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Sound wavesare longitudinal waves: theairmoves back and forth along the same line as thewave travels, making alternate patterns of compressions and rarefactions.

Ocean wavesare transverse waves: the water moves back and forth at right angles to the line in which thewave travels.

If an object's speed (velocity) is increasing at a constant rate then we say it has uniform acceleration. The rate of acceleration is constant. If a car speeds up then slows down then speeds up it doesn't have uniform acceleration. Acceleration is the rate of change in velocity expressed mathematically as dv/dt = a.

An object moving at uniform or constant velocity has zero acceleration because there is no change in velocity.

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speed of train is 54km/h , so in m/s the speed will be 54*5/18 = 15m/s

now acceleration is =v/t =15/10 = 1.5m/s².

distance travelled is s = 1/2at² = 1/2*1.5*10*10 = 75m

Initial odometer reading=2000kmFinal odometer reading=2400kmTotal distance= Final distance- Initial distance=2400-200=400kmTotal time=8hAverage speed =?

Formula to be used :Average speed= Total Distance/Total time

Average speed in Km/hr:Average speed=400/8=50 km/hr

Average Speed in m/s:1km/hr=5/18 m/s∴50km/hr=50x5/18=250/18=13.88m/s

the average speed of car is 50km/h Or 13.9m/ s

Initial odometer reading=2000kmFinal odometer reading=2400kmTotal distance= Final distance- Initial distance=2400-200=400kmTotal time=8hAverage speed =?

Formula to be used :Average speed= Total Distance/Total time

Average speed in Km/hr:Average speed=400/8=50 km/hr

Average Speed in m/s:1km/hr=5/18 m/s∴50km/hr=50x5/18=250/18=13.88m/s

Initial odometer reading=2000kmFinal odometer reading=2400kmTotal distance= Final distance- Initial distance=2400-200=400kmTotal time=8hAverage speed =?

Formula to be used :Average speed= Total Distance/Total time

Average speed in Km/hr:Average speed=400/8=50 km/hr

Average Speed in m/s:1km/hr=5/18 m/s∴50km/hr=50x5/18=250/18=13.88m/s

my answer is 13.9 m-1

Heat Energy = Voltage*Current*time =230*3*30*60 Joules = 1242 kilojoules

Given,

Power = P = 400W = 400/1000 kW = 0.4 kW

Total time for which the refrigerator operated = t = 8 hours x 30 days = 240 h

Since, Energy consumed = P x t E = 0.4 x 240 kWh = 96 kWh

Therefore, total cost required to operate the refrigerator for the month = 96 x 5 = 480 INR.

Given,

Power = P = 400W = 400/1000 kW = 0.4 kW

Total time for which the refrigerator operated = t = 8 hours x 30 days = 240 h

Since, Energy consumed = P x t E = 0.4 x 240 kWh = 96 kWh

Therefore, total cost required to operate the refrigerator for the month = 96 x 30 = 2880 INR.

Option- A

1) 3.5 V is the correct answer

A is 3/4 is correct answer in this questions

b is 2 is Answers in this questions

Pressure is given asP=Force/Area=Mg/area=40*9.8/10*10 ^-4=39.2*10 ^-4 N/m2(10cm2=10*10 ^ -4m2

Thank you dear, you spent your valuable time to do my question.it is not just pressure, Average pressure.😊

P = VII = P/V = 40/220 = 0.18A

P = V×II = P/V

The formula we will use to calculate the current drawn by an electric bulb of 40W when it is connected to a source of 220V is -

I = P/V I = 40/220 I = 0.18 A

The current drawn by an electric bulb of 40W when it is connected to a source of 220V is 0.18A

CURRENT= P/V= 60/120=1/2=0.5 Ampresistance=v x v /P=120 X 120 /60240 OHM

Given,Forbulb,Power,P=100W,V=200V

Asweknow,P=V^2/R,R=V^2/P=200×200/100=400Ohm

So, For160Vsupply,asV=IRSo,I=160400=0.4A

PowerConsumption,P=V I=160×0.4=64W

momentum acquired is area under the graph = 10*5 + 1/2*10*4 = 50+20 = 70N-s.

option C

We are able to see the sun 2 minutes before theactualsunrise and 2 minutes after theactual sunsetdue to refraction of light by the atmosphere. ... Thus, thetime difference between actual sunsetand theapparent sunsetis about 2 minutes.

The layers of air nearer to earth are denser than those above it. At sunrise and sunset when the sun is below the horizon, the light rays starting from sun are incident on these layers. They pass through successively denser layers and thus get bent more and more towards the normal until they fall upon the eye of the observer O. To the observer O these rays appear to come from S’ which is above horizon. It is for this reason that the sun is visible to us a little before it rises above the horizon and so also till a little later it sets below the horizon. The difference of time is about 2 minutes each for early rise and late setting of the Sun

Advanced sunrise and delayed sunsetThesunriseisadvanceddue to atmospheric refraction of sunlight. An observer on the earth sees the sun two minutes before the sun reaches the horizon. A ray of sunlight entering the earth's atmosphere follows a curved path due to atmosphere refraction before reaching the earth

Within the visible range of light,redlight waves are scattered the least by atmospheric gas molecules. So atsunrise andsunset, when the sunlight travels a long path through the atmosphere to reach our eyes, the blue light has been mostly removed, leaving mostlyredand yellow light remaining.

becoz of spectrum of light with atmospheric molecule

For voltage to get 440V from 220V , we need to connect 2 capacitors in series.

but, on connecting these 2 in series, the resultant will become Half i.e = 3μF.

so, we need to connect 4 rows of 3μF resutant capacitors in parallel to get 4*3 = 12μF capacitance.

there total capacitance needed is 4*2 = 8

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Velocity of police van( Vp) = 30 km\ h= 25/3 mpsVelocity of theif ( Vt) = 192 kph = 160/3 mpsMuzzle velocity ( Vbg) = Vb - Vg = 150 mps Vg = Vp = 25/3 mpsVb = 475/3 mpsDamaging speed = velocity of bullet with respect to thief car = Vbt = Vb - Vt = 475/3 - 160 /3 ` = 105 mps

how u get the value 25/3

Duration isan amountof timeor a particulartime interval whilelength isthe measurementofdistance along the longest dimensionofan object.

difference

As nouns thedifference between durationandlength.isthatduration isan amountof timeor a particulartimeinterval whilelength isthe measurementofdistance along the longest dimensionofan object.

1) It depends on shape of the object. The shadow increases and decreases in the ratio same as the shape of the object.2)It depends on source of light whether it is plane parallel rays or spherical.3) It depends on position of the object whether the object is at infinite or finite distance.4) It depends on the position of source of light.If the source of light is kept closer to the object the shadow will be smaller and if it farther then shadow will be longer

The new time period is given by T₁ = √3T/2

Explanation:

Case I

string length = l

string is stretched to 2l, so net increase in length = 2l - l = l

=> spring force, F = kl

where k = spring constant

when the string is rotated with 2l radius,

we know that centripetal force is given by,

F = mrω² = m x 2l x (2π/T)²

Since the centripetal force and spring force should be equal, hence,

kl = m x 2l x (2π/T)²

=> k = 2m x (2π/T)².............eq1

Case II

string length = l

string is stretched to 3l, so net increase in length = 3l - l = 2l

=> spring force, F = k x 2l = 2kl

when the string is rotated with 3l radius,

we know that centripetal force is given by,

F = mrω₁² = m x 3l x (2π/T₁)²

Since the centripetal force and spring force should be equal, hence,

2kl = m x 3l x (2π/T₁)²

=> k = 3m/2 x (2π/T₁)².............eq2

equating eq1 and eq2 we get:

2m x (2π/T)² = 3m/2 x (2π/T₁)²

=> T₁²/T² = 3/4

=> T₁ = √3T/2

Hence the new time period is given by T₁ = √3T/2

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F = ma,m = 20kg Let force of friction = f, it always resists the motion & 1st the body moves wth uniform velocity by action of force p means acceleration is 0, ie p - f = 0,-> f = p &in 2nd time 1.2p - f = 1.2p - (p) = 0.2p = 20 *0.05 = 1N --->p = 1/0.2 = 5N

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The horizontal floor has a frictional force F that inhibits the movement of the cart.

Acceleration of cart = P - F = 0 as the cart moves with constant velocity and acceleration is 0 So F = P

When a force of 1.2 P acts on the cart, acceleration a of the cart is 1.2 P - F = m a 1.2 P - P = 20kg * 0.05 m/sec²

P = 1/0.2 = 5 Newtons

W=Fdcos angleW= 10×10cos60W= 100×1/2W= 50J