InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 351. |
Calculate the area of triangle formed by the points A(5,3),B(-2,1)and C(2,4). |
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Answer» Step-by-step EXPLANATION: formula for area of traingle joining the points is 1/2[x1(y2-y3)+x2(y3-y1)+X3(y1-y2)] As per Question x1=5,y1=3,x2=-2,y2=1,x3=2,y3=4 so APPLYING to the formula we get, 1/2[5(1-4)+(-2)(4-3)+2(3-1)] = 1/2[5(-3)+(-2)(1)+2(2)] = 1/2[-15-2+4] = 1/2[-13] = -6.5 sq.units Therefore,area of the traingle is -6.5 |
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| 352. |
If xy=180 and HCF(x,y)=3,then find the LCM(x,y) |
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Answer» Step-by-step EXPLANATION: We know that, LCM(x, y) × HCF(x, y) = xy → LCM(x, y) × 3 = 180 → LCM(x, y) = 180 ÷ 3 = 60 → LCM(x, y) = 60 |
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| 353. |
Find the equation of the circle with centre (-9,0) and radius root a |
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Answer» Answer: Equation of circle: Step-by-step explanation: Centre coordinates = (-9,0) = (h,k) .: where h = -9 and k = 0 Radius = We know, the general equation of circle is So, INSERTING the values in the equation, we GET So, the equation of circle is PLEASE MARK IT THE BRAINLIEST |
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| 354. |
Plz help me I put a screen shot |
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Answer» Step-by-step EXPLANATION: fbxvfedgdffcvvvvvvvvvvvv |
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| 355. |
(a+b)×(a-b) |
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Answer» (a+b)×(a-b) =a²-b² Good MORNING... |
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| 356. |
A train leaves at 09.46 and arrives at its destination at 10.34. If the train travelled 74 km, what was it's average speed in km/h? Give your answer rounded to 1 dp. |
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Answer» Answer: 84.1 Step-by-step EXPLANATION: TOTAL distance per total time TAKEN is AVERAGE speed so; (74)/0.88 84.1 hope this will help you ; |
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| 357. |
Find at what speed in km per hour you must travel to complete a journey of 40000m in 300 minutes |
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Answer» Answer: find at what speed in km per hour you MUST travel to COMPLETE a JOURNEY of 40000m in 300 minutes |
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| 358. |
What is the proportion ratio of 750G per 3kg proportion |
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Answer» GOOD night so joi JADA PADE math kero matalb karo |
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| 359. |
If the area of a semicircle be 77sq.cm find its perimeter |
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| 360. |
Please help me I have to make a graph of these equations. |
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Answer» TV show you how much more than IU voice is your favorite SONG I was in my HEART is Step-by-step EXPLANATION: v for me and my heart is |
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| 361. |
(x-4)(4x +3)(2x +3) |
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Answer» Answer: 8x^3-14x^2-63x-36 Step-by-step EXPLANATION: (4x^2-13x-12)(2x+3) 8x^3+12x^2-26x^2-39x-24x-36 8x^3-14x^2-63x-36 hope this will HELP you ; |
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| 362. |
Alta dove 9 meters below the ocean’s surface. She then dove 15 meters deeper. She then rose 19 1/4 meters. What was her position in relation to the surface of the water?1.) -43 1/4 M2.) -4 3/4 M3.) 4 3/4 M4.) 43 1/4 M |
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Answer» Answer: 2.) - 4 3/4 M Step-by-step explanation: 9 Take up as + ve and down as -ve. -9-15+19 1/4 M = -24+19 1/4 M = -4 3/4 M |
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| 363. |
Guys I don't get this, please help meIts a math problemA centre seat cost 25 dollars less than an aisle seat. (The problem is set on a plane) or window seat. A window or aisle seat costs 'a' (The algebra letter) and a centre seat costs 342 dollarsCOMPLETE THE EQUATION(dollar) ___= a- (Dollar) Guys this is really complicated so please help |
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Answer» .................................. Step-by-step EXPLANATION: |
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| 364. |
A group of biologists found a total of 28 loggerhead turtle nests along a beach during a certain season. This was 40% of the total number of turtle nests the group found during that season. What was the total number of turtle nests the group found during that season? |
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Answer» TOTAL NUMBER of TURTLE nests=70 Step-by-step EXPLANATION: X x 40/100=28 X=100x28/40 X=70 |
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| 365. |
(x - 3)^2 – (x + 2)^2 |
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Answer» Answer: 5(1-2x) Step-by-step EXPLANATION: (x-3+x+2)(x-3-x-2) [a^2+b^2=(a+b)(a-b)] (2x-1)(-5) 5-10x 5(1-2x) [ANS] |
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| 366. |
Plz don't spam.only useless people are spam.and plz answer without solving L hospital rule.Thanks |
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Answer» HEY There Here's The Answer __________________________ • REFER to the Attachment. Hope It HELPS. |
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| 367. |
(iv) Length = 4.5 m, breadth = 2 m 25 cm |
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Answer» Answer= 13.5Step-by-step explanation: =2(4.5m)+2(2m 25 CM) =9M+ 4.5m i.e= 13.5m |
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| 368. |
Find the equation if the circle with centre of the origin and radius 7 |
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| 369. |
Please tell..,....... |
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Answer» what should we need to TELL Step-by-step explanation: it's your practical book and U need to WRITE it same as in book |
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| 370. |
Elliana wants to make a scale drawing of her bedroom. Her bedroom is a rectangle with length 9m and width 4m. She decides on a scale of 1 to 40 . What is the length of the scale drawing |
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Answer» please I am kira subscriber he is the FOLLOWING ad I will be a GOOD day paka dalan ghor poriskar KORE ki sharir ke badh kar DUNGA |
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| 371. |
A lever OA 1 m long is inclined at 60° with horizontal. Aforce of 200 N is acting at A vertically down words. Themoment about 'O' is(a) 75 N·m (b) 100 N·m(c) 50 Nm (d) 200 N·m |
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Answer» Answer: 1.for making the text look coloured refer the below syntax and IGNORE the dots [.tex]\red{the\:text\:appears\:in\:red}[./tex] \red{the\:text\:appears\:in\:red}thetextappearsinred 2.for making the text marquee [.tex][./tex] result = < marquee > {the\:text\:appears\:like\:this} < /marquee > 3. for making the text look bold [.tex]\bold{the\:text\: appears\: like\: this }[./tex] result = \bold{the\:text\: appears\: like\: this }thetextappearslikethis 4. for showing the exponential value [.tex]{no.}^{power}[./tex] result = {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\sqrt{no.}[./tex] result = no.
[./tex]result=[tex] no.
\bold{\BOXED{thanx}} thanx
FOLLOW me next |
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| 372. |
(cosalpha-cosbeta)2+(sinalpha-sinbeta)2prove that it is equal to 4sin2 alpha-beta÷2 |
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Answer» I have finded it CHECK it out... |
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| 373. |
8. In the following figure, angle ACB = angle AQP and AP is x cm.ci. Find x.ii. Find the length of QP.iii. Find the ratio between area of quadrilateral QPCB and area of triangle AQP. p |
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Answer» i. 5cm ii. 5cm iii. 1:8 Step-by-step EXPLANATION: In tri ABC and tri AQP ang PAQ=ang CAB[Common] ang ACB=ang AQP[Given] So, ang APQ=ang ABC[3rd ang] hence, tri AQP ~ tri ACB [By AAA axiom] By Similarity, QP/BC=AP/AB=AQ/AC so, QP/15=x/15=3/x+4 so, x/15=3/x+4 so, x(x+4)=15×3=45 so, x^2+4x-45=0 so, x^2+(9-5)x-45=0 so, x(x+9)-5(x+9)=0 so, (x+9)(x-5)=0 so, either x=-9 or x=5 As length cannot be negative so x= 5cm [Ans..i] so, QP/15=5/15 so, QP=5cm [Ans..ii] AR tri AQP= 1/2×5×5=12.5cm^2 ar tri ABC=1/2×15×15=112.5cm^2 so, ar QUAD QPCB= 112.5-12.5=100cm^2 hence, ar quad QPCB:ar tri AQP =100/12.5 =1/8 so, ratio =1:8 [Ans..iii]
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| 374. |
A player tosses three coins. he wins rupees 5 if three heads appear and rupees 3 if two heads appear and rupees 1 if one head appear and he loses rupees 15 if no head appears how do you find he is expected game explain |
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Answer» Answer: 5×1/8+ 3×3/8 + 1×3/8 - 15×1/8 = 1/4 |
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| 375. |
28 A force of 50 N acting tangentially to a circle of radius 2m. Its moment about diametrically opposite point will be(a) 300 N·m(b) 200 NomC) 400 Nm(d) 100 N.m |
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Answer» b Step-by-step EXPLANATION: |
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| 376. |
For a given co-planer force system EF, = 30 N and theangle made by resultant with X-axis is 60°. Themagnitude of Ris(a) 25 N (6) 20.64 N (c) 34.64 N (d) 28.28 NAns.: (c) |
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Answer» Step-by-step EXPLANATION: ENQUIRY Letter Sample Refer to the following Enquiry Letter SAMPLES before WRITING it. Enquiry Letter Sample |
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| 377. |
The map shows the location of the house of Dan, Joe, and Roy the coordinates of the community center are (-5, -1 . who has a house in the same quadrant as the community center?A. Dan B. Joe C.LeeD.Roy Please help me i need this done in ten mins |
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Answer» Answer: 1.for MAKING the text LOOK coloured refer the below syntax and ignore the dots [.tex]\red{the\:text\:appears\:in\:red}[./tex] result \red{the\:text\:appears\:in\:red}thetextappearsinred 2.for making the text marquee [.tex][./tex] result = < marquee > {the\:text\:appears\:like\:this} < /marquee > 3. for making the text look bold [.tex]\bold{the\:text\: appears\: like\: this }[./tex] result = \bold{the\:text\: appears\: like\: this }thetextappearslikethis 4. for showing the exponential VALUE [.tex]{no.}^{power}[./tex] result = {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\sqrt{no.}[./tex] result = no.
[./tex]result=[tex] no.
\bold{\boxed{thanx}} thanx
follow me next |
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| 378. |
Three forces each of magnitude 10 N are acting alongthree sides of an equilateral triangle of side 2 m. The totalmoment about apex is(a) 20 N·m (b) Zero (c) 10V3 N·m (d) V10 N·m |
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Answer» Answer: 20Nm is the ANWER PLEASE MARK me BRAINLIEST if I am RIGHT |
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| 379. |
find the equation of the circle whose centre lies on the line x-4y =1 and which passes through (3,7),(5,5) |
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Answer» Step-by-step EXPLANATION: please follow me THANKS to me and mark me BRAINALIST |
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| 380. |
R1 000 is invested at 10% simple interest for three years and R1 000 is invested at 8% compounded annually for three years. Which is a better investment and by how much? |
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Answer» Simple INTREST =(Principal *rate *time)/100 Compound Interest= principle (1+R/100)^time put the values in the FORMULA you will get the amount which you have to SUBTRACT from principle and the REMAINING amount which is higher will be better |
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| 381. |
Write a suitable digit in the units place to make it divisible by 2.(i) 197_(ii) 1235_ (iii) 9655_ (iv) 1999_ |
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Answer» 1 |
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| 382. |
Given 1 cubic metre = 1 000 litres, how many litres of water will be required to fill an empty swimming pool so that it gets to a level of 2m in height? The length of the pool is 600cm and the breadth is 0.004km. Volume is length x breadth x height. Please take care when converting your units. |
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Answer» Answer: 1.for making the text look coloured refer the below syntax and ignore the dots [.tex]\red{the\:text\:appears\:in\:red}[./tex] result \red{the\:text\:appears\:in\:red}thetextappearsinred 2.for making the text MARQUEE [.tex][./tex] result = < marquee > {the\:text\:appears\:like\:this} < /marquee > 3. for making the text look BOLD [.tex]\bold{the\:text\: appears\: like\: this }[./tex] result = \bold{the\:text\: appears\: like\: this }thetextappearslikethis 4. for showing the exponential value [.tex]{no.}^{POWER}[./tex] result = {no.}^{power}[ /tex] 5. for showing the SQUARE ROOT value [.tex]\sqrt{no.}[./tex] result = no.
[./tex]result=[tex] no.
\bold{\boxed{thanx}} thanx
follow me next |
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| 383. |
7×5×3×2+3 a Compositenumber? Justify youranswer? |
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Answer» Step-by-step explanation: A COMPOSITE has more than TWO factors other than itself. 7∗5∗3∗2+3 =3(7∗5∗2+1)=3∗(70+1)=3∗71 The given NUMBER has two factors 3 and 71. ∴ It is a composite number. |
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| 384. |
Find the area of the iron sheet required to prepare a cone 24cm hight with base radious 7cm? |
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Answer» Step-by-step explanation: AREA of IRON sheet = TSA of cone. => TSA of cone = πr(L+r) l = 25 => TSA= 703.7cm^2
.•. area of iron sheet REQUIRED is 703.7 cm^2 |
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| 385. |
A farmer has a rectangular field of length and breadth 240 m and 180 m respectively. Hewants to fence it with 3 rounds of rope. What is the total length of rope he must use? |
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Answer» The farmer has to cover THREE times the perimeter of that field. Therefore, Total length of ROPE REQUIRED is thrice its perimeter. Perimeter of the field = 2 × (length + BREADTH) Perimeter of the field = 2 × (240 m + 180 m) Perimeter of the field = 2 × 420 m Perimeter of the field = 840 m ____________________ Total length of rope required = 3 × 840 m Total length of rope required = 2520 m |
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| 386. |
A square fence encloses a circle. Calculate the area of the circle in m2 if the area of the square is 800 m2. The area of a circle is Pi x r2. Pi can be taken as 22/7. |
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Answer» Step-by-step EXPLANATION: AREA of square=a² 800=a² a=20√2 radius of a circle=half the SIDE of a square r=20√2/2 r=10√2 area of circle=πr² a=22/7*(10√2)² a=628.57m² |
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| 387. |
Whats the product of the 3rd square number |
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Answer» .................................................... Step-by-step EXPLANATION: |
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| 388. |
Composite number? Jutsfy you་ནང་answer |
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Answer» Step-by-step EXPLANATION: in which LANGUAGE it is |
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| 389. |
What are the measures of the four angles in the figure? |
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Answer» Answer: 2x + x - 12 = 180 3x -12=180 3x= 180+12=192 x= 192÷3= 64 so we get first angle 2x= 64×2=128 degree and SECOND angle x-12 = 64-12=52 degree Now, 3Y +y+20=180 so, 4y+20=180 4y=180-20=160 y=160÷4 = 40 so we get third angle 3y= 40×3= 120 degree and FOURTH angle y+20= 40+20=60 degree hope this helps you pls mark it as brain list ❤❤ |
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| 390. |
If y = 7x − 5, which of the following sets represents possible inputs and outputs of the function, represented as ordered pairs? (5 points) a {(−5, 0), (9, 2), (−26, −3)} b {(2, 7), (1, 6), (3, 13)} c {(0, −5), (2, 9), (−3, −26)} d {(1, 3), (6, 18), (8, 15)} |
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Answer» hsjdjssmsmsms msmmsmamssm nsnsmsmsnsnssmsm 25i85eery0itdicm.ug70gpgi UGGS G 9vu V i uogxuoxi0gzi0gxiogd bsbwvegeveveicpe g7e 7g9 e96f e9u9gegu9 g0ieig9eeu9g |
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| 391. |
pinky runs around a square field of side 75 m bob runs around a rectangular field with length 160m and breadth 105m who cover more distance and by how much |
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Answer» DISTANCE covered by PINKY in one round = Perimeter of the square Distance covered by Pinky in one round = 4 × length of a side Distance covered by Pinky in one round = 4 × 75 m Distance covered by Pinky in one round = 300 m _____________________ Distance covered by Bob in one round = Perimeter of the rectangle Distance covered by Bob in one round = 2 × (length + breadth) Distance covered by Bob in one round = 2 × (160 m + 105 m) Distance covered by Bob in one round = 2 × 265 m Distance covered by Bob in one round = 530 m ____________________ Difference in the distance covered = 530m - 300m Difference in the distance covered = 230 m Therefore:- Bob covers more distance by 230 m. |
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| 392. |
Gini has three times as many stickers as Bala how many stickers does Bala have |
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Answer» Answer: if Gini has 3x stickers then Bala have X stickers... Step-by-step explanation: please mark me the branliest also please follow me... MARRY Christmas in advance...stay safe and happy and healthy... |
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| 393. |
Vijay wants to cover the floor of a room 3 m wide and 4 metre long by square tiles if each square tile in side 0.5 then the number of tiles required to cover the floor of the room |
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Answer» TOTAL AREA of tiles MUST be equal to the area of the floor of the ROOM. Length of the room = 4 m Breadth of the room = 3 m Formula used:- Area of the floor = length × breadth Putting the values according to the formula: => Area of the floor = 4 m × 3 m => Area of the floor = 12 sq m Area of one square tile = Side × Side => Area of one square tile = 0.5 m × 0.5 m => Area of one square tile = 0.25 sq m Number of tiles required = Area of the floor/Area of one tile => Number of tiles required = 12/0.25 => Number of tiles required = 1200/25 => Number of tiles required = 48 tiles Hence:- The number of tiles required to cover the floor of the room is 48 tiles. |
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| 394. |
Is there any possibility of reopening of colleges for class 11, in December. |
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Answer» no way |
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| 395. |
The product of two fractions is 6. if one fraction is 5/3,find the other |
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Answer» Answer: 18/5 Step-by-step EXPLANATION: LET the other fraction be x/y Acc to the condition Therefore the other fraction is 18/5 or an EQUIVALENT fraction of 18/5 for eg 36/10, 72/15, ETC |
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| 396. |
1. If Zw= 62°, find Zx, Zy and Zz.WXNy |
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Answer» hsjsjksksksksksksjhsbdhdhdjd |
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| 398. |
Q6. Find the area in square metre of a piece of cloth 1 metre 25 cm wideand 2 metre long. |
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Answer» Length of the cloth = 2 m Breadth of the cloth = 1 m 25 m Breadth of the cloth = 1 m + 0.25 m Breadth of the cloth = 1.25 m (Since 25 cm = 0.25 m) Area of the cloth = length of the cloth × BREATH of the cloth => Area of the cloth = 2 m × 1.25 m => Area of the cloth = 2.50 sq m Hence:- The area of the cloth is 2.50 sq m. More Information: The amount of surface enclosed by a closed figure is CALLED its area. To calculate the area of a figure using a squared paper, the following CONVENTIONS are adopted: IGNORE portions of the area that are less than half a square. If more than half a square is in a region. Count it as one square. If exactly half the square is COUNTED, take its area as ½ sq units. Area of a rectangle = length × breadth Area of a square = Side × Side |
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| 399. |
A radio tower is 87 feet tall. Find the angle of elevation to the top of the tower at a point on level ground 46 feet from its base. Round your answer to the nearest degree. |
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Answer» By using formula θ = atan (H / d) answer=62.133 Step-by-step explanation: |
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| 400. |
What is the magnitude of force required to accelerate a car of mass1.7 × 103 kilograms by 4.75 meters/second2? |
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Answer» Given Information:- The mass of the car is 1.7 × 10³ KILOGRAMS by 4.75 meters/second² Need to find out:- The magnitude of force REQUIRED to ACCELERATE a car = ? Formula USED:- Force = Mass × Acceleration F = M × A Putting the values ACCORDING to the formula:- => Magnitude of Force = 1.7 × 10³ × 4.75 => Magnitude of Force = 1.7 × (10 × 10 × 10) × 4.75 => Magnitude of Force = 1.7 × 1000 × 4.75 => Magnitude of Force = 1.7 × 475 => Magnitude of Force = 17 × 475 => Magnitude of Force = 8075 Newton Hence:- The magnitude of force required to accelerate a car is 8075 Newton. |
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