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351.

Calculate the area of triangle formed by the points A(5,3),B(-2,1)and C(2,4).​

Answer»

Step-by-step EXPLANATION:

formula for area of traingle joining the points is

1/2[x1(y2-y3)+x2(y3-y1)+X3(y1-y2)]

As per Question

x1=5,y1=3,x2=-2,y2=1,x3=2,y3=4

so APPLYING to the formula

we get, 1/2[5(1-4)+(-2)(4-3)+2(3-1)]

= 1/2[5(-3)+(-2)(1)+2(2)]

= 1/2[-15-2+4]

= 1/2[-13]

= -6.5 sq.units

Therefore,area of the traingle is -6.5

352.

If xy=180 and HCF(x,y)=3,then find the LCM(x,y)

Answer»

Step-by-step EXPLANATION:

We know that,

LCM(x, y) × HCF(x, y) = xy

→ LCM(x, y) × 3 = 180

→ LCM(x, y) = 180 ÷ 3 = 60

→ LCM(x, y) = 60

353.

Find the equation of the circle with centre (-9,0) and radius root a​

Answer»

Answer:

Equation of circle: x^{2} + y^{2} +18x + 81 - a = 0

Step-by-step explanation:

Centre coordinates = (-9,0) = (h,k)   .: where h = -9 and k = 0

Radius = \sqrt{a} = r

We know, the general equation of circle is (x - h)^{2} + (y - k)^{2} = r^{2}

So, INSERTING the values in the equation, we GET

(x - (-9))^{2} + (y - 0)^{2} = (\sqrt{a} )^{2}\\(x + 9)^{2} + (y)^{2} = a\\x^{2} +18x +81 + y^{2} = a\\x^{2} + y^{2} +18x + 81 - a = 0

So, the equation of circle is x^{2} + y^{2} +18x + 81 - a = 0

PLEASE MARK IT THE BRAINLIEST

354.

Plz help me I put a screen shot

Answer»

Step-by-step EXPLANATION:

fbxvfedgdffcvvvvvvvvvvvv

355.

(a+b)×(a-b)​

Answer»

(a+b)×(a-b)

=a²-b²

Good MORNING...

356.

A train leaves at 09.46 and arrives at its destination at 10.34. If the train travelled 74 km, what was it's average speed in km/h? Give your answer rounded to 1 dp.

Answer»

Answer:

84.1

Step-by-step EXPLANATION:

TOTAL distance per total time TAKEN is AVERAGE speed

so;

(74)/0.88

84.1

hope this will help you ;

357.

Find at what speed in km per hour you must travel to complete a journey of 40000m in 300 minutes

Answer»

Answer:

find at what speed in km per hour you MUST travel to COMPLETE a JOURNEY of 40000m in 300 minutes

358.

What is the proportion ratio of 750G per 3kg proportion​

Answer»

GOOD night so joi JADA PADE math kero

matalb karo

359.

If the area of a semicircle be 77sq.cm find its perimeter​

Answer»

ANSWER:

Answer. THEREFORE,PERIMETER is 36CM

360.

Please help me I have to make a graph of these equations.​

Answer»

ANSWER:

TV show you how much more than IU voice is your favorite SONG I was in my HEART is

Step-by-step EXPLANATION:

v for me and my heart is

361.

(x-4)(4x +3)(2x +3)​

Answer»

Answer:

8x^3-14x^2-63x-36

Step-by-step EXPLANATION:

(4x^2-13x-12)(2x+3)

8x^3+12x^2-26x^2-39x-24x-36

8x^3-14x^2-63x-36

hope this will HELP you ;

362.

Alta dove 9 meters below the ocean’s surface. She then dove 15 meters deeper. She then rose 19 1/4 meters. What was her position in relation to the surface of the water?1.) -43 1/4 M2.) -4 3/4 M3.) 4 3/4 M4.) 43 1/4 M

Answer»

Answer:

2.) - 4 3/4 M

Step-by-step explanation:

9

Take up as + ve and down as -ve.

-9-15+19 1/4 M

= -24+19 1/4 M

= -4 3/4 M

363.

Guys I don't get this, please help meIts a math problemA centre seat cost 25 dollars less than an aisle seat. (The problem is set on a plane) or window seat. A window or aisle seat costs 'a' (The algebra letter) and a centre seat costs 342 dollarsCOMPLETE THE EQUATION(dollar) ___= a- (Dollar) Guys this is really complicated so please help

Answer»

ANSWER:

..................................

Step-by-step EXPLANATION:

364.

A group of biologists found a total of 28 loggerhead turtle nests along a beach during a certain season. This was 40% of the total number of turtle nests the group found during that season. What was the total number of turtle nests the group found during that season?

Answer»

TOTAL NUMBER of TURTLE nests=70

Step-by-step EXPLANATION:

X x 40/100=28

X=100x28/40

X=70

365.

(x - 3)^2 – (x + 2)^2​

Answer»

Answer:

5(1-2x)

Step-by-step EXPLANATION:

(x-3+x+2)(x-3-x-2) [a^2+b^2=(a+b)(a-b)]

(2x-1)(-5)

5-10x

5(1-2x) [ANS]

366.

Plz don't spam.only useless people are spam.and plz answer without solving L hospital rule.Thanks​

Answer»

HEY There

Here's The Answer

__________________________

REFER to the Attachment.

Hope It HELPS.

367.

(iv) Length = 4.5 m, breadth = 2 m 25 cm​

Answer»

Answer=

13.5

Step-by-step explanation:

2(L)+2(B)

=2(4.5m)+2(2m 25 CM)

=9M+ 4.5m

i.e= 13.5m

368.

Find the equation if the circle with centre of the origin and radius 7​

Answer»

ANSWER:

X2+ Y2 =49 is the answer

369.

Please tell..,.......​

Answer»

ANSWER:

what should we need to TELL

Step-by-step explanation:

it's your practical book and U need to WRITE it same as in book

370.

Elliana wants to make a scale drawing of her bedroom. Her bedroom is a rectangle with length 9m and width 4m. She decides on a scale of 1 to 40 . What is the length of the scale drawing

Answer»

ANSWER:

please I am kira subscriber he is the FOLLOWING ad I will be a GOOD day paka dalan ghor poriskar KORE ki sharir ke badh kar DUNGA

371.

A lever OA 1 m long is inclined at 60° with horizontal. Aforce of 200 N is acting at A vertically down words. Themoment about 'O' is(a) 75 N·m (b) 100 N·m(c) 50 Nm (d) 200 N·m​

Answer»

Answer:

1.for making the text look coloured refer the below syntax and IGNORE the dots

[.tex]\red{the\:text\:appears\:in\:red}[./tex]

RESULT

\red{the\:text\:appears\:in\:red}thetextappearsinred

2.for making the text marquee

[.tex]{the\:text\:appears\:like\:this}[./tex]

result

= < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis

3. for making the text look bold

[.tex]\bold{the\:text\: appears\: like\: this }[./tex]

result =

\bold{the\:text\: appears\: like\: this }thetextappearslikethis

4. for showing the exponential value

[.tex]{no.}^{power}[./tex]

result

= {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\sqrt{no.}[./tex] result = \sqrt{no.}no. power5.forshowingthesquarerootvalue[.tex]

no.

[./tex]result=[tex]

no.

\bold{\BOXED{thanx}}

thanx

FOLLOW me next

372.

(cosalpha-cosbeta)2+(sinalpha-sinbeta)2prove that it is equal to 4sin2 alpha-beta÷2​

Answer»

I have finded it CHECK it out...

373.

8. In the following figure, angle ACB = angle AQP and AP is x cm.ci. Find x.ii. Find the length of QP.iii. Find the ratio between area of quadrilateral QPCB and area of triangle AQP. p​

Answer»

ANSWER:

i. 5cm

ii. 5cm

iii. 1:8

Step-by-step EXPLANATION:

In tri ABC and tri AQP

ang PAQ=ang CAB[Common]

ang ACB=ang AQP[Given]

So, ang APQ=ang ABC[3rd ang]

hence, tri AQP ~ tri ACB [By AAA axiom]

By Similarity,

QP/BC=AP/AB=AQ/AC

so, QP/15=x/15=3/x+4

so, x/15=3/x+4

so, x(x+4)=15×3=45

so, x^2+4x-45=0

so, x^2+(9-5)x-45=0

so, x(x+9)-5(x+9)=0

so, (x+9)(x-5)=0

so, either x=-9 or x=5

As length cannot be negative so x= 5cm [Ans..i]

so, QP/15=5/15

so, QP=5cm [Ans..ii]

AR tri AQP= 1/2×5×5=12.5cm^2

ar tri ABC=1/2×15×15=112.5cm^2

so, ar QUAD QPCB= 112.5-12.5=100cm^2

hence,

ar quad QPCB:ar tri AQP

=100/12.5

=1/8

so, ratio =1:8 [Ans..iii]

374.

A player tosses three coins. he wins rupees 5 if three heads appear and rupees 3 if two heads appear and rupees 1 if one head appear and he loses rupees 15 if no head appears how do you find he is expected game explain​

Answer»

Answer:

5×1/8+ 3×3/8 + 1×3/8 - 15×1/8 = 1/4

375.

28 A force of 50 N acting tangentially to a circle of radius 2m. Its moment about diametrically opposite point will be(a) 300 N·m(b) 200 NomC) 400 Nm(d) 100 N.m​

Answer»

ANSWER:

b

Step-by-step EXPLANATION:

the answer is ATTACHED above I HOPE that this will HELP you

376.

For a given co-planer force system EF, = 30 N and theangle made by resultant with X-axis is 60°. Themagnitude of Ris(a) 25 N (6) 20.64 N (c) 34.64 N (d) 28.28 NAns.: (c)​

Answer»

Step-by-step EXPLANATION:

ENQUIRY Letter Sample

Refer to the following Enquiry Letter SAMPLES before WRITING it.

Enquiry Letter Sample

377.

The map shows the location of the house of Dan, Joe, and Roy the coordinates of the community center are (-5, -1 . who has a house in the same quadrant as the community center?A. Dan B. Joe C.LeeD.Roy Please help me i need this done in ten mins

Answer»

Answer:

1.for MAKING the text LOOK coloured refer the below syntax and ignore the dots

[.tex]\red{the\:text\:appears\:in\:red}[./tex]

result

\red{the\:text\:appears\:in\:red}thetextappearsinred

2.for making the text marquee

[.tex]{the\:text\:appears\:like\:this}[./tex]

result

= < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis

3. for making the text look bold

[.tex]\bold{the\:text\: appears\: like\: this }[./tex]

result =

\bold{the\:text\: appears\: like\: this }thetextappearslikethis

4. for showing the exponential VALUE

[.tex]{no.}^{power}[./tex]

result

= {no.}^{power}[ /tex] 5. for showing the square root value [.tex]\sqrt{no.}[./tex] result = \sqrt{no.}no. power5.forshowingthesquarerootvalue[.tex]

no.

[./tex]result=[tex]

no.

\bold{\boxed{thanx}}

thanx

follow me next

378.

Three forces each of magnitude 10 N are acting alongthree sides of an equilateral triangle of side 2 m. The totalmoment about apex is(a) 20 N·m (b) Zero (c) 10V3 N·m (d) V10 N·m​

Answer»

Answer:

20Nm is the ANWER PLEASE MARK me BRAINLIEST if I am RIGHT

379.

find the equation of the circle whose centre lies on the line x-4y =1 and which passes through (3,7),(5,5)​

Answer»

Step-by-step EXPLANATION:

please follow me THANKS to me and mark me BRAINALIST

380.

R1 000 is invested at 10% simple interest for three years and R1 000 is invested at 8% compounded annually for three years. Which is a better investment and by how much?

Answer»

ANSWER:

Simple INTREST =(Principal *rate *time)/100

Compound Interest= principle (1+R/100)^time

put the values in the FORMULA you will get the amount which you have to SUBTRACT from principle and the REMAINING amount which is higher will be better

381.

Write a suitable digit in the units place to make it divisible by 2.(i) 197_(ii) 1235_ (iii) 9655_ (iv) 1999_​

Answer»

ANSWER:

1

is the RIGHT answer PLEASE CHECK it

382.

Given 1 cubic metre = 1 000 litres, how many litres of water will be required to fill an empty swimming pool so that it gets to a level of 2m in height? The length of the pool is 600cm and the breadth is 0.004km. Volume is length x breadth x height. Please take care when converting your units.

Answer»

Answer:

1.for making the text look coloured refer the below syntax and ignore the dots

[.tex]\red{the\:text\:appears\:in\:red}[./tex]

result

\red{the\:text\:appears\:in\:red}thetextappearsinred

2.for making the text MARQUEE

[.tex]{the\:text\:appears\:like\:this}[./tex]

result

= < marquee > {the\:text\:appears\:like\:this} < /marquee > thetextappearslikethis

3. for making the text look BOLD

[.tex]\bold{the\:text\: appears\: like\: this }[./tex]

result =

\bold{the\:text\: appears\: like\: this }thetextappearslikethis

4. for showing the exponential value

[.tex]{no.}^{POWER}[./tex]

result

= {no.}^{power}[ /tex] 5. for showing the SQUARE ROOT value [.tex]\sqrt{no.}[./tex] result = \sqrt{no.}no. power5.forshowingthesquarerootvalue[.tex]

no.

[./tex]result=[tex]

no.

\bold{\boxed{thanx}}

thanx

follow me next

383.

7×5×3×2+3 a Compositenumber? Justify youranswer?​

Answer»

Step-by-step explanation:

A COMPOSITE has more than TWO factors other than itself.

7∗5∗3∗2+3

=3(7∗5∗2+1)=3∗(70+1)=3∗71

The given NUMBER has two factors 3 and 71.

∴ It is a composite number.

384.

Find the area of the iron sheet required to prepare a cone 24cm hight with base radious 7cm?​

Answer»

Step-by-step explanation:

AREA of IRON sheet = TSA of cone.

=> TSA of cone = πr(L+r)

l = 25

=> TSA= 703.7cm^2

.•. area of iron sheet REQUIRED is 703.7 cm^2

385.

A farmer has a rectangular field of length and breadth 240 m and 180 m respectively. Hewants to fence it with 3 rounds of rope. What is the total length of rope he must use?​

Answer»

The farmer has to cover THREE times the perimeter of that field.

Therefore,

Total length of ROPE REQUIRED is thrice its perimeter.

Perimeter of the field = 2 × (length + BREADTH)

Perimeter of the field = 2 × (240 m + 180 m)

Perimeter of the field = 2 × 420 m

Perimeter of the field = 840 m

____________________

Total length of rope required = 3 × 840 m

Total length of rope required = 2520 m

386.

A square fence encloses a circle. Calculate the area of the circle in m2 if the area of the square is 800 m2. The area of a circle is Pi x r2. Pi can be taken as 22/7.

Answer»

Step-by-step EXPLANATION:

AREA of square=a²

800=a²

a=20√2

radius of a circle=half the SIDE of a square

r=20√2/2

r=10√2

area of circle=πr²

a=22/7*(10√2)²

a=628.57m²

387.

Whats the product of the 3rd square number

Answer»

ANSWER:

....................................................

Step-by-step EXPLANATION:

388.

Composite number? Jutsfy you་ནང་answer​

Answer»

Step-by-step EXPLANATION:

in which LANGUAGE it is

389.

What are the measures of the four angles in the figure?

Answer»

Answer:

HEY MATE!

2x + x - 12 = 180

3x -12=180

3x= 180+12=192

x= 192÷3= 64

so we get first angle 2x= 64×2=128 degree

and

SECOND angle x-12 = 64-12=52 degree

Now, 3Y +y+20=180

so, 4y+20=180

4y=180-20=160

y=160÷4 = 40

so we get third angle 3y= 40×3= 120 degree

and

FOURTH angle y+20= 40+20=60 degree

hope this helps you

pls mark it as brain list

❤❤

390.

If y = 7x − 5, which of the following sets represents possible inputs and outputs of the function, represented as ordered pairs? (5 points) a {(−5, 0), (9, 2), (−26, −3)} b {(2, 7), (1, 6), (3, 13)} c {(0, −5), (2, 9), (−3, −26)} d {(1, 3), (6, 18), (8, 15)}

Answer»

ANSWER:

hsjdjssmsmsms

msmmsmamssm

nsnsmsmsnsnssmsm

25i85eery0itdicm.ug70gpgi UGGS G 9vu V i uogxuoxi0gzi0gxiogd

bsbwvegeveveicpe g7e 7g9 e96f e9u9gegu9 g0ieig9eeu9g

391.

pinky runs around a square field of side 75 m bob runs around a rectangular field with length 160m and breadth 105m who cover more distance and by how much​

Answer»

DISTANCE covered by PINKY in one round = Perimeter of the square

Distance covered by Pinky in one round = 4 × length of a side

Distance covered by Pinky in one round = 4 × 75 m

Distance covered by Pinky in one round = 300 m

_____________________

Distance covered by Bob in one round = Perimeter of the rectangle

Distance covered by Bob in one round = 2 × (length + breadth)

Distance covered by Bob in one round = 2 × (160 m + 105 m)

Distance covered by Bob in one round = 2 × 265 m

Distance covered by Bob in one round = 530 m

____________________

Difference in the distance covered = 530m - 300m

Difference in the distance covered = 230 m

Therefore:-

Bob covers more distance by 230 m.

392.

Gini has three times as many stickers as Bala how many stickers does Bala have​

Answer»

Answer:

if Gini has 3x stickers then Bala have X stickers...

Step-by-step explanation:

please mark me the branliest also please follow me...

MARRY Christmas in advance...stay safe and happy and healthy...

lots of LOVE for you and your FAMILY...❤️♥️

393.

Vijay wants to cover the floor of a room 3 m wide and 4 metre long by square tiles if each square tile in side 0.5 then the number of tiles required to cover the floor of the room​

Answer»

TOTAL AREA of tiles MUST be equal to the area of the floor of the ROOM.

Length of the room = 4 m

Breadth of the room = 3 m

Formula used:-

Area of the floor = length × breadth

Putting the values according to the formula:

=> Area of the floor = 4 m × 3 m

=> Area of the floor = 12 sq m

Area of one square tile = Side × Side

=> Area of one square tile = 0.5 m × 0.5 m

=> Area of one square tile = 0.25 sq m

Number of tiles required = Area of the floor/Area of one tile

=> Number of tiles required = 12/0.25

=> Number of tiles required = 1200/25

=> Number of tiles required = 48 tiles

Hence:-

The number of tiles required to cover the floor of the room is 48 tiles.

394.

Is there any possibility of reopening of colleges for class 11, in December. ​

Answer»

ANSWER:

no way

for which STATE are U ASKING

395.

The product of two fractions is 6. if one fraction is 5/3,find the other​

Answer»

Answer:

18/5

Step-by-step EXPLANATION:

LET the other fraction be x/y

Acc to the condition

\frac{5}{3}  \times  \frac{x}{y}  = 6

\frac{x}{y}  =  \frac{3 \times 6}{5}

\frac{x}{y}  =  \frac{18}{5}

Therefore the other fraction is 18/5 or an EQUIVALENT fraction of 18/5 for eg 36/10, 72/15, ETC

396.

1. If Zw= 62°, find Zx, Zy and Zz.WXNy​

Answer»

ANSWER:

hsjsjksksksksksksjhsbdhdhdjd

397.

Solve the given integral with explanation​

Answer»

ANSWER:

OK PLEASE FOLLOW me........

398.

Q6. Find the area in square metre of a piece of cloth 1 metre 25 cm wideand 2 metre long.​

Answer»

Length of the cloth = 2 m

Breadth of the cloth = 1 m 25 m

Breadth of the cloth = 1 m + 0.25 m

Breadth of the cloth = 1.25 m

(Since 25 cm = 0.25 m)

Area of the cloth = length of the cloth × BREATH of the cloth

=> Area of the cloth = 2 m × 1.25 m

=> Area of the cloth = 2.50 sq m

Hence:-

The area of the cloth is 2.50 sq m.

More Information:

The amount of surface enclosed by a closed figure is CALLED its area.

To calculate the area of a figure using a squared paper, the following CONVENTIONS are adopted:

IGNORE portions of the area that are less than half a square.

If more than half a square is in a region. Count it as one square.

If exactly half the square is COUNTED, take its area as ½ sq units.

Area of a rectangle = length × breadth

Area of a square = Side × Side

399.

A radio tower is 87 feet tall. Find the angle of elevation to the top of the tower at a point on level ground 46 feet from its base. Round your answer to the nearest degree.

Answer»

ANSWER:

By using formula θ = atan (H / d) answer=62.133

Step-by-step explanation:

400.

What is the magnitude of force required to accelerate a car of mass1.7 × 103 kilograms by 4.75 meters/second2?​

Answer»

Given Information:-

The mass of the car is 1.7 × 10³ KILOGRAMS by 4.75 meters/second²

Need to find out:-

The magnitude of force REQUIRED to ACCELERATE a car = ?

Formula USED:-

Force = Mass × Acceleration

F = M × A

Putting the values ACCORDING to the formula:-

=> Magnitude of Force = 1.7 × 10³ × 4.75

=> Magnitude of Force = 1.7 × (10 × 10 × 10) × 4.75

=> Magnitude of Force = 1.7 × 1000 × 4.75

=> Magnitude of Force = 1.7 × 475

=> Magnitude of Force = 17 × 475

=> Magnitude of Force = 8075 Newton

Hence:-

The magnitude of force required to accelerate a car is 8075 Newton.