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951.

Explain the relation between osmotic pressure and concentration of solution.

Answer»

(1) Consider V dm3 of a solution in which n1 moles of a solvent contains n2 moles of a nonvolatile solute at absolute temperature T.

(2) The osmotic pressure, n of a solution is given by,

π = \(\frac{nRT}{V}\)

R is gas constant having value 0.08206 dm3 atm K-1 mol-1 (OR L atm K-1 mol-1). Since concentration, C of a solution is in mol dm-3 or molarity is,

C = \(\frac{n}{V}\) mol dm-3 or M 

∴ π = CRT

(If concentration C is expressed in mol-3 m and R = 8.314 J K-1 mol-1, then π will be in SI units, pascals or Nm-2)

952.

What do you understand by the terms : (1) permeable membrane (2) semipermeable membrane?

Answer»

(1) Permeable membrane : A membrane which allows free transfer of the solute molecules from a solution of a higher concentration to a solution of a lower concentration through it is called a permeable membrane and the transfer is called diffusion, e.g., a membrane of a paper.

(2) Semipermeable membrane : A membrane which allows free passage of only the solvent molecules but not the large solute molecules or ions of large molecular mass from a solution of a lower concentration (or a pure solvent) to a solution of higher concentration through it, is called a semi-permeable membrane, 

e.g., parchment paper, complex like Cu2[Fe(CN)6], etc.

953.

Osmotic pressure of a solution isA. Directly proportional to the molar concentration of the solution.B. Inversely proportional to the molecular weight of the solue.C. Inversely proportional to the temperature.D. Directly proportional to the volume of the solution.

Answer» Correct Answer - A::B
`pi=CRT rArr pi = (n_(2)RT)/V = (W_(2)RT)/(Mw_(2)V)`
954.

Which of the following statements is/are correct?A. Minimum boiling azeotropic mixtue boils at temperature lower than either of the two pure components.B. Maximum boiling azeotropic mixtue boils at temperature higher than either of the two pure components.C. Minimum boiling azeotropic mixture shows positive deviation.D. Maximum boiling azeotropic mixture shows negative deviation.

Answer» Correct Answer - A::B::C::D
955.

In non-ideal solutions, at one of the intermediate compositions, the total vapour pressure is highest and the boiling point is lowest. At this point, the composition of the liquid and vapour phase is same. So, if liquid mixture vapourises at this point and vapours are condensed, the condensate contains same composition as present in orginal liquid mixture. It means that at this point liquid behaves like a pure and is called as Azeotropic mixture. Choose the correct answer : A and B form non-ideal solution showing positive devialtion. Boiling point of pure A and B are 350 K and 380 K repectively. The solution will boil at (approximate )A. `250 K`B. `380 K`C. `gt 380 K`D. `lt 350 K`

Answer» Correct Answer - d
it is corrct answer.
956.

For a non-volatile soluteA. The vapour pressure of a solute is zero.B. Vapour pressure of solution = Vapour pressure of pure solvent.C. Vapour pressure of solution = Vapour pressure of pure solvent in solution.D. All of these

Answer» Correct Answer - A::C
957.

A solution having the highest vapour pressure is :(a) 1 M Al2(SO4)3(b) 0.1 M NaNO3(c) 1 M BaCl2(d) 1 M Ca(NO3)2

Answer»

Option : (b) 0.1 M NaNO3

958.

Compreshension-II In non-ideal solutions, at one of the intermediate compostions, the total vapour pressure is highest and the boiling point is lowest. At this point, the composition of the liquid and vapour phase is same. So, if liquid mixture vapouriese at this point and vapours are condensed, the condensate contains same compositon as present in original liquid mixture. it means at this point liquid behaves like a pure liquid and is called an Azeotropic mixture. A and B forms non-ideal solution showing positive deviation. Boiling point of pure A and B is 350 K and 380 K respectively. The solution will bpoil at (approximate)A. 250 KB. 380 KC. `gt 380 K`D. `lt 350 K`

Answer» Correct Answer - 4
959.

In non-ideal solutions, at one of the intermediate compositions, the total vapour pressure is highest and the boiling point is lowest. At this point, the composition of the liquid and vapour phase is same. So, if liquid mixture vapourises at this point and vapours are condensed, the condensate contains same composition as present in orginal liquid mixture. It means that at this point liquid behaves like a pure and is called as Azeotropic mixture. Choose the correct answer : (22) Which of the following cannot form minimum boiling azeotrope ?A. n-heptane & n-hexaneB. Acetone & anilineC. Both (a) & (b)D. `CHCI_(3)&C_(2)H_(5)OH`

Answer» Correct Answer - c
it is corrct answer.
960.

Molal elevation constant is elevation in boiling point produced by :(a) 1 g of solute in 100 g of solvent (b) 100 g of solute in 1000 g of solvent (c) 1 mole of solute in one litre of solvent (d) 1 mole of solute in one kg of solvent

Answer»

Option : (d) 1 mole of solute in one kg of solvent

961.

Which of the following solutions will have the highest boiling point?A. `0.1M FeCI_(3)`B. `0.1M BaCI_(2)`C. `0.1M NaCI`D. `0.1M` urea `(NH_(2)CONH_(2))`

Answer» Correct Answer - D
Except for urea (a non electrolyte) the ionisation of `FeCI_(3),BaCI_(2),NaCI` can be represented as follows
`FeCI_(3) rarr Fe^(3+) +3CI^(-)`
`BaCI_(2) rarr Ba^(2+)+2CI^(-)`
`NaCI rarr Na^(+)+CI^(-1)`
As number of particles (ions) produced is maximum in `FeCI_(3)` the elevation in boiling point (a colligative property) will be maximum in case of `FeCI_(3)`.
962.

The determination of molar mass from elevation in boiling point is called :(a) cryoscopy (b) osmometry (c) ebullioscopy (d) spectroscopy

Answer»

Option : (c) ebullioscopy

963.

Which one of the following solutions exhibits the maximum elevation in boiling point?A. `0.1m NaCI`B. `0.1m CaCI_(2)`C. `0.1m BaCI_(2)`D. `0.1m FeCI_(3)`

Answer» Correct Answer - D
Greater the number of ions (particles) greater will be elevation in boiling point.
964.

Which of the following is a colligative property?A. Change in free energyB. Dipole momentC. Heat of vaporisationD. Osmotic pressure.

Answer» Correct Answer - B
Only osmotive pressure is dependent upon number of solute molecules.
965.

Choose the correct statementA. The boiling point of the solution falls on increasing the amount of the soluteB. The freezing point of the solution is lowered on adding more of solventC. The freezing point of the solution is raised on adding more of soluteD. The freezing point of the solution decreases on increasing the amount of the solute.

Answer» Correct Answer - D
ore the solute, more is the depression in F.P., lower the freezing point of the solution.
966.

200 cm3 of an aqueous of a protein contains 1.26 g of the protein. The osmotic pressure of such a solution at 300 K is found to be 2.57 × 10-3 bar. Calculate the molar mass of the protein.

Answer»

\(\pi = \frac{W_BRT}{M_BV}\)

\(M_B= \frac{W_BRT}{\pi V}\)

\(\frac{1.26\,g\,\times\,0.083\,L\,bar\,K^{-1}\,mol^{-1}\times300\,K}{2.57\times10^{-3}\,bar\times0.2\,L}\)

= 61,039 g mol-1

967.

3 moles of P and 2 moles of Q are mixed , what will be their total vapour pressure in the solution if their partial vapour pressures are 80 and 60 torr respectively ?A. 80 torrB. 140 torrC. 72 torrD. 70 torr

Answer» Correct Answer - C
Mole fraction of P = `3/(3+2)`=0.6
Mole fraction of Q =`2/(3+2)`=0.4
`P_"total"=p_P+p_Q=p_P^@ x_P+p_Q^@x_Q`
=80 x 0.6 + 60 x 0.4 = 72 torr.
968.

Solubility of a gas in a liquid solvent increases withA. decrease of pressure as well as temperatureB. increase of pressure and decrease of temperatureC. decrease of perssure and increase of temperatureD. increase of pressure as well as temperrature

Answer» Correct Answer - 2
Changing the pressure has no appreciable effect on the solubilites of either solids or liquids in liquids. However, the solubilitier of gases in all liquid solvents increase as the partial pressures of the gases increase.
A carbonated benerage is produced by dissolving `CO_(2)(g)` in beverage solution under pressure. More `CO_(2)(g)` dissolves at the higher pressure than otherwise. When we open a can of carbonated drink, undissolved `CO_(2)(g)` escapes and the bubbles of excess dissolved `CO_(2)(g)` immediately come fizzing of solution because the pressure of undissolved `CO_(2)` in the can drops and hence `CO_(2)(g)` suddenly becomes less soluble.
The solibility of gases in water usually decreases with increasing remperature. One consequence of this decreased solubility is that carbonated drinks bubble continously as they warm up to room temperature after being refrigerated. Soon, they lose so much dissolved `CO_(2)` that they become "flat". A much more important consequence is the damage to aquatic life that can result from the decrease in concentration of dissolved `O_(2)(g)` in lakes and rivers when hot `H_(2)O` is discharged from industrial plants, an effect known as thermal pollution.
969.

Calculate osmotic pressure of a solution obtained by mixing `100 mL` of `3.4%` solution "(weight/volume)" of urea "(molecular weight 60)" and `100 mL` of `1.6%` solution "(weight/volume)" of cane sugar "(molecular weight 342)" at `20^(@)C`.

Answer» No. of moles of urea `= (3.4)/(60)=0.0567`
No. of moles of can sugar `=(1.6)/(342)=0.0047`
Total number of moles `=(0.0567+0.0047)=0.0614`
Total volume of solution `= (100+100)=200` mL
`=0.1` litre
PV = (Total number of moles) `xx S xx T`
`P=(0.0614)/(0.2)xx0.0821xx293=7.385`atm.
970.

Assertion:At equilibrium , vapour phase will be always rich in component which is more volatile Reason : The composition of vapour phase in equilibrium with the solution is determined by the partial pressures of the componentsA. If both assertion and reason are true and reason is the correct explanation of assertionB. If both assertion and reason are true but reason is not the correct explanation of assertion.C. If assertion is true but reason is falseD. If both assertion and reason are false

Answer» Correct Answer - A
971.

In a mixture of A and B components show negative deviation whenA. A-B interaction is stronger than A-A and B-B interactionB. A-B interaction is weaker than A-A and B-B interactionC. `DeltaV_(mix) gt 0, DeltaS_(miax) gt 0`D. `DeltaV_(mix) = 0, DeltaS_(mix) gt 0`

Answer» Correct Answer - A
972.

Which has the highest freezing point:A. `1M` glucoseB. `1M NaCl`C. `1M CaCl_(2)`D. `1 M AIF_(3)`?

Answer» (a) `1 M` glucose solution has highest freezing point because it has lowest `DeltaT_(f)`.
973.

Vapour pressure of solution of a nonvolatile solute is always :(a) equal to the vapour pressure of pure solvent (b) higher than vapour pressure of pure solvent (c) lower than vapour pressure of pure solvent (d) constant

Answer»

Option : (c) lower than vapour pressure of pure solvent.

974.

For an ideal solution containing a nonvolatile solute, which of the following expression represents the vapour pressure of the solute ? `(x_(1)rarr` mole fraction of solvent)A. `p = x_(2) p_(2)`B. `p = x_(1)p_(2)`C. `p = x_(1)p_(1)`D. `p_(1) - p = x_(2)`

Answer» Correct Answer - C
975.

The concentration term used when the solute is present in trace quantities is _______

Answer»

ppm (parts per million)

976.

Molarity of liquid HCl with density equal to `1.17 g//mL` is:A. `36.5`B. `18.25`C. `32.05`D. `42.10`

Answer» Correct Answer - 3
`Density=(mass)/(volume)=1.17 g//c c`
This implies that in every `1 c c` there is `1.17 g HCl`. Thus, mass of `HCl` in `1000 c c (1000 mL or 1 L)` will be `1170 g`.
`n_(HCl)=(mass_(HCl))/(mm_(HCl))`
`=(1170 g)/(36.5 g mol^(-1))=32.05 mol`
`M_(HCl)=n_(HCl)/V_(mL)xx(1000 mL)/L`
`=(32.05 mol)/(1000 mL)xx(1000 mL)/L`
`=32.05 M`
977.

Correct eqution of Freundlich isotherm is :A. `log(x/m)=log K+1/n log C`B. `log(x/m)=log m+1/m log C`C. `log (x/m)=log C+1/K log C`D. `log (x/m)=log C+1/n log K`

Answer» Correct Answer - A
According to Freundlich adsorption isotherm, `x/m=Kp^(1//n)` or `"log"x/m=log K+1/n log P` (For solution, P=C).
978.

The physical adsorption of gases on the solid surface is due to :A. vander Waals forcesB. convalent bondingC. hydrogen bondingD. All of these

Answer» Correct Answer - A
Physical adsorption is due to vander waals forces.
979.

Following is the variation of physical adsorption with temperature.A. B. C. D.

Answer» Correct Answer - B
As temperature increases, physical adsorption decreases because physical adsorption is exothermic and reversible process.
980.

Which of the following statements about physical adsorption is correct ?A. It is usually monolayerB. It is reversible in natureC. It involves van der Waals interactions between adsorbent and adsorbateD. It involves samll enthalpy of adsorption as compared to chemisorption

Answer» Correct Answer - B::C::D
981.

Maximum freezing point fall isA. ComphorB. NepththaleneC. BenzeneD. Water

Answer» Correct Answer - A
Maximum depression in f.pt. is in camphor. `K_(f)` for camphor is `37.70K` kg `mol^(-1)`
982.

Explain : (1) Homogeneous solution (2) Heterogeneous solution.

Answer»

(1) Homogeneous solution : A solution in which solute and solvent form uniform homogeneous one phase due to attraction between their molecules/particles is called homogeneous solution. 

E.g. A solution of NaCl or sugar.

(2) Heterogeneous solution : A solution consisting of two or more phases is called a heterogeneous solution. 

E.g. A colloidal solution of starch.

983.

Physical adsorption is essentially quite appreciable :A. at room temperatureB. at higher temperatureC. at lower temperatureD. none if these

Answer» Correct Answer - C
Rate of physical adsorption decreases with increase in temperature.
Therefore, (C) is correct option.
984.

Which of the following solutions will have the highest b.d?A. `0.1M FeCI_(3)`B. `0.1M BaCI_(2)`C. `0.1M NaCI`D. `0.1M` Urea

Answer» Correct Answer - A
Highest b.pt. `rArr` Maximum `Delta T_(b)`
`rArr` Maximum number of particles per unit volume in solution.
(A) `0.1 M FeCl_(2)` has 0.4M particles in solution (maximum)
985.

100 cc of `0.6 N H_(2)SO_(4)` and 200 cc of `0.3 N HCI` were mixed together. The normality of the solution will beA. 0.2NB. 0.4NC. 0.8ND. 0.6N

Answer» Correct Answer - B
Total volume of solution `= 100+200=300` cc
For `H_(2)SO_(4)`
`N_(1)V_(1)=N_(2)V_(2)`
`0.6N xx100=N_(2)xx300`
`N_(2)=(60N)/(300)=(N)/(5)`
For HCl
`N_(1)V_(1)=N_(2)V_(2)`
`0.3N xx200=N_(2)xx300`
`N_(2)=(N)/(5)`
Total normality `= N(H_(2)SO_(4))+N(HCl)`
`=(N)/(5)+(N)/(5)=(2N)/(5)=0.4N`
986.

Which of the following is more accurate method to express the concentration of a solution?A. MolarityB. MolalityC. NormalityD. Mole fraction

Answer» Correct Answer - B::D
Molality and moles fraction are more accurate as they do not depend upon temperature of solution.
987.

Which statement is incorrect about osmotic pressure`(pi)`, volume `(V)`, and temperature `(T)`?A. `pi prop (1)/(V)` if T is constantB. `pi prop T` if V is constantC. `pi prop V` if T is constantD. `piV` is constant if T is constant

Answer» Correct Answer - A::B::D
For a solution containing n moles of a non electrolyte solute
`pi prop (1)/(V)` (at constant T)
or `piV` = Constant (at constant T)
`pi prop T` (at constant V)
988.

Which statement is incorrect about osmotic pressure `(pi)`, volume `(V)` and temperature `(T)`:A. `pi prop (1)/(V)` if T is constantB. `pi prop T` if V is constantC. `pi prop V` if T is constantD. `pi V` is constant if T is constant

Answer» Correct Answer - C
`(5)/(342) = (0.877)/(X) X = 59.98`
989.

A solution containing 0.2563g of naphthalene (molecular mass = 128) in 50g of carbon tetrachloride yields a boiling point elevation of `0.201^(@)C` while a solution of 0.6216g of an unknown solute in the same mass of the solvent gives a boiling point elevation of `0.647^(@)C`. Find the molecular mass of the unknown solute.

Answer» We know that,
`K_(b)=(DeltaT_(b)xxWxxm)/(1000xxw)`
For `C Cl_(4),K_(b)=(0.201xx50xx128)/(1000xx0.2563)=5.019`
`K_(b)` is now used in the second part of the problem
`m=(1000xxK_(b)xxw)/(DeltaT_(b)xxW)`
`=(1000xx5.019xx0.6216)/(0.647xx50)=96.44`.
990.

A semipermeable membrane used in the measurement of osmotic pressure of a solution allows the passage ofA. only solute molecules through itB. only solvent molecules through itC. both solute and solvent molecules through itD. either solute or sovent molecules through it

Answer» Correct Answer - 1
Certain membranes allow solvent molecules to pass through them but not solute molecules, particularly, not those of large molecular mass. Such a membrane is called semipermeable and might be an animal bladder, a piece of cellophane.
991.

Which one of the following statements is incorrect?A. Osmotic pressure is directly proportional to the temperature of the solutionB. Osmotic pressure is the pressure applied on the solution to prevent the entry of the solvent into it through the semipermeable membrane.C. Osmotic pressure is the hydrostatic pressure of the liquid column set up due to osmosis.D. During osmosis, the flow of solvent is only form dilute solution to concentrated solution.

Answer» Correct Answer - 4
Certain materials, including those that make up the membranes around living cells, are semipermeable. That is, they allow `H_(2)O` or other small molecules to pass through, but they block the passage of large solute molecules or ions.
When a solution and a pure solvent (or two solutions of different concentration) are separated by the right kind of semipermeable membrane, solvent molecules pass through the membrane in a process called osmosis.
Although the passage of solvent through the membrane takes place in both direction, passage from the pure solvent side to the solution side (or from the dilute solution side to more concentrated solution side) is more favored and occurs faster.
As a result, the amount of liquid on the pure solvent side decreases, the amount of liquid on the solution side increases and the concentration of the solution decreases.
992.

What is Vant Hoff factor?

Answer»

It is the ratio of normal molecular mass to observed molecular mass . H is denoted as ‘i’ 

i = normal m.m / observed m.m 

= no. of particles after association or dissociation / no. of particles before

993.

How molarity is related with percentage and density of solution ?

Answer»

M = P x d x 10/M.M

994.

Give an example of a solid solution in which the solute is a gas.

Answer»

Solution of hydrogen in palladium.

995.

What role does the molecular interaction play in solution of alcohol and water?

Answer»

There is strong hydrogen bonding in alcohol molecules as well as water molecules. The intermolecular forces both in alcohol and water are H-bonds. 

When alcohol and water are mixed, they form solution because of formation of H-bonds between alcohol and H2O molecules hut these interactions are weaker and less extensive than those in pure water. 

Hence, they show positive deviation from ideal behaviour.

996.

What role does the molecular interaction play in the solution of alcohol and water?

Answer»

Positive deviation from ideal behavior.

997.

What role does the molecular interaction play in solution of alcohol and water? 

Answer»

 In alcohol and water solution interaction between alcohol and water molecules show inter molecular hydrogen bonding but it is weaker than water – water and alcohol – alcohol hydrogen bonding. 

998.

 State Henry’s Law and mention its two important applications ?

Answer»

Henry’s Law states that the solubility of a gas in liquid is directly proportional to the partial pressure of the gas.  

Applications:- 

(1) In deep sea diving. 

(2) In aerated water e.g. soft drinks. 

999.

What role does the molecular interaction play in a solution of alcohol and water?

Answer»

There is strong hydrogen bonding in alcohol molecules as well as water molecules. On mixing the molecular interactions are weekend. Hence, they show positive deviations from ideal behaviour. AS a result, the solution will have higher vapour pressure and lower boiling point than that of water and alcohol.

1000.

State Henry’s law and mention some important applications?

Answer»

Henry’s law states that at constant temperature, the solubility of a gas in a liquid is directly proportional to the pressure of the gas. 

Applications: It is used

  • in the production of carbonated beverages
  • in the deep sea diving
  • in the function of lungs.