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601.

The end products of aerobic respiration are .......A) Lactic acid + Energy B) Ethanol + CO2 + Energy C) Lactic acid + Ethanol + Energy D) CO2 + Water + Energy

Answer»

D) CO2 + Water + Energy

602.

End product of fermentation of sugars isA. Water and carbon dioxideB. Alcohol and carbon dioxideC. Carbon dioxideD. Alcohol.

Answer» Correct Answer - B
603.

In hexose monophosphate shunt, the net formation of ATP molecules isA. 36B. 35C. 38D. 34

Answer» Correct Answer - B
One molecule of ATP is used in the initial phosphorylation of glucose.
604.

Hexose monophosphate pathway takes place inA. Mitochondrial matrixB. CristaeC. CytoplasmD. E.R.

Answer» Correct Answer - C
605.

Which one produces more energy per glucose moleculeA. Alcoholic fermentationB. GlycolysisC. Pentose phosphate pathwayD. Lactic acid fermentation

Answer» Correct Answer - C
606.

Write the name of end products formed by complete oxidation of glucose.

Answer»

The CO2H2O and energy (ATP).

607.

What is meant by fermentation?

Answer»

Anaerobic respiration taking place in bacteria and fungi, in which glucose is oxidized into alcohol and CO2 or some organic acid, is called fermentation.

608.

End product of aerobic respiration areA. Sugar and oxygenB. Water and energyC. Carbon dioxide, water and energyD. Carbon dioxide and energy.

Answer» Correct Answer - C
609.

Phosphogluconate shunt occurs inA. MitochondiraB. ChloroplastsC. CytoplasmD. Both A and B

Answer» Correct Answer - C
610.

Which one undergoes decarboxylation in hexose monophosphate shuntA. Glucose 6-phosphateB. `6-glucono gamma-lactone`C. 6-phosphogluconateD. Fructose 6- phosphate

Answer» Correct Answer - C
611.

Write a brief account of the factors affecting respiration

Answer»

Factors affecting respiration are divided into two categories. 

(1) External or environmental factors 

(2) Internal or plant factors. 

(1) External factors 

  • Temperature
  • Oxygen
  • Water
  • Light 
  • Carbon dioxide 

(2) Internal factors 

  • Protoplasm
  • Respiratory substrate
  • Age of Cell 
  • Wound and injury 

1. External factors or Environmental Factors: 

1. Temperature: It is the most important factor affecting the rate of respiration. Normally the rate of respiration increases to a certain limit by an increase in temperature from 5.0°C to 30.0°C. In this range, the rate of respiration increases as per Vont Hoff’s rule. According to this a rise in temperature by 10°C, the rate of respiration becomes double. Increase in temperature beyond 35.0°C results into decrease in rate as the enzymes begin to denaturalize. At very low temperatures also enzymes become inactive and the rate of respiration decreases. In cold storage, the fruits and vegetables escape spoilage because of this. 

2. Oxygen: Oxygen is necessary for aerobic respiration because it acts as a terminal acceptor of electrons. At low concentration of oxygen both aerobic and anaerobic respiration may take place, but when the concentration of oxygen becomes zero only anaerobic respiration takes place. Under such a condition value of R.Q. becomes infinite (∞)

3.Water: Water acts as a medium for all metabolic activities. The protoplasm contains up to 90-95% of water. Water plays an important role in enzyme activation, gaseous diffusion, transportation etc. In dry seeds and fruits rate of respiration is extremely low due to the shortage of water and so these can be stored for a long duration. In the presence of water stored carbohydrates convert into soluble sugar and the rate of respiration increases. 

4. Light: Rate of respiration is not influenced directly by light and so it takes place in the presence as well as an absence of light.

5. Carbon dioxide (CO2): Increase in concentration of CO2 inhibits respiration. Hence it has an adverse effect on the germination of seeds and rate of growth of plants. Heath experimentally proved that an increase in the concentration of CO2 causes the closure of stomata and the rate of respiration decreases due to a shortage of oxygen. 

Internal factors or Plant Factors: 

1. Protoplasm: Meristematic cells have dense and active cytoplasm and so the rate of respiration is relatively high in these cells as compared to the mature cells. The activity of protoplasm is affected by several factors such as hydration, pH, temperature etc. 

2. Respiratory substrate: Different types of sugars such as glucose, fructose, maltose etc. present in the cell are quickly used in respiration. In comparison to these starch and fats need to be first converted into a soluble form and only then they can be used as a respiratory substrate. This is the reason why in hospitals a patient is administered directly with, glucose, whereas the normal diet of healthy persons contains starch and fats.

3. Age of Cells: The rate of respiration is much higher in the young cells as compared to mature and old cells. 

4. Wound and Injured part: Rate of respiration sharply increases in the wound and injured part to promote healing.

612.

What are the products formed during fermentation?

Answer»

Ethyl alcohol and CO2 or Lactic acid, Acetic acid, Butyric acid etc.

613.

Write short notes on the following 1. Fermentation. 2. Oxidative break down of pyruvic acid. 3. Respiratory Quotient. 4. Chemiosmotic theory of Peter Mitchell.

Answer»

1. Fermentation: Anaerobic respiration taking place in bacteria and fungi, in which glucose is incompletely oxidized into alcohol and CO2 or organic acid is called fermentation. 

2. Oxidative break-down of pyruvic acid: Pyruvic acid formed as an end product of glycolysis enters mitochondria and in the matrix region of mitochondria, it is completely oxidized into CO2 and H2O in the presence of oxygen. This is called an oxidative breakdown of pyruvic acid. Before entry into mitochondria, pyruvic acid is converted into Acetyl Coenzyme-A by decarboxylation and dehydrogenase enzyme. This complex reaction is catalyzed by five co-factors. These are Coenzyme A; NAD+ ; Mg++; Thymine pyrophosphate (TPP) and Lipoic acid. Acetyl Coenzyme – A formed in this reaction acts as a connecting link between glycolysis and Krebs cycle. 

3. Respiratory Quotient: The ratio of the volume of CO2 released in respiration to the volume of O2 used is called respiratory quotient. 

The value of R.Q. of different respiratory substrates is as follows: 

R.Q. of carbohydrate = 1.0 

R.Q. of fats = 0.7 

R.Q. of proteins = 0.8 

R.Q. of organic acids = 1.33 

R.Q. of succulents = zero Anaerobic respiration 

R.Q. = infinite (∝). 

4. Chemiosmotic theory of Mitchell: This theory was proposed by Mitchell to explain ATP formation during respiration and photosynthetic process. According to this theory, transport of positively charged protons (Hydrogen ions) across the membrane of mitochondria or chloroplasts takes place through the enzymes involved in these processes via an electron transport system. Due to this, the electrochemical gradient is created on two sides of the membrane.

614.

What is meant by respiratory substrates?

Answer»
  • High energy-containing complex organic compounds oxidized during respiration are called respiratory substrates. 
  • Example: Carbohydrates, fats proteins etc.
615.

Define respiratory quotient?

Answer»

The respiratory quotient is the ratio of the volume of CO2 released to the volume of O2 used in respiration. It can be represented as

616.

First reduction in pentose phosphate pathway isA. Oxidation of 6-phosphogluconateB. Oxidation of fructose 6-phosphateC. Oxidation of glucose 6-phosphateD. Oxidation of fructose 5-phosphate.

Answer» Correct Answer - C
617.

Pentose phosphate pathway is a mode ofA. Amphibolic pathwayB. Anabolic pathwayC. Aerobic pathwayD. Anaerobic respiration.

Answer» Correct Answer - C
618.

Name the scientist who proposed the chemiosmotic theory.

Answer»

Peter Mitchell proposed the chemiosmotic theory.

619.

Who proposed the chemiosmotic theory of oxidative phosphorylation? (a) Krebs (b) Gibbs (c) Mitchell (d) Dixons

Answer»

The answer is (c) Mitchell

620.

Write a note on pentose phosphate path (PPP)

Answer»

Pentose phosphate path is an alternative path for complete oxidation of glucose. In this process hexose sugar is oxidized through the involvement of a five carbon-containing sugar, hence it is called a pentose phosphate path. 

Racker and coworkers (1954) studied details of pentose phosphate path. The reactions of PPP take place in the presence of oxygen. This process is completed in the cytoplasm of the cell. The main steps of PPP are as follows: 

  • Phosphorylation of glucose.
  • Oxidation of glucose 6-phosphate.
  • Oxidative decarboxylation of phosphoglucose acid and formation of ribulose-5 phosphate.
  • A complete break down of ribulose – 5 phosphates through several reactions.
621.

The substrate for pentose phosphate pathway isA. Glucose 6-phosphateB. Glucose 1-phosphateC. Fructose 6-phosphateD. Fructose 1-phosphate

Answer» Correct Answer - A
622.

In mitochondria, ATP synthesis occursA. At the outer membraneB. At the cristaeC. In the matrixD. In the intra-cristal space.

Answer» Correct Answer - B
623.

The site Krebs cycle in bacteria isA. NucleoidB. CytoplasmC. Plasma membraneD. Ribosomes

Answer» Correct Answer - C
624.

During the Krebs cycle, the first and the only five carbon-containing compounds formed are? (a) Cis-aconitic acid (b) Oxaloacetic acid (c) α-ketoglutaric acid (d) Fumaric acid

Answer»

The answer is (c) α-ketoglutaric acid

625.

The site of reactions of the pentose phosphate path in cells is – (a) Mitochondria (b) Peroxisomes (c) Cytoplasm (d) Nucleus

Answer»

The answer is (c) Cytoplasm

626.

Respiration differs from combustion inA. Liberating more energy as compared to combustionB. Liberating of all the energy at once in contrast to combustionC. Liberation of energy gradually in steps in contrast to combustionD. Carbohydrates take part as the combustion substance

Answer» Correct Answer - C
627.

R.Q. would depend uponA. Nature of enzymesB. Nature of substrateC. Amount of `CO_(2)` releasedD. Amount of `O_(2)` utilised.

Answer» Correct Answer - B
628.

What is the total gain of energy during anaerobic respirationA. Two ATPB. One ATPC. Four ATPD. Three ATP

Answer» Correct Answer - A
629.

How many ATP are formed as a net gain in anaerobic respiration? (a) Three (b) Four (c) Eight (d) Two

Answer»

The answer is (d) Two

630.

Oxidative phosphorylation refers toA. Anaerobic production of ATPB. Citric acid cycle production of ATPC. Production acid cycle production of ATPD. Alcoholic fermentaion.

Answer» Correct Answer - B
631.

Three major ways for metabolism of pyruvic acid produced in glycolysis areA. Lactic acid fermentation, alcoholic fermentation and aerobic respirationB. Oxaloacetic acid fermentation, lactic acid fermentation, aerobic fermentation, lactic acid fermentation, anaerobic fermentationC. Alcoholic fermentation, oxaloacetic acid fermentation, citric acid fermentationD. Citric acid fermentation, lactic acid fermentation, alcoholic fermentation.

Answer» Correct Answer - A
632.

Pyruvic acid, the last product of glycolysis, is degraded to `CO_(2)" and "H_(2)`A. CytoplasmB. Inner membrane of mitochondiraC. Matrix of mitochondiraD. Matrix of chlorolasts.

Answer» Correct Answer - C
633.

Respiratory organs in earthworm A) skin B) trachea C) lungs D) gills

Answer»

Respiratory organs in earthworm skin

634.

What are pleura?

Answer»

Pleura are the two membranes that protect lungs from injury.

635.

Which of the following is right regarding the bronchioles? (a) trachea divides into bronchioles (b) bronchioles have cartilaginous rings (c) bronchioles collapse when the air pressure is more (d) bronchioles are without cartilaginous rings

Answer»

(d) bronchioles are without cartilaginous rings

636.

What is pleura? What is its function?

Answer»

The lungs are covered by double layered pleural membrane containing several layers of elastic connective tissues and capillaries. It encloses the pleural fluid which reduces friction when the lungs expand and contract.

637.

The lungs are protected ventrally by ……….. (a) vertebral column (b) sternum (c) ribs (d) diaphragm

Answer»

Correct Answer is : (b) sternum

638.

Exchange of gases in lung alveoli occurs through ………(a) Active transport (b) Osmosis (c) Simple diffusion (d) Passive transport

Answer»

(c) Simple diffusion

639.

How are lungs protected?

Answer»

The lungs are light spongy tissues enclosed in the thoracic cavity surrounded by an air tight space. It is bound dorsally by the vertebral column and ventrally by the sternum, laterally by the ribs and on the lower side by the dome shaped diaphragm.

640.

The ciliated epithelial cells lining the trachea, bronchi and bronchioles secrete …………

Answer»

The ciliated epithelial cells lining the trachea, bronchi and bronchioles secrete Mucus.

641.

What are the layers of the diffusion membrane of the alveolus?

Answer»

The diffusion membrane of the alveolus is made up of three layers. 

They are:

  • The thin squamous epithelial cells of the alveoli. 
  • The endothelium of the alveolar capillaries and 
  • The basement substance found in between them.
642.

What are the cells of the squamous epithelial cells of the alveoli?

Answer»

The thin squamous epithelial cells of the alveoli are composed of Type I and Type II cells. Type I cells are very thin so that gases can diffuse rigidly through them. Type II cells are thicker. They synthesize and secrete a substance called surfactant. It lowers the surface tension in the alveoli and prevents pulmonary edema.

643.

Gradual break down of the thin walls of the alveoli decreasing the total surface area of the gaseous exchange is ……….. (a) bronchitis (b) emphysema (c) asthma (d) tuberculosis

Answer»

(b) emphysema

644.

Which of the following is incorrect with regard to the formation of oxyhaemoglobin in the alveoli? (a) high pCO2(b) less H+ concentration (c) low pCO2 (d) low temperature

Answer»

Correct Answer is : (a) high pCO2

645.

A molecule of haemoglobin carries how many oxygen molecules ……(a) 1 (b) 2 (c) 3 (d) 4

Answer»

A molecule of haemoglobin carries how many oxygen molecules 4.

646.

Carbon dioxide is carried in the RBCs as ……….. (a) bicarbonate ions (b) carbon dioxide (c) carbonic acid (d) carbaminohaemoglobin

Answer»

(d) carbaminohaemoglobin

647.

Respiratory centre of brain is stimulated by ………(a) Carbon dioxide content in venous blood (b) Carbon dioxide content in arterial blood (c) Oxygen content in venous blood (d) Oxygen content in arterial blood

Answer»

(d) Oxygen content in arterial blood

648.

Oxygen haemoglobin dissociation curve will shift to right on decrease of ……(a) Acidity . (b) Carbon dioxide concentration (c) Temperature (d) pH

Answer»

Oxygen haemoglobin dissociation curve will shift to right on decrease of pH.

649.

Each haemoglobin can combine with molecules of oxygen. (a) one (b) four (c) three (d) two

Answer»

Correct Answer is : (b) four

650.

At higher CO concentration, oxygen dissociation curve of haemoglobin will ……(a) Move to left(b) Move to right (c) Become irregular (d) Move upwardly

Answer»

(b) Move to right