

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
651. |
The reversible reaction of formation of carbonic acid from carbon dioxide and water is catalyzed by the enzyme called ……… |
Answer» Carbonic anhydrase. |
|
652. |
Body tissue obtain oxygen from haemoglobin due to its dissociation in tissues is caused by ……(a) Low oxygen concentration and high carbon dioxide concentration (b) Low oxygen concentration (c) Low carbon dioxide concentration (d) High carbon dioxide concentration |
Answer» (b) Low oxygen concentration |
|
653. |
About 70% of CO transport occurs as ions. |
Answer» Bicarbonate. |
|
654. |
Every 100 mL of oxygenated blood can deliver about mL of O, to the tissues. |
Answer» Correct Answer is : 5. |
|
655. |
the structre which prevents the entry of food into respiratory is |
Answer» Correct Answer - Epiglottis | |
656. |
Which of the following is caused by bacteria? (a) pneumonia (b) emphysema (c) silicosis (d) tuberculosis |
Answer» (d) tuberculosis |
|
657. |
During respiration……………………..A. 2 PGAL during glycolysis and none in Krebs cycleB. 2 PGAL during glycolysis and two pyruvic acid in Krebs cycleC. 2 PGAL during glycolysis and 4 pyruvic acid in Krebs cycleD. PGAL is not produced during respiratory events. |
Answer» Correct Answer - A | |
658. |
When a pair of electron from `NADH(H^(+))` is transported through respiratory ETS, it results in the formation ofA. 2 mol. Of ATPB. 4 mol. Of ATPC. 3 mol. Of ATPD. 5 mol. Of ATP. |
Answer» Correct Answer - C | |
659. |
Choose the correct sequence of electron pathway in ETSA. Cyt oxidase `rarr` Cyt reductase `rarr` Succinate dehydrogenase `rarr` NAD dehydrogenaseB. NADH dehyrogenase `rarr` Succinate dehydrogenase `rarr` Cyt c reductase `rarr` Cyt. C oxidaseC. NADH dehydrogenase `rarr` Cyt c reductase `rarr` Cyt c oxidase `rarrO_(2)`D. Succinic dehydrogenase `rarr` Cyt oxidase `rarr` Cyt. Reductase `rarr`O_(2)`. |
Answer» Correct Answer - C | |
660. |
The respiratory structures of insects are ……….. (a) tracheal tubes (b) gills (c) green glands (d) lungs |
Answer» (a) tracheal tubes |
|
661. |
The reactions of the TCA cycle occur in (A) ribosomes (B) grana (C) mitochondria (D) endoplasmic reticulum |
Answer» (C) mitochondria |
|
662. |
How are glycolysis, TCA cycle and electron transport chain-linked? Explain. |
Answer» Glycolysis, TCA cycle and electron transport chain are linked in the following manner: 1. The coenzymes are initially present in the form of NAD+ and FAD+ which latter get reduced to NADH+H+ and FADH+H+ by accepting the hydrogen from organic substrate during glycolysis, link reaction and Krebs cycle. 2. During glycolysis, glucose is oxidised to two molecules of pyruvic acid with net gain 2 molecules of NADH+H+ . 3. This pyruvic acid undergoes link reaction to form two molecules of acetyl COA and two molecules of NADH+H+ . 4. Acetyl COA, thus formed enters into the Krebs cycle and it gets completely oxidised to CO2 and H2O; with a net gain of 6 NADH+H+ and 2 FADH+H+ are formed. 5. During ETS, reduced coenzymes are reoxidized to NAD+ and FAD+ with a net gain of 34 ATPs. The ATPs thus formed are used during glycolysis. 6. The oxidized NAD+ and FAD+ will again accept the hydrogen from organic substrate. Thus, reduced coenzymes are converted back to their oxidized forms by dehydrogenation to keep the process going. |
|
663. |
How would you demonstrate that yeast can respire both aerobically and anaerobically? |
Answer» Respiration in yeast can be demonstrated with the help of an experiment. Anaerobic respiration in yeast: 1. A pinch of dry baker’s yeast suspended in water containing 10ml of 10% glucose in a test tube (test tube A). 2. The surface of the liquid is covered with oil to prevent entry of air and the test tube is closed tightly with rubber stopper to prevent leakage. 3. One end of a short-bent glass tube is inserted through it to reach the air inside the tube. 4. Other end of the glass tube is connected by a polyethylene or rubber tubing to another bent glass tube fitted into a stopper. 5. The open end of the glass tube (delivery tube) is dipped into lime water containing in a test tube (Tube B). 6. Stoppers of both the tubes are fitted tightly to prevent leakage of gases. First test tube is placed in warm water (37° C-38° C) in a beaker. 7. Lime water gradually turns milky, indicating the evolution of carbon dioxide from the yeast preparation. 8. Level of the lime water in the delivery tube does not rise, showing that there is no decline in volume of gas in test tube A and consequently no utilization of oxygen by yeast. Preparation is stored for a day or two. 9. When we open the stopper of tube A we will notice a smell of alcohol indicating the formation of ethanol. 10. From this activity it may be inferred that yeast respires anaerobically to ferment glucose to ethanol and carbon dioxide. Aerobic respiration in yeast: Experiment explained can be carried out for demonstrating aerobic respiration in yeast. 1. If the level of the lime water in the test tube B rises, indicating intake of oxygen, hence the level of volume of gas rises. 2. The preparation tube is stored for a day or two, if no smell of alcohol is noticed it indicates that the yeast respires aerobically. |
|
664. |
the chemiosmotic coupling hypothesis of oxidative phosporylaion propass that adenosine triphoshate (ATP) is formed becouseA. A proton gradient forms across the inner mitochondrial membraneB. There is change in the permeability of the inner mitochondrial membrane towards adenosine diphosphateC. High energy bonds are formed in mitochondrial proteinsD. ADP is pumped out of matrix into the intermembrane space. |
Answer» Correct Answer - A | |
665. |
the chemiosmotic coupling hypothesis of oxidative phosporylaion propass that adenosine triphoshate (ATP) is formed becouseA. Proton gradient forms across inner membraneB. Changed impermeability of inner mitochondrial membrane to ADPC. High energy bonds are formed in mitochondrial proteinsD. ADP is pumped out of the matrix into intermembrane space. |
Answer» Correct Answer - A | |
666. |
Iron porphyrin occurs inA. AnthocyaninB. PhytochromeC. CytoplasmD. FAD. |
Answer» Correct Answer - C | |
667. |
What is the advantage of step wise energy release in respiration? |
Answer» In ETS energy is released in step wise manner to prevent damage of cells. 1. A stepwise release of the chemical bond energy facilitates the utilization of a relatively higher proportion of that energy in ATP synthesis. 2. Activities of enzymes for the different steps may be enhanced or inhibited by specific compounds. This provides a means of controlling the rate of the pathway and the energy output according to need of the cell. 3. The same pathway may be utilized for forming intermediates used in the synthesis of other biomolecules like amino acids. |
|
668. |
Which is the site for ETS in mitochondrial respiration? |
Answer» The inner mitochondrial membrane is the site for ETS in mitochondrial respiration. |
|
669. |
Bond between first phosphate and adenosine in ATP isA. Phosphoester bondB. Nitrophosphate bondC. Phosphoanhydride bondD. Adenophosphate bond. |
Answer» Correct Answer - A | |
670. |
Explain ETS. |
Answer» 1. NADH2 and FADH2 produced during glycolysis, connecting link reaction and Krebs cycle are oxidized with the help of various electron carriers and enzymes. 2. These carriers and enzymes are arranged on inner mitochondrial membrane in the form of various complexes as complex I, II, III, VI and V. 3. NADH+H+ is oxidised by NADH dehydrogenase (complex I) and it’s electrons are transferred to ubiquinone (coenzyme Q-CoQ) present on inner membrane of mitochondria. Reduced ubiquinone is called as ubiqunol. 4. FADH2 is oxidised by complex II (Succinate dehydrogenase) and these electrons are also transferred to CoQ. 5. During oxidation of NADH+H+ and FADH2 , electrons and protons are released but only electrons are canned forward whereas protons are released into outer chamber of mitochondria (intermembrane space). 6. Ubiquinol is oxidised by complex-III (Cytochrome bcl complex) and it’s electrons are transferred to cytochrome C. Cytochrome C is a small, ironcontaining protein, loosely associated with inner membrane. It acts as a mobile electron carrier, transferring the electrons between complex III and IV. 7. Cytochrome C is oxidised by complex IV or cytochrome C oxidase consisting of cytochrome a and a3 . Electrons are transferred by this complex to the molecular oxygen. This is terminal oxidation. 8. Reduced molecular oxygen reacts with protons to form water molecule called as metabolic water. 9. Protons necessary for this are channelled from outer chamber of mitochondria into inner chamber by F0 part of oxysome (complex V) present in inner mitochondrial membrane. 10. This proton channelling by F0 is coupled to catalytic site of F1 which catalyses the synthesis of ATP from ADP and inorganic phosphate. This is oxidative phosphorylation. 11. As transfer of protons is accompanied with synthesis of ATP, this process is named as ‘Chemiosmosis’ by Peter Mitchell. |
|
671. |
Cytochromes areA. Electron acceptorsB. Protein acceptorsC. Oxygen acceptorsD. Passage way for carbohydrates. |
Answer» Correct Answer - A | |
672. |
In cytochromes, electrons are picked up and released byA. FeB. MoC. CuD. Zn |
Answer» Correct Answer - A | |
673. |
In electron transport system (ETS) which of the following cytochromes reacts with oxygenA. Cyt `a_(3)`B. Cyt bC. Cyt `b_(3)`D. Cyt `b_(6)` |
Answer» Correct Answer - A | |
674. |
During glycolysis, glucose is first changed toA. Glucose 6-phosphateB. Fructose 6-phosphateC. Glucose 1,6-phosphateD. Adenophosphate bond. |
Answer» Correct Answer - A | |
675. |
Which statement is wrong for Krebs cycle ?A. there is one point in the cycle where FAD is reduced to `FADH_2`B. during conversion of succinyl CoA to succine acid, a molecule of GTP is synthesised.C. the cycle starts with condensation of acetyl group acetyl Co a with pyruvic acid to yield citric acidD. there are three points in the cycle where `NAD^+` is reduced to `NADH+H^+` |
Answer» Correct Answer - C |
|
676. |
What is RQ.? What is its value for fats? |
Answer» 1. Respiratory quotient (R.Q.) or respiratory ratio is the ratio of volume of CO2 released to the volume of O2 consumed in respiration. 2. R.Q. = Volume of CO2 released / Volume of O2 consumed |
|
677. |
Discuss “The respiratory pathway is an amphibolic pathway”.ORWhy is Krebs cycle referred as amphibolic pathway? |
Answer» 1. Respiration is considered as a catabolic process; however, it is not entirely correct in case of Krebs cycle. 2. Many reactions of Krebs cycle involve oxidation of acetyl CoA to release energy and CO2. 3. However, the breakdown of respiratory substrates provides intermediates like a-ketoglutarate, oxaloacetate are used as precursors for synthesis of fatty acids, glutamic acid and aspartic acid respectively. 4. Thus, as the same respiratory process acts as catabolic as well as anabolic pathway for synthesis of various intermediate metabolic products, it is called amphibolic pathway. |
|
678. |
For their functioning, cytochromes possessA. MgB. FeC. MnD. Na. |
Answer» Correct Answer - B | |
679. |
Mention any two industrial uses of alcoholic fermentation. |
Answer» Two industrial uses of alcoholic fermentation: 1. In bakeries, it is used for preparing bread, cakes, biscuits. 2. In beverage industries for preparing wine and alcoholic drinks. |
|
680. |
Sequence of organic acids in Krebs cycle isA. `"Citric acid" rarr "oxalosuccinic acid" rarr "isocitric acid"`B. `"Citric acid" rarr "isocitric acid" rarr "oxalosuccinic acid"`C. `"Isocitric acid" rarr "oxalosuccinic acid" rarr "citric acid"`D. `"Oxalosuccinic acd" rarr "isocitric acId" rarr "citric acid."` |
Answer» Correct Answer - B | |
681. |
Calculate the RQ for different respiratory substrates using appropriate formula. |
Answer» The RQ for different respiratory substrates are: 1. Carbohydrates (R.Q. is 1) When carbohydrates are used as substrate, equal volumes of CO2 and O2 are released and consumed respectively, thus its R.Q. is 1. C6H12O6 + 6O2 → 6 CO2 + 6H2O R.Q. = 6CO2 / 6O2 = 1.0 2. Fats (R.Q. is less than 1) Substrates like fats are poorer in oxygen than carbohydrates. Thus, more oxygen is utilized for its complete oxidation. 2(C51H98O6) + 145O2 → 102CO2 + 98H2O + Energy R.Q. = CO2 / O2 = 102 / 145 = 0.7 3. Protein respiration (R.Q. is less than 1) 1. When proteins serve as respiratory substrate, they are first degraded to amino acids. 2. Then, amino acids are converted into various intermediates of carbohydrates. 3. However, amino acids have low proportion of O2 as compared to carbohydrates. 4. Thus, they require more O2 during their complete oxidation and value of R.Q. becomes less than 1. 5. In case of proteins, the R.Q. is approximately 0.9. |
|
682. |
Alcoholic fermentation usesA. RibosomesB. Golgi bodiesC. Mitochondrial enzymesD. Cytoplasmic enzymes. |
Answer» Correct Answer - D | |
683. |
In alcoholic fermentationA. Triose phosphate is electron donor while acetaldehyde is electron acceptorB. Triose phosphate is electron donor while pyruvic acid is electron acceptorC. There is no electron donorD. Oxygen is electron acceptor. |
Answer» Correct Answer - A | |
684. |
`{:(1.,"Proteins" ,(i),"4.0 (RQ)"),(2.,"Oleic acid ",(ii),"1.6 (RQ)"),(3.,"Tortaric acid",(iii),"0.71 (RQ)"),(4.,"Oxalic acid",(iv),"0.8-0.9 (RQ)"):}`A. `{:(1,2,3,4),(ii,iii,iv,i):}`B. `{:(1,2,3,4),(iv,iii,ii,i):}`C. `{:(1,2,3,4),(iii,iv,ii,i):}`D. `{:(1,2,3,4),(iii,I,ii,iv):}` |
Answer» Correct Answer - B |
|
685. |
How many ATP molecules can be produced through oxidative phosphorylation of `2 NADH_(2)" and "3 FADH_(2)`A. 15B. 24C. 6D. 12 |
Answer» Correct Answer - D | |
686. |
In anaerobic respiration, acetaldehyde is reduced to form alcohol by utilising `NADH_(2)` obtained fromA. GlycolysisB. Terminal oxidationC. Krebs cycleD. Acetylation. |
Answer» Correct Answer - A | |
687. |
Alcoholic fermentation is carried out byA. SaccharomycesB. LactobacillusC. ClostridriumD. Aspergillus. |
Answer» Correct Answer - A | |
688. |
`{:(1.,"Karl Lohman" ,(i),"Divided respiration upon nature"),(2.,"Pepys",(ii),"Discovery of ATP"),(3.,"Blackman",(iii),"EMP Pathway"),(4.,"Embden",(iv),"Coined term repiration"):}`A. `{:(1,2,3,4),(ii,iii,iv,i):}`B. `{:(1,2,3,4),(I,ii,iii,iv):}`C. `{:(1,2,3,4),(ii,iv,I,iii):}`D. `{:(1,2,3,4),(iii,I,ii,iv):}` |
Answer» Correct Answer - C |
|
689. |
Identify the correct statements from the below about "ATP". (I) ATP is a nucleotide (II) It consists of a base -adenine (III) If releases energy on hydrolysis. (IV) It is not found in all living cells.A. I and IV onlyB. I and II onlyC. I and III onlyD. I,II and III only |
Answer» Correct Answer - B |
|
690. |
One `NADH_(2)//NADPH_(2)` yieldsA. 2 ATPB. 3 ATPC. 12 ATPD. 6 ATP |
Answer» Correct Answer - B | |
691. |
Which one froms ATP ?A. Fe and PB. N and PC. Fe and MoD. Mg and Mn |
Answer» Correct Answer - B | |
692. |
Energy for ATP synthesis is obtained fromA. Oxygen ion gradientB. Hydrogen ion gradientC. Nitrogen ion gradientD. All the above |
Answer» Correct Answer - B | |
693. |
Metabolism of one plamitic acid yields ATPA. 36 ATPB. 56 ATPC. 129 ATPD. 48 ATP |
Answer» Correct Answer - C One plamitic acid, `C_(16)H_(32)O_(2)`, yields eight acetyl CoA molecules seven `(NADH+H^(+),FADH_(2))` through `beta`-oxidation. One acetyl CoA yields 12 ATP in Krebs cycle. One `NADH+" one "FADH_(2)` are equivalent to 5 ATP. The total is `(8xx12)+(7xx5)=131` ATP. Two molecules of ATP are used in initiation of `beta`-oxidation. |
|
694. |
Identify the correct statements from the below about "Glycolysis". (I) Glucose is converted into pyruvic acid (II) Net gain is 2 ATP (III) It takes place in the absence of oxygen. (IV) 2NADH `+H^+` molecules are produced.A. I,III and IV onlyB. I,II and IV onlyC. I and III onlyD. I and II only |
Answer» Correct Answer - B |
|
695. |
According to recent view,complete oxidation of 1 glucose molecule yields ……………..ATP.A. 32B. 30C. 34D. 38 |
Answer» Correct Answer - B |
|
696. |
In aerobic prokaryotes, one glucose molecule produces ……………..ATP molecules.A. 40B. 38C. 34D. 32 |
Answer» Correct Answer - A |
|
697. |
During complet metabolism of glucose, the number of ATP formed isA. 20B. 32C. 36D. 40 |
Answer» Correct Answer - D | |
698. |
In acerobic respiration which of the following is a reactantA. `CO_(2)`B. `O_(2)`C. `H_(2)O`D. Sugars |
Answer» Correct Answer - B | |
699. |
Which of the following statement correctly describes the lungs ? A) They are not of same size and are spongy in nature.B) The right lung is slightly smaller for making space for the heart.C) A fluid filled between two membranes of lungs called interstitial fluid.D) They are of uniform size and hard in nature. |
Answer» A) They are not of same size and are spongy in nature. |
|
700. |
When air is blown from mouth into a test tube containing lime water, the lime water turned milky. This shows that exhaled air consists of: A) Oxygen B) Nitrogen C) Water vapour D) Carbon dioxide |
Answer» (D) Carbon dioxide |
|