98971 + Interview Questions in Primary School in Math

1.	The average of 20 values is 18.if 3 is subtracted from each of the values,then the new average will be
Answer» If the average value of all the VALUES is given and a constant NUMBER is substracted or added to all the numbers, then the average value ALSO decreases or increases by the same constant number respectively. In this question, Average of 20 values = A = 18 Sum of all the 20 values= S = average * 20 =A20 =1820 =360 If 3 is substracted from each of the 20 values, then total value substracted = 3*20=60 Now NEW Total Sum = S1=S - 60 =360–60 =300 New Average = (New Sum) / 20 =300/20=15 __________________________

1.

The average of 20 values is 18.if 3 is subtracted from each of the values,then the new average will be

Answer»

If the average value of all the VALUES is given and a constant NUMBER is substracted or added to all the numbers, then the average value ALSO decreases or increases by the same constant number respectively.

In this question,

Average of 20 values = A = 18

Sum of all the 20 values= S = average * 20

=A*20

=18*20

=360

If 3 is substracted from each of the 20 values, then total value substracted = 3*20=60

Now NEW Total Sum = S1=S - 60

=360–60

=300

New Average = (New Sum) / 20

=300/20=15

__________________________

Discussion

2.	Please fast Tomorrow my exam
Answer» Answer: Hope this hel U MARK my answer brainliest Step-by-step EXPLANATION: All 4 options are your answer

2.

Please fast Tomorrow my exam

Answer»

Answer:

Hope this hel U MARK my answer brainliest

Step-by-step EXPLANATION:

All 4 options are your answer

Discussion

3.	(Class 8 )Answer Please
Answer» Answer: iam 6TH CLASS school SAINIK school I will tell Step-by-step explanation: do 5/2×2545 OK it will HELP you

3.

(Class 8 )Answer Please

Answer»

Answer:

iam 6TH CLASS school SAINIK school I will tell

Step-by-step explanation:

do 5/2×2545 OK it will HELP you

Discussion

4.	3. Identify the like terms from each of the following expressions :(i) 9a2 + 3b2- 4a2 + 2b2 - 6(iii) a2b2c – 9a2cb2 + 14a2b2c2 - 32abc2(iv) pqr + 24p2q2 – 32pqr + 19p2q + 16pqr2(v) x²y + yx2 – xy2 – x2y2 + 4x²y + 815vi) _ XY2+ 4YX2 + 2XY2- 7Y 2YZ + 3XY - 4YZ + 9YZ -19 by 2 YX
Answer» Step-by-step EXPLANATION: the ANSWER is nsjsubsdisjvsjsnsgusbsg#;₹-₹+++_73(-2637(3;4;_+_+₹;₹-6₹₹;;₹;₹(₹!₹:

4.

3. Identify the like terms from each of the following expressions :(i) 9a2 + 3b2- 4a2 + 2b2 - 6(iii) a2b2c – 9a2cb2 + 14a2b2c2 - 32abc2(iv) pqr + 24p2q2 – 32pqr + 19p2q + 16pqr2(v) x²y + yx2 – xy2 – x2y2 + 4x²y + 815vi) _ XY2+ 4YX2 + 2XY2- 7Y 2YZ + 3XY - 4YZ + 9YZ -19 by 2 YX

Answer»

Step-by-step EXPLANATION:

the ANSWER is nsjsubsdisjvsjsnsgusbsg#;₹-₹+++_73(-2637(3;4;_+_+₹;₹-6₹₹;;₹;₹(₹!₹:

Discussion

5.	29 - [7+{16-(2+2)}]
Answer» Answer: 10 Step-by-step EXPLANATION:

5.

29 - [7+{16-(2+2)}]

Answer»

Answer:

10

Step-by-step EXPLANATION:

Discussion

6.	Factorise:a)100-p^2 b) a^2-(b+c)^2
Answer» SOLUTION :- _______________________ a). 100 - p^2 USING a^2 - b^2 => 10^2 - p^2 => (10-p)(10+p) ______________________ b). a^2 - (b+c)^2 using a^2 - b^2 => { a + ( b+c)} { a - (b+c)} => { a + b + c } { a - b - c } _______________________

6.

Factorise:a)100-p^2 b) a^2-(b+c)^2

Answer»

SOLUTION :-

_______________________

a). 100 - p^2

USING a^2 - b^2

=> 10^2 - p^2

=> (10-p)(10+p)

______________________

b). a^2 - (b+c)^2

using a^2 - b^2

=> { a + ( b+c)} { a - (b+c)}

=> { a + b + c } { a - b - c }

_______________________

Discussion

7.	(2^8×2^-2)x=32plz give me ans
Answer» ANSWER: =(2⁶)x=32 =(2⁶)x=2⁵ =x=2⁵/2⁶ =x=1/2=.5

7.

(2^8×2^-2)x=32plz give me ans

Answer»

ANSWER:

=(2⁶)x=32

=(2⁶)x=2⁵

=x=2⁵/2⁶

=x=1/2=.5

Discussion

8.	From the sum of 9a³ -4a²p + b and -7a²b + 11b² subtract 6a³ - 15abplease tellit is compulsory
Answer» Answer: 3a³ - 11a²b + 11b² - 15AB + B Step-by-step EXPLANATION: = 9a³ - 6a³ - 4a²b - 7a²b + b + 11b² - 15ab = 3a³ - 11a²b + 11b² - 15ab + b

8.

From the sum of 9a³ -4a²p + b and -7a²b + 11b² subtract 6a³ - 15abplease tellit is compulsory

Answer»

Answer:

3a³ - 11a²b + 11b² - 15AB + B

Step-by-step EXPLANATION:

= 9a³ - 6a³ - 4a²b - 7a²b + b + 11b² - 15ab

= 3a³ - 11a²b + 11b² - 15ab + b

Discussion

9.	टू इन सिस्टर मैट्रिक्स मेथड 1 - 4 ओवर 22 - 7
Answer» Answer: 18 Step-by-step explanation: 22-7=15 4-1=3 15+3=18

9.

टू इन सिस्टर मैट्रिक्स मेथड 1 - 4 ओवर 22 - 7

Answer»

Answer:

18

Step-by-step explanation:

22-7=15

4-1=3

15+3=18

Discussion

10.	Guys do this sum........pls give it first pls!!!!!!pls!!!
Answer» ANSWER: I don't KNOW this to SOLVE MARK me as the BRAINLIEST

10.

Guys do this sum........pls give it first pls!!!!!!pls!!!

Answer»

ANSWER:

I don't KNOW this to SOLVE MARK me as the BRAINLIEST

Discussion

11.	What is the supplement of 166 degree?
Answer» $\huge\star{\red{\underline{\mathfrak{Answer!!!!!}}}}$ The SUPPLEMENT of 166° = 180°-166°= 14° ${\huge{\overbrace{\underbrace{\green{Follow\:Me}}}}}$

11.

What is the supplement of 166 degree?

Answer»

$\huge\star{\red{\underline{\mathfrak{Answer!!!!!}}}}$

The SUPPLEMENT of 166° = 180°-166°= 14°

${\huge{\overbrace{\underbrace{\green{Follow\:Me}}}}}$

Discussion

12.	the mean of 3 different natural numbers is 40 if lowest is 19 what could be highest possible number of remaining two numbers
Answer» ANSWER: I didn't understand this QUESTION ǫᴜᴇsᴛɪᴏɴ- means Step-by-step explanation: xo GO

12.

the mean of 3 different natural numbers is 40 if lowest is 19 what could be highest possible number of remaining two numbers

Answer»

ANSWER:

I didn't understand this QUESTION ǫᴜᴇsᴛɪᴏɴ- means

Step-by-step explanation:

xo GO

Discussion

13.	Help me in this question please who give me answer firstI will mark him / her as a brainlist.
Answer» OPTION B is the CORRECT ANSWER of this QUESTION

13.

Help me in this question please who give me answer firstI will mark him / her as a brainlist.

Answer»

OPTION B is the

CORRECT ANSWER of this QUESTION

Discussion

14.	2a²-17ab+26ab²?need the solution.
Answer» Step-by-step explanation: 2A2 – 17ab + 26b2 = 2a2 – 13ab – 4ab + 26b2 = a (2A – 13B) – 2b (2a – 13b) = (2a – 13b) (a – 2b) PLEASE follow me

14.

2a²-17ab+26ab²?need the solution.

Answer»

Step-by-step explanation:

2A2 – 17ab + 26b2

= 2a2 – 13ab – 4ab + 26b2

= a (2A – 13B) – 2b (2a – 13b)

= (2a – 13b) (a – 2b)

PLEASE follow me

Discussion

15.	If5/12 isequivalent of 113 then X is equalsto5/44/55/33/5
Answer» ANSWER: i THINK i didn't GIVE the answer to you .

15.

If5/12 isequivalent of 113 then X is equalsto5/44/55/33/5

Answer»

ANSWER:

i THINK i didn't GIVE the answer to you .

Discussion

16.	Solve the following1) Solve 3(x + 6) = 24pls with stepss
Answer» ANSWER: x= 2 Step-by-step EXPLANATION: =>3X+18 = 24 => 3x = 24-18 =>x = 2

16.

Solve the following1) Solve 3(x + 6) = 24pls with stepss

Answer»

ANSWER:

x= 2

Step-by-step EXPLANATION:

=>3X+18 = 24

=> 3x = 24-18

=>x = 2

Discussion

17.	Find the value of (-7)-(-9) using number line
Answer» ANSWER: ♡´･ᴗ･`♡♡´･ᴗ･`♡♡´･ᴗ･`♡♡´･ᴗ･`♡

17.

Find the value of (-7)-(-9) using number line

Answer»

ANSWER:

♡´･ᴗ･`♡♡´･ᴗ･`♡♡´･ᴗ･`♡♡´･ᴗ･`♡

Discussion

18.	Divide pls anyone give answer for this question
Answer» ANSWER: -x+4 Step-by-step EXPLANATION: if my answer is CORRECT MARK me as BRAINLIST

18.

Divide pls anyone give answer for this question

Answer»

ANSWER:

-x+4

Step-by-step EXPLANATION:

if my answer is CORRECT MARK me as BRAINLIST

Discussion

19.	Which one of the following letters does not have the Horizontal line of symmetry?A. HB. MC. ED. V
Answer» ANSWER: V and M both doesn't have horizontal LINE of symmetry if it is vertical line of symmetry it is E

19.

Which one of the following letters does not have the Horizontal line of symmetry?A. HB. MC. ED. V

Answer»

ANSWER:

V and M both doesn't have horizontal LINE of symmetry

if it is vertical line of symmetry it is E

Discussion

20.	Find the value of(i) 1 - 491
Answer» ANSWER: $1 - 491 = - 490$ RIGHT answer .......

20.

Find the value of(i) 1 - 491

Answer»

ANSWER:

$1 - 491 = - 490$

RIGHT answer .......

Discussion

21.	राइट द वन रोडस्टर एंड द सक्सेसर ऑफ द फॉलोइंग नंबर 9999
Answer» ANSWER: फाइंड द ग्रेटेस्ट नंबर विच ऑलवेज डिवाइड द प्रोडक्ट ऑफ प्रेडिसेसर एंड सक्सेसर ऑफ एंडॉयड रोल नंबर अदर देन वनफाइंड द ग्रेटेस्ट नंबर विच ऑलवेज डिवाइड द प्रोडक्ट ऑफ प्रेडिसेसर एंड सक्सेसर ऑफ एंडॉयड रोल नंबर अदर देन वनफाइंड द ग्रेटेस्ट नंबर विच ऑलवेज डिवाइड द प्रोडक्ट ऑफ प्रेडिसेसर एंड सक्सेसर ऑफ एंडॉयड रोल नंबर अदर देन वनफाइंड द ग्रेटेस्ट नंबर विच ऑलवेज डिवाइड द प्रोडक्ट ऑफ प्रेडिसेसर एंड सक्सेसर ऑफ एंडॉयड रोल नंबर अदर देन वनफाइंड द ग्रेटेस्ट नंबर विच ऑलवेज डिवाइड द प्रोडक्ट ऑफ प्रेडिसेसर एंड सक्सेसर ऑफ एंडॉयड रोल नंबर अदर देन वनफाइंड द ग्रेटेस्ट नंबर विच ऑलवेज डिवाइड द प्रोडक्ट ऑफ $\\$ प्रेडिसेसर एंड सक्सेसर ऑफ एंडॉयड रोल नंबर अदर देन वन

21.

राइट द वन रोडस्टर एंड द सक्सेसर ऑफ द फॉलोइंग नंबर 9999

Answer»

ANSWER:

फाइंड द ग्रेटेस्ट नंबर विच ऑलवेज डिवाइड द प्रोडक्ट ऑफ प्रेडिसेसर एंड सक्सेसर ऑफ एंडॉयड रोल नंबर अदर देन वनफाइंड द ग्रेटेस्ट नंबर विच ऑलवेज डिवाइड द प्रोडक्ट ऑफ प्रेडिसेसर एंड सक्सेसर ऑफ एंडॉयड रोल नंबर अदर देन वनफाइंड द ग्रेटेस्ट नंबर विच ऑलवेज डिवाइड द प्रोडक्ट ऑफ प्रेडिसेसर एंड सक्सेसर ऑफ एंडॉयड रोल नंबर अदर देन वनफाइंड द ग्रेटेस्ट नंबर विच ऑलवेज डिवाइड द प्रोडक्ट ऑफ प्रेडिसेसर एंड सक्सेसर ऑफ एंडॉयड रोल नंबर अदर देन वनफाइंड द ग्रेटेस्ट नंबर विच ऑलवेज डिवाइड द प्रोडक्ट ऑफ प्रेडिसेसर एंड सक्सेसर ऑफ एंडॉयड रोल नंबर अदर देन वनफाइंड द ग्रेटेस्ट नंबर विच ऑलवेज डिवाइड द प्रोडक्ट ऑफ

$\\$

प्रेडिसेसर एंड सक्सेसर ऑफ एंडॉयड रोल नंबर अदर देन वन

Discussion

22.	The root equation 4×+ 5 = 3(×+2) is
Answer» The ANSWER is 1 (ONE) after CANCELLATION.

Discussion

23.	Number? Think ab(iv) 222222TRY THESE1. Can we say whether the following numbers are perfect squares? How do we know?() 23453(iii) 7928(vi) 20610 1057(V) 1069
Answer» Answer: α ραятıcłє ıs єxєcυтıηg sнм ıтs αccєłєяαтıση ωнєη ıт ıs αт α ∂ısтαηcє σƒ 2м ƒяσм мєαη ρσsıтıση ıs 4мs αмρłıтυ∂є ıs 3м. Step-by-step EXPLANATION: plss GIVE my answer to BRAINLIEST answer this is my humble REQUEST friendsHOPE THIS HELPS YOU ✌️✌️☘️☘️.!!

23.

Number? Think ab(iv) 222222TRY THESE1. Can we say whether the following numbers are perfect squares? How do we know?() 23453(iii) 7928(vi) 20610 1057(V) 1069

Answer»

Answer:

α ραятıcłє ıs єxєcυтıηg sнм ıтs αccєłєяαтıση ωнєη ıт ıs αт α ∂ısтαηcє σƒ 2м ƒяσм мєαη ρσsıтıση ıs 4мs αмρłıтυ∂є ıs 3м.

Step-by-step EXPLANATION:

plss GIVE my answer to BRAINLIEST answer this is my humble REQUEST friendsHOPE THIS HELPS YOU ✌️✌️☘️☘️.!!

Discussion

24.	Find the value of 2/3÷5/3
Answer» ANSWER: 2/3÷5/3 2/33/5 2/5 Hence, answer is 2/5 Hope ITZ HELPFUL to u Step-by-step EXPLANATION:*

24.

Find the value of 2/3÷5/3

Answer»

ANSWER:

2/3÷5/3

2/3*3/5

2/5

Hence, answer is 2/5

Hope ITZ HELPFUL to u

Step-by-step EXPLANATION:

Discussion

25.	Find the perimeter and area of the given figure.
Answer» Step-by-step explanation: HOPE it will HELP you please MARK me BRAINLEAST and follow me

25.

Find the perimeter and area of the given figure.

Answer»

Step-by-step explanation:

HOPE it will HELP you please MARK me BRAINLEAST and follow me

Discussion

26.	खालील ओळींतील भाव स्पष्ट करा.(अ) गोधडीला आईच्या फाटक्या लुगड्याचे आणि बापाच्या फाटक्या धोतराचे अस्तर असते.'(आ) 'गोधडी म्हणजे नसतो चिंध्यांचा बोचका, ऊब असते ऊब.'. please tell correct answer
Answer» I am not know Hindi OK you are UNDERSTAND please send me your ENGLISH questions or TAMIL

Discussion

27.	The second class railway fare for 240km of journey is rs 15 what would be the fare for journey of 139.2km
Answer» Answer: 240 KM----RS 15 1 km ------ rs 15/240 139.2 km ------ rs 15/240×139.2= rs 8.7

27.

The second class railway fare for 240km of journey is rs 15 what would be the fare for journey of 139.2km

Answer»

Answer:

240 KM----RS 15

1 km ------ rs 15/240

139.2 km ------ rs 15/240×139.2= rs 8.7

Discussion

28.	1 1Divide 880 between Rajan and Kamal in the ratio5 6
Answer» ANSWER: if it is 5:6 thus, 5/11×880=rs 400= rajan's share thus , 6/11×880=rs 480= KAMAL's share

28.

1 1Divide 880 between Rajan and Kamal in the ratio5 6

Answer»

ANSWER:

if it is 5:6

thus, 5/11×880=rs 400= rajan's share

thus , 6/11×880=rs 480= KAMAL's share

Discussion

29.	6. Simplify (a + b) (2a – 3b + c) – (2a – 3b) c. Find the value at a=1, b= 0 c= 1
Answer» Step-by-step explanation: (a+b)(2a-3b+c)-(2a-3b)c a(2a-3b+c) +b(2a-3b+c) -[ 2a(c) - 3b(c)] 2A2 - 3AB+ ac + 2ab - 3b2 +bc - 2ac + 3bc =2a2 -AB -ac+4bc-3b2

29.

6. Simplify (a + b) (2a – 3b + c) – (2a – 3b) c. Find the value at a=1, b= 0 c= 1

Answer»

Step-by-step explanation:

(a+b)(2a-3b+c)-(2a-3b)c

a(2a-3b+c) +b(2a-3b+c) -[ 2a(c) - 3b(c)]

2A2 - 3AB+ ac + 2ab - 3b2 +bc - 2ac + 3bc

=2a2 -AB -ac+4bc-3b2

Discussion

30.	Houses 9.10 kilometre from her school she wants some distance and then to cover bus for 1.2 kilometre to reach School how far dis she walkanswer fast I will mark as brainlest answer
Answer» ANSWER DISTANCE WALKED by Nandhini = TOTAL distance - Distance for Which she took the bus = 10 9 − 2 1 = 10 9−1×5 = 10 9−5 = 10 4 = 5 2 KM

30.

Houses 9.10 kilometre from her school she wants some distance and then to cover bus for 1.2 kilometre to reach School how far dis she walkanswer fast I will mark as brainlest answer

Answer»

ANSWER

DISTANCE WALKED by Nandhini = TOTAL distance - Distance for Which she took the bus

=

10

9

−

2

1

=

10

9−1×5

=

10

9−5

=

10

4

=

5

2

KM

Discussion

31.	Show that: ( − )( + ) + ( − )( + ) + ( − )( + ) = 0.
Answer» ANSWER: 0 Step-by-step EXPLANATION: =( − )( + ) + ( − )( + ) + ( − )( + ) =(-)+(-)+(-) =-3 nope I didn't GET answer as 0

31.

Show that: ( − )( + ) + ( − )( + ) + ( − )( + ) = 0.

Answer»

ANSWER:

0

Step-by-step EXPLANATION:

=( − )( + ) + ( − )( + ) + ( − )( + )

=(-)+(-)+(-)

=-3

nope I didn't GET answer as 0

Discussion

32.	My mother went to mark she brought 4kg apple is ₹200.09 then what is the 1kg of apple is what ?
Answer» Answer: 200.9/4 = 50.02 is RUPPE of 1 KG

32.

My mother went to mark she brought 4kg apple is ₹200.09 then what is the 1kg of apple is what ?

Answer»

Answer:

200.9/4 = 50.02 is RUPPE of 1 KG

Discussion

33.	Simpilfy (6²)² divided 6⁴)X6²
Answer» $\huge\bf\boxed\mathcal {Answer-:}$ $\frac{6^{22}}{6^46^2}\\ \\ \frac{6^]{4}}{6^4*6^2}\\ \\ \frac{1}{6^2}\\ \\ \frac{1}{36}\\ \\ \\$ HOPE IT HELPS!!!!

33.

Simpilfy (6²)² divided 6⁴)X6²

Answer»

$\huge\bf\boxed\mathcal {Answer-:}$

$\frac{6^{2*2}}{6^4*6^2}\\ \\ \frac{6^]{4}}{6^4*6^2}\\ \\ \frac{1}{6^2}\\ \\ \frac{1}{36}\\ \\ \\$

HOPE IT HELPS!!!!

Discussion

34.	A farmer has 11 cows. He purchased 5 more cows and washed to give 1/2 of the total cows to his eldest son, 1/4 to the middle son, and remaining to the young son. Find the number of cows each son will get.Please answer me in fraction only not in other process please my request.........
Answer» FIRST SON will GET 8 cows second son 4 cows last son 3 cows

34.

A farmer has 11 cows. He purchased 5 more cows and washed to give 1/2 of the total cows to his eldest son, 1/4 to the middle son, and remaining to the young son. Find the number of cows each son will get.Please answer me in fraction only not in other process please my request.........

Answer»

FIRST SON will GET 8 cows

second son 4 cows

last son 3 cows

Discussion

35.	10 x + 5 x = 20+ 5x
Answer» Answer: 10x=20 x=2 . . . . THANKU

35.

10 x + 5 x = 20+ 5x

Answer»

Answer:

10x=20

x=2

.

. .

.

THANKU

Discussion

36.	7. Find the sum :a) 5/4 + (-11/4)
Answer» Answer: 5/4 + -11/4 = (5-11) /4 = -6/4 Step-by-step EXPLANATION:

36.

7. Find the sum :a) 5/4 + (-11/4)

Answer»

Answer:

5/4 + -11/4

= (5-11) /4

= -6/4

Step-by-step EXPLANATION:

Discussion

37.	Solve it out.... ??!!
Answer» $\sf{\bold{\purple{\star{\underline{\underline{Given}}}}}}$ Perimeter = 30cm equal sides = 12CM ⠀⠀⠀⠀ $\sf{\bold{\purple{\star{\underline{\underline{To\: Find }}}}}}$ ⠀⠀⠀⠀ Area = ?? ⠀⠀⠀⠀ $\sf{\bold{\purple{\star{\underline{\underline{Solution}}}}}}$ ⠀⠀⠀⠀ let the UNKNOWN side be x ⠀⠀⠀⠀ $\sf{\star{\boxed{\orange{\frak{ Perimeter = sum \: of \: all \: sides }}}}}$ ⠀⠀⠀⠀ $\sf : \implies\:{\frak{ 30 = 12 + 12 + x }}$ ⠀⠀⠀⠀ $\sf : \implies\:{\frak{ 30 = 24 + x }}$ ⠀⠀⠀⠀ $\sf : \implies\:{\frak{ x = 30 - 24}}$ ⠀⠀⠀⠀ $\sf : \implies\:{\frak{ x = 6 }}$ ⠀⠀⠀⠀ All the sides of the TRIANGLE are 6CM , 12cm and 12cm ⠀⠀⠀ $\sf{\star{\boxed{\orange{\frak{ Semi\: perimeter = \dfrac{perimeter}{2} }}}}}$ ⠀⠀⠀⠀ $\sf : \implies\:{\frak{ Semi perimeter = \dfrac{30}{2}}}$ ⠀⠀⠀⠀ $\sf : \implies\:{\frak{ Semi\: perimeter = 15cm }}$ ⠀⠀⠀⠀ $\sf{\star{\boxed{\orange{\frak{ Area = \sqrt{s(s-a)(s-b)(s-c)} }}}}}$ ⠀⠀⠀⠀ $\sf : \implies\:{\frak{ Area = \sqrt{ 15 ( 15 - 12 ) ( 15 - 12 )( 15 - 6) }}}$ ⠀⠀⠀⠀ $\sf : \implies\:{\frak{ Area = \sqrt{15\times 3\times 3 \times 9}}}$ ⠀⠀⠀⠀ $\sf : \implies\:{\frak{ Area = \sqrt{15\times 3\times 3 \times 3\times 3 }}}$ ⠀⠀⠀⠀ $\sf : \implies\:{\frak{ Area = 9 \sqrt{15}}}$ ⠀⠀⠀⠀ $\sf : \implies\:{\frak{ Area = 9\times 3.88}}$ ⠀⠀⠀⠀ $\sf : \implies\:{\frak{ Area = 34.92cm^2}}$ ⠀⠀⠀⠀ ⠀⠀⠀⠀ ⠀⠀⠀⠀ $\sf{\star{\boxed{\green{\frak{ Area = 34.92cm^2 }}}}}$ ⠀⠀⠀⠀ ⠀⠀⠀

37.

Solve it out.... ??!!

Answer»

$\sf{\bold{\purple{\star{\underline{\underline{Given}}}}}}$

Perimeter = 30cm

equal sides = 12CM

⠀⠀⠀⠀

$\sf{\bold{\purple{\star{\underline{\underline{To\: Find }}}}}}$

⠀⠀⠀⠀

Area = ??

⠀⠀⠀⠀

$\sf{\bold{\purple{\star{\underline{\underline{Solution}}}}}}$

⠀⠀⠀⠀

let the UNKNOWN side be x

⠀⠀⠀⠀

$\sf{\star{\boxed{\orange{\frak{ Perimeter = sum \: of \: all \: sides }}}}}$

⠀⠀⠀⠀

$\sf : \implies\:{\frak{ 30 = 12 + 12 + x }}$

⠀⠀⠀⠀

$\sf : \implies\:{\frak{ 30 = 24 + x }}$

⠀⠀⠀⠀

$\sf : \implies\:{\frak{ x = 30 - 24}}$

⠀⠀⠀⠀

$\sf : \implies\:{\frak{ x = 6 }}$

⠀⠀⠀⠀

All the sides of the TRIANGLE are 6CM , 12cm and 12cm

⠀⠀⠀

$\sf{\star{\boxed{\orange{\frak{ Semi\: perimeter = \dfrac{perimeter}{2} }}}}}$

⠀⠀⠀⠀

$\sf : \implies\:{\frak{ Semi perimeter = \dfrac{30}{2}}}$

⠀⠀⠀⠀

$\sf : \implies\:{\frak{ Semi\: perimeter = 15cm }}$

⠀⠀⠀⠀

$\sf{\star{\boxed{\orange{\frak{ Area = \sqrt{s(s-a)(s-b)(s-c)} }}}}}$

⠀⠀⠀⠀

$\sf : \implies\:{\frak{ Area = \sqrt{ 15 ( 15 - 12 ) ( 15 - 12 )( 15 - 6) }}}$

⠀⠀⠀⠀

$\sf : \implies\:{\frak{ Area = \sqrt{15\times 3\times 3 \times 9}}}$

⠀⠀⠀⠀

$\sf : \implies\:{\frak{ Area = \sqrt{15\times 3\times 3 \times 3\times 3 }}}$

⠀⠀⠀⠀

$\sf : \implies\:{\frak{ Area = 9 \sqrt{15}}}$

⠀⠀⠀⠀

$\sf : \implies\:{\frak{ Area = 9\times 3.88}}$

⠀⠀⠀⠀

$\sf : \implies\:{\frak{ Area = 34.92cm^2}}$

⠀⠀⠀⠀

$\sf{\star{\boxed{\green{\frak{ Area = 34.92cm^2 }}}}}$

⠀⠀⠀⠀

⠀⠀⠀

Discussion

38.	D5 find the area of theshaded region.ABCO is a square ofside14cm and radius of circleIron 3.5cm ③8A
Answer» Step-by-step EXPLANATION: pujdtiskydhlfkgsgjdkxulfyod

38.

D5 find the area of theshaded region.ABCO is a square ofside14cm and radius of circleIron 3.5cm ③8A

Answer»

Step-by-step EXPLANATION:

pujdtiskydhlfkgsgjdkxulfyod

Discussion

39.	Plz help.....?!???!!
Answer» Answer: ANSWER Since △APB and parallelogram ABCD are on the same base AB and between the same parallels. Therefore, ar(△APB)= 2 1 ar(∥ gm ABCD) .......(1) SIMILARLY, ar(△BQC)= 2 1 ar(∥ gm ABCD) ......(2) From 1 and 2, we GET, ar(△APB)=ar(△BQC) solution please mark as BRAIN list

39.

Plz help.....?!???!!

Answer»

Answer:

ANSWER

Since △APB and parallelogram ABCD are on the same base AB and between the same parallels.

Therefore,

ar(△APB)=

2

1

ar(∥

gm

ABCD) .......(1)

SIMILARLY,

ar(△BQC)=

2

1

ar(∥

gm

ABCD) ......(2)

From 1 and 2, we GET,

ar(△APB)=ar(△BQC)

solution

please mark as BRAIN list

Discussion

40.	Please help me solve the question
Answer» Step-by-step explanation: in the triangle x=2x+3 in the square x=3x/2+7 in the CIRCLE x=x-3 a) 2∆6+[]3-O1 = 2(26+3)+(33/2+7)-(1-3) = (215)+(9/2+7)-(-2) = 30+23/2+2 = 32+23/2 = 87/2 b) 1/2[]2+O8-3∆0 = 1/2(32/2+7)+(8-3)-3(20+3) = 1/2(3+7)+5-3(0+3) = 1/2*10+5-9 = 5+5-9 = 1

40.

Please help me solve the question

Answer»

Step-by-step explanation:

in the triangle x=2x+3

in the square x=3x/2+7

in the CIRCLE x=x-3

a) 2*∆6+[]3-O1

= 2(2*6+3)+(3*3/2+7)-(1-3)

= (2*15)+(9/2+7)-(-2)

= 30+23/2+2

= 32+23/2

= 87/2

b) 1/2*[]2+O8-3*∆0

= 1/2(3*2/2+7)+(8-3)-3(2*0+3)

= 1/2(3+7)+5-3(0+3)

= 1/2*10+5-9

= 5+5-9

= 1

Discussion

41.	I need answer please
Answer» Step-by-step explanation: i THINK 19 is a RYT ANSWER PLZZZ follow me

41.

I need answer please

Answer»

Step-by-step explanation:

i THINK 19 is a RYT ANSWER PLZZZ follow me

Discussion

42.	Find:(i) 7/3 ÷2(ii) 4/9 ÷5(iii) 6/13 ÷7(iv) 4 1/3 ÷3
Answer» Answer: Step-by-step explanation: (i) 7 / 3 ÷ 2 = 7 / 3 X 1 / 2 = 7 / 6 (ii) 4 / 9 ÷ 5 = 4 / 9 X 1 / 5 = 4 / 45 (iii) 6 / 13 ÷ 7 = 6 / 13 X 1 / 7 = 6 / 91 (iv) 4 1/3 ÷ 3 = 13 / 3 X 1 / 3 = 13 / 9

42.

Find:(i) 7/3 ÷2(ii) 4/9 ÷5(iii) 6/13 ÷7(iv) 4 1/3 ÷3

Answer»

Answer:

Step-by-step explanation:

(i) 7 / 3 ÷ 2 = 7 / 3 X 1 / 2 = 7 / 6

(ii) 4 / 9 ÷ 5 = 4 / 9 X 1 / 5 = 4 / 45

(iii) 6 / 13 ÷ 7 = 6 / 13 X 1 / 7 = 6 / 91

(iv) 4 1/3 ÷ 3 = 13 / 3 X 1 / 3 = 13 / 9

Discussion

43.	Tha lines which intersect each other at a point is called ________
Answer» ANSWER: I THINK the answer is INTERSECTING LINES

43.

Tha lines which intersect each other at a point is called ________

Answer»

ANSWER:

I THINK the answer is INTERSECTING LINES

Discussion

44.	Find the area of the following trapezium:
Answer» Answer: Here are our top 5 free and easy ways to save energy in your home: TURN off the fan when you leave a room. Close your drapes or DROP your WINDOW shades during the day. Wash your clothes in cold water. Wrap or cover FOODS and drinks in the refrigerator. Always use the cold water faucet, unless you really want hot water. Step-by-step EXPLANATION:*

44.

Find the area of the following trapezium:

Answer»

Answer:

Here are our top 5 free and easy ways to save energy in your home:

*TURN off the fan when you leave a room.

*Close your drapes or DROP your WINDOW shades during the day.

*Wash your clothes in cold water.

*Wrap or cover FOODS and drinks in the refrigerator.

*Always use the cold water faucet, unless you really want hot water.

Step-by-step EXPLANATION:

Discussion

45.	What is the other name of voice box
Answer» Answer: ${\tt{\red{\underline{\underline{\huge{Answer:}}}}}}$ ⭐larynx ☘The area of the throat containing the VOCAL cords and USED for breathing, swallowing, and talking. ALSO CALLED larynx.

45.

What is the other name of voice box

Answer»

Answer:

${\tt{\red{\underline{\underline{\huge{Answer:}}}}}}$

⭐larynx

☘The area of the throat containing the VOCAL cords and USED for breathing, swallowing, and talking. ALSO CALLED larynx.

Discussion

46.	Categorise the triangle as right angle triangle active angle triangle or obtuse angle triangle
Answer» It is ACUTE ANGLE TRIANGLE... HOPE this will HELP you ...

46.

Categorise the triangle as right angle triangle active angle triangle or obtuse angle triangle

Answer»

It is ACUTE ANGLE TRIANGLE...

HOPE this will HELP you ...

Discussion

47.	प्रकाश संश्लेषण में कौन सी गैस मुक्त होती है
Answer» Answer: i dunno PLZ im also WEAK in hindi plz SORRY to you Step-by-step explanation: my hindi sir ALWAYS scolding u dunno hindi and telling to PARENTS and they beat me

47.

प्रकाश संश्लेषण में कौन सी गैस मुक्त होती है

Answer»

Answer:

i dunno PLZ im also WEAK in hindi plz SORRY to you

Step-by-step explanation: my hindi sir ALWAYS scolding u dunno hindi and telling to PARENTS and they beat me

Discussion

48.	Solve these two question in note book then take picture
Answer» ANSWER: 21/16. 3/4 is answer of tgese QUESTION

48.

Solve these two question in note book then take picture

Answer»

ANSWER:

21/16. 3/4 is answer of tgese QUESTION

Discussion

49.	1) Find the common factors of : 3x²y, 10x'y and 6x?y?z.
Answer» ANSWER: COMMON FACTOR are :- X & y

49.

1) Find the common factors of : 3x²y, 10x'y and 6x?y?z.

Answer»

ANSWER:

COMMON FACTOR are :- X & y

Discussion

50.	Pls answer the question. i hope the question is clear. Thanks,
Answer» ANSWER: p-1/36 Step-by-step explanation: 5p-2p=3/4-2/3 LCM 3p=9-8/12 p=1/12*3 p=1/36

50.

Pls answer the question. i hope the question is clear. Thanks,

Answer»

ANSWER:

p-1/36

Step-by-step explanation:

5p-2p=3/4-2/3

LCM

3p=9-8/12

p=1/12*3

p=1/36

Discussion

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_______________________

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______________________

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_______________________

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Factorise:a)100-p^2 b) a^2-(b+c)^2

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1 1Divide 880 between Rajan and Kamal in the ratio5 6

6. Simplify (a + b) (2a – 3b + c) – (2a – 3b) c. Find the value at a=1, b= 0 c= 1

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7. Find the sum :a) 5/4 + (-11/4)

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Please help me solve the question

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Tha lines which intersect each other at a point is called ________

Find the area of the following trapezium:

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Solve these two question in note book then take picture

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