332354 + Interview Questions in Secondary School in Math Page 11 InterviewSolution

501.	Pls help me these questions
Answer» Answer: first SHOW UR face or PROVE that U r a girlid:5762496420bromemsico1976kjd-mzxm-kbcibc-hgfb-pmh

501.

Pls help me these questions

Answer»

Answer:

first SHOW UR face or PROVE that U r a girlid:5762496420bromemsico1976kjd-mzxm-kbcibc-hgfb-pmh

Discussion

502.	Pls help me, 3.039/9.8 = ?
Answer» Answer: 0.31010204081 (this was HARD for me TWT)

502.

Pls help me, 3.039/9.8 = ?

Answer»

Answer:

0.31010204081

(this was HARD for me TWT)

Discussion

503.	Pls help me with these qustions.
Answer» Answer: first SHOW ur face or PROVE that U R a girlid:5762496420bromemsico1976kjd-mzxm-kbcibc-hgfb-pmh

503.

Pls help me with these qustions.

Answer»

Answer:

first SHOW ur face or PROVE that U R a girlid:5762496420bromemsico1976kjd-mzxm-kbcibc-hgfb-pmh

Discussion

504.	Find the solution set of the equationx 2 + x -2 =0 in Roster form
Answer» ANSWER: I THINK 0X is the answer

504.

Find the solution set of the equationx 2 + x -2 =0 in Roster form

Answer»

ANSWER:

I THINK 0X is the answer

Discussion

505.	Pls help me with these qustions
Answer» ANSWER: PLEASE MARK me as BRAINLIEST then I will answer your question and please don't forget to FOLLOW me

505.

Pls help me with these qustions

Answer»

ANSWER:

PLEASE MARK me as BRAINLIEST then I will answer your question
and please don't forget to FOLLOW me

Discussion

506.	Problemy-3=2(x+1)y−3=2(x+1)y, minus, 3, equals, 2, left parenthesis, x, plus, 1, right parenthesisComplete the missing value in the solution to the equation.(-1,(−1,left parenthesis, minus, 1, comma ))
Answer» Given : y-3=2(X+1) Solution to Equation ( - 1 , ? ) To Find : Find missing value Solution: y-3=2(x+1) Solution to Equation ( - 1 , ? ) x = - 1 y = ? Substitute x = - 1 in the equation y - 3 = 2( -1 + 1) => y - 3 = 2(0) => y - 3 = 0 => y = 3 Solution to Equation ( - 1 , 3 ) Missing Value in Solution to Equation = 3 Learn More: PLEASE solve this Amit SIR @amitnrw - Brainly.in brainly.in/question/12861151 Solve the following x+y/xy=5 and x-5/xy=7 - Brainly.in brainly.in/question/8168066 solve for x and y : x+y/xy=2,xy/=6 brainly.in/question/12892518

506.

Problemy-3=2(x+1)y−3=2(x+1)y, minus, 3, equals, 2, left parenthesis, x, plus, 1, right parenthesisComplete the missing value in the solution to the equation.(-1,(−1,left parenthesis, minus, 1, comma ))

Answer»

Given : y-3=2(X+1)

Solution to Equation ( - 1 , ? )

To Find : Find missing value

Solution:

y-3=2(x+1)

Solution to Equation ( - 1 , ? )

x = - 1

y = ?

Substitute x = - 1 in the equation

y - 3 = 2( -1 + 1)

=> y - 3 = 2(0)

=> y - 3 = 0

=> y = 3

Solution to Equation ( - 1 , 3 )

Missing Value in Solution to Equation = 3

Learn More:

PLEASE solve this Amit SIR @amitnrw - Brainly.in

brainly.in/question/12861151

Solve the following x+y/xy=5 and x-5/xy=7 - Brainly.in

brainly.in/question/8168066

solve for x and y : x+y/xy=2,xy/=6

brainly.in/question/12892518

Discussion

507.	Fill up the blankIn stratosphere temperaturewith increase in altitude.2Write anchether the following staternoot is tore or false
Answer» ANSWER: cannot UNDERSTAND the QUESTION

507.

Fill up the blankIn stratosphere temperaturewith increase in altitude.2Write anchether the following staternoot is tore or false

Answer»

ANSWER:

cannot UNDERSTAND the QUESTION

Discussion

508.	The bicycle travelling?14. A small cart is being driven at 10 km per hour. Ifeach wheel is 91 cm in diameter, find the number ofrevolutions made by each wheel per minute.
Answer» SPEED of the cart = 10km/hr = 10×1000/60 m/ min = 1000/6 m/min. Diameter of the wheel = 91 cm= 0.91 m Radius of the wheel = 0.91/2 m Circumference of the wheel= 2πr = 2 × (22/7) × (0.91/2) m= 22×0.13 m No.of REVOLUTIONS PER minute= (1000/6)/(22×o.13) = 1000×100/(6×22×13) = 1000×25/429

508.

The bicycle travelling?14. A small cart is being driven at 10 km per hour. Ifeach wheel is 91 cm in diameter, find the number ofrevolutions made by each wheel per minute.

Answer»

SPEED of the cart = 10km/hr

= 10×1000/60 m/ min = 1000/6 m/min.

Diameter of the wheel = 91 cm= 0.91 m

Radius of the wheel = 0.91/2 m

Circumference of the wheel= 2πr

= 2 × (22/7) × (0.91/2) m= 22×0.13 m

No.of REVOLUTIONS PER minute= (1000/6)/(22×o.13) = 1000×100/(6×22×13)

= 1000×25/429

Discussion

509.	Fine the derivative of
Answer» ANSWER IS GIVEN AT END IN EACH PART. EACH STEP IS EXPLAINED CAREFULLY ! Step-by-step explanation: (i) y= $\frac{4x-8}{3x+11}$ Now, $\frac{dy}{dx} = \frac{(4x-8)'.(3x+11) - (3x+11)'.(4x-8)}{(3x+11)^{2}}$ (by applying DIVIDING RULE) ⇒ $\frac{dy}{dx}= \frac{4(3x+11) - 3(4x-8)}{(3x+11)^{2} }$ ⇒ $\frac{dy}{dx}= \frac{12x+44-12x+24}{(3x+11)^{2} }$ ⇒ $\frac{dy}{dx}= \frac{64}{(3x+11)^{2} }$ (∵ Both 12x will cancel eachother) Hence, this is the answer. (II)y= $\frac{x^{2} }{x^{3}+1 }$ Now, $\frac{dy}{dx}=\frac{(x^{2} )'.(x^{3}+1)-x^{2}.(x^{3} +1)'}{(x^{3}+1) ^{2} }$ (by applying dividing rule) ⇒ $\frac{dy}{dx}=\frac{2x.(x^{3}+1 )-x^{2} .(3x^{2} )}{(x^{3}+1) ^{2} }$ ⇒ $\frac{dy}{dx}=\frac{2x^{4}+2x-3x^{4} }{(x^{3}+1) ^{2} }$ ⇒ $\frac{dy}{dx}=\frac{-x^{4} +2x}{(x^{3}+1) ^{2} }$ Hence, this is the answer. (iii)y= $\frac{1+x^{2} -x}{1-x^{2} +x}$ Now, $\frac{dy}{dx} =\frac{(1+x^{2} -x)'.(1-x^{2} +x)-(1+x^{2} -x).(1-x^{2} +x)'}{(1-x^{2} +x)^{2} }$ (by applying dividing rule) ⇒ $\frac{dy}{dx} =\frac{2x-1.(1-x^{2} +x)-(1+x^{2} -x).(-2x+1)}{(1-x^{2} +x)^{2} }$ ⇒ $\frac{dy}{dx} =\frac{2x-2x^{3}+2x^{2} -1+x^{2} -x-[-2x+1-2x^{3}+x^{2} +2x^{2} -x] }{(1-x^{2} +x)^{2} }$ ⇒ $\frac{dy}{dx} =\frac{x-2x^{3}+3x^{2} -1-[-3x+1-2x^{3}+3x^{2}] }{(1-x^{2} +x)^{2} }$ ⇒ $\frac{dy}{dx} =\frac{x-2x^{3}+3x^{2} -1+3x-1+2x^{3}-3x^{2} }{(1-x^{2} +x)^{2} }$ ⇒ $\frac{dy}{dx} =\frac{4x-2}{(1-x^{2} +x)^{2} }$ (∵ both $2x^{3}$ and $3x^{2}$ will cancel out eachother) Hence, this is the answer. MARK ME AS BRAINLIEST... ;)

509.

Fine the derivative of

Answer»

ANSWER IS GIVEN AT END IN EACH PART.

EACH STEP IS EXPLAINED CAREFULLY !

Step-by-step explanation:

(i) y= $\frac{4x-8}{3x+11}$

Now, $\frac{dy}{dx} = \frac{(4x-8)'.(3x+11) - (3x+11)'.(4x-8)}{(3x+11)^{2}}$ (by applying DIVIDING RULE)

⇒ $\frac{dy}{dx}= \frac{4(3x+11) - 3(4x-8)}{(3x+11)^{2} }$

⇒ $\frac{dy}{dx}= \frac{12x+44-12x+24}{(3x+11)^{2} }$

⇒ $\frac{dy}{dx}= \frac{64}{(3x+11)^{2} }$ (∵ Both 12x will cancel eachother)

Hence, this is the answer.

(II)y= $\frac{x^{2} }{x^{3}+1 }$

Now, $\frac{dy}{dx}=\frac{(x^{2} )'.(x^{3}+1)-x^{2}.(x^{3} +1)'}{(x^{3}+1) ^{2} }$ (by applying dividing rule)

⇒ $\frac{dy}{dx}=\frac{2x.(x^{3}+1 )-x^{2} .(3x^{2} )}{(x^{3}+1) ^{2} }$

⇒ $\frac{dy}{dx}=\frac{2x^{4}+2x-3x^{4} }{(x^{3}+1) ^{2} }$

⇒ $\frac{dy}{dx}=\frac{-x^{4} +2x}{(x^{3}+1) ^{2} }$

Hence, this is the answer.

(iii)y= $\frac{1+x^{2} -x}{1-x^{2} +x}$

Now, $\frac{dy}{dx} =\frac{(1+x^{2} -x)'.(1-x^{2} +x)-(1+x^{2} -x).(1-x^{2} +x)'}{(1-x^{2} +x)^{2} }$ (by applying dividing rule)

⇒ $\frac{dy}{dx} =\frac{2x-1.(1-x^{2} +x)-(1+x^{2} -x).(-2x+1)}{(1-x^{2} +x)^{2} }$

⇒ $\frac{dy}{dx} =\frac{2x-2x^{3}+2x^{2} -1+x^{2} -x-[-2x+1-2x^{3}+x^{2} +2x^{2} -x] }{(1-x^{2} +x)^{2} }$

⇒ $\frac{dy}{dx} =\frac{x-2x^{3}+3x^{2} -1-[-3x+1-2x^{3}+3x^{2}] }{(1-x^{2} +x)^{2} }$

⇒ $\frac{dy}{dx} =\frac{x-2x^{3}+3x^{2} -1+3x-1+2x^{3}-3x^{2} }{(1-x^{2} +x)^{2} }$

⇒ $\frac{dy}{dx} =\frac{4x-2}{(1-x^{2} +x)^{2} }$ (∵ both $2x^{3}$ and $3x^{2}$ will cancel out eachother)

Hence, this is the answer.

MARK ME AS BRAINLIEST... ;)

Discussion

510.	obtain truth values of compound statements of the type pVq by using switch connection in parallel. please somebody help me this is my project topic and i don't have any ideas about it! can anybody please help me completing this project
Answer» ANSWER: obtain truth values of compound statements of the type pVq by using switch connection in PARALLEL. please somebody help me this is my PROJECT topic and i don't have any ideas about it! can anybody please help me completing this project

510.

obtain truth values of compound statements of the type pVq by using switch connection in parallel. please somebody help me this is my project topic and i don't have any ideas about it! can anybody please help me completing this project

Answer»

ANSWER:

obtain truth values of compound statements of the type pVq by using switch connection in PARALLEL. please somebody help me this is my PROJECT topic and i don't have any ideas about it! can anybody please help me completing this project

Discussion

511.	We can run animation from ______ menu is adobe flash?
Answer» CTRL PLUS ENTER" is a shortcut KEY that is used to "play the ANIMATION in flash"

511.

We can run animation from ______ menu is adobe flash?

Answer»

CTRL PLUS ENTER" is a shortcut KEY that is used to "play the ANIMATION in flash"

Discussion

512.	A boat goes 30km upstream and 44km downstream in 1 hour. The same boat goes40km upstream and 53 km downstream in 13 hours. Determine the speed of streamand that of boat in still water.
Answer» Let the speed of boat in still water=x km\hr and The speed of stream=y km\hr Speed of boat at downstream ⇒(x+y)km/hr Speed of boat at upstream ⇒(x−y)km/hr ∵time= speed distance Time taken to cover 30 km upstream ⇒ x−y 30 Time taken to cover 44 km downstream⇒ x+y 44 According to the first condition, ⇒ x−y 30 = x+y 44 =10 Time taken to cover 40 km upstream ⇒ x−y 40 Time taken to cover 55 km downstream ⇒ x+y 55 According to the second condition, ⇒ x−y 40 = x+y 55 =13 Let x−y 1 =uand x+y 1 =v ⇒30u+44v=10.....eq1 ⇒40u+55v=13.....eq2 Multiplying eq1 by 3 and eq2 by 5 and SUBTRACT both ⇒(150u+220v=50)−(160u+220v=52) ⇒−10u=−2⇒U= 5 1 put u= 5 1 in eq1 ⇒30× 5 1 +44v=10⇒44v=4⇒v= 4 1 ⇒u= x−y 1 = 5 1 ⇒x−y=5...eq3 ⇒v= x+y 1 = 11 1 ⇒x+y=11...eq4 Subtracting eq3 and eq4, we get ⇒x=8 Put x=8 in eq3 ⇒y=3 Hence, the speed of the boat in still water=8km\hr The speed of stream=3km\hr

512.

A boat goes 30km upstream and 44km downstream in 1 hour. The same boat goes40km upstream and 53 km downstream in 13 hours. Determine the speed of streamand that of boat in still water.

Answer»

Let the speed of boat in still water=x km\hr and The speed of stream=y km\hr

Speed of boat at downstream

⇒(x+y)km/hr

Speed of boat at upstream

⇒(x−y)km/hr

∵time=

speed

distance

Time taken to cover 30 km upstream ⇒

x−y

30 Time taken to cover 44 km downstream⇒

x+y

44 According to the first condition,

⇒

x−y

30 =

x+y

44 =10

Time taken to cover 40 km upstream ⇒

x−y

40 Time taken to cover 55 km downstream ⇒

x+y

55 According to the second condition,

⇒

x−y

40 =

x+y

55 =13

Let

x−y

1 =uand

x+y

1 =v

⇒30u+44v=10.....eq1

⇒40u+55v=13.....eq2

Multiplying eq1 by 3 and eq2 by 5 and SUBTRACT both

⇒(150u+220v=50)−(160u+220v=52)

⇒−10u=−2⇒U=

5

1 put u=

5

1 in eq1

⇒30×

5

1 +44v=10⇒44v=4⇒v=

4

1 ⇒u=

x−y

1 =

5

1 ⇒x−y=5...eq3

⇒v=

x+y

1 =

11

1 ⇒x+y=11...eq4

Subtracting eq3 and eq4, we get

⇒x=8

Put x=8 in eq3

⇒y=3

Hence, the speed of the boat in still water=8km\hr

The speed of stream=3km\hr

Discussion

513.	Marnie conducted a survey of the cats in four shelters and wrote the following observations: 4 of the 18 cats in Shelter 1 were black 13 of the 24 cats in Shelter 2 were black 12 of the 20 cats in Shelter 3 were black 18 of the 25 cats in Shelter 4 were black Based on the survey, which shelter had the greatest percentage of black cats?a Shelter 1bShelter 2cShelter 3dShelter 4
Answer» Answer: 1. 4/18 = 0.22 2. 13/24 = 0.54 3. 12/20 = 0.60 4. 18/25 = 0.72 Shelter 4 has the HIGHEST percentage of BLACK CATS with 72% Step-by-step EXPLANATION:

513.

Marnie conducted a survey of the cats in four shelters and wrote the following observations: 4 of the 18 cats in Shelter 1 were black 13 of the 24 cats in Shelter 2 were black 12 of the 20 cats in Shelter 3 were black 18 of the 25 cats in Shelter 4 were black Based on the survey, which shelter had the greatest percentage of black cats?a Shelter 1bShelter 2cShelter 3dShelter 4

Answer»

Answer:

1. 4/18 = 0.22

2. 13/24 = 0.54

3. 12/20 = 0.60

4. 18/25 = 0.72

Shelter 4 has the HIGHEST percentage of BLACK CATS with 72%

Step-by-step EXPLANATION:

Discussion

514.	Which of the following graphs below is the graph of a function?help me quickly
Answer» Answer: sorry BRO don't know but tomorrow I will GIVE you answer I'm FOLLOWING you byyy good night

514.

Which of the following graphs below is the graph of a function?help me quickly

Answer»

Answer:

sorry BRO don't know but tomorrow I will GIVE you answer I'm FOLLOWING you byyy good night

Discussion

515.	Express log[log(costhita+ isinthita)] in form of A +iB
Answer» Answer:A = ln π B = π / 2 + 2 n π where n is an integer. Explanation: Instead of a vague log , let's USE the natural logarithm so things simplify nicely. We have a complex number z = ln ln ( cos π + i sin π ) for which we want to find the real part, A and the imaginary part, B respectively. What we have inside of the composed ln function resembles Euler's identity, which states that e i x = cos x + i sin x In our particular case, x = π , hence cos π + i sin π = e i π If we plug this in our ORIGINAL expression, we get a simplified form: ln ln ( cos π + i sin π ) = ln ln e i π = ln i π This can be expanded using the PROPERTIES of logarithms: ln i π = ln i + ln π All that is left is finding ln i . We already know a relation between the base of the natural logarithm, e , and complex numbers. To find out ln i , suppose there exists α such i = e i α . If we write these in their complex number form we can see the similarity: i = 0 + 1 ⋅ i e i α = cos α + i sin α ⇒ { cos α = 0 sin α = 1 One solution to this would be α = π / 2 , and since the trigonometric functions are periodic with period ρ = 2 n π for any integer n , the set of solutions is α = π 2 + 2 n π Our complex number can be YET again written as z = ln i + ln π = ln e i α + ln π = ln π + α i ∴ z = ln π + i ( π 2 + 2 n π ) , n ∈ Z We have solved the question in discussion: { A = ln π B = π / 2 + 2 n π Answer linkA = ln π B = π / 2 + 2 n π where n is an integer. Explanation: Instead of a vague log , let's use the natural logarithm so things simplify nicely. We have a complex number z = ln ln ( cos π + i sin π ) for which we want to find the real part, A and the imaginary part, B respectively. What we have inside of the composed ln function resembles Euler's identity, which states that e i x = cos x + i sin x In our particular case, x = π , hence cos π + i sin π = e i π If we plug this in our original expression, we get a simplified form: ln ln ( cos π + i sin π ) = ln ln e i π = ln i π This can be expanded using the properties of logarithms: ln i π = ln i + ln π All that is left is finding ln i . We already know a relation between the base of the natural logarithm, e , and complex numbers. To find out ln i , suppose there exists α such i = e i α . If we write these in their complex number form we can see the similarity: i = 0 + 1 ⋅ i e i α = cos α + i sin α ⇒ { cos α = 0 sin α = 1 One solution to this would be α = π / 2 , and since the trigonometric functions are periodic with period ρ = 2 n π for any integer n , the set of solutions is α = π 2 + 2 n π Our complex number can be yet again written as z = ln i + ln π = ln e i α + ln π = ln π + α i ∴ z = ln π + i ( π 2 + 2 n π ) , n ∈ Z We have solved the question in discussion: { A = ln π B = π / 2 + 2 n π Answer link Step-by-step explanation:

515.

Express log[log(costhita+ isinthita)] in form of A +iB

Answer»

Answer:A

=

ln

π

B

=

π

/

2

+

2

n

π

where

n

is an integer.

Explanation:

Instead of a vague

log

, let's USE the natural logarithm so things simplify nicely.

We have a complex number

z

=

ln

(

cos

π

+

i

sin

π

)

for which we want to find the real part,

A

and the imaginary part,

B

respectively.

What we have inside of the composed

ln

function resembles Euler's identity, which states that

e

i

x

=

cos

x

+

i

sin

x

In our particular case,

x

=

π

, hence

cos

π

+

i

sin

π

=

e

i

π

If we plug this in our ORIGINAL expression, we get a simplified form:

ln

(

cos

π

+

i

sin

π

)

=

ln

e

i

π

=

ln

i

π

This can be expanded using the PROPERTIES of logarithms:

ln

i

π

=

ln

i

+

ln

π

All that is left is finding

ln

i

.

We already know a relation between the base of the natural logarithm,

e

, and complex numbers. To find out

ln

i

, suppose there exists

α

such

i

=

e

i

α

.

If we write these in their complex number form we can see the similarity:

i

=

0

+

1

⋅

i

e

i

α

=

cos

α

+

i

sin

α

⇒

{

cos

α

=

0

sin

α

=

1

One solution to this would be

α

=

π

/

2

, and since the trigonometric functions are periodic with period

ρ

=

2

n

π

for any integer

n

, the set of solutions is

α

=

π

2

+

2

n

π

Our complex number can be YET again written as

z

=

ln

i

+

ln

π

=

ln

e

i

α

+

ln

π

=

ln

π

+

α

i

∴

z

=

ln

π

+

i

(

π

2

+

2

n

π

)

,

n

∈

Z

We have solved the question in discussion:

{

A

=

ln

π

B

=

π

/

2

+

2

n

π

Answer linkA

=

ln

π

B

=

π

/

2

+

2

n

π

where

n

is an integer.

Explanation:

Instead of a vague

log

, let's use the natural logarithm so things simplify nicely.

We have a complex number

z

=

ln

(

cos

π

+

i

sin

π

)

for which we want to find the real part,

A

and the imaginary part,

B

respectively.

What we have inside of the composed

ln

function resembles Euler's identity, which states that

e

i

x

=

cos

x

+

i

sin

x

In our particular case,

x

=

π

, hence

cos

π

+

i

sin

π

=

e

i

π

If we plug this in our original expression, we get a simplified form:

ln

(

cos

π

+

i

sin

π

)

=

ln

e

i

π

=

ln

i

π

This can be expanded using the properties of logarithms:

ln

i

π

=

ln

i

+

ln

π

All that is left is finding

ln

i

.

We already know a relation between the base of the natural logarithm,

e

, and complex numbers. To find out

ln

i

, suppose there exists

α

such

i

=

e

i

α

.

If we write these in their complex number form we can see the similarity:

i

=

0

+

1

⋅

i

e

i

α

=

cos

α

+

i

sin

α

⇒

{

cos

α

=

0

sin

α

=

1

One solution to this would be

α

=

π

/

2

, and since the trigonometric functions are periodic with period

ρ

=

2

n

π

for any integer

n

, the set of solutions is

α

=

π

2

+

2

n

π

Our complex number can be yet again written as

z

=

ln

i

+

ln

π

=

ln

e

i

α

+

ln

π

=

ln

π

+

α

i

∴

z

=

ln

π

+

i

(

π

2

+

2

n

π

)

,

n

∈

Z

We have solved the question in discussion:

{

A

=

ln

π

B

=

π

/

2

+

2

n

π

Answer link

Step-by-step explanation:

Discussion

516.	2.Given:PR=~QS. Is PQ=~ RS and why?
Answer» ANSWER: PQ =~ RS Step-by-step explanation: PR =~ PQ + QR QS =~ QR + RS You will notice the BOTHTHE equations have QR common. We also KNOW that PR =~ QS. Thus, equating the FIRST two equations, PQ + QR =~ QR + RS cancelling QR on both sides PQ =~ RS

516.

2.Given:PR=~QS. Is PQ=~ RS and why?

Answer»

ANSWER:

PQ =~ RS

Step-by-step explanation:

PR =~ PQ + QR

QS =~ QR + RS

You will notice the BOTHTHE equations have QR common.

We also KNOW that PR =~ QS.

Thus, equating the FIRST two equations,

PQ + QR =~ QR + RS

cancelling QR on both sides

PQ =~ RS

Discussion

517.	Jayden and Isabella share a reward of $40 in a ratio of 2 : 3. How much does Jayden get?
Answer» ANSWER: Apka answer niche h please mark me as Brainlist answer please please Step-by-step EXPLANATION: Hello Yesenia, If JAYDEN and Isabella share the reward in a ratio of 2:3, this MEANS that Jayden RECEIVED 2/5 of the reward and Isabella receives 3/5 of the reward.

517.

Jayden and Isabella share a reward of $40 in a ratio of 2 : 3. How much does Jayden get?

Answer»

ANSWER:

Apka answer niche h please mark me as Brainlist answer please please

Step-by-step EXPLANATION:

Hello Yesenia, If JAYDEN and Isabella share the reward in a ratio of 2:3, this MEANS that Jayden RECEIVED 2/5 of the reward and Isabella receives 3/5 of the reward.

Discussion

518.	3.5 L of water is added to be a certain quantity of pure milk costing Rs.3L. If by selling themixture is same price as before, a profit of 20% is made, then what is the amount of pure mik inthe mixture?
Answer» ANS=21 R of MISTURE MILK Step-by-step explanation: 10.5L is cost of pure milk than according to percentage formula answer is 2 so 2 multiply with 10.5L ANS=21 R of misture milk Please MARK me as Brainlist answer please please

518.

3.5 L of water is added to be a certain quantity of pure milk costing Rs.3L. If by selling themixture is same price as before, a profit of 20% is made, then what is the amount of pure mik inthe mixture?

Answer»

ANS=21 R of MISTURE MILK

Step-by-step explanation:

10.5L is cost of pure milk

than according to percentage formula

answer is 2 so 2 multiply with 10.5L

ANS=21 R of misture milk

Please MARK me as Brainlist answer please please

Discussion

519.	(b) 5,20,52,060 in word
Answer» ANSWER: Namaste MATE! Here is your answer. b.) Five, TWENTY, FIFTY two, Sixty

519.

(b) 5,20,52,060 in word

Answer»

ANSWER:

Namaste MATE! Here is your answer.

b.) Five, TWENTY, FIFTY two, Sixty

Discussion

520.	let n , a, b and c be positive integers sucht that n= 2a square , n= 3 b cube and n= 5 c power of 5 find the smallest possible no of positive divisors of n
Answer» Step-by-step EXPLANATION: hhhhhhhhhhhhhhhggggghhhh the WORLD to

520.

let n , a, b and c be positive integers sucht that n= 2a square , n= 3 b cube and n= 5 c power of 5 find the smallest possible no of positive divisors of n

Answer»

Step-by-step EXPLANATION:

hhhhhhhhhhhhhhhggggghhhh the WORLD to

Discussion

521.	Write in numbers five millions and seventy six
Answer» Answer: 5,000,076 Step-by-step EXPLANATION: Five MILLION and SEVENTY SIX in numbers is 5,000,076.

521.

Write in numbers five millions and seventy six

Answer»

Answer:

5,000,076

Step-by-step EXPLANATION:

Five MILLION and SEVENTY SIX in numbers is 5,000,076.

Discussion

522.	Which equation can be used to calculate the area of the shaded triangle in the figure below?a2(14 + 8) = 44 square feetb1/2 x (14 + 8) = 11 square feetc2(14 × 8) = 224 square feetd1/2 x (14 × 8) = 56 square feet
Answer» ANSWER: Step-by-step EXPLANATION: he talola QU

522.

Which equation can be used to calculate the area of the shaded triangle in the figure below?a2(14 + 8) = 44 square feetb1/2 x (14 + 8) = 11 square feetc2(14 × 8) = 224 square feetd1/2 x (14 × 8) = 56 square feet

Answer»

ANSWER:

Step-by-step EXPLANATION:

he talola QU

Discussion

523.	Twelve large bottles of water cost $9.a. How many bottles can you buy for $3?b. What is the cost per bottle of water?c. How much would 7 bottles of water cost?ANSWER ALL OF THEM
Answer» ANSWER . 4bottle can be bought b. 1.333$ C. 9.333

523.

Twelve large bottles of water cost $9.a. How many bottles can you buy for $3?b. What is the cost per bottle of water?c. How much would 7 bottles of water cost?ANSWER ALL OF THEM

Answer»

ANSWER

. 4bottle can be bought

b. 1.333$

C. 9.333

Discussion

524.	CWhich equation can be used to calculate the area of the shaded triangle in the figure below?a2(14 + 8) = 44 square feetb1/2 x (14 + 8) = 11 square feetc2(14 × 8) = 224 square feetd1/2 x (14 × 8) = 56 square feet
Answer» ANSWER: (14×8)/2 Step-by-step explanation: 1. Area=bh/2 i HOPE it HELP you..

524.

CWhich equation can be used to calculate the area of the shaded triangle in the figure below?a2(14 + 8) = 44 square feetb1/2 x (14 + 8) = 11 square feetc2(14 × 8) = 224 square feetd1/2 x (14 × 8) = 56 square feet

Answer»

ANSWER:

(14×8)/2

Step-by-step explanation:

1. Area=bh/2

i HOPE it HELP you..

Discussion

525.	Please solve this question as soon as possible..
Answer» ANSWER: OPTION C is the CORRECT answer

525.

Please solve this question as soon as possible..

Answer»

ANSWER:

OPTION C is the CORRECT answer

Discussion

526.	The graph and table shows the relationship between y, the number of words Jean has typed for her essay and x, the number of minutes she has been typing on the computer.According to the line of best fit, about how many words will Jean have typed when she completes 60 minutes of typing?2,5002,7503,0003,250
Answer» ANSWER: I don't know Step-by-step EXPLANATION: but I HELP you

526.

The graph and table shows the relationship between y, the number of words Jean has typed for her essay and x, the number of minutes she has been typing on the computer.According to the line of best fit, about how many words will Jean have typed when she completes 60 minutes of typing?2,5002,7503,0003,250

Answer»

ANSWER:

I don't know

Step-by-step EXPLANATION:

but I HELP you

Discussion

527.	A square is drawn on the altitude of an equilateraltriangle of side 2 meters.a) What is the area of the square?b) What is the altitude of the triangle?
Answer» Answer: AREA=3 altitude=√3 Step-by-step EXPLANATION: SINCE it is a equilateral triangle, altitude is also a median hence it DIVIDES the base side of traingle into EQUAL parts using pythagorus theorem altitude^2=2^2-1^1 =4-1 =3 altitude=√3 since square is constructed on altitude it is one of its side hence area of square=side^2=√3^2=3

527.

A square is drawn on the altitude of an equilateraltriangle of side 2 meters.a) What is the area of the square?b) What is the altitude of the triangle?

Answer»

Answer:

AREA=3

altitude=√3

Step-by-step EXPLANATION:

SINCE it is a equilateral triangle, altitude is also a median

hence it DIVIDES the base side of traingle into EQUAL parts

using pythagorus theorem

altitude^2=2^2-1^1

=4-1

=3

altitude=√3

since square is constructed on altitude it is one of its side

hence area of square=side^2=√3^2=3

Discussion

528.	55) மூன்று எண்களின் விகிதம் முறையே 3 : 4 : 6 என்றால் அதன் பெருக்கல் தொகை 1944 வருவதற்கு மிகப் பெரிய எண்எது?a)6b) 12C) 18d) 20
Answer» Answer: PLZ WRITE in ENGLISH then I try to solve your dout

528.

55) மூன்று எண்களின் விகிதம் முறையே 3 : 4 : 6 என்றால் அதன் பெருக்கல் தொகை 1944 வருவதற்கு மிகப் பெரிய எண்எது?a)6b) 12C) 18d) 20

Answer»

Answer:

PLZ WRITE in ENGLISH then I try to solve your dout

Discussion

529.	What is X%=? fill in tje blanks
Answer» ????????????.........

Discussion

530.	AB=9cm, BC =7cm, CA=8cm
Answer» ANSWER: but what to do....? TELL the QUESTION

530.

AB=9cm, BC =7cm, CA=8cm

Answer»

ANSWER:

but what to do....? TELL the QUESTION

Discussion

531.	Find the total surface area of a cuboid with dimensions 6cmx4cmx2cm
Answer» ANSWER: The TOTAL surface AREA of a CUBOID with DIMENSIONS 6cmx4cmx2cm $= 2(lb + bh + hl) \\ = 2(24 + 8 + 12) \\ = 2(44) = 88 \: {cm}^{2}$

531.

Find the total surface area of a cuboid with dimensions 6cmx4cmx2cm

Answer»

ANSWER:

The TOTAL surface AREA of a CUBOID with DIMENSIONS 6cmx4cmx2cm

$= 2(lb + bh + hl) \\ = 2(24 + 8 + 12) \\ = 2(44) = 88 \: {cm}^{2}$

Discussion

532.	What is the smallest positive integer that leaves a remainder of 1 when divided by 12, 25 and 2020
Answer» Step-by-step explanation: If and are positive integers, there exist UNIQUE integers and , called the quotient and remainder, respectively, such that and . For example, when 15 is divided by 6, the quotient is 2 and the remainder is 3 since . Notice that means that remainder is a non-negative integer and ALWAYS less than divisor. This formula can also be WRITTEN as .

532.

What is the smallest positive integer that leaves a remainder of 1 when divided by 12, 25 and 2020

Answer»

Step-by-step explanation:

If and are positive integers, there exist UNIQUE integers and , called the quotient and remainder, respectively, such that and .

For example, when 15 is divided by 6, the quotient is 2 and the remainder is 3 since .

Notice that means that remainder is a non-negative integer and ALWAYS less than divisor.

This formula can also be WRITTEN as .

Discussion

533.	4x+y=10 ( ,-6) Complete the missing value in the solution to the equation.
Answer» STEP by step solution -6 is the y coordinate So substituting it in equation 4x-6=10 4x=10+6 4x=16 x=16/4 x=4 Therefore the x coordinate is 4 So it will become (4,-6) MARK as brainliest answer Also if SATISFIED hit the thanks button

Discussion

534.	Wright 10 sentences based on the first victers online class in 11 standard
Answer» ANSWER: please like and subscribe to the group and the world is a universal please like and subscribe my YOUTUBE CHANNEL Yashraj YADAV

534.

Wright 10 sentences based on the first victers online class in 11 standard

Answer»

ANSWER:

please like and subscribe to the group and the world is a universal please like and subscribe my YOUTUBE CHANNEL Yashraj YADAV

Discussion

535.	(ii) Niyamat chacha and Karabi didi have started a partnership business together byinvesting Rs. 30,000 and Rs. 50,000 respectively. After 6 months Niyamat chachahas invested Rs. 40,000 more but Karabi didi has withdrawn Rs. 10,000 for personalneed. If the profit at the end of the year is Rs. 19.000, let us write by calculating theprofit share of each of them.
Answer» ANSWER: Niyamat chacha's Profit share = Rs 10,000 Karabi didi's Profit share = Rs 9,000 Step-by-step explanation: Given : • Niyamat chacha and Karabi investing Rs. 30,000 and Rs. 50,000 respectively • After 6 MONTHS Niyamat chacha has INVESTED Rs. 40,000 more • Karabi didi has withdrawn Rs. 10,000 To FIND : • Profit share of each SOLUTION : ★ Niyamat chacha's share = ⇒ (30,000 × 6) + (30,000 + 40,000) × 6 ⇒ 1,80,000 + 4,20,000 ⇒ 600,000 ★ Karabi didi's share = ⇒ (50,000 × 6) + (50,000 − 10,000) × 6 ⇒ 3,00,000 + 2,40,000 ⇒ 540,000 Niyamat chacha's share : Karabi didi's share 600,000 : 540,000 60 : 54 10 : 9 Total profit = Rs. 19,000 ★ Niyamat chacha's Profit share : ⇒ 10 / 19 × 19,000 ⇒ 10,000 ★ Karabi didi's Profit share : ⇒ 9 / 19 × 19,000 ⇒ 9,000 Therefore, Niyamat chacha's Profit share = Rs 10,000 Karabi didi's Profit share = Rs 9,000

535.

(ii) Niyamat chacha and Karabi didi have started a partnership business together byinvesting Rs. 30,000 and Rs. 50,000 respectively. After 6 months Niyamat chachahas invested Rs. 40,000 more but Karabi didi has withdrawn Rs. 10,000 for personalneed. If the profit at the end of the year is Rs. 19.000, let us write by calculating theprofit share of each of them.

Answer»

ANSWER:

Niyamat chacha's Profit share = Rs 10,000

Karabi didi's Profit share = Rs 9,000

Step-by-step explanation:

Given :

• Niyamat chacha and Karabi investing Rs. 30,000 and Rs. 50,000 respectively

• After 6 MONTHS Niyamat chacha

has INVESTED Rs. 40,000 more

• Karabi didi has withdrawn Rs. 10,000

To FIND :

• Profit share of each

SOLUTION :

★ Niyamat chacha's share =

⇒ (30,000 × 6) + (30,000 + 40,000) × 6

⇒ 1,80,000 + 4,20,000

⇒ 600,000

★ Karabi didi's share =

⇒ (50,000 × 6) + (50,000 − 10,000) × 6

⇒ 3,00,000 + 2,40,000

⇒ 540,000

Niyamat chacha's share : Karabi didi's share

600,000 : 540,000

60 : 54

10 : 9

Total profit = Rs. 19,000

★ Niyamat chacha's Profit share :

⇒ 10 / 19 × 19,000

⇒ 10,000

★ Karabi didi's Profit share :

⇒ 9 / 19 × 19,000

⇒ 9,000

Therefore,

Niyamat chacha's Profit share = Rs 10,000

Karabi didi's Profit share = Rs 9,000

Discussion

536.	O1 function power (n) {2 if (n > 1) {3n = n - 14return5 }6 else {7return8 }910 print (power(6))la
Answer» Step-by-step explanation: WRITE it in PROPER way or tag a image i can't understand it

536.

O1 function power (n) {2 if (n > 1) {3n = n - 14return5 }6 else {7return8 }910 print (power(6))la

Answer»

Step-by-step explanation:

WRITE it in PROPER way or tag a image i can't understand it

Discussion

537.	In question figure is embedded in one of the answer figures. find the correct in which embedded.
Answer» Answer: 2 PLS MARK me as BRAINLIST

537.

In question figure is embedded in one of the answer figures. find the correct in which embedded.

Answer»

Answer:

2 PLS MARK me as BRAINLIST

Discussion

538.	Hoecost of painting8. Find the volume, curved surface area and the total surface area of acone having base radius 35 cm and height 12 cm.and the total surface area ofם
Answer» Step-by-step EXPLANATION: QUESTION is incomplete WRITE it in proper WAY

538.

Hoecost of painting8. Find the volume, curved surface area and the total surface area of acone having base radius 35 cm and height 12 cm.and the total surface area ofם

Answer»

Step-by-step EXPLANATION:

QUESTION is incomplete WRITE it in proper WAY

Discussion

539.	Pls answer me fast
Answer» ANSWER: in EQUILATERAL TRIANGLE all SIDES are equal ps BISECTS the triangle ABC so pq=qr=rs

539.

Pls answer me fast

Answer»

ANSWER:

in EQUILATERAL TRIANGLE all SIDES are equal

ps BISECTS the triangle ABC

so pq=qr=rs

Discussion

540.	Factorise x ^2 + 4 x − 60
Answer» Step-by-step explanation: =>x^2 +(10-6)x -60 => x^2 +10X -6X -60 =>x(x+10) -6(x+10) =>(x+10)(x-6) this is the answer.....

540.

Factorise x ^2 + 4 x − 60

Answer»

Step-by-step explanation:

=>x^2 +(10-6)x -60

=> x^2 +10X -6X -60

=>x(x+10) -6(x+10)

=>(x+10)(x-6)

this is the answer.....

Discussion

541.	2 2/3 × 1 1/7 multiply
Answer» Answer: 61/21 Step-by-step EXPLANATION:

541.

2 2/3 × 1 1/7 multiply

Answer»

Answer:

61/21

Step-by-step EXPLANATION:

Discussion

542.	Smallest composite nuber is
Answer» Answer: 4 is the SMALLEST COMPOSITE NUMBER

542.

Smallest composite nuber is

Answer»

Answer:

4 is the SMALLEST COMPOSITE NUMBER

Discussion

543.	Selling priceProfit/loss %Cost price3450?5002Profit % - 20%6002500Loss % 10%9fill the blank Area
Answer» Answer: SORRY I can't able to UNDERSTAND the question sorry

543.

Selling priceProfit/loss %Cost price3450?5002Profit % - 20%6002500Loss % 10%9fill the blank Area

Answer»

Answer:

SORRY I can't able to UNDERSTAND the question sorry

Discussion

544.	I will give brainliest to the answer
Answer» ANSWER: A: 2, 4 Step-by-step EXPLANATION:

544.

I will give brainliest to the answer

Answer»

ANSWER:

A: 2, 4

Step-by-step EXPLANATION:

Discussion

545.	Fifteen litres of a milk solution with 75% milk is added to a certain quantity of another solutionhaving 60% milk to form a solution having 69% milk. What is the quantity of the other solutionto which the first solution is added?
Answer» ANSWER: rhrhrhrheheheueueueurhrhhrbrbrhrhr

545.

Fifteen litres of a milk solution with 75% milk is added to a certain quantity of another solutionhaving 60% milk to form a solution having 69% milk. What is the quantity of the other solutionto which the first solution is added?

Answer»

ANSWER:

rhrhrhrheheheueueueurhrhhrbrbrhrhr

Discussion

546.	11. TThe curved surface area of a right circular cylinder of height 14 cm is 88 cm”. Findediameter of the base of the cylinder.d
Answer» Answer: MARK me as brainliest Step-by-step explanation: CSA of cylinder=88cm height=14cm diameter=? put the formula then FIND the value hope it HELPS

546.

11. TThe curved surface area of a right circular cylinder of height 14 cm is 88 cm”. Findediameter of the base of the cylinder.d

Answer»

Answer:

MARK me as brainliest

Step-by-step explanation:

CSA of cylinder=88cm

height=14cm

diameter=?

put the formula

then FIND the value

hope it HELPS

Discussion

547.	Yadi ABCD – kram 1 2 3 4 – hai to book ki sankhya kya hogi
Answer» Step-by-step EXPLANATION: very GOOD question ,i think 4 ANS

547.

Yadi ABCD – kram 1 2 3 4 – hai to book ki sankhya kya hogi

Answer»

Step-by-step EXPLANATION:

very GOOD question ,i think 4 ANS

Discussion

548.	PP.1 Arrange the following angles ascending order
Answer» ANSWER: PLEASE which ANGLES???

548.

PP.1 Arrange the following angles ascending order

Answer»

ANSWER:

PLEASE which ANGLES???

Discussion

549.	(divide 45 km in the ratio 7:8)?
Answer» 7x + 8x = 45 15 X = 45 x = 3 thus, 7/1545 = 21km and 8/1545 = 24 km

549.

(divide 45 km in the ratio 7:8)?

Answer»

7x + 8x = 45

15 X = 45

x = 3

thus, 7/15*45 = 21km and 8/15*45 = 24 km

Discussion

550.	12. A ball is thrown upwards with an initial speed of 20ms-1. Calculate the maximumheight attained by it?
Answer» Time to reach maximum height can be obtained from v=u+at 0=20+(−10)t t=2s s=ut+0.5at 2 =20(2)+0.5(−10)(2) 2 =20m Thus, total DISTANCE for maximum height is 45 m s=ut+0.5at 2 45=0+0.5(10)(t ′ ) 2 t ′ =3s Total time= 3+2= 5s HI DEAR SHRESTA HERE PLEASE FOLLOW ME FRNDS AND THANK MY ANSWER TOOO..(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(●♡∀♡)

550.

12. A ball is thrown upwards with an initial speed of 20ms-1. Calculate the maximumheight attained by it?

Answer»

Time to reach maximum height can be obtained from v=u+at

0=20+(−10)t

t=2s

s=ut+0.5at

2 =20(2)+0.5(−10)(2)

2 =20m

Thus, total DISTANCE for maximum height is 45 m

s=ut+0.5at

2 45=0+0.5(10)(t

′

)

2 t

′

=3s

Total time= 3+2= 5s

HI DEAR SHRESTA HERE PLEASE FOLLOW ME FRNDS AND THANK MY ANSWER TOOO..(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(◍•ᴗ•◍)❤(●♡∀♡)

Discussion

Explore topic-wise InterviewSolutions in .

Pls help me these questions​

Pls help me, 3.039/9.8 = ?

Pls help me with these qustions. ​

Find the solution set of the equationx 2 + x -2 =0 in Roster form

Pls help me with these qustions​

Problemy-3=2(x+1)y−3=2(x+1)y, minus, 3, equals, 2, left parenthesis, x, plus, 1, right parenthesisComplete the missing value in the solution to the equation.(-1,(−1,left parenthesis, minus, 1, comma ))

Fill up the blankIn stratosphere temperaturewith increase in altitude.2Write anchether the following staternoot is tore or false​

The bicycle travelling?14. A small cart is being driven at 10 km per hour. Ifeach wheel is 91 cm in diameter, find the number ofrevolutions made by each wheel per minute.​

SPEED of the cart = 10km/hr

= 10×1000/60 m/ min = 1000/6 m/min.

Diameter of the wheel = 91 cm= 0.91 m

Radius of the wheel = 0.91/2 m

Circumference of the wheel= 2πr

= 2 × (22/7) × (0.91/2) m= 22×0.13 m

No.of REVOLUTIONS PER minute= (1000/6)/(22×o.13) = 1000×100/(6×22×13)

= 1000×25/429

Fine the derivative of​

obtain truth values of compound statements of the type pVq by using switch connection in parallel. please somebody help me this is my project topic and i don't have any ideas about it! can anybody please help me completing this project ​

We can run animation from ______ menu is adobe flash?​

A boat goes 30km upstream and 44km downstream in 1 hour. The same boat goes40km upstream and 53 km downstream in 13 hours. Determine the speed of streamand that of boat in still water.​

Let the speed of boat in still water=x km\hr and The speed of stream=y km\hr

Speed of boat at downstream

⇒(x+y)km/hr

Speed of boat at upstream

⇒(x−y)km/hr

∵time=

speed

distance

Time taken to cover 30 km upstream ⇒

x−y

30

Time taken to cover 44 km downstream⇒

x+y

44

According to the first condition,

⇒

x−y

30

=

x+y

44

=10

Time taken to cover 40 km upstream ⇒

x−y

40

Time taken to cover 55 km downstream ⇒

x+y

55

According to the second condition,

⇒

x−y

40

=

x+y

55

=13

Let

x−y

1

=uand

x+y

1

=v

⇒30u+44v=10.....eq1

⇒40u+55v=13.....eq2

Multiplying eq1 by 3 and eq2 by 5 and SUBTRACT both

⇒(150u+220v=50)−(160u+220v=52)

⇒−10u=−2⇒U=

5

1

put u=

5

1

in eq1

⇒30×

5

1

+44v=10⇒44v=4⇒v=

4

Pls help me these questions

Pls help me with these qustions.

Pls help me with these qustions

Fill up the blankIn stratosphere temperaturewith increase in altitude.2Write anchether the following staternoot is tore or false

The bicycle travelling?14. A small cart is being driven at 10 km per hour. Ifeach wheel is 91 cm in diameter, find the number ofrevolutions made by each wheel per minute.

Fine the derivative of

obtain truth values of compound statements of the type pVq by using switch connection in parallel. please somebody help me this is my project topic and i don't have any ideas about it! can anybody please help me completing this project

We can run animation from ______ menu is adobe flash?

A boat goes 30km upstream and 44km downstream in 1 hour. The same boat goes40km upstream and 53 km downstream in 13 hours. Determine the speed of streamand that of boat in still water.