

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
451. |
A quadrilateral in which one pair of opposite sides are parallel is a A) parallelogram B) kite C) trapeziumD) rhombus |
Answer» Correct option is (C) trapezium A quadrilateral in which one pair of opposite sides are parallel is a trapezium. C) trapezium |
|
452. |
If diagonal of a parallelogram bisects one of the angles of theparallelogram, it also bisects the second angle. Also, prove that it is arhombus. |
Answer» Given- AC diagonal bisects `/_A` AB||CD and AC is transverse `/_3=/_1-(1)` AD||BC and AC is transverse `/_2=/_4-(2)` AC bisects`/_A` `/_1=/_2-(3)` `/_3=/_4` AC bisects `/_A` `/_1=/_4` AB=DC and BC=AB AB=BC-CD=CD ABCD is a rhombus. |
|
453. |
In Figure, `M ,N`and `P`are the mid-points of `A B ,A C`and `B C`respectively. If `M N=3c m ,N P=3. 5c m`and `M P=2. 5c m ,`calculate `B C ,A B`and `A Cdot` |
Answer» In`/_ABC` Since, H is the mid point of AB and N is the mid point of AC MN||BC and `MN=1/2BC` BC=2MN P is midpoint of BC PN||AB and `PN=1/2AB` NP||AC and `MP=1/2AC` BC=2*3=6cm AB=2*3.5=7cm AC=2*2.5=5cm. |
|
454. |
In ` A B C ,A D`is the median through `A`and `E`is the mid-point of `A D`. `B E`produced meets `A C`in `F`(Figure). Prove that `A F=1/3A Cdot` |
Answer» Construction DK||BF In`/_ADK` E is the midpoint od AD and EF||DK F is the midpoint of AK AF=FK-(1) K is the mid point of FC FK=KC-(2) FK=KC=KC AC=AF+FK+KC AC=AF+AF+AF=3AF `AF=1/3AC`. |
|
455. |
In a ` A B C`, find the measures of the angles of the triangle formed by joining themid-points of the sides of this triangle. |
Answer» Given D,E,F are mid point AB,BC and CA DE||AB,FE||BC and DF||CA DE||AB and BC and CA tranverse `/_CDE=/_B` `/_CED=/_A` EF||BC `/_AEF=/_C` and `/_AFE=/_B` OF||CA `/_BDF=/_C` and `/_BFD=/_A` `/_BDF+/_FDE+/_EDC=180^@` `/_C+/_FOE+/_B=180^@` `/_FDE=180-(/_B+/_C)` `/_FDE=/_A` `/_DEF=180^@-(/_A+/_C)=/_B` `/_EFD=180^@-(/_A+/_B)=/_A` `/_D=/_A,/_E=/_B,/_F=/_C`. |
|
456. |
Fill in the blanks to make the following statements correct :(i) The triangle formed by joining the mid-points of the sides of an isosceles triangle is….. (ii) The triangle formed by joining the mid-points of the sides of a right triangle is….. (iii) The figure formed by joining the mid-points of consecutive sides of a quadrilateral is…… |
Answer» (i) Isosceles. (ii) Right triangle. (iii) Parallelogram. |
|
457. |
Show that the line segments joining the mid-points of the opposite sides of a quadrilateral bisect each other. |
Answer» Data : P, Q, R and S are mid-points of AB, BC, CD and DA respectively in quadrilateral ABCD. To Prove: PR and SQ line segments bisect mutually. Construction: Join the diagonal AC. Proof: In ∆ADC, S and R are the mid-points of AD and DC. ∴ SR || AC SR = \(\frac{1}{2}\)AC ………… (i) (Mid-point Theorem) Similarly, in ∆ABC, PQ || AC PQ = \(\frac{1}{2}\)AC …………. (ii) From (i) and (ii), SR = PQ and SR || PQ ∴ PQRS is a parallelogram. PR and SQ are the diagonals of parallelogram PQRS. ∴PR and SQ meet at O’. |
|
458. |
Show that the line segments joining the mid points of the opposite sides of a quadrilateral and bisect each other. |
Answer» Let ABCD be a quadrilateral. P, Q, R, S are the midpoints of sides of □ABCD. Join (P, Q), (Q, R), (R, S) and (S, P). In ΔABC; P, Q are the midpoints of AB and BC. ∴ PQ // AC and PQ = 1/2 AC ………….(1) Also from ΔADC S, R are the midpoints of AD and CD SR // AC and SR = 1/2 AC …………………(2) ∴ From (1) & (2) PQ = SR and PQ //SR ∴ □PQRS is a parallelogram. Now PR and QS are the diagonals of □ PQRS. ∴ PR and QS bisect each other. |
|
459. |
The quadrilateral in which the diagonals are equal but not perpendicular to each other is A) Square B) Rhombus C) Parallelogram D) Rectangle |
Answer» Correct option is (D) Rectangle The quadrilateral in which the diagonals are equal but not perpendicular to each other is a rectangle. Correct option is D) Rectangle |
|
460. |
The quadrilateral in which the diagonals bisect each other and they are perpendicular to each other A) Rectangle B) Rhombus C) Parallelogram D) Trapezium |
Answer» Correct option is: B) Rhombus |
|
461. |
What is Polygons? |
Answer» We are familiar with plane figures bounded by straight line segments as sides. They are known as Polygons. |
|
462. |
The three angles of a quadrilateral measure 56°, 100° and 88°. Find the measure of the fourth angle. |
Answer» Let the measure of the fourth angle be x. As we know that sum of the angles of a quadrilateral is 360°. 56° + 100° + 88° + x = 360° ⇒ 244° + x = 360° ⇒ 360° – 244° = 116° Hence, the measure of the fourth angle is 116°. |
|
463. |
If the degree measures of the angles of quadrilateral are 4x, 7x, 9x and 10x, what is the sum of the measures of the smallest angle and largest angle?A. 140° B. 150° C. 168° D. 180° |
Answer» Option : (C) Given, ABCD is a parallelogram, Angles of quadrilateral 4x , 7x , 9x , 10x = 4x+7x+9x+10x = 360° [angle sum property of quadrilateral] = 30x = 360° = x = \(\frac{360°}{30}\) = 12° Hence, Sum of smallest and largest angles = 4x+10x = 4×12+10×12 = 48°+120° = 168° |
|
464. |
How many diagonals does each of the following have?(a) A convex quadrilateral(b) A regular hexagon(c) A triangle |
Answer» (a) Two, (b) 9, (c) 0 (zero) |
|
465. |
What is the sum of the measures of the angles of a convex quadrilateral? Why this property hold if the quadrilateral is not convex? (Make a non-convex quadrilateral and try!) |
Answer» Solution: Angle sum of a convex quadrilateral = (4 – 2) x 180⁰ = 2 x 180⁰ = 360⁰ |
|
466. |
In the given Q figure, ABCD is a parallelogram in which ∠ADC = 130°, then ∠CBE is equal to:(A) 60°(B) 130°(C) 50°(D) 70° |
Answer» Answer is (C) 50° |
|
467. |
In figure, ABCD is a parallelogram then the value of x is:(A) 25°(B) 60°(C) 75°(D) 45° |
Answer» Answer is (D) 45° |
|
468. |
In the given figure, PQR is a triangle in which X and Y are the mid-point of the sides PR and QR respectively. If PQ = 6 cm, QR = 7 cm and PR = 8 cm, then XY is equal to:(A) 12 cm(B) 3.5 cm(C) 3 cm(D) 4 cm |
Answer» Answer is (C) 3 cm |
|