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151.

What is a diode?

Answer»

Diode is a combination of n- type and p- type semiconductors. It is used as a rectifier.

152.

How will you distinguish between the following pairs of terms:(i) Hexagonal close-packing and cubic close-packing?(ii) Crystal lattice and unit cell?(iii) Tetrahedral void and octahedral void?

Answer»

(a) Cubic close packing: When a third layer is placed over the second layer in a manner that the octahedral voids are covered by the spheres, a layer different from the first (A) and second (B) is obtained. If we continue packing in this manner we get the cubic close packing.

Hexagonal close packing: When the third layer is placed over the second layer in a way that the tetrahedral voids are covered by the spheres, a 3D close packing is produced where spheres in each third or alternate layers are vertically aligned. If we continue packing in this order we get hexagonal close packing.

(b) Unit cell: It is the smallest 3D dimensional portion of a complete space lattice, which when repeated over and over again in different directions from the crystal lattice.

Crystal lattice – it is a regular orientation of particles of a crystal in a 3D space.

(c) Octahedral void – it is a void surrounded by 6 spheres.

Tetrahedral void – it is a void surrounded by 4 spheres.

153.

(i) What is meant by the term ‘coordination number’?(ii) What is the coordination number of atoms:(a) in a cubic close-packed structure?(b) in a body-centred cubic structure?

Answer»

(i) Coordination number is the number of nearest neighbours of a particle.

(ii) 

(a) coordination number =12

(b) coordination number = 8

154.

What is forbidden zone?

Answer»

The space between valence band and conduction band represent energies forbidden to electrons are called forbidden zone.

155.

Which of the following statements is TRUE? (A) In metals, the forbidden zone is very small and in insulators, the forbidden zone is very large.(B) Forbidden zone is very large in metals and insulators.(C) Forbidden zone is very small in metals and insulators.(D) In metals, the forbidden zone is very large and in insulators, the forbidden zone is very small.

Answer»

Correct answer is: (A) In metals, the forbidden zone is very small and in insulators, the forbidden zone is very large.

156.

Write a note about metallic solids.

Answer»

1. In metallic solids, the lattice points are occupied by positive metal ions and a cloud of electrons pervades the space.

2. They are hard and have high melting point.

3. Metallic solids possess excellent electrical and thermal conductivity. They possess bright lustre. 

4. Examples – Metals and metal alloys Cu, Fe, Zn, Ag, Ay, Cu – Zn etc.

157.

Why are solids rigid?

Answer»

In a solid, the constituent particles are very closely – packed. Hence, the forces of attraction among these particles are very strong, that is why they are rigid.

158.

How can a student join Solid State Class 12  Mock Tests?

Answer»

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159.

What is a lattice point?

Answer»

Lattice point : A position occupied by a crystal constituent particle like an atom, ion or a molecule in the crystal lattice is called lattice point or lattice site.

OR 

Any point at the intersection of the lines in the unit cell occupied by a constituent particle like an atom, an ion or a molecule in the crystalline solid is called a lattice point.

160.

What is meant by piezo electricity?

Answer»

Piezo electricity is the appearance of an electrical potential across the sides of a crystal. When you subject it to mechanical stress. The word piezo electricity means electricity resulting from pressure and latent heat. Even the inverse is possible which is known as inverse piezo electric effect.

161.

Cubic crystal has dimensions.............(A) a \(\neq\) b \(\neq\) c, \(\alpha\) = \(\beta\) = 90\(^\circ\), \(\gamma\) \(\neq\) 90\(^\circ\)(B) a = b = c, \(\alpha\) = \(\beta\) = \(\gamma\) = 90\(^\circ\) (C) a = b \(\neq\) c, \(\alpha\) = \(\beta\) = \(\gamma\) = 90\(^\circ\) (D) a \(\neq\) b \(\neq\) c, \(\alpha\) \(\neq\) \(\beta\) \(\neq\) \(\gamma\) \(\neq\) 90\(^\circ\)

Answer»

Correct answer is: (B) a = b = c, \(\alpha\) = \(\beta\) = \(\gamma\) = 90\(^\circ\) 

162.

TiCl has structure similar to CsCl, the coordination number of Ti^+ is..............(A) 4(B) 6(C) 10(D) 8

Answer»

Correct answer is: (D) 8

163.

For an ionic crystal of the type AB, the value of (limiting) radius ratio is 0.40. The value suggests that the crystal structure should be........(A) octahedral(B) tetrahedral(C) square planar(D) planar triangular

Answer»

Correct answer is: (B) tetrahedral

164.

Schottky defect is shown by......... (A) strongly ionic compounds(B) compounds having high coordination number(C) compounds containing cations and anions of almost similar size(D) all of these

Answer»

Correct answer is: (D) all of these

165.

In the unit cell of NaCl lattice, there are ..........(A) 3 Na+ ions(B) 6 Na+ ions(C) 6 Cl– ions(D) 4 NaCl units

Answer»

Correct answer is: (D) 4 NaCl units

166.

State any three differences between Schottky and Frankel defect?

Answer»

Schottky defect

I. It occurs due to missing of equal no of cations and anions from lattice point.

II. It decreases the density of the crystal.

III. It occurs in compounds with high Co-ordination number.

             OR

It occurs in compounds in which cations and anions are of similar size.

Examples: NaCl, KCl, KBr, Ag Br CsCl.

Frankel defect

I. It occurs due to missing of cations from their lattice point and occupies interstitial sites

II. It does not decrease the density of the crystal.

III. It occurs in compounds with low Co-ordination number.

               OR

It occurs in compounds in which cations and anions differ in their size to a large extent.

Examples: ZnS, AgCl, AgBr, Agl.

167.

Write two examples of amorphous solids.

Answer»

 Rubber and quartz glass are examples of amorphous solids.

168.

Name two metals which have cubic close packed structure. 

Answer»

Silver (Ag) and copper (Cu) have cubic close packed structure.

169.

Atoms C and D form fcc crystalline structure. Atom C is present at the corners of the cube and D is at the faces of the cube. What is the formula of the compound?

Answer»

Given: Atoms C and D form fcc lattice.

C is present at corners of the cube.

D is at the faces of the cube.

To find: Formula of the compound

Calculation: As C is present at the 8 corners of the cube, number of atoms of C in the unit cell\(=\frac{1}{8}\times8=1\)

As D atoms are present at the face centres of the 6 faces of the cube, the number of atoms of D in the unit cell =\(=\frac{1}{2}\times6=3\)

\(\therefore\) Ratio of atoms C : D = 1 : 3.

Ans: The formula of the compound is CD3.

170.

An element A and B constitute bcc type crystalline structure. Element A occupies body centre position and B is at the corners of cube. What is the formula of the compound? What are the coordination numbers of A and B?

Answer»

Given: Elements A and B form bcc lattice.

Element A occupies body centre position and B is at the corner.

To find: Formula of the compound Coordination numbers of A and B

Calculation: As atoms B are present at the 8 corners of the cube, number of atoms of B in the unit cell =\(\frac{1}{8}\times8=1\)

As atoms A are present at the body centre, number of atoms of A in the unit cell = 1

\(\therefore\) Ratio of A : B = 1 : 1

\(\therefore\) Formula of the compound = AB

Coordination number of A occupying body centre position = 8

Coordination number of B at corners of the cube = 8

Ans: The formula of the compound is AB.

Coordination number of each A and B is 8.

171.

Define F- Centers.

Answer»

The anionic vacancies occupied by unpaired electrons. 

F-centers impart colour to the crystals (Eg. NaCl toYellow, KCl to violet) due to excitation of these electrons by absorbing energy from the visible light falling on the crystals. 

172.

Which of the following is a crystalline solid? (A) Tar(B) Butter(C) Glass(D) Common salt

Answer»

Correct answer is: (D) Common salt

173.

Among the following, which crystal will be soft and has low melting point?(A) Covalent(B) Ionic(C) Metallic(D) Molecular

Answer»

Correct answer is: (D) Molecular

174.

Which of the following statement is TRUE?(A) Solid changes into liquid on heating to its melting point.(B) Liquid changes into gas, on cooling to its freezing point.(C) Liquid changes into solid, on heating to its boiling point.(D) Solid changes into gas, on heating to its melting point.

Answer»

Correct answer is: (A) Solid changes into liquid on heating to its melting point.

175.

Distinguish between ionic solids and molecular solids.

Answer»
Type/ PropertyIonic solidsMolecular solids
1. Particles of unit cellCations and anionsMonoatomic or polyatomic molecules
2. Interparticle forcesElectrostaticLondon, dipole-dipole forces and/or hydrogen bonds
3. HardnessHard and brittleSoft
4. Melting pointsHigh 600°C to 3000°CLow (-272°C to 400°C)
5. Thermal and electrical conductivityPoor electrical conductors in solid state. Good conductors when melted or dissolved in water.Poor conductor of heat and electricity
6. ExamplesNaCl, CaF2ice, benzoic acid
176.

For a solid with the structure as shown in the figure, the coordination number of the point B is ..............(A) 3(B) 4(C) 5(D) 6

Answer»

Correct answer is: (D) 6

177.

In fullerene, carbon atoms are ........... hybridized.(A) sp(B) sp2(C) sp3(D) sp3d

Answer»

Correct answer is: (B) sp2

178.

The maximum percentage of available volume that can be filled in a face centered cubic system by an atom is........(A) 74%(B) 68%(C) 34%(D) 26%

Answer»

Correct answer is: (A) 74%

Total volume of unit cell = 8\(\sqrt{8}r^3\)

Volume occupied = \(\cfrac{16}{3}\pi r^3\)

\(\therefore\) Packing efficiency =\(\cfrac{16}{3}\pi r^3\)\(\times\)\(\cfrac{1}{8\sqrt{8}r^3}\times100\)

= 74.0 %

179.

Which of the following is an example of ionic crystal solid?(A) Diamond(B) LiF(C) Li(D) Silicon

Answer»

Correct answer is: (B) LiF

180.

Body centred cubic lattice has a coordination number of ............(A) 4(B) 8(C) 12(D) 6

Answer»

Correct answer: (B) 8

181.

In body centred cubic structure the space occupied is about............(A) 68%(B) 53% (C) 38%(D) 32%

Answer»

Correct answer: (A) 68%

182.

What is Packing efficiency? 

Answer»

The percentage of total space filled by the particles in a crystal. 

Example: Packing efficiency of BCC structure = 68%.

183.

The number of close neighbour in a body centered cubic lattice of identical sphere is ..........(A) 8(B) 6(C) 4(D) 2

Answer»

Correct answer is: (A) 8

184.

The interionic distance for caesium chloride crystal will be ............(A) a (B) \(\cfrac{a}{2}\)(C) \(\cfrac{\sqrt{3}a}{2}\)(D) \(\cfrac{2a}{\sqrt{3}}\)

Answer»

Correct answer is: (C) \(\cfrac{\sqrt{3}a}{2}\)

185.

What is the Co.No. of cation and anion in Caesium Chloride?

Answer»

The Co-ordination No. of cation and anion in Caesium Chloride is 8 and 8.

186.

Experiment shows that Nickel oxide has the formula Ni096 O1.00 . What fraction of Nickel exists as of Ni2+ and Ni3+ ions ?

Answer»

Let the number of Ni2+ . Then the number of Ni3+ ion will be = (0.96 – x). 

Total number of cation, = 2 x + 3 (0.96 – x) 

= 2x + 2.88 – 3x 

= ( – x) + 2.88

Number of anions O2- ( – 2) x 1 = -2. Number of cations = Number of anions – x + 2.88 2

– x = – 2.88 + 2

x = 0.88

 % of Ni as Ni2 = \(\frac{0.08}{0.96}\times 100\) = 91.66% 

Number of Ni3+ ion will be = 0.96 – x 

= 0.96 – 0.88 = 0.08 

% of Ni as Ni3+ =   \(\frac{0.08}{0.96}\times 100\)  = 8.3 %

187.

What is the two-dimensional coordination number in square close packed layer?

Answer»

In square close packing , each atom is in contact with four neighbouring atoms, so its coordination number is 4.

188.

In face centred cubic unit cell, the edge length is ..........(A) \(\cfrac{4}{\sqrt{3}}r\)(B) \(\cfrac{4}{\sqrt{2}}r\)(C) 2r(D) \(\cfrac{\sqrt{3}}{2}r\)

Answer»

Correct answer is:  (B) \(\cfrac{4}{\sqrt{2}}r\)

189.

A compound is made up of two elements M and N. The element N forms ccp and atoms of M occupy \(\frac { 1 }{ 3 }\)rd of tetrahedral voids. What is the formula of compound?

Answer»

Let the atoms N in cep = x
No of tetrahedral voids = 2x
As \(\frac { 1 }{ 3 }\) rd of the tetrahedral voids are occupied by atoms M,
Hence, no. of atoms of M = \(\frac { 2x }{ 3 }\)
Ratio of M:N = 20 : \(\frac { 2x }{ 3 }\) = 2:3
Hence formula of compound is M2 N3

190.

Na and Mg crystallize in bcc and fcc type crystals respectively, then the number of atoms of Na and Mg present in the unit cell of their respective crystal is.........(A) 4 and 2(B) 9 and 14(C) 14 and 9(D) 2 and 4

Answer»

Correct answer: (D) 2 and 4

191.

What is a glass?

Answer»

i. Silicon dioxide is fused with sodium oxide and boron oxide to form an optically transparent material known as glass. The colour of glass is due to addition of a trace amount of transition metal oxide.

ii. Different types of glass are manufactured by changing its composition. Almost eight hundred different types of glasses are manufactured. Quartz glass is obtained from only silicon dioxide.

iii. Pyrex glass is obtained by fusing together 60 to 80% SiO2, 10 to 25% B2O3 and remaining amount of Al2O3.

iv. When 75% SiO2 is fused with 15% Na2O and 10% CaO, sodalime glass is obtained.

v. Red glass contains trace amount of gold and copper. Yellow glass contains UO2.

vi. Blue glass contains CoO or CuO. Green glass contains Fe2O3 or CuO.

192.

Describe the term “amorphous’. Give a few examples of amorphous solids.

Answer»

Amorphous solids are those solids in which the constituent particles may have a short range order, have irregular shape and isotropic in nature. They do not show clean cleavage. They do not have sharp melting points and do not have definite heat of fusion.

Examples: glass, plastics and rubber etc.

193.

Classify the following as amorphous or crystalline solids: Polyurethane, naphthalene, benzoic acid, teflon, potassium nitrate, cellophane, polyvinyl chloride, fibre glass, copper.

Answer»

Amorphous solids: Polyurethane, teflon, cellophane, polyvinyl chloride, fibre glass. Crystalline solids: Benzoic acid, potassium nitrate, copper, naphthalene.

  1. -Crystalline solids are also known as true solids and amorphous solids are also known as pseudo solids or supercooled liquids.
  2. So Polyurethane is an amorphous solid.
  3. Naphthalene is a crystalline solid.
  4. Benzoic acid is a crystalline solid.
  5. Teflon is an amorphous solid.
  6. Potassium nitrate is a crystalline solid.
  7. Cellophane is an amorphous solid.
  8. Polyvinyl chloride is an amorphous solid.
  9. Fiberglass is an amorphous solid.
  10. Copper is a crystalline solid.
194.

Define line defect.

Answer»

The defect due to irregularity in a complete line, i.e., a row of lattice points of constituent particles is called line defect.

195.

What type of defect can arise when a solid is heated ?

Answer»

Vacancy defect.

196.

Why does crystal defect arise?

Answer»

The defect may arise due to the heat absorbed by the crystals from the surrounding or due to the presence of impurities in the crystals and also due to the irregularities in the arrangement of constituent particles. When the rate of crystallisation is fast, more defects are present. When the rate of crystallisation is slowest, the defects are minimized. The physical and chemical properties of crystalline solids are affected due to presence of crystal defects

197.

Define crystal defect

Answer»

Any deviation or irregularity from the perfectly ordered arrangement of constituent particles in crystal is called crystal imperfection or defect.

198.

Explain how to deduce coordination number of cations.

Answer»

i. The coordination number of constituent particle of the crystal lattice is the number of particles surrounding a single particle in the crystal lattice. 

ii. In case of ionic crystals, coordination number of an ion in the crystal is the number of oppositely charged ions surrounding that ion. 

iii. The stoichiometry and the size of the cation and anion determines the structure of ionic compounds. 

iv. In ionic solids, the bigger ions (usually anions) form close packed structure and smaller ions (usually cations) occupy the voids. If the latter ion is small enough then tetrahedral voids are occupied; but if it is bigger, then octahedral voids are occupied. Generally, for an ionic crystalline structure to be stable, there is definite radiusratio (r+ /r- ) limit for a cation to fit perfectly in the lattice of anions. This also defines the coordination number of the cation. 

v. The limiting values of r+/r- for the coordination number and the hole occupied by the cation are given in the following table:

Coordination number of cationLimiting value of r+ /r-Type of hole occupiedExample
30.155 to 0.225Planar triangulaB2O3
40.225 to 0.414TetrahedralZnS
60.414 to 0.732OctahedralNaCl
8> 0.732CubicCsC

199.

Write a note on radius ratio rule of ionic compounds.

Answer»

i. The stoichiometry and the size of the cation and anion determines the structure of ionic compounds.

ii. Smaller cations occupy tetrahedral voids and bigger cations occupy octahedral voids or cubic voids.

iii. The coordination number of the ion also determines the geometry of the unit cell.

iv. The ratio of the radius of the cation (r+ ) to the radius of the anion (r- ) is the radius ratio \(\left(\cfrac{r^+}{r^-}\right)\). For a given coordination number, the radius ratio has a limiting value.

v. The ionic structure is unstable when the radius ratio is less than the expected value.

vi. By using radius ratio rule, the structures of ionic solids can be predicted. This rule is not applicable to covalent compounds.

200.

What is coordination number? What is its significance?

Answer»

(1) Coordination number : The number of the closest neighbouring constituent particles like atoms, ions or molecules which are in contact with a particular particle or an atom in the crystal lattice is called coordination number of that particle.

(In the crystal lattice, all atoms may have same or different coordination numbers.)

(2) The magnitude of the coordination number is a measure of compactness of spheres in close-packed structures.

(3) The higher the coordination number, the closer are the spheres to each other.