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Hi ,

P : Q = 2 : 3

p : q = ( 2 × 4 ) : ( 3 × 4 )

= 8 : 12 ----( 1 )

q : r = 4 : 5

q : r = ( 4 × 3 ) : ( 5 × 3 )

= 12 : 15 ----( 2 )

Therefore ,

From ( 1 ) and ( 2 ) ,

p : q = 8 : 12

q : r = 12 : 15

p : q : r = 8 : 12 : 15

I HOPE this helps you.

: )

Question

The COST of the PAINTING the whole surface area of a cube at the RATE of 13 PAISE per centimetre square is Rs 343.98 the VOLUME of the cube is

Solution:

ATQ, 150A+100B= 10 tons.
=>15A+10B= 1.....(1)

Now according to second condition,

=>260A+ 40 B= 10

=> 26A+ 4B= 1....(2)

solving 1 &2 by elimination method.

multiply 1 with 2 and 2 with 5. we get.

=>30A+20B= 2.....(3)
=>130A+ 20B= 5.....(4)

Now,subtract 3 from 4.

=>-100A= -3

=> A= 3/100 tones.

putting the value of A. in 1

=> 15*3/100+4B= 1
=> 9/20+4B=1
=> (9+80B)/20=1
=> 9+80B=20
=> 80B= 11
=> B= 11/80

__________________

Hi ,

It is given that ,

X = -4/7 , y = -3/8 , z = 16/5

i ) x × ( y × z )

= ( -4/7 ) × [ ( - 3/8 ) × ( 16/5 ) ]

= ( -4/7 ) × ( -6/5 )

= 24/35 -------( 1 )

ii ) ( x × y ) × z

= [ ( - 4/7 ) × ( -3/8 ) ] × ( 16/5 )

= ( 12/56 ) × ( 16/5 )

= ( 12 × 16 )/( 56 × 5 )

= 24/35----( 2 )

From ( 1 ) and ( 2 ) , we CONCLUDE that,

x × ( y × z ) = ( x × y ) × z

[ Associative proporty under multiplication ]

I hope this HELPS you.

: )

Hi ,

( -7 ) ( - 7 ) ( - 7 ) = ( 49 ) × ( - 7 )

REQUIRED value = 49

I hope this HELPS you.

: )

Factorisation
a. LET x+y be z

A/Q 2z^2-9z-5 (middle term factorisation)
2z^2-10z+z-5
2z(z-5)+1(z-5)
(z-5)(2z+1)

substitute values of z as x and y
(x+y-5)(2x+2y+1) (ans)

B. let x^2+x be y then proceed
y^2+4y-12
=y^2-6y+2y-12
=y(y-6)+2(y-6)
=(y-6)(y+2)
(x^2+x-6)(x^2+x+2)

75/25
15/5
3/1
3distance COVERD

Bro according to me
1.draw a simple rough SKETCH of your topic
2.then U can give a small description on your topic
3.then u can raise the questions which you THINK could come in anyone's mind
4.prepare the ANSWER for those questions
5.u can give a small conclusion on your topic

Answer:

Your question is incomplete

The taxi FARE after each KM, when the fare is Rs 15 for the first km and Rs 8 for each additional km, does not form an AP as the total fare (in Rs) after each km is

15, 8, 8, 8, ...

If true then ENTER 1 and if false then enter 0

Step-by-step explanation:

The taxi fare for first km=15

The taxi fare for 2nd km=15+8=23

The taxi fare for 3rd km=15+8+8=31 and so on,

Therefore, the taxi fare form the sequence 15,23,31,...

Clearly, it is an AP with first term a=15 and common difference d=8

Therefore, answer is 0.

If x-2 is a FACTOR the GIVEN EXPRESSION then 4p+10+r=0 
if x-1/2 is a factor then p/4 +5/2+r =0 
p+10+4r=0 
p+4r = 4p+r 
3p =3R 
p=r

Its solution is
5 18 17 4
10 13 14 11
12 9 10 15
19 6 5 16

Hey!!!!

__________

Let p(x) = ax³ + 3x² - 3
and f(x) = 2x³ - 5X + a

=> p(x) is divided by x + 1

=> For REMAINDER p(-1)

=> p(-1) = a(-1)³ + 3(-1)² - 3

=> - a + 3 - 3

=> - a -------(R1)

Similarly

=> f(x) is divided by x + 2

=> p(-2) = 2(-2)³ - 5(-2) + a

=> 2(-8) + 10 + a

=> a - 6 ------- (R2)

Condition = R2 - 2R1 = 0

Let's put values

=> a - 6 + 2A = 0

=> 3a = 6

=> a = 2

__________

Hope this helps ✌️

Divide x into twop PARTS
1st will be x
2nd will be 105-x

Now QUESTION saus 1/2 of first part EXCEEDS i.e. is greater than 1/5 of SECOND part by 35. Which i have done in the FOLLOWING equation

Sum of TWO NUMBERS- 9+5
=14
and the product is 45- 9×5
=45
so the numbers are 9 and 5...
hope U like it and PLEASE follow me

Hey Mate
Here is your answer in the attachment


Hope it HELPS
Cheers!!
Pls MARK as brainliest if it helps

You should DIVIDE 6 8900 /256 then your answer will come if you answer will not come you please COMMENT me then I will GIVE you the correct answer

Two numbers = -4/5 and 1/4

these two numbers are unlike fractions so LETS make them like fractions by multiplying FIRST fraction numerator to SECOND denominator and secong to first

-4/5 *4/4 and 1/4*5/5 

-16 /20 and 5/20

now we can write rational numbers

-16/20 ,-15/20.................................3/20 ,4/20 ,5/20

mark mine as BRAINLIEST if u wish

Let the numbers be x and y
given: x-y=3........(i) and 1/x + 1/y = 7/10....(ii)
from eqn..(i)
x = 3+y....(iii)
PUTTING the value of eqn (iii) in eqn (ii)
(3+y+y)/(3+y)y= 7/10
(3+2y)/(3y+y^2) = 7/10
by cross multiplication
10(3+2y) = 7(3y + y^2)
30 + 20y = 21y + 7y^2
7y^2 + y - 30 = 0
7y^2 - 14y + 15y -30 = 0
7y( y -2 ) + 15( y -2) = 0
(7y + 15)(y - 2) = 0
equating both FACTORS to zero we get
y = -15/7 and y = 2
x = 3-15/7=6/7 , x = 3+2=5
hence,
x = 5 and y = 2
the two numbers are 5 and 2
I hope it will help you so please MARK me brainlist

Hhhhrhvfvr ycuþjrhbebrbr

Hello BUDDY..
Check this out..

6*6=36

Hence PROBABILITIES are, 2, 4 and 6

Hope it helps you buddy

It is SIMPLE
Do by BALANCING the EQUATION
Why you NEED to ASK ? Do it yourself

Hey mate here's your ANSWER....

The NAME of our GALAXY is MILKY way.

Hope it helps ☺️

let the time taken by the first PIPE be x HOURS and the time taken by the SECOND pipe be y hours.

 in 1 hour the first pipe can fill it = 1/x

 in 1 hour the second pipe can fill it = 1/y

1/x +1/y = 1/12 --------------(1)

4/x = 9/9 =1/2---------------(2)

Consider 1/x be a and 1/y be b.

a + b = 1/12 -------------(3)

4A + 9b = 1/2 ----------------(4)

multiply 3 by equ (4) and then subtract equ(5) from equ(4).

4a + 4B =1/3 --------------(5)

we get, b = 1/30

y = 30.

sustituting the value of y in equ(3) we get

a + 1/30 = 1/12

x = 20.

Hence the first pipe would take 20 hours and the second pipe would take 30 hours

The ANSWER will be +49
______________________

➡️Steps:

➡️-7×-7×-7 = __ × -7

➡️49 × -7 = 49× -7

➡️343=343
___________________________
Therefore, 49 must be placed in the blank to MAKE both sides equal.
____________________________

Hope that HELPS!

Hi ,

REQUIRED rational NUMBERS = n = 6

Multiply and divide GIVEN numbers

with = ( n + 1 ) = ( 6 + 1 ) = 7

-2 = ( -2 × 7 )/ 7 = -14/7

3 = ( 3 × 7 )/7 = 21/7

Now required 6 numbers are ,

- 13/7 , - 12/7 , -11/7 , -10/7 , -9/7, -8/7

I HOPE this helps you.

: )

Hope it helps!
PLEASE mark my ANSWER BRAINLIEST!

Hey!!!!

let the share of A,B,C and D be 4x,5x,7x and 11x.

But ATQ,

=> 7x = 1351

=> X = 193

Thus A's share = 4x
=> Share = 4(193)
=> Share = 772

Similarly D's share = 11x
=> Share = 2123

Hope this HELPS ✌️

-28/84 can be EXPRESSED in SMALLER terms by dividing both the NUMERATOR and the denominator by the same number. Here when we divide both the numerator and the denominator by 7 we get -4/12.
The answer is option d.
Hope this HELPS you

1212/0.5=2424
then 6.06*y=2424
so y=2424/6.06
y=400 this is the PERFECT ND BRAINLIEST ANSWER

3056.189922480620
Hope it HELPS you

Hi ,

6 )
a ) 10,00,007

b ) 1,000,002

c ) 1,100,000

d ) 12,00,000

Ascending ORDER of above numbers,

1000002 < 1000007<1100000<1200000

Therefore ,

SMALLEST AMONG the given numbers

is 1000002 ,

Option ( b ) is correct.

7 ) we know that ,

C = 100

X = 10

L = 50

CCCXL

= 100 + 100+ 100+ ( 50 - 10 )

= 300+ 40

= 340

I hope this helps you.

: )

(2A)^2-2(2a)(3)+(3)^2-(7b)^2
ACCORDING to the EQUATION (a-B)^2
(a-b)^2=(a)^2-2ab+(b)^2
(2a-3)^2-(7b)^2
according to (a)^2-(b)^2
(a)^2-(b)^2=(a+b)(a-b)
(2a-3+7b)(2a-3-7b)

A³+b³+c³+3abc(ab+ac+ba).

ANSWER:

Which RATIONAL number

Step-by-step EXPLANATION:

ANSWER:

Rate of tax is 5%

Step-by-step EXPLANATION:

The list price of the item = RS 850

After Paying tax =  Rs 892. 50

Tax = Rs (892. 50- 850)

= 42.50

Now, let the x% is the rate of tax

42.50 = x% of 850

42.50 = (x/100) *850

42.50 = x*85/10

42.50*10/85 = x

425/85 = x

x= 5%

The rate of tax is 5%

2/1 ANSWER has the same ABSOLUTE VALUE as 4/3

HELLO MY DEAR FRIEND

IN MY OPINION HARDIK PANDYA.

I HOPE THIS WILL HELP'S U..............*-*

# ✌️SWETHAPAVS ✌️#

Given,
p(x) = x^3 - 2x^2 + 3x - 1
g(x) = x^2 - 1

just PUT values of g(x) in every x in p(x)...

∴ p(g(x)) = (x^2-1)^3 - 2(x^2 - 1)^2 + 3(x^2 -1) - 1
               = x^6 + 1 + 3x^2(x^2 + 1) - 2(x^4 +1 - 2x^2) + 3x^2 - 3 - 1
               = x^6 +1 + 3x^4 + 3x^2 - 2x^4 - 2 + 4x^2 + 3x^2 - 4
   p(g(x)) = x^6 + x^4 +10x^2 - 5

∴ p(g(1)) = 1 + 1 + 10 - 5 = 7                ...............(1)
   p(-1) = -1 - 2 -3 -1 = - 7                     ...............(2)
   p(1/2) = 1/8 - 2/4 + 3/2 -1 = (1 - 4 + 12 - 8)/8 = 1/8     .....................(3)

∴ p(-1) + p(1/2) - p(g(1)) = - 7 +1/8 - 7
                                       = (- 56 + 1 - 56)/8 
                                       = -111/8 
                                       ≈ -13.875

hope this answer helped you ....
PLEASE mark it as the brainliest if the answer is correct and it helped you. :)