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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4651. |
2 Two charges of 125 10 coulomb and -25 x 10° coulomb areplaced 6 m apart, Find the electric field at a point 4 m from thecentre of the electric dipole (i)on axial line (Hi) on equatorial lineans- SS.1 NC: 10.8 NC |
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| 4652. |
If a sprinter runs a distance of 100 metres in 9.83 seconds, calculate his average speedi |
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| 4653. |
(a) 3.3x1097(c) 5.3 x 10°A scale made of iron is exactly a metre in length at204C. What will be its length at 40°C?(*) 200004 m(b) 1.00044 m(e) 100034 m(d) 1.50024 m39. How much heof mechanic: |
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Answer» 1.00024 will be its length at 40C |
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| 4654. |
(2) What are the don'ts for a sprinter?Ans. |
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Answer» Ans :- 1) skip stretching. Flexibility improvement is a terrible gradually but only if performed on a daily basis. 2) Overemphasized one particular muscle, most notably the hamstrings, while stretching. 3) under-strech, which means not performing a full movement or relaxing by doing only half stretch. 4) perform stretching only when convenient, make it necessary ,regular habit. PLEASE LIKE THE ANSWER answer in one sentence |
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| 4655. |
17. A body falls from rest in the gravitational field of the earth. The distance travelled in the fifth second of itsmotion is (g = 10m /s 2)(A) 25mイB)45m(C) 90m(D) 125m |
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Answer» a = g = 10 S(n th) = u +a/2(2n-1) S(5 th) = 0 + 10/2(2*5-1) = 5*9 = 45m |
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| 4656. |
33. A ball is thrown at a speed of 40 m/s at an angle of 60with the horizontal. Find (a) the maximum heightreached and (b) the range of the ball. Take g 10m/ |
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| 4657. |
if a sprinter runs a distance of 100 metres in 9.83 seconds calculate his average speed in km/h. |
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| 4658. |
(c)The size of the pupil ............... becomeswhen you see in dim light. |
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Answer» The size of the pupil becomes __large__ when you see in dim light. |
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| 4659. |
State the functions of Iris and Pupil of the human eye (3 Marks) |
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Answer» PupilThe pupil is essentially a hole in the center of your iris that controls how much light enters the eye. It's size is controlled by the relaxing and contracting of the iris. When there is high light intensity, the pupil shrinks while it grows in low light intensity. This is to ensure there is enough light for vision without damaging the sensitive retina. Theirisis a ring-shaped membrane inside the eye that surrounds an openingin thecenter, called thepupil. Theiriscontains muscles that allow thepupilto become larger (open up or dilate) and smaller (close up or constrict). ... In addition, it is theiristhat determines your eye color Thanks for giving this answer in ainformative form |
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| 4660. |
A body falls from rest in the gravitational field of the earth.The distance travelled in the fifth second of its motion is(g-10m/s)(a) 25 m(c) 90 m(b) 45 m(d) 125 m |
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Answer» Hn = (g/2)(2n - 1)H5 = (10/2)(2×5 - 1) = 5 × 9 = 45m s=u+a/2(2n-1) u is 0a is 10n is 5 therefore s will be 45 m |
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| 4661. |
4 - i eकान 7 ¢ ‘r, L_A__-"V‘r",jfly.g;X2 >>. ब्8 62/52/2028 25245:=g B 1s |
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Answer» डायनेमो में घूर्णन करती हुई तारों की कुंडली और चुम्बकीय क्षेत्र का उपयोग करके यांत्रिक घूर्णन की ऊर्जा कोफैराडे के नियमके अनुसार दिष्ट विद्युत धारा में रूपान्तरित किया जाता है। डायनेमो में एक स्थिर सरंचना होती है, जिसे 'स्टेटर' कहा जाता है, जो एक स्थिर चुम्बकीय क्षेत्र उपलब्ध कराती है। तथा घूर्णन करती हुई वाइनडिंग्स का एक सेट होता है, जो आर्मेचर कहलाता है, यह चुम्बकीय क्षेत्र में तेजी से घूमता है। चुंबकीय क्षेत्र में तार की गति के कारण धातु में उपस्थित इलेक्ट्रॉनों पर बल उत्पन्न होता है, जिससे तार में विद्युत धारा उत्पन्न होती है। छोटी मशीनों में स्थिर चुम्बकीय क्षेत्र को एक या अधिक स्थायी चुम्बकों के द्वारा उपलब्ध कराया जा सकता है; बड़ी मशीनों में स्थिर चुम्बकीय क्षेत्र एक या अधिक विद्युत चुम्बकों के द्वारा उपलब्ध कराया जाता है, जिसे आमतौर पर क्षेत्र कुंडली (field coils) कहा जाता है। कम्यूटेटर की आवश्यकता दिष्ट धारा के उत्पादन के लिए हुई। जब तार का एक लूप एक चुम्बकीय क्षेत्र में घूर्णन करता है, इसमें उत्पन्न प्रेरित विभव प्रत्येक आधे घूर्णन के बाद उलट जाता है, जिसके परिणामस्वरूपप्रत्यावर्ती धाराका उत्पादन होता है। हालांकि, विद्युतीय प्रयोगों के प्रारम्भिक दिनों में, प्रत्यावर्ती धारा का कोई ज्ञात उपयोग नहीं था। विद्युत के कुछ उपयोगों जैसेविद्युत लेपनमें, तरल बैटरियों की सहायता से दिष्ट धारा का उपयोग किया जाता था। डायनेमो का आविष्कारबैटरीके प्रतिस्थापन के रूप में किया गया। कम्यूटेटर मोटे तौर पर एक रोटरी स्विच होता है। इसमें मशीन के शाफ्ट पर चढ़ाये गए संपर्कों का एक सेट होता है, जिन्हेंग्रेफाइट-ब्लॉकके स्टेशनरी (स्थिर) संपर्कों के साथ संयोजित किया जाता है, जो "ब्रश" कहलाते हैं, क्योंकि सबसे पहले लगाये गए इस प्रकार के संपर्कधातुके ब्रश थे। जब विभव उलटता है, कम्यूटेटर बाह्य परिपथ के लिए वाइनडिंग्स कनेक्शन को उलट देता है, इसलिए प्रत्यावर्ती धारा के बजाय, निरंतर एक दिष्ट धारा का उत्पादन होता है। |
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| 4662. |
Q. 9. Explain the terms (i) Attenuation and(ii) Demodulation used in CommunicationSystem. |
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Answer» Ans :- 1 -Attenuation is a general term that refers to any reduction in the strength of a signal. Attenuation occurs with any type of signal, whether digital or analog. Sometimes called loss, attenuation is a natural consequence of signal transmission over long distances. 2- Demodulationis extracting the original information-bearing signal from a carrier wave. Ademodulatoris an electronic circuit (or computer program in a software-defined radio) that isusedto recover the information content from the modulated carrier wave. |
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| 4663. |
Rajan exerts a force of 150 N in pulling a cart at aconstant speed of 10 m s1. Calculate the powerexertedAns. 1500 W |
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| 4664. |
calculate average speeds1=70km/hs2=20km/hs3= 50km/h |
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Answer» Average speed = sum of speed / no. of speed = (70+20+50)/3 = 140/3 = 46.6 km /hr |
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| 4665. |
10.Match the followingSection ASection BSending signal to the brairnA delicate membraneControls the amount of lightrisOptic NerveRetinaenteringPupilA dark muscular diaphragm |
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Answer» Iris is dark muscular diaphragmOptic nerve send signal to brainRetina is a delicate membranePupil controls amount of light entering |
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| 4666. |
42. The black muscular object behind the cornea is(1) Iris(2) Pupil(3) Retina(4) Optic nerve |
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Answer» The pupil is a hole located in the center of the iris of the eye that allows light to strike the retina. It appears black because light rays entering the pupil are either absorbed by the tissues inside the eye directly, or absorbed after diffuse reflections within the eye that mostlymissexiting the narrow pupil |
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| 4667. |
A tent is cylindrical to a height of 4.8 m. and conical above it. The radius of t4.5m. and total height of the tent is 10.8 m. Find the canvas required for the temeters. -so |
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| 4668. |
5. A 1.8 kgblock is moved at constant speed over a surface for which coefficient of friction μ--ltis pulled by a force Facting at 45e with horizontal as shown in Fig. 9.9. The block is displaced by2 m. Find the work done on the block by (a) the force F (b) friction (c) gravity45°Fig. 9.9noton and x in |
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| 4669. |
What is the momentum of an object of mass m, moving with avelocity u?(a) (mu)2 (b) mu29.(d) mu |
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Answer» a b c ka |
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| 4670. |
3. A car which is accelerated at 4 m/s2 has a velocity of 10m/s when it crosselamp post. Find the distance travelled by the car in 8th spost.a) 400mafter crossing the lab) 112mc) 30md) 40m |
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Answer» u = 10 m/s a = 4 m/s² s = ut + 1/2 at² = 10m/s*8s + 1/2 * 4m/s² * 8²s² = 80m + 128m = 208m Like my answer if you find it useful! |
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| 4671. |
Calculate thmoves with a constant velocity through a distance 'd'. (given that the ground is rough with coefficient ofcane work done in pulling an object with a constant force F as shown in figure, so that the blockEafriction R) |
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Answer» if velocity is constant there will be no acc. and if there is no acc. there will be no force wrong better u tell whats right i don't think if I will tell you whats right you will understand..because you don't knoe the basics ...so you first see newtons first and 2nd law of motion and their explanations dear better u tell bro dont that much over confident okay lets see the example of conveyer belt, rocket...in all these velocity is constant...then according to you the force is 0..???... how can mass differ? its not about confidence I just told you that you answered wrong so that you can rectify your knowledge and understanding about the topic ok thanx bro for q good question nd telling my level😀😀 its a specialised case in rocket propagation and water jet as when the rocket moves up....fule is given out every scond..which is expressed in rate no I m sorry if I offended you that i have not studied yet its ok bro I am a girl ok then its ok sis thnks hope it hepls you thanx a lot sister u lives in kota? |
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| 4672. |
The velocity of a particle moving at 6 ms-11eastwards changes to 8 ms-1 northwards in 10 s.What is the magnitude of the average accelerationduring this interval of time? |
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| 4673. |
A shell at rest on a smooth horizontal surfaceexplodes into two fragments of masses m, andm. If just after explosion, m, move with speedu, then work done by internal forces duringexplosion is:(1) 5m, +m.). (2) }(m, +m.)u(3) zmu(1+) (4) (m. -mu |
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Answer» 1 one answer because of masses of fragments are of contains two speeds |
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| 4674. |
60. The index of refraction of diamond is 2.0, velocity of light indiamond in cm/s is approximately(a) 6x1010 (b) 3.0x1010 (c) 2x1010 ey 1.5x 10 |
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Answer» Index of refraction of diamond is 2.0speed of light is 3×10^8 m/sso velocity of light in diamond is 3×10^8/2=1.5×10^8 m/s=1.5×10^10 cm/s |
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| 4675. |
VECTORSA particle is moving eastwards with a velocityof 5m/sec. In 10 seconds the velocity changesto 56m/sec northwards. The averageacceleration in this time is... |
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| 4676. |
028. A body is moving with velocity 30m/sec towards each. After 10seconds its velocity becomes 40m/s towards north. Find its acceleratioa) 1m/sec b) 7m/sec cV7 m/sec d) 5m/sec |
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Answer» Initial velocity = The velocity in east direction = 30i , where i is unit vector along x axis. Final velocity = The velocity in north direction = 40j , where j is unit vector along y axis. Average acceleration = { (root over(30^2+40^2))/10} m/s2 = 5 m/s^2 in north east direction! |
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| 4677. |
A car decreses its speed from 20m/s to 5m/s in 3 sec Find a |
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Answer» but question has two parts |
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| 4678. |
diamond is10) Reloactive index of diamond isced thach a 19ss :Scakthe resactive index diamondcontre repect togland |
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Answer» Ur answer is 1.89. and you can reciprocal it for glass w.r.t diamond |
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| 4679. |
A train moves a distance of 10 metre with a constant speed of 40m/sec. and moves the next 5m with a constant speed of 30 m/sec.Calculate its average speed. |
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Answer» Let this frame of reference be moving with a speed of 10 m/s . Now lets calculate new velocities of train and parrot. and the answer is 36 meter per second |
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| 4680. |
AExplain why a transformer is required to lower the voltage to avalue suitable for use at2a station? |
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Answer» We step up voltage during transmission because At high voltage power transmitted is high. At high voltage losses are loss. Conductor used for transmission is less at high voltage. And at distribution end our appliances are rated at low voltage so we have to step down voltage at distribution end |
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| 4681. |
33. Which one of the following can also act as alubricant in the machines?a) Iron fillingsb) Polish on machines n machinec) Flow of water through the machined) flow of compreĹsed and purjfied air. |
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Answer» Small shuttles and wheels on axles made from single moleculescan be sped up with a small amount of water. hence option (c) is correct. |
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| 4682. |
7· The relation 3r =-3x + 6 describes the displacement of a particle in one direction where r s in metesand t in sec. The displacement, when velocity is zero, is(A) 24 metres (B) 12 metres(C) 5 metresZero |
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| 4683. |
An object has moved through adistance. Can it have zerodisplacement? If yes, supportyour answer with an example. |
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Answer» yes there is a choice that displacement is 0 when distance is not 0 example : when a particle completes 1 rotation then distannce not 0 but displacement is 0 |
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| 4684. |
An object has moved through adistance. Can it have zerodisplacement? If yes, supportyour answer with an example |
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| 4685. |
Two unequal masses have the same K.E. bodyProve that the momentum of the heavieris more. |
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| 4686. |
Renewable energy resources - |
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Answer» some renewable energy resources are solar energy hydroelectric energy wind energy biomass energy etc. |
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| 4687. |
23(c) g(d) 2gF 2mgIn the figure s>d. They are connected by a lightinextensible string passing over a smooth pulley.When the system is released, then mass m, willaccelerate towards the pulley provided:.30°60 |
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| 4688. |
In a simple Atwood machine, two unequal masses nmand m are connected by a string going over a clampedlight smooth pulley. In a typical arrangement(figure 5-E7) m, = 300 g and m2=600 g. The system isreleased from rest. (a) Find the distance travelled bythe first block in the first two secones. (b) Find thetension in the string. (c) Find the force exerted by theclamp on the pulley.22.m2 |
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| 4689. |
a constant velocity?22. In a simple Atwood machine, two unequal masses mand m2 are connected by a string going over a clampedlight smooth pulley. In a typical arrangement(figure 5-E7) m,- 300 g and m2- 600 g. The system isreleased from rest. (a) Find the distance travelled bythe first block in the first two seconds.(b) Find thetension in the string. (c) Find the force exerted by theclamp on the pulley.m,m2Figure 5-E7 |
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| 4690. |
16. Find the reading of the spring balance shown in figure(5-E6). The elevator is going up with an acceleration ofg/10, the pulley and the string are light and the pulleyis smooth. |
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| 4691. |
s. Find the reading of the spring balance shown in figuree elevator is going up with an acceleration of(5-E6). Thg/10, the pulley and the string are light and the pulleyis smooth. |
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Answer» thanks... |
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| 4692. |
mpeleahdcoitrastbiĂł-massandhydroelectricity as sources of energyWhat are the limitations of extracting energy from-(a) the wind?6.(b) waves?(c) tides? |
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| 4693. |
42, A block of mass m is placed on a smooth sphere of radiusR. It slides when pushed slightly. At what distance h,from the top, will it leave the sphere?(c) 52 (d) R |
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| 4694. |
25. A particle is kept at rest at the top of a sphere of diameter 42 m. When disturbed slightly, it slides down.what height 'h' from the bottom, the particle will leave the sphere.(1) 14 m(2) 28 m(3) 35 m(4) 7 m |
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Answer» The answer is option C |
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| 4695. |
A metal 'X' reacts with hot water to form compound Y along wevolution of hydrogen gas() Identify 'X and Y(ii) Write the chemical reaction for conversion ofX' to 'Y. |
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Answer» Magnesium or Calcium react with hot water to give magnesium or Calcium oxideHenceX is Mg and Y-Mg(OH)^2Mg+2H2O---->Mg(OH)2+H2 |
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| 4696. |
Differentiate between compost & vermicompost. |
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Answer» Compost1.Manure prepared from farm waste material, vegetable waste, animal refuse, sewage waste, domestic waste, straw etc. on decomposition in pits.2.It takes 3-6 months to prepare.3. Organic remains decomposed by microbes naturally.Vermi compost1.Compost which is prepared by using earthworms.2.It takes 1-2 months to prepare.3.Organic remains are pulverized by earthworms. compost is organic matter that has been decomposed in a process called composting. vermicompost is the product of the compositing process using various species of worms usually red wiggled and other earthworms to create a mixture of decompositing vegetables or food east and vermicast. |
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| 4697. |
- If a car goes from a place X to aplace Y with a speed of 60 km/hand returns from Y to X with a speedof 40 km/h, what is its average speedfor the whole journey ? |
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Answer» Let the Distance travelled by man = x km Speed (S1) = 40 km/h Speed (S2)= 60 km/h Time taken by man to travel from city B to C(T1)= Distance/ speed(s1) T1= x/40= x/40 h Time taken by man to return from city C to B(T2)= Distance/ speed(s2) T2= x/60 Total time taken (T) = T1+T2 T= x/40+x/60=( 3x+2x)/120= 5x/120 T= x/24 h Total distance (D)= x+x= 2x Average speed= Total Distance (D)/Total time (T) Average speed = D/T= 2x / (x/24) = 2x×( 24/x)= 48 km/h Hence, His average speed for the round trip= 48 km/hr |
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| 4698. |
If a car gocs from a place X to aplace Y with a speed of 60 km/hand returns from Y to X with a speedof 40 km/h, what is its average speedfor the whole journey ? |
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Answer» Let the Distance travelled by man = x km Speed (S1) = 40 km/h Speed (S2)= 60 km/h Time taken by man to travel from city B to C(T1)= Distance/ speed(s1) T1= x/40= x/40 h Time taken by man to return from city C to B(T2)= Distance/ speed(s2) T2= x/60 Total time taken (T) = T1+T2 T= x/40+x/60=( 3x+2x)/120= 5x/120 T= x/24 h Total distance (D)= x+x= 2x Average speed= Total Distance (D)/Total time (T) Average speed = D/T= 2x / (x/24) = 2x×( 24/x)= 48 km/h Hence, His average speed for the round trip= 48 km/hr 48 km/hr is the answer |
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| 4699. |
PHYSICSBrine has a density of 1.2 g/cc. 40cc of it are mixed with 30 cc of water. The density of solution is(AX 2.11 g/cc (B) 1.11 g/cc (C) 12.2 g/cc (D) 20.4 g/cc |
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Answer» (A) 2.11g/cc my Answer right |
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| 4700. |
A body starts from rest with a uniform accelerationIf its velocity after 'n' sec is 'v', then itsdisplacement in the last 2 s is(1) 2v(n +1)/n(2)V(n+1)/n(3) V(n-1)/n(4)2v(n-l)/n |
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