98971 + Interview Questions in Primary School in Math

1.	25a^2-4b^2+28bc-49c^2
Answer» Step-by-step EXPLANATION: HOPE it HELPS you and MARK me as a braienlist and FOLLOW me

1.

25a^2-4b^2+28bc-49c^2

Answer»

Step-by-step EXPLANATION:

HOPE it HELPS you and MARK me as a braienlist and FOLLOW me

Discussion

2.	8. If the coordinates of the two points are P (–7, 5) and Q (–6, 9), then (abscissa of P) – (abscissa of Q) isa) –3b) 1c) –2d) –1
Answer» ANSWER: *If the COORDINATES of the two points are P (–7, 5) and Q (–6, 9), then ( ABSCISSA of P) – (abscissa of Q) is. 2 ... Neetu gave her 3/5 of a cheese BLOCK . How much of cheese ..*

2.

8. If the coordinates of the two points are P (–7, 5) and Q (–6, 9), then (abscissa of P) – (abscissa of Q) isa) –3b) 1c) –2d) –1

Answer»

ANSWER:

If the COORDINATES of the two points are P (–7, 5) and Q (–6, 9), then ( ABSCISSA of P) – (abscissa of Q) is. 2 ... Neetu gave her 3/5 of a cheese BLOCK . How much of cheese ..

Discussion

3.	Find the cost of fencing a square garden of side 150cm at the rate of rupees 18 per meter.
Answer» Answer: rupees 4050 Step-by-step explanation: SIDE of square=150cm area of square=side×side 150×150 =22500cm² cost of fencing at rate of rupees 18 PER meter convert cm into meters 1m=100 cm 1cm=1/100m 22500cm=22500/100 =225m cost of fencing =225×18 = rupees 4050 answer HOPE it HELPS you......

3.

Find the cost of fencing a square garden of side 150cm at the rate of rupees 18 per meter.

Answer»

Answer:

rupees 4050

Step-by-step explanation:

SIDE of square=150cm

area of square=side×side

150×150

=22500cm²

cost of fencing at rate of rupees 18 PER meter

convert cm into meters

1m=100 cm

1cm=1/100m

22500cm=22500/100

=225m

cost of fencing =225×18

= rupees 4050 answer

HOPE it HELPS you......

Discussion

4.	If the diagonal of a rectangle measures 65cm and its sides are in the ratio 12:5, find the sides of the rectangleI will mark him as the brainliest who answers first and correctly
Answer» Given: Diagonal of a rectangle = 65 cm Ratio of the sides of a rectangle is 12:5. ⠀⠀⠀ To FIND: Sides of the rectangle? ⠀⠀⠀ Solution: ☯ Let ABCD be the rectangle and AC be the Diagonal. ⠀⠀⠀⠀ Given that, Ratio of the sides of a rectangle is 12:5. ⠀⠀⠀⠀ So, Let's consider the sides of rectangle are 12X and 5x. ⠀⠀⠀⠀ $\dag\;{\underline{\frak{As\;we\;know\;that,}}}\\ \\$ Each angles of a rectangle are of MEASURE 90°. ⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━ $\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,2.74){\framebox(0.25,0.25)}\put(4.74,0.01){\framebox(0.25,0.25)}\put(2,-0.7){\sf\large 12x}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\qbezier(0,0)(0,0)(5,3)\put(1.65,1.8){\sf\large 65 cm}\put(5.5,1.5){\sf\large 5x}\end{picture}$ ⠀⠀⠀⠀ Now, In ∆ABC, ⠀⠀⠀⠀ $\bigstar\:{\underline{\sf{\pink{Using\; Pythagoras\; Theroem\;\::}}}}\\ \\$ $:\implies\sf (AC)^2 = (AB)^2 + (BC)^2\\ \\$ $:\implies\sf (65)^2 = (12x)^2 + (5x)^2\\ \\$ $:\implies\sf 4225 = 144x^2 + 25x^2\\ \\$ $:\implies\sf 4225 = 169x^2\\ \\$ $:\implies\sf x^2 = \cancel{ \dfrac{4225}{169}}\\ \\$ $:\implies\sf x^2 = 25\\ \\$ $:\implies\sf \sqrt{x^2} = \sqrt{25}\\ \\$ $:\implies{\underline{\boxed{\sf{\purple{x = 5}}}}}\;\bigstar$ ⠀⠀━━━━━━━━━━━━━━━━━━━━ Therefore, Sides of Rectangle are, ⠀⠀⠀ 12x = 12 × 5 = 60 cm 5x = 5 × 5 = 25 cm ⠀⠀⠀ $\therefore\;{\underline{\sf{Hence,\;sides\;of\;rectangle\;are\; {\textsf{\textbf{60\;cm\;and\;25\;cm}}}.}}}$

4.

If the diagonal of a rectangle measures 65cm and its sides are in the ratio 12:5, find the sides of the rectangleI will mark him as the brainliest who answers first and correctly

Answer»

Given:

Diagonal of a rectangle = 65 cm
Ratio of the sides of a rectangle is 12:5.

⠀⠀⠀

To FIND:

Sides of the rectangle?

⠀⠀⠀

Solution:

☯ Let ABCD be the rectangle and AC be the Diagonal.

⠀⠀⠀⠀

Given that,

Ratio of the sides of a rectangle is 12:5.

⠀⠀⠀⠀

So, Let's consider the sides of rectangle are 12X and 5x.

⠀⠀⠀⠀

$\dag\;{\underline{\frak{As\;we\;know\;that,}}}\\ \\$

Each angles of a rectangle are of MEASURE 90°.

⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,2.74){\framebox(0.25,0.25)}\put(4.74,0.01){\framebox(0.25,0.25)}\put(2,-0.7){\sf\large 12x}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\qbezier(0,0)(0,0)(5,3)\put(1.65,1.8){\sf\large 65 cm}\put(5.5,1.5){\sf\large 5x}\end{picture}$

⠀⠀⠀⠀

Now, In ∆ABC,

⠀⠀⠀⠀

$\bigstar\:{\underline{\sf{\pink{Using\; Pythagoras\; Theroem\;\::}}}}\\ \\$

$:\implies\sf (AC)^2 = (AB)^2 + (BC)^2\\ \\$

$:\implies\sf (65)^2 = (12x)^2 + (5x)^2\\ \\$

$:\implies\sf 4225 = 144x^2 + 25x^2\\ \\$

$:\implies\sf 4225 = 169x^2\\ \\$

$:\implies\sf x^2 = \cancel{ \dfrac{4225}{169}}\\ \\$

$:\implies\sf x^2 = 25\\ \\$

$:\implies\sf \sqrt{x^2} = \sqrt{25}\\ \\$

$:\implies{\underline{\boxed{\sf{\purple{x = 5}}}}}\;\bigstar$

⠀⠀━━━━━━━━━━━━━━━━━━━━

Therefore, Sides of Rectangle are,

⠀⠀⠀

12x = 12 × 5 = 60 cm
5x = 5 × 5 = 25 cm

⠀⠀⠀

$\therefore\;{\underline{\sf{Hence,\;sides\;of\;rectangle\;are\; {\textsf{\textbf{60\;cm\;and\;25\;cm}}}.}}}$

Discussion

5.	Write the expression:1. m Increased by 8.2. b decreased by B.
Answer» Answer: 1. m+8 2. b-31

5.

Write the expression:1. m Increased by 8.2. b decreased by B.

Answer»

Answer:

1. m+8

2. b-31

Discussion

6.	8. Convert each part of the given ratio into percentage:(a) 2:5(b) 1:2:3
Answer» Answer: 1. 40% Step-by-step explanation: 2/5×100 2×20=40

6.

8. Convert each part of the given ratio into percentage:(a) 2:5(b) 1:2:3

Answer»

Answer:

1. 40%

Step-by-step explanation:

2/5×100

2×20=40

Discussion

7.	Please re.move following meplzzzzzzzzzzzzzzz
Answer» ANSWER: whyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

7.

Please re.move following meplzzzzzzzzzzzzzzz

Answer»

ANSWER:

whyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

Discussion

8.	Please friends it's urgent solve this questions please. CHAPTER-4 EXPONENTS & POWERS WORKSHEET 4, CLASS VII DAVPLEASE FRIENDS NO SPAMING
Answer» ANSWER: CBSE or STATE board i cant UNDERSTAND the question PLEASE type the question

8.

Please friends it's urgent solve this questions please. CHAPTER-4 EXPONENTS & POWERS WORKSHEET 4, CLASS VII DAVPLEASE FRIENDS NO SPAMING

Answer»

ANSWER:

CBSE or STATE board i cant UNDERSTAND the question PLEASE type the question

Discussion

9.	Write the expression :1. m increased by 82. b decreased by 31
Answer» Answer: 1. m+8 2. b-31

9.

Write the expression :1. m increased by 82. b decreased by 31

Answer»

Answer:

1. m+8

2. b-31

Discussion

10.	The area for trapezium is 405 centimetres square and the ratio of parallel sides is 4:5 and height is 18 centimetres find the actual length of the parallel sides.No spam✔
Answer» Given: Area of the trapezium = 405cm² ratio of PARALLEL sides = 4:5 height of the trapezium = 18cm To Find: Actual LENGTH of the parallel sides Solution: Let the parallel side be 4X and 5x respectively height = 18cm the area of trapezium = 405cm² ⠀⠀⟹ $\frac{<klux>1</klux>}{2} h(a + b) = 405$ ⠀⠀⟹ $\frac{1}{2} \times 18 \times (4x + 5x) = 405$ ⠀⠀⟹ $9 \times 9x = 405⟹9×9x=405$ ⠀⠀⟹ $81x = 405⟹81x=405$ $\: x = \frac{405}{81} = 5$ ➞actual Length of parallel side 1 = 4 × 5 ${\boxed{\sf{\red{=\:20\:cm}}}}$ ➞actual Length of parallel side 2 = 5 × 5 ${\boxed{\sf{\red{=\:25\:cm}}}}$

10.

The area for trapezium is 405 centimetres square and the ratio of parallel sides is 4:5 and height is 18 centimetres find the actual length of the parallel sides.No spam✔

Answer»

Given:

Area of the trapezium = 405cm²

ratio of PARALLEL sides = 4:5

height of the trapezium = 18cm

To Find:

Actual LENGTH of the parallel sides

Solution:

Let the parallel side be 4X and 5x respectively

height = 18cm

the area of trapezium = 405cm²

⠀⠀⟹ $\frac{<klux>1</klux>}{2} h(a + b) = 405$

⠀⠀⟹ $\frac{1}{2} \times 18 \times (4x + 5x) = 405$

⠀⠀⟹ $9 \times 9x = 405⟹9×9x=405$

⠀⠀⟹ $81x = 405⟹81x=405$

$\: x = \frac{405}{81} = 5$

➞actual Length of parallel side 1 = 4 × 5

${\boxed{\sf{\red{=\:20\:cm}}}}$

➞actual Length of parallel side 2 = 5 × 5

${\boxed{\sf{\red{=\:25\:cm}}}}$

Discussion

11.	Find the square of 4x-5 by using identity. Write the identity used also.
Answer» ANSWER: (4x-5)^2=16x^2-40x+25 Step-by-step EXPLANATION: ${(4x - 5)}^{2} \\ {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} \\ {(4x - 5)}^{2} = {(4x)}^{2} - 2(4x)(5) + {5}^{2} \\ = ( {4})^{2} ( {x})^{2} - 10(4x) + 25 \\ = 16 {x}^{2} - 40x + 25 \\ therefore \: ({4x - 5})^{2} = 16 {x}^{2} - 40x + 25$

11.

Find the square of 4x-5 by using identity. Write the identity used also.

Answer»

ANSWER:

(4x-5)^2=16x^2-40x+25

Step-by-step EXPLANATION:

${(4x - 5)}^{2} \\ {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} \\ {(4x - 5)}^{2} = {(4x)}^{2} - 2(4x)(5) + {5}^{2} \\ = ( {4})^{2} ( {x})^{2} - 10(4x) + 25 \\ = 16 {x}^{2} - 40x + 25 \\ therefore \: ({4x - 5})^{2} = 16 {x}^{2} - 40x + 25$

Discussion

12.	The sides of the triangular field is in the ratio 13:12:5 and its perimeter is 900m find the area of the field and also find the cost of ploughing the field at the rate of Rs 25/msquare. BY USING HERON'S FORMULAplsssss help its urgent
Answer» Answer: 13+12+5=30 900/30=30

12.

The sides of the triangular field is in the ratio 13:12:5 and its perimeter is 900m find the area of the field and also find the cost of ploughing the field at the rate of Rs 25/msquare. BY USING HERON'S FORMULAplsssss help its urgent

Answer»

Answer:

13+12+5=30

900/30=30

Discussion

13.	If 25/2 % of a number is 90, find the number
Answer» Answer: 720 Step-by-step explanation: LET the NUMBER be x (25/2 )/100 × x = 90 25/ 2 × 1/100 × x = 90 25/200 × x = 90 1/ 8 × x = 90 x = 90 × 8 x = 720 *HOPE* *THIS* *WILL* *HELP* *YOU*!

13.

If 25/2 % of a number is 90, find the number

Answer»

Answer:

720

Step-by-step explanation:

LET the NUMBER be x

(25/2 )/100 × x = 90

25/ 2 × 1/100 × x = 90

25/200 × x = 90

1/ 8 × x = 90

x = 90 × 8

x = 720

HOPE THIS WILL HELP YOU!

Discussion

14.	What is 10+10 and 20+20 and 30+30 and 40+40
Answer» Answer: 10+10= 20 20+20= 40 30+30= 60 40+40= 80 Step-by-step EXPLANATION: if they ASKED to ADD the answers then all together is EQUAL to 200

14.

What is 10+10 and 20+20 and 30+30 and 40+40

Answer»

Answer:

10+10= 20

20+20= 40

30+30= 60

40+40= 80

Step-by-step EXPLANATION:

if they ASKED to ADD the answers then all together is EQUAL to 200

Discussion

15.	2x - 2 = 6x + 8what's the answer.......
Answer» Answer: 2x - 2 = 6X + 8 2x - 6x = 8 + 2 -4x = 10 x = -5/2

15.

2x - 2 = 6x + 8what's the answer.......

Answer»

Answer:

2x - 2 = 6X + 8

2x - 6x = 8 + 2

-4x = 10

x = -5/2

Discussion

16.	Find simple interest when ₹ 340.50 for 6 months at rate of 20% per annum
Answer» Step-by-step EXPLANATION: PLS FOLLOW me ☺️ ❣️

16.

Find simple interest when ₹ 340.50 for 6 months at rate of 20% per annum

Answer»

Step-by-step EXPLANATION:

PLS FOLLOW me ☺️ ❣️

Discussion

17.	Divide -: (axy+bcxy-az-bcz) by (xy-z) using factorization method
Answer» ANSWER: a+bc Step-by-step EXPLANATION: after FACTORISING RESULT:— (a+bc)(xy‐z) so now DIVIDE (a+bc)(xy‐z)/(xy‐z) =a+bc

17.

Divide -: (axy+bcxy-az-bcz) by (xy-z) using factorization method

Answer»

ANSWER:

a+bc

Step-by-step EXPLANATION:

after FACTORISING RESULT:—

(a+bc)(xy‐z)

so now DIVIDE

(a+bc)(xy‐z)/(xy‐z)

=a+bc

Discussion

18.	Still I am having 21 followers plzzz remove it
Answer» ANSWER: how is this MATHS????? Step-by-step EXPLANATION:

18.

Still I am having 21 followers plzzz remove it

Answer»

ANSWER:

how is this MATHS?????

Step-by-step EXPLANATION:

Discussion

19.	Are 15,20,30,40 proportion
Answer» YES they are in PROPORTION because PRODUCT of MEAN and EXTREME is same 15×40=20×30 600=600

19.

Are 15,20,30,40 proportion

Answer»

YES they are in PROPORTION because PRODUCT of MEAN and EXTREME is same

15×40=20×30

600=600

Discussion

20.	কমবেশি ১৫ শব্দে উত্তর দাও :‘পাগলা ভােলা কে ?ব) বাঘে-কৃষতে যার অর্থ কী ?) তারা শ্বেতাঙ্গদের এড়িয়ে চলে’ - এড়িয়ে চলার কারণ কী ?) সহজদের সঙ্গে কোন্ কোন্ বিভক্তি যুক্ত হয় ?) বাক্যের মাধ্যমে সাপেক্ষ সর্বনামের উদাহরণ দাও।মবেশি ১৫০ টি শব্দে উত্তর দাও :৫x৩= ১৫) আবহমান কবিতার মধ্য দিয়ে গ্রামীণ প্রকৃতির যে প্রতিচ্ছবি প্রকাশিত হয়েছেতার পরিচয় দাও।‘রাধারানী গন্যাংশে রাধারানীর চরিত্র আলােচনা করাে।‘হিমালয় দর্শন’ প্রবন্ধ অবলম্বনে ভুটিয়ানিদের জীবনযাত্রার পরিচয় দাও।
Answer» ANSWER: I can't UNDERSTAND this LANGUAGE..........

20.

কমবেশি ১৫ শব্দে উত্তর দাও :‘পাগলা ভােলা কে ?ব) বাঘে-কৃষতে যার অর্থ কী ?) তারা শ্বেতাঙ্গদের এড়িয়ে চলে’ - এড়িয়ে চলার কারণ কী ?) সহজদের সঙ্গে কোন্ কোন্ বিভক্তি যুক্ত হয় ?) বাক্যের মাধ্যমে সাপেক্ষ সর্বনামের উদাহরণ দাও।মবেশি ১৫০ টি শব্দে উত্তর দাও :৫x৩= ১৫) আবহমান কবিতার মধ্য দিয়ে গ্রামীণ প্রকৃতির যে প্রতিচ্ছবি প্রকাশিত হয়েছেতার পরিচয় দাও।‘রাধারানী গন্যাংশে রাধারানীর চরিত্র আলােচনা করাে।‘হিমালয় দর্শন’ প্রবন্ধ অবলম্বনে ভুটিয়ানিদের জীবনযাত্রার পরিচয় দাও।

Answer»

ANSWER:

I can't UNDERSTAND this LANGUAGE..........

Discussion

21.	Express 200 km with the ratio 45000m
Answer» Answer: 200:45 I HOPE it will HELP you

21.

Express 200 km with the ratio 45000m

Answer»

Answer:

200:45

I HOPE it will HELP you

Discussion

22.	Find the product (-1) ×(-2) ×(-3) ×4
Answer» Step-by-step EXPLANATION: (-1)×(-2)×(-3)×4 = -24

22.

Find the product (-1) ×(-2) ×(-3) ×4

Answer»

Step-by-step EXPLANATION:

(-1)×(-2)×(-3)×4

= -24

Discussion

23.	GUYS PLZ ANS QUICKLY THEN WILL MARK AS BRILLIANT LIST
Answer» Answer: 18. 6 shirts Step-by-step EXPLANATION:

23.

GUYS PLZ ANS QUICKLY THEN WILL MARK AS BRILLIANT LIST

Answer»

Answer:

18. 6 shirts

Step-by-step EXPLANATION:

Discussion

24.	-5z = 4 simple linear equationsAns
Answer» Step-by-step EXPLANATION: -5Z = 4 -z = 4/5 z = -4/5 plz THANK me

24.

-5z = 4 simple linear equationsAns

Answer»

Step-by-step EXPLANATION:

-5Z = 4

-z = 4/5

z = -4/5

plz THANK me

Discussion

25.	Divide (16pr² - 8pr³- 4p²r5) by -4pr²
Answer» ANSWER: HOPE it's HELP you plese mark me as BRAINLIST

25.

Divide (16pr² - 8pr³- 4p²r5) by -4pr²

Answer»

ANSWER:

HOPE it's HELP you plese mark me as BRAINLIST

Discussion

26.	Value of x in 7:14::x:30
Answer» Step-by-step EXPLANATION: PRODUCT of exremes = product of means 7×30=14×x 210/14=x x=15

26.

Value of x in 7:14::x:30

Answer»

Step-by-step EXPLANATION:

PRODUCT of exremes = product of means

7×30=14×x

210/14=x

x=15

Discussion

27.	(256)1/2find the ans for the above ques and show the working of it
Answer» $\large\underline\bold{\mathcal{\orange{ANSWER}} }$ $\rm{\boxed{\sf{ \purple{ \mathfrak{ \:\:\:\:\:\:128.\:\:\:\:\:\:} }}}}$ $\rm\underline{\underline{\bold{\pink{\mathfrak{explanation\:in\:detail:-}}}}}$ $\red{\huge{\star}}\:\:\:\: \dfrac{(256)1}{2} \\ \\ :\implies \dfrac{256 \times 1}{2} \\ \\:\implies \dfrac{\cancel{256} \times 1}{ \cancel{\:2\:}} \\ \\ :\implies \dfrac{128 \times 1}{ 1} \\ \\ :\implies \dfrac{128}{1} \\ \\ :\implies 128 .$ $\\ \rm{\boxed{\underline{ \pink{ \mathcal{ \:\:\:\:\:\: 128\:\:\:\:\:\:}}}}}$ $\rm{\underline{\bold{ \underline{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:}}}}$

27.

(256)1/2find the ans for the above ques and show the working of it

Answer»

$\large\underline\bold{\mathcal{\orange{ANSWER}} }$

$\rm{\boxed{\sf{ \purple{ \mathfrak{ \:\:\:\:\:\:128.\:\:\:\:\:\:} }}}}$

$\rm\underline{\underline{\bold{\pink{\mathfrak{explanation\:in\:detail:-}}}}}$

$\red{\huge{\star}}\:\:\:\: \dfrac{(256)1}{2} \\ \\ :\implies \dfrac{256 \times 1}{2} \\ \\:\implies \dfrac{\cancel{256} \times 1}{ \cancel{\:2\:}} \\ \\ :\implies \dfrac{128 \times 1}{ 1} \\ \\ :\implies \dfrac{128}{1} \\ \\ :\implies 128 .$

$\\ \rm{\boxed{\underline{ \pink{ \mathcal{ \:\:\:\:\:\: 128\:\:\:\:\:\:}}}}}$

$\rm{\underline{\bold{ \underline{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:}}}}$

Discussion

28.	क्रियाकलापअधिकांश धर्मा में मानवप्राणियों की रचना के बारेमें अनेक कहानियाँ कहीगई हैं, पर अक्सर वेवैज्ञानिक खोजों से मेल नहींखाती। ऐसी कुछ धार्मिककथाओं के बारे में पतालगाइए और उनकी तुलनाइस अध्याय में चर्चित मानवके क्रमिक विकास केइतिहास से कीजिए। आपउनके बीच क्या समानताएँऔर अंतर देखत है।
Answer» Step-by-step EXPLANATION: rzd-zxgk-dce join it PLEASE GIRLS'

28.

क्रियाकलापअधिकांश धर्मा में मानवप्राणियों की रचना के बारेमें अनेक कहानियाँ कहीगई हैं, पर अक्सर वेवैज्ञानिक खोजों से मेल नहींखाती। ऐसी कुछ धार्मिककथाओं के बारे में पतालगाइए और उनकी तुलनाइस अध्याय में चर्चित मानवके क्रमिक विकास केइतिहास से कीजिए। आपउनके बीच क्या समानताएँऔर अंतर देखत है।

Answer»

Step-by-step EXPLANATION:

rzd-zxgk-dce

join it PLEASE GIRLS'

Discussion

29.	A)Look carefully at the circuits shown & answer which bulb will glow in each case.C2a) Ab) Bc) Cd) all of thesetoa) Ab) Bc) Cno none of these
Answer» Step-by-step explanation: ) Look carefully at the circuits shown & answer which BULB will GLOW in each case. C 2 a) A b) B c) C d) all of these to a) A b) B c) C no NONE of these

29.

A)Look carefully at the circuits shown & answer which bulb will glow in each case.C2a) Ab) Bc) Cd) all of thesetoa) Ab) Bc) Cno none of these

Answer»

Step-by-step explanation:

)

Look carefully at the circuits shown & answer which BULB will GLOW in each case.

C

2

a) A

b) B

c) C

d) all of these

to

a) A

b) B

c) C

no NONE of these

Discussion

30.	the numerator of a rational no.is less than its denominator if the numerator is increased by 1 and denominator is incrased by 3 the no. becomes 1/2 find the rational no.
Answer» Answer: 2/3 Step-by-step explanation: 2+1=3 and 3+3= 6 3/6 in LOWEST FORM is 1/2

30.

the numerator of a rational no.is less than its denominator if the numerator is increased by 1 and denominator is incrased by 3 the no. becomes 1/2 find the rational no.

Answer»

Answer:

2/3

Step-by-step explanation:

2+1=3 and 3+3= 6

3/6 in LOWEST FORM is 1/2

Discussion

31.	15. The radii of two circles are 20 cm and 13 cm. Find the difference between their circumference
Answer» Step-by-step explanation: Radius of 1st circle = 20 cm CIRCUMFERENCE of the circle = 2πr = 2 × 22/7 × 20 = 880/7 = 122.8 cm Radius of 2ND circle = 13 cm Circumference of the circle = 2 πr = 2 × 22/7 × 13 = 572/7 = 81.7 ∴ Difference of circumference of TWO CIRCLES = 122.8 – 81.7 cm = 41.1 cm follow me ✌️❤️ this is done✌️❤️

31.

15. The radii of two circles are 20 cm and 13 cm. Find the difference between their circumference

Answer»

Step-by-step explanation:

Radius of 1st circle = 20 cm

CIRCUMFERENCE of the circle = 2πr

= 2 × 22/7 × 20

= 880/7 = 122.8 cm

Radius of 2ND circle = 13 cm

Circumference of the circle = 2 πr

= 2 × 22/7 × 13 = 572/7 = 81.7

∴ Difference of circumference of TWO CIRCLES

= 122.8 – 81.7 cm = 41.1 cm

follow me ✌️❤️

this is done✌️❤️

Discussion

32.	A rectangular piece of land measures 0.8 km by 0.6 km. Each side is to be fenced withthree rows of wire. Find the length of the wire needed. If the cost of fencing is 250 permetre, find the total cost of fencing the land
Answer» Given a rectangular PIECE of land with dimensions length(L)=.8KM and breadth= .6km To FIND: the cost of fencing the land Perimeter of the land= 2(l+b) =2(.8+.6) = 2× 1.4=2.8km Wire needed to fence THREE rows=3×2.8= 8.4km =8.4×1000=8400m (1km=1000m) Cost per metre=250Rs Therefore cost for fencing 8400m= 8400×250=21,00,000Rs

32.

A rectangular piece of land measures 0.8 km by 0.6 km. Each side is to be fenced withthree rows of wire. Find the length of the wire needed. If the cost of fencing is 250 permetre, find the total cost of fencing the land

Answer»

Given a rectangular PIECE of land with dimensions length(L)=.8KM and breadth= .6km

To FIND: the cost of fencing the land

Perimeter of the land= 2(l+b)

=2(.8+.6)

= 2× 1.4=2.8km

Wire needed to fence THREE rows=3×2.8= 8.4km

=8.4×1000=8400m

(1km=1000m)

Cost per metre=250Rs

Therefore cost for fencing 8400m= 8400×250=21,00,000Rs

Discussion

33.	If x=20 and y=40 then x and yare
Answer» ANSWER: hanakaalabbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbvv

33.

If x=20 and y=40 then x and yare

Answer»

ANSWER:

hanakaalabbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbvv

Discussion

34.	Are 15,20,30,40 I.
Answer» ANSWER:UHM i do not GET the QUESTION, POST it again

Discussion

35.	A man borrows rupees 6250 at 4% per annum compounded annually .the amount will receive after 2 year is what
Answer» Answer: Answer: Up Helly Aa is a type of fire FESTIVAL held annually from January to March in various communities in Shetland, Scotland to mark the END of the YULE season. \: \: Step-by-step EXPLANATION: PLEZZZZZ

35.

A man borrows rupees 6250 at 4% per annum compounded annually .the amount will receive after 2 year is what

Answer»

Answer:

Answer:

Up Helly Aa is a type of fire FESTIVAL held annually from January to March in various communities in Shetland, Scotland to mark the END of the YULE season.

\: \:

Step-by-step EXPLANATION:

PLEZZZZZ

Discussion

36.	Simplify (a+b) (2a – 3b +c) –c(2a-3b)
Answer» ANSWER: $2a {}^{2} - 3ab + ac + 2ab - 3b {}^{2} + cb - 2ac + 3bc$ $2a {}^{2} - 3b {}^{2} - 3ab + 2ab + ac - 2ac + bc + 3bc$ $2a {}^{2} - 3b {}^{2} - ab - ac + 4cb$

36.

Simplify (a+b) (2a – 3b +c) –c(2a-3b)

Answer»

ANSWER:

$2a {}^{2} - 3ab + ac + 2ab - 3b {}^{2} + cb - 2ac + 3bc$

$2a {}^{2} - 3b {}^{2} - 3ab + 2ab + ac - 2ac + bc + 3bc$

$2a {}^{2} - 3b {}^{2} - ab - ac + 4cb$

Discussion

37.	Find the following i) 5(-1) ii)(-1)6 iii) (-6)(-1) iv) (-1)(-10) v) (-1)*aQuickly please
Answer» Answer: 1. -5 2. -6 3. 6 4. 10 5 -1a Step-by-step explanation: 1. 5×1 PLUS MINUS is minus 2. 6×1 plus minus is minus 3. 6×1 minus minus is plus 4 1×10 minus minus is plus 5. 1×a plus minus is minus hope it HELPS u........

37.

Find the following i) 5(-1) ii)(-1)6 iii) (-6)(-1) iv) (-1)(-10) v) (-1)*aQuickly please

Answer»

Answer:

1. -5

2. -6

3. 6

4. 10

5 -1a

Step-by-step explanation:

1. 5×1 PLUS MINUS is minus

2. 6×1 plus minus is minus

3. 6×1 minus minus is plus

4 1×10 minus minus is plus

5. 1×a plus minus is minus

hope it HELPS u........

Discussion

38.	Find the HCF of 48,36,24 by prime factorisation
Answer» Answer: step 1 Address the method, input PARAMETERS & values Integers: 24, 36, 48 find gcf (24, 36 and 48) = ? step 2 Find the prime factors of all integers of the GROUP 24 = 2 x 2 x 2 x 3 36 = 2 x 2 x 3 x 3 48 = 2 x 2 x 2 x 2 x 3 step 3 The COMMON prime factor or the product of all common prime factors between all integers is the highest common factor of this group of integers (24, 36 & 48). HCF(24, 36, 48) = 12

38.

Find the HCF of 48,36,24 by prime factorisation

Answer»

Answer:

step 1

Address the method, input PARAMETERS & values

Integers: 24, 36, 48

find gcf (24, 36 and 48) = ?

step 2

Find the prime factors of all integers of the GROUP

24 = 2 x 2 x 2 x 3

36 = 2 x 2 x 3 x 3

48 = 2 x 2 x 2 x 2 x 3

step 3

The COMMON prime factor or the product of all common prime factors between all integers is the highest common factor of this group of integers (24, 36 & 48).

HCF(24, 36, 48) = 12

Discussion

39.	Solve fastt.. plz zzz
Answer» <P> $\Large{\underline{\underline{\tt{\purple{Given}}}}}$ FORCE (F) = 48000N Pressure (P) = 120 P $\Large{\underline{\underline{\tt{\purple{Find\:out}}}}}$ Find the area of base ? $\Large{\underline{\underline{\tt{\purple{Solution}}}}}$ As we know that $\begin{gathered}\implies\sf P=\dfrac{F}{A} \\ \\ \\ \implies\sf 120=\dfrac{48000}{A} \\ \\ \\ \implies\sf 120A=48000 \\ \\ \\ \implies\sf A=\cancel\dfrac{48000}{120}=400m^2\end{gathered}$ $\large{\underline{\boxed{\bf{\red{Area\:of\:statue=400m^2}}}}}$ $\Large{\underline{\underline{\tt{\purple{Extra\: Information}}}}}$ —: Acceleration = v - u/t —: Force = mass × acceleration —: SPEED = distance/time

39.

Solve fastt.. plz zzz

Answer»

<P> $\Large{\underline{\underline{\tt{\purple{Given}}}}}$

FORCE (F) = 48000N

Pressure (P) = 120 P

$\Large{\underline{\underline{\tt{\purple{Find\:out}}}}}$

Find the area of base ?

$\Large{\underline{\underline{\tt{\purple{Solution}}}}}$

As we know that

$\begin{gathered}\implies\sf P=\dfrac{F}{A} \\ \\ \\ \implies\sf 120=\dfrac{48000}{A} \\ \\ \\ \implies\sf 120A=48000 \\ \\ \\ \implies\sf A=\cancel\dfrac{48000}{120}=400m^2\end{gathered}$

$\large{\underline{\boxed{\bf{\red{Area\:of\:statue=400m^2}}}}}$

$\Large{\underline{\underline{\tt{\purple{Extra\: Information}}}}}$

—: Acceleration = v - u/t

—: Force = mass × acceleration

—: SPEED = distance/time

Discussion

40.	Decimal representation of 11/2. is
Answer» Answer: decimal representation of 11/(2^3× 5) will A. TERMINATE after 1 decimal PLACE B. terminate after 2 ...

40.

Decimal representation of 11/2. is

Answer»

Answer:

decimal representation of 11/(2^3× 5) will A. TERMINATE after 1 decimal PLACE B. terminate after 2 ...

Discussion

41.	Answer my question and put tanks for me pls
Answer» Step-by-step EXPLANATION: I am TRYING to SOLVE your PROBLEM

41.

Answer my question and put tanks for me pls

Answer»

Step-by-step EXPLANATION:

I am TRYING to SOLVE your PROBLEM

Discussion

42.	Why is money considered so portant class 9th english
Answer» Answer: Money is not everything, but money is something very important. BEYOND the basic needs, money helps us achieve our LIFE's goals and SUPPORTS — the things we CARE about most deeply — family, education, health care, charity, adventure and fun.

42.

Why is money considered so portant class 9th english

Answer»

Answer:

Money is not everything, but money is something very important. BEYOND the basic needs, money helps us achieve our LIFE's goals and SUPPORTS — the things we CARE about most deeply — family, education, health care, charity, adventure and fun.

Discussion

43.	Factorise and divide (25p2 -121q2) by (5p+11q)
Answer» ANSWER: HOPE it will HELP you....

43.

Factorise and divide (25p2 -121q2) by (5p+11q)

Answer»

ANSWER:

HOPE it will HELP you....

Discussion

44.	2. WhatWhat will be the value of x
Answer» Answer: 1 Step-by-step EXPLANATION: PLS MAKES me BRAINLIEST and FOLLOW me

44.

2. WhatWhat will be the value of x

Answer»

Answer:

1

Step-by-step EXPLANATION:

PLS MAKES me BRAINLIEST and FOLLOW me

Discussion

45.	sun of the angles of a polygon is 2700. Find the sum of angle in the polygon with one side less than it
Answer» Answer: 2520.......................... Step-by-step EXPLANATION: the SUM of angle in the POLYGON is (n-2)×180 (n-2)×180=2700 n-2=15 n=17 we REQUIRE the sum of angle in the polygon with one side less than it so 17-1=16 (16-2)×180=14×180=2520

45.

sun of the angles of a polygon is 2700. Find the sum of angle in the polygon with one side less than it

Answer»

Answer:

2520..........................

Step-by-step EXPLANATION:

the SUM of angle in the POLYGON is (n-2)×180

(n-2)×180=2700

n-2=15

n=17

we REQUIRE the sum of angle in the polygon with one side less than it so 17-1=16

(16-2)×180=14×180=2520

Discussion

46.	Find the ans for:-A) [256]1/2
Answer» ANSWER: CORRECT answer is 128.

46.

Find the ans for:-A) [256]1/2

Answer»

ANSWER:

CORRECT answer is 128.

Discussion

47.	Express 200 kg with the ratio 1.6 kg
Answer» ANSWER: (12.5:0.1)KG RATIO in kg (125:1)G ratio in GRAM

47.

Express 200 kg with the ratio 1.6 kg

Answer»

ANSWER:

(12.5:0.1)KG RATIO in kg

(125:1)G ratio in GRAM

Discussion

48.	Formula of selling price
Answer» ANSWER: CP + Profit/loss hope it HELPS

48.

Formula of selling price

Answer»

ANSWER:

CP + Profit/loss

hope it HELPS

Discussion

49.	Find the product (-1) ×225
Answer» ANSWER: ANS is _225 it's helpful PLEASE follow me

49.

Find the product (-1) ×225

Answer»

ANSWER:

ANS is _225

it's helpful

PLEASE follow me

Discussion

50.	Please help me...............☺️
Answer» Answer: use COMPONENDO dividendo PROPERTY to REMOVE the square roots

50.

Please help me...............☺️

Answer»

Answer:

use COMPONENDO dividendo PROPERTY to REMOVE the square roots

Discussion

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