InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4501. |
The work done by a body is directly proportional to(A) force acting on the body(C) mass of the body(B) displacement produced in the bodyboth (A) and (B) |
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Answer» option D is the answer. Sir please tell the reason |
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| 4502. |
Convert an acceleration of 100 mis into km/hr |
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Answer» 100 m/s² = 0.1km/(1/60*1/60)² = 3600*3600*0.1 = 1296000 km/hr² |
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| 4503. |
A river 400 m wide is fowing at a rate of 20 mis Aboat is sailing at a velocity of 10 mis with respect to thewater, in a direction perpendisular to the river la) Findthe time taken by the boat to reach the(b) How far from the point direetly epposite to thestarting point doee the beet reach the opposite bank ?opposite bank |
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| 4504. |
9Pwhy pazH0) A balloon is inflated and released. Why does it ly forward as air escapes out of iforce on an object immersed in a liqaid act? |
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Answer» The case of deflating balloon can be explained by Newton's third law of motion.As the air escapes the balloon, it provides an equal and opposite reaction which makes the balloon move forward. |
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| 4505. |
why surface tension is independent of area ? |
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Answer» dont tell this answer using formula answer it using feelingfeel aani chahiya answer logically explain kro Logic and formula are the same.So do you want a logical answer or an explanation? both i want both That's because surface tension is due to intermolecular attraction between the molecules so change in temp results in change in kinetic energy of molecule which further affects attractive force between molecules.But intermolecular attraction has nothing to do with area of surface so it is not dependent on area. how length depends on surface tension ?explain without using formula. how length depends on surface tension ?explain without using formula. |
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| 4506. |
Listfourertiesldepenasrbepropofsurface tension of liquids?) Show with the help of necessarymathematical calculations thatincreasing the surface area of a free surface by gne unit?surface tension of a liquid is equal to the work done inIve |
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Answer» Surface tension is the energy required to increase the surface area of a liquid by a unit amount .Molecules in the interior experience an attractive force from neighboring molecules which surround on all sides Molecules on the surface have neighboring molecules only on one side (the side facing the interior) and thus experience an attractive force which tends to pull them into the interior The surface of the liquid will rearrange until the least number of molecules are present on the surface .The surface molecules will pack somewhat closer together than the rest of the molecules in the liquid |
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| 4507. |
15. Define surface tension. Give the SI unit and dimensional formula of surface tension.016 What is effluy velocity2 Water flows out of a small hole in the wall of a large tank naar te hatta |
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Answer» Surface tension is the force per unit length (or surface energy per unit area) acting in the plane of the interface between the plane of the liquid and any other substance. It is also the extra energy possessed by the molecules at the interface compared to that possessed by the molecules in the interior.This tends to minimise the area of the surface. The SI unit of surface tension is N/m or J/m2. Its dimensional formula is MT−2. |
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| 4508. |
1. The dimensional formula of surface tension is ................ |
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Answer» Surface Tension= Force/LengthDimensional Formula of Force= M1L1T-2Divide it by Length L1 So Dimensional Formula of Surface Tension = M1L0T-2 |
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| 4509. |
How does the surface tension vary with temperature |
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Answer» The surface tension of a liquid decreases with rise in temperature. There is a particular temperature at which the surface tension of a liquid becomes zero. This temperature is called the critical temperature of a liquid. |
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| 4510. |
State the C.G.S. and SI Unit of surface tension. |
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Answer» Surface tension, usually represented by the symbol σ, is measured in force per unit length. Its SI unit isnewton per meter and the cgs unit is dyne per centimeter. Please hit the like button if this helped you. |
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| 4511. |
I. A block of 10 kg is pulled by a constantrough horizontal surface by a force ofcoefficient of friction isspeed on a19.6 N. TheAns. 0.2] |
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| 4512. |
A solid sphere of radius 'R' and maspurely on rough horizontal surface. If itswall elastically then angular momentum ofjust after strike isnd mass 'm' rollsit strikes theintum of sphere(1) 17 MVR(2) MVR(3) - MVR(4) mVoR |
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Answer» 2) is the correct answer a is the correct answer |
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| 4513. |
R et 1८4 समरूप R जिनमें प्रत्येक की धारिता 5८7८4. है मिलकर &हैं। बड़े बुँद की धारिता क्या होगी ? |
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Answer» Capacitance for drop => धारिता होगीR/k where R is the radii. जहां trizya R है From Volume conservation, आयतन संरक्षण नियम के अनुसार Vnet = 64V R^3 = 64r^3 R = 4r For big drop, बड़ी बूंद के लिए please like the solution 👍 ✔️👍 C = R/k.......(1) For small dop, छोटी बूंद के लिए 5 = r/k........(2) Divdng the eqns. we get, भाग देने पर हमें प्राप्त होगा C = 5*(R/r) => 5*4 = 20 mF. |
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| 4514. |
9. The force of buoyancy exerted by the atmosphere on aballoon is B in the upward direction and remainsconstant. The force of air resistance on the balloon actsopposite to the direction of velocity and is proportionalto it. The balloon carries a mass M and is found to falldown near the earth's surface with a constant velocityv. How much mass should be removed from the balloonso that it may rise with a constant velocity v? |
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| 4515. |
.6 A body of 0.02 kg falls from a height of 5 metre into a pile ofsand. The body penetrates the sand a dístance of 5 em beforestoping. What force has the sand exerted on the body |
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| 4516. |
et 11. What is the name given to push or pull exerted on abody? |
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Answer» A pull or push exerted on a body is called force. |
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| 4517. |
35.A body, having kinetic energy k, moving on a rough horizontal surface, is stopped in a distance x.The force of friction exerted on the body is(4) kx6/16 |
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Answer» From Work Energy Theorem, Wtotal = change in kinetic enrgy -f*x = 0 – k f = k/x is the required friction force. |
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| 4518. |
2. Consider the situation of the previous problem. Take"the table plus the ball" as the system. Friction betweenthe table and the ball is then an internal force. As theball slows down, the momentum of the system decreases.Which external force is responsible for this change inthe momentum ?o |
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| 4519. |
.Abody,starting from rest and moving with aconstant acceleration, covers a distance s, in the4" second and a distance s, in the 6" second. Theratio s,/s; is.o0 O (29 (c) |
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Answer» Distance covered in nth is Sn= u+a/2(2n-1) For n=3, u = 0 S4 = 0 + a/2(2*4 - 1)S4 = 7a/2 m Similarly, For n=6, u = 0S6= 0 + a/2(2*6 - 1) S6 = 11a/2 m S4/S6 = 7a/2*2/11a S4:S6 = 7:11 (d) is correct option |
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| 4520. |
uuntheTriends51. Suppose A and B in the previous problem change theinpositions in such a way that the line joinjng thanbecomes perpendicular to the direction of wind whilemaintaining the separation x. What will be the time laeby A ?B finds between seeing and hearing the drum beatine |
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| 4521. |
1. Definite lateral strain, and Poisson's ratio. |
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Answer» lateral strain, also known as transverse strain, is defined as the ratio of the change in diameter of a circular bar of a material due to deformation in the longitudinal direction. Poisson's ratio is the ratio of the proportional decrease in a lateral measurement to the proportional increase in length in a sample of material that is elastically stretched. |
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| 4522. |
ohat is definite integral andtheir formula with example |
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Answer» Thedefinite integralof a function is closely related to the antiderivative and indefinite integral of a function. The primary difference is that the indefinite integral, if it exists, is a real number value, while the latter two represent an infinite number of functions that differ only by a constant. The relationship between these concepts is will be discussed in the section on the Fundamental Theorem of Calculus, and you will see that the definite integral will have applications to many problems in calculus. let me example |
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| 4523. |
ean Ja moan. Hualso calerlota a due doaon moA |
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Answer» Can u say me which formula have u applied |
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| 4524. |
foA bodgiven byrce(NCERT) ;y constrained to move along the z-axis of a coordinate system is subject to a constantwhere ĂŽ, j, k are unit vectors along the x-, y- and z-axis of the system respectively. What is the workdone by this force in moving the body a distance of 4 m along the z-axis? |
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| 4525. |
8. A ball dropped from a balloon at rest cltower 81 m high during the lastof its journey. Find the height of the alldand the velocity of the body when itthe ground.quarter secoreacheAns 2684.2 m 324 30 |
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Answer» The last quarter of the jouney means 1/4th of the total time it requires in its total journey. Let total time be 4t, u = 0. So, v at 3t = 3gt, and at 4t = 4gt. by v² = u² + 2as, 16g²t² = 9g²t² + 2g(81) 7g²t² = 162g 7gt2= 162 t² = 162 / 7g t = 1.5 sec. but time is 4t = 6 sec. So velocity on reaching = 4gt =58.8 m/s With this velocity, height of fall = 2t(58.8) =705.6m |
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| 4526. |
A point is on the x-axis. What are its y-coordinate and z-coordinates ?1.to 92 |
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| 4527. |
12.A metallic wire of resistance R is cut into 10 parts of equallength. Two pieces each are joined in series and then five suchcombinations are joined in parallel. What will be the effectiveresistance of this combination. |
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Answer» Resistance of 10 equal parts = 1/10Rresistance of two 1/10 parts joined in series = 1/5Rlet equivalent resistance be Rp1/Rp = 1/1/5R*51/Rp = 25RRp = 1/25R |
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| 4528. |
From a rifle of mass 4kg, a bullet of mass 50gm is fired with an initial velocity 35m/sec.calculate the initial velocity of the rifle |
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| 4529. |
A ball is thrown horizontally from a height of20 m.It hits the ground with a velocity three times its initialvelocity. The initial velocity of ball is(A) 2 m/s(C) 5 m/s(B) 3 m/s(D) 7 m/s |
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| 4530. |
TCH THE FOLLOWINGColumn A1. Convex mirror2. Concave mirror3. Sir Issac Newton4. Shaving mirror5. Rear view mirror in vehiclesColumn B(a) dispersion of white light(b) convex mirror(c) diverging mirror(d) real focus(e) concave mirroru Trends in ICSE Physics -8 |
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Answer» 1. d2. c3. a4.e5.b |
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| 4531. |
Calculate the horse power of a man who canchew ice at the rate of 30 g per minute. Given 1 hp 746 Wand J =4.2 J cal 1. |
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Answer» so in watt horse power divide the watt by 746 |
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| 4532. |
EXERCISE 3.2Find the values of other five trigonometric functions in Exercises I1. cos x =--, x lies in third quadrant.2, sin x = , x lies in second quadrant.3. cot x =-, x lies in third quadrant.4. sec x=-, x lies in fourth quadrant.5. tan x lies in second quadrant.1312Find the values of the trigonometric functions in Exercises 6 to 10.6. sin 7657. cosec ( 1410°)19π11π9. sin )8. tan15π10. cot (-) |
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Answer» Kindly post one question per post to experience the instant solution feature of scholr at its best. see, which u can give answer of that. |
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| 4533. |
efine - coefficient of linear expansion, coefficientof superficial expansion and coefficient of cubicalexpansion of solids. State their units. |
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Answer» 1.TheCoefficient of linear expansionof the given solid is denoted as a. then for aunitis per degree Celsius) in the CGS and in the SI system it is per kelvin K-1.The coefficient of linear expansion is the change in length of a specimen one unit long when its temperature is changed by one degree. 2. The amount by whichunitarea of a material increases when the temperature is raised by one degree is called thecoefficient of superficial(i.e. area)expansionand is represented by β (Greek beta).The coefficient of superficial expansion is defined as the increase in area per unit original area at 00c per unit rise intemperature. 3.Increase in volume of a body on heating is referred to as. "VOLUMETRICEXPANSION" or "CUBICAL EXPANSION". Consider a metallic body of volume = V1 . Let it's temperature is raised by T. then experimentally "Increase in volume ( V) is directly proportional to its initial volume (V1) and rise in temperature ( T). |
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| 4534. |
A man standing on a road has to hold his umbrella at 30° with the vertical to keep the rain away. He throws the umbrella and starts running at 10 km h-1.He finds that raindrops are hitting his head vertically The actual speed of raindrops is |
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Answer» See we have constructed this vector diagram,whereVris the velocity of rain,Vmis the velocity of man, andVrmis the velocity of rain w.r.t man. So,using Lami's theorem, Vm/sin30=Vrm/sin60so,(Vrm)=Vm sin60/sin30=10⋅√3=17.31Km/hr |
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| 4535. |
A man standing on a road has to hold his umbrella at 37°with the vertical to keep the rain away. He throws theumbrella and starts running at 12 km/h. He finds thatraindrops are hitting his head vertically. Find the speed (inkm/hr) of raindrops with resepect to the moving man. |
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Answer» When the man is at rest w.r.t. the ground, the rain comes to him at an angle 37° with the vertical. This is the direction of the velocity of raindrops with respect to the ground. Here v→rg=velocity of rain with respect to the ground v→mg= velocity of the man with respect to the ground. and v→rm=velocity of the rain with respect to the man, We have v→rg=v→rm+v→mg ......(i) Taking horizontal components equation (i) gives vrgsin37∘=vmg3/5 can you please explain it in detail and the solution is incomplete |
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| 4536. |
22. A calorimeter takes 200 cal of heat to rise its temperature through 10°C, Its water equivalent in gmis1) 22) 103) 204) 40 |
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Answer» 1cal=4.186jouls....So you calculate 200cal heat rises temperature into 10 degrees..So we change it into kelvinscale.. |
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| 4537. |
6. A car of mass 1000 kg travelling at 30 m/s stops aftera distance of 50 m, decelerating uniformly. What isthe force exerted by it on the brakes? What is thework done by the brakes? Ans. 9000 N, 4.5 x 105 |
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Answer» Givenm=1000kgu=30m/ss=50m v=0 v^2-u^2=2asa =( v^2-u^2)/2sa= (0^2-30^2)/2×50a= -900/100a= -9m/s^2retardation=9m/s^2 Force exerted by brakes = Mass×Retardation =1000×9 =9000N (Ans) Work exerted by brakes = Retarding force×Displacement = 9000×50 = 4.5×10^5J (Ans) |
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| 4538. |
A ball is projected at an angle of 30° and 60° to thehorizontal with the same initial velocity in each case.Ratio of their times of flight is32.(3) 1: V3(4) 2: V3 |
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Answer» time of flight is directly proportional to sinthetahenceT1/t2=sintheta1/sintheta2=sin30/cos60=1/2/1/2=1:1 |
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| 4539. |
A body weighing 1,000kg accelerates uniformly from 10m/s to 20m/s. Find the amount of work doneduring this period.[(150kl]4. |
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Answer» Kinetic energy=1/2mv2change in velocity means=1/2mv2- 1/2mu2 ( v= final , and u=intial)taking common, we get=1/2m(v2-u2)=1/2*1000(202-102)=500*300=150000J thz |
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| 4540. |
A bike accelerates uniformly from rest toa speed of 7.10 m s^-1 over a distance of35.4 m. Determine the acceleration of thebike. |
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Answer» I think this is the answer. I think this is the answer. I think this is the answer. |
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| 4541. |
distanc=100 m, time=15 min ,calculate speed km/h |
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Answer» Distance = speed * timeDistance = 100 m = 100/1000= 1/10 kmTime = 15 min = 15/60 = 1/4 hrSpeed = Distance /time = (1/10)÷(1/4) = 4/10 = 2/5 km/hr |
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| 4542. |
he angular displacement of a particle is givenbyD. Tθ = t3 + t2 + t + 1 then, its angular velocityat t 2 sec is. rads1) 27In the above problem, the angular accelerationof the particle at t 2 sec is.. rads2) 173) 154) 16.2 |
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Answer» angular velocity is d∅/dt = 3t²+2t+1 at t = 2sec , d∅/dt = 3*(2)²+2*(2)+1 = 12+4+1 = 17 rad-¹ angular acceleration = d²∅/dt² = 6t+2 at t = 2 => d²∅/dt² = 6(2)+2 = 14 rad-² |
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| 4543. |
A wheel is subjected to uniform angular accelerationabout its axis. Initially its angular velocity is zero. Inthe first 2 sec, it rotates through an angle θ! ; in thenext 2 sec, it rotates through an additional angle θ,The ratio ofo, /9, is-(A) IC) 3(D) 5 |
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| 4544. |
A wheel is subjected to uniform angularacceleration about its axis. Initially its angularvelocity is zero. In the first 2 sec, it rotatesthrough an angle 6, in the next 2 sec, itrotates through an additional angle θ2. The ratioof θ2 / θ 1 is-(A) 1(C) 3(B) 2(D) 5 |
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Answer» hi i am deepak and im in colleage my ans is b |
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| 4545. |
Q.9 A wheel of an engine executes 4800revolutions per minute. Its angular velocity(in rad/sec) would be(A) 4800π(C) 1607(B) 2400T(D) 80m |
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Answer» angular velocity = number of revolution / time taken = 4800 / 60 = 80 pie |
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| 4546. |
Q.14 If a rigid body a point rotates 60° in 6 minutes Qthe angular velocity of the body is(A) 1/6 rad/sec(C) 3.14/180 x 6.(B) 3.14/18 rad/sedc(D) of these |
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Answer» option (C) is correct. thaku |
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| 4547. |
A body of mass 10 kg is rotated in vertical circle ofradius 4 cm at constant angular velocity of 5 rad/ sec.The maximum tension in the string is- |
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Answer» maximum tension in the string is T = mg + mw²r = 10*(10+ (5)²*(4/100)) = 10*(10+1) = 110N |
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| 4548. |
Explain why: (a) passengers moves forward from their seats when speding bus stops sadenly.Or(b) A cricketer moves his hands backward while holding a catch.(c) It is easier to pull a lawn mower than to push it. |
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| 4549. |
.17A boy is standing at the centre of a boat whichis free to move on water. If the masses of theboy and the boat are mi and m2 respectivelyand the boy moves a distance of 1 m forwardthen the movement of the boat is.. metres |
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Answer» thanku |
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| 4550. |
as resting on the butom of a beakes filled wiA ray of light from the coin travels upto the sutfaot the liquid and moves along its surface as shown in tfigureHow fast is the light travelling in the liquid ?(A) 1-8 x 10% ms- (B) 24 x 108 m s-1O 30 x 10 ms1 (D) 12 x 108 m sl |
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