and stronger string will exert more pressure and hence it is difficult to hold it.

It isdifficult to hold a school bag havinga strap made of a thin and strong string because the area under the strap is small. ... Due to the large pressure, the strap tends to cut the skin and hence pain is caused

Ans :- Surface tension gives them their near-spherical shape because a sphere has the smallest possible surface area to volume ratio. Formation of drops occurs when a mass of liquid isstretched.

their answer is mass

ac = v^2 / R

15 cos 30° = V^2 / 2.5

V^2 = 32.73

V = 5.7 m/sec.

A force is said to be conservative if its work along a trajectory to go from a point Ato a point B is equal to the difference U(A)−U(B) where U is a function called potential energy. This implies that if A=Bthen there is no change in potential energy. This fact is independent of the increase or not of the kinetic energy. If a conservative force were to form loops, it could provide a non zero net work (because the direction of the force could always be the same as that of the looping trajectory) to go from A and then back to A, while at the same time its conservative character would ensure that this work should be zero; which is a contradiction.

Hence, "conservative force" and "forming loops" are two incompatible properties that cannot be satisfied at the same time.

And electrostatic fields are conservative in nature and hence do not form close loops.

In given fig.

I1 + I2 = I3 + I4

2 + 5 = 1.5 + X

X = 7 - 1.5

X = 5.5 A

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A habit is a routine of behavior that is repeated regularly and tends to occur subconsciously. The American Journal of Psychology defines a "habit, from the standpoint of psychology, [as] a more or less fixed way of thinking, willing, or feeling acquired through previous repetition of a mental experience."

Option (c) Because the mass of CO2 is= 6+(16×2) = 6+32= 38

answer (c) 6+(16×2)=6+32=38

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D to E line is not realistic as distance cannot be decreased

The principle is that the slope of the line on a velocity-time graph revealsusefulinformation about the acceleration of the object. If the acceleration is zero, then the slope is zero (i.e., a horizontal line). If the acceleration ispositive, then the slope ispositive(i.e., anupwardsloping line).

7 as distilled water is neutral

The formula for reactance of series LC combination is

Z = (xC -xL) = 1/ωC -ωL so, the best representation is 4th one

so , option D

W= Q. V = 2(128-118)2.10 20joule

it means light years

Ohm Law: the current through a conductor between two points is directly proportional to the voltage across the two points.

The slope of the V-I curve represents the Resistance of the conductor.