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451.

A quadrilateral in which one pair of opposite sides are parallel is a A) parallelogram B) kite C) trapeziumD) rhombus

Answer»

Correct option is (C) trapezium

A quadrilateral in which one pair of opposite sides are parallel is a trapezium.

C) trapezium

452.

If diagonal of a parallelogram bisects one of the angles of theparallelogram, it also bisects the second angle. Also, prove that it is arhombus.

Answer» Given- AC diagonal bisects `/_A`
AB||CD and AC is transverse
`/_3=/_1-(1)`
AD||BC and AC is transverse
`/_2=/_4-(2)`
AC bisects`/_A`
`/_1=/_2-(3)`
`/_3=/_4`
AC bisects `/_A`
`/_1=/_4`
AB=DC and BC=AB
AB=BC-CD=CD
ABCD is a rhombus.
453.

In Figure, `M ,N`and `P`are the mid-points of `A B ,A C`and `B C`respectively. If `M N=3c m ,N P=3. 5c m`and `M P=2. 5c m ,`calculate `B C ,A B`and `A Cdot`

Answer» In`/_ABC`
Since, H is the mid point of AB and N is the mid point of AC
MN||BC and `MN=1/2BC`
BC=2MN
P is midpoint of BC
PN||AB and `PN=1/2AB`
NP||AC and `MP=1/2AC`
BC=2*3=6cm
AB=2*3.5=7cm
AC=2*2.5=5cm.
454.

In ` A B C ,A D`is the median through `A`and `E`is the mid-point of `A D`. `B E`produced meets `A C`in `F`(Figure). Prove that `A F=1/3A Cdot`

Answer» Construction
DK||BF
In`/_ADK` E is the midpoint od AD and EF||DK
F is the midpoint of AK
AF=FK-(1)
K is the mid point of FC
FK=KC-(2)
FK=KC=KC
AC=AF+FK+KC
AC=AF+AF+AF=3AF
`AF=1/3AC`.
455.

In a ` A B C`, find the measures of the angles of the triangle formed by joining themid-points of the sides of this triangle.

Answer» Given D,E,F are mid point AB,BC and CA
DE||AB,FE||BC and DF||CA
DE||AB and BC and CA tranverse
`/_CDE=/_B`
`/_CED=/_A`
EF||BC `/_AEF=/_C` and `/_AFE=/_B`
OF||CA `/_BDF=/_C` and `/_BFD=/_A`
`/_BDF+/_FDE+/_EDC=180^@`
`/_C+/_FOE+/_B=180^@`
`/_FDE=180-(/_B+/_C)`
`/_FDE=/_A`
`/_DEF=180^@-(/_A+/_C)=/_B`
`/_EFD=180^@-(/_A+/_B)=/_A`
`/_D=/_A,/_E=/_B,/_F=/_C`.
456.

Fill in the blanks to make the following statements correct :(i) The triangle formed by joining the mid-points of the sides of an isosceles triangle is….. (ii) The triangle formed by joining the mid-points of the sides of a right triangle is….. (iii) The figure formed by joining the mid-points of consecutive sides of a quadrilateral is……

Answer»

(i) Isosceles. 

(ii) Right triangle. 

(iii) Parallelogram.

457.

Show that the line segments joining the mid-points of the opposite sides of a quadrilateral bisect each other.

Answer»

Data : P, Q, R and S are mid-points of AB, BC, CD and DA respectively in quadrilateral ABCD. 

To Prove: PR and SQ line segments bisect mutually. 

Construction: Join the diagonal AC. 

Proof: In ∆ADC, S and R are the mid-points of AD and DC. 

∴ SR || AC 

SR = \(\frac{1}{2}\)AC ………… (i) 

(Mid-point Theorem) 

Similarly, in ∆ABC, 

PQ || AC 

PQ = \(\frac{1}{2}\)AC …………. (ii) 

From (i) and (ii), 

SR = PQ and 

SR || PQ 

∴ PQRS is a parallelogram. PR and SQ are the diagonals of parallelogram PQRS. 

∴PR and SQ meet at O’.

458.

Show that the line segments joining the mid points of the opposite sides of a quadrilateral and bisect each other.

Answer»

Let ABCD be a quadrilateral. 

P, Q, R, S are the midpoints of sides of □ABCD. 

Join (P, Q), (Q, R), (R, S) and (S, P). 

In ΔABC; P, Q are the midpoints of AB and BC. 

∴ PQ // AC and PQ = 1/2  AC ………….(1)

Also from ΔADC

S, R are the midpoints of AD and CD 

SR // AC and SR = 1/2 AC …………………(2)

∴ From (1) & (2) 

PQ = SR and PQ //SR 

∴ □PQRS is a parallelogram. 

Now PR and QS are the diagonals of □ PQRS. 

∴ PR and QS bisect each other.

459.

The quadrilateral in which the diagonals are equal but not perpendicular to each other is A) Square B) Rhombus C) Parallelogram D) Rectangle

Answer»

Correct option is (D) Rectangle

The quadrilateral in which the diagonals are equal but not perpendicular to each other is a rectangle.

Correct option is  D) Rectangle

460.

The quadrilateral in which the diagonals bisect each other and they are perpendicular to each other A) Rectangle B) Rhombus C) Parallelogram D) Trapezium

Answer»

Correct option is: B) Rhombus

461.

What is Polygons?

Answer»

We are familiar with plane figures bounded by straight line segments as sides. They are known as Polygons.

462.

The three angles of a quadrilateral measure 56°, 100° and 88°. Find the measure of the fourth angle.

Answer»

Let the measure of the fourth angle be x.

As we know that sum of the angles of a quadrilateral is 360°.

56° + 100° + 88° + x = 360°

⇒ 244° + x = 360°

⇒ 360° – 244° = 116°

Hence, the measure of the fourth angle is 116°.

463.

If the degree measures of the angles of quadrilateral are 4x, 7x, 9x and 10x, what is the sum of the measures of the smallest angle and largest angle?A. 140° B. 150° C. 168° D. 180°

Answer»

Option : (C)

Given, 

ABCD is a parallelogram, 

Angles of quadrilateral 4x , 7x , 9x , 10x 

= 4x+7x+9x+10x = 360° 

[angle sum property of quadrilateral] 

= 30x = 360°

= x = \(\frac{360°}{30}\) = 12°

Hence, 

Sum of smallest and largest angles = 4x+10x 

= 4×12+10×12 

= 48°+120° = 168°

464.

How many diagonals does each of the following have?(a) A convex quadrilateral(b) A regular hexagon(c) A triangle

Answer»

(a) Two, (b) 9, (c) 0 (zero)

465.

What is the sum of the measures of the angles of a convex quadrilateral? Why this property hold if the quadrilateral is not convex? (Make a non-convex quadrilateral and try!)

Answer»

Solution: Angle sum of a convex quadrilateral = (4 – 2) x 180⁰ = 2 x 180⁰ = 360⁰
Since, quadrilateral, which is not convex, i.e. concave has
same number of sides i.e. 4 as a convex quadrilateral have, thus, a quadrilateral which not convex also hold this property. i.e. angle some of a concave quadrilateral is also equal to 360⁰

466.

In the given Q figure, ABCD is a parallelogram in which ∠ADC = 130°, then ∠CBE is equal to:(A) 60°(B) 130°(C) 50°(D) 70°

Answer»

Answer is (C) 50°

467.

In figure, ABCD is a parallelogram then the value of x is:(A) 25°(B) 60°(C) 75°(D) 45°

Answer»

Answer is (D) 45°

468.

In the given figure, PQR is a triangle in which X and Y are the mid-point of the sides PR and QR respectively. If PQ = 6 cm, QR = 7 cm and PR = 8 cm, then XY is equal to:(A) 12 cm(B) 3.5 cm(C) 3 cm(D) 4 cm

Answer»

Answer is (C) 3 cm