34 + Interview Questions in TEMPERATURE-AND-THERMAL-EXPANSION IN GENERAL AWARENESS Page 1 InterviewSolution

1.	Which of the curves in figure represents the telation between Celsius and Fahrenheit temperatures? ` `A. `a`B. `a`C. `a`D. `a`
Answer» Correct Answer - B See solution of problem 6.

Discussion

2.	If a graph is plotted taking the temperature in Fahrenheit along the `Y`-axis and the corresponding temperature in Celsius along the `X`-axis, it will be a straight lineA. having a positive intercept on the `Y`-axisB. having a positive intercept on the `X`-axisC. passing through the originD. having a negative intercepts on both the axis
Answer» Correct Answer - A `(F-32)/(9)=(C)/(5)` `F=(9)/(5)C+32` `y=(9)/(5)x+32` , `y=mx+c` , `m=(9)/(5)=+ve` , `C=32=+ve` `Fv//sC` graph will be a straight line of position slope and positive intercept

Discussion

3.	A vernier calliper has 10 divisions on vernier scale coinciding with 9 main scale divisions. It is made of a material whose coefficient of linear expansion is `alpha= 10^(-3).^(@)C^(-1)`. At `0^(@)C` each main scale division = 1mm. An object has a length of 10 cm at a temperature of `0^(@)C` and its material has coefficient of linear expansion equal to `alpha_(1)=1xx10^(-4).^(@)C^(-1)`. The length of this object is measured using the said vernier calliper when room temperature is `50^(@)C`. (a) Find the reading on the main scale and the vernier scale (b) The same object is measured (at `50^(@)C`) using a wooden scale whose least count is 1mm. Write the measured reading using this scale assuming it to be correct at all temperature.
Answer» Correct Answer - (a) MSR =95 mm; VSR =7 (b) `100 pm 1`mm

Discussion

4.	Two samples of a liquid have volumes 400 cc and 220 cc and their temperature are `10^(@)C` and `110^@C` respectively. Find the final temperature and volume of the mixture if the two samples are mixed. Assume no heat exchange with the surroundings. Coefficient of volume expansion of the liquid is `g = 10^(-3).^(@)C^(-1)` and its specific heat capacity is a constant for the entire range of temperature.
Answer» Correct Answer - `43.33^(@)C; 620 c c `

Discussion

5.	A composite bar has two segments of equal length L each. Both segments are made of same material but cross sectional area of segment OB is twice that of OA. The bar is kept on a smooth table with the joint at the origin of the co - ordinate system attached to the table. Temperature of the composite bar is uniformly raised by `Delta theta`. Calculate the x co-ordinate of the joint if coefficient of linear thermal expansion for the material is `alpha^(@)C^(-1)`
Answer» Correct Answer - `-(Lalpha Delta theta)/6`

Discussion

6.	A water in glass thermometer has density of water marked on its stem [Density of water is the thermometric property in this case]. When this thermometer is dipped in liquid A the density of water read is 0.99995 g `cm^(3)`. Thereafter it is dipped in liquid B and the reading remains unchanged. Maximum density of water is 1.00000 g `cm^(-3)`. (a) Can we say that liquid A and B are necessarily in thermal equilibrium? (b) If two liquids are mixed and the thermometer is inserted in the mixture, the height of water column in stem is found to change (i.e. reading is different from 0.99995 g `cm^(-3)`). Has the height increased or decreased?
Answer» Correct Answer - (a) NO (b) decreases

Discussion

7.	An iron rod of length `50cm` is joined at an end to an aluminium rod of length `100cm` . All measurements refer to `20^(@)C` . Find the length of the composite system at `100^(@)C` and its average coefficient of linear expansion. The coefficient of linear expansion of iron and aluminium are `12xx10^(-6)//^(@)C` and `24xx10^(-6)//^(@)C` respectively.
Answer» `(l_(i))_(100)=(l_(i))_(0)[1+alpha_(i)(theta-theta_(0)]` `=50[1+12xx10^(-6)(100-20)]` `=50.048cm` `(l_(a))_(100)=(l_(a)_(0)[1+alpha_(a)(theta-theta_(0)]` `=100[1+24xx10^(-6)(100-20)]` `=100.192cm` Total length at `100^(@)C` `=50.048+100.192=150.24cm` Total length at `20^(@)` `=50+100=150cm` Let average coefficient of linear expansion be `alpha` `150.24=150[1+alpha(100-20)]` `alpha=2xx10^(-5)//^(@)C` .

Discussion

8.	Two rods , one of aluminium and the other made of steel, having initial length `l_(1)` and `l_(2)` are connected together to from a sinlge rod of length `l_(1)+l_(2)` . The coefficient of linear expansion for aluminium and steel are `alpha_(a)` and `alpha_(s)` for `AC` and `BC` . If the distance `DC` remains constant for small changes in temperature,A. `(alpha_(s))/(alpha_(a))`B. `(alpha_(a))/(alpha_(s))`C. `(alpha_(s))/((alpha_(a)+alpha_(s)))`D. `(alpha_(a))/((alpha_(a)+alpha_(s)))`
Answer» Correct Answer - C `(Delta l)_(1)=(Delta l)_(2)` `l_(1)alpha_(1)Deltatheta=l_(2)alphaDeltatheta` `l_(2)=(alpha_(a))/(alpha_(s))l_(1)` `(l_(1))/(l_(1)+l_(1))=(l_(1))/(l_(1)+(alpha_(a))/(alpha_(s)l_(1)))=(alpha_(s))/(alpha_(a)+alpha_(s))`

Discussion

9.	(a) A steel tank has internal volume `V_0` (= 100 litre). It contains half water ( volume = `(V_0)/2` ) and half kerosene oil at temperature `theta_(1) = 10^(@)C` Calculate the mass of kerosene that flows out of the tank at temperature of `theta_(2)=40^(@)C`. Coefficient of cubical expansion for different substances are: `gamma_(k)=10^(-3).^(@)C^(-1), gamma_(w)=2xx10^(-4) .^(@)C^(-1), gamma_("steel")=1.2xx10^(-5).^(@)C^(-1)`. density of kerosene at `10^(@)C` is `rho_(1)=0.8 kg` /litre. (b) In the last problem the height of water in the container at `theta_(1)=10^(@)C` is `H_1 = 1.0 m`. Find the height of water at `theta_(2) = 40^(@)C`.
Answer» Correct Answer - `(a) Delta m =(V_(0) rho_(1))/2 ((gamma_(k)+gamma_(w)-2gamma_(s)))/((1+gamma_(k) Delta theta)) Delta theta`; =1.37 kg [where `Delta theta=theta_(2) -theta_(1)`] (b) `(H_(1)[1+gamma_(w)Delta theta])/([1+2/3gamma_(s)Delta theta]) =1.0057 m`

Discussion

10.	There are two sphers of same radius and material at the same temperature but one being solid while the other hollow. Which sphere will expand more if they are given the same amount of heat ?A. sameB. hollow sphereC. solid sphereD. no conclusion
Answer» Correct Answer - A `DeltaV=VgammaDeltatheta`

Discussion

11.	A metal ball immersed in alcohol weights `W_1` at `0^@C` and `W_2` at `50^@C`. The coefficient of expansion of cubical the metal is less than that of the alcohol. Assuming that the density of the metal is large compared to that of alcohol, it can be shown thatA. `W_(1)gtW_(2)`B. `W_(1)=W_(2)`C. `W_(1) lt W_(2)`D. `W_(2)= W_(1)//2`
Answer» Correct Answer - C `gamma_("metal") lt gamma_("liquid")`, neglect expansion of metal ball `W_(1)=W_(0)-p_(0)Vg , W_(0)` : weight of ball in air `W_(2)=W_(0)-p_(50)Vg` `p_(50)=(p_(0))/(1+gamma_(l)(50-0) implies p_(50) lt p_(0)` `W_(2) gt W_(1) or W_(1) lt W_(2)`

Discussion

12.	An iron rod and a copper rod lie side by side. As the temperature is changed, the difference in the lengths of the rods remains constant at a value of `10cm` . Find the lengths at `0^(@)C` . Coefficient of linear expansion of iron and copper are `1.1xx10^(-5)//^(@)C` and `1.7xx10^(-5)//^(@)C` respectively.
Answer» Given `alpha_(i)=1.1xx10^(-5)//^(@)C` , `alpha_(c)=1.7xx10^(-5)//^(@)C` `(l theta)_(i) : "length of iron rod at" 0^(@)C` `(l theta)_(c)` : length of copper rod at `0^(@)C` `(l theta)_(i)` : length of iron rod at `theta^(@)C` `(l theta)_(c)` : length of copper rod at `theta^(@)C` `(l_(0))_(i)-(l_(0))_(c)=10` `(Deltal)_(i)=(Deltal)_(c)` `(l_(0))_(i)alpha_(i)(theta-0)=(l_(0))=(l_(0))_(c)alpha_(c)(theta-0)` `(l_(0))_(i)=(l_(0))_(c)alpha_(c)` `(l_(0))_(i)=(l_(0))_(c)(alpha_(c))/(alpha_(i))=(l_(0))_(c)=(l_(0))_(c)((1.7))/((1.1))` in (i) `(1.7)/(1.1)(l_(0))_(c)-(l_(0))_(c)=10` `0.6(l_(0))_(c)=11` `(l_(0))_(c)=18.3cm` `(l_(0))_(i)=10+(l_(0))_(c)=28.3cm`

Discussion

13.	A beaker contains a liquid of volume `V_0`. A solid block of volume V floats in the liquid with 90% of its volume submerged in the liquid. The whole system is heated to raise its temperature by `Delta theta`. It is observed that the height of liquid in the beaker does not change and the solid in now floating with its entire volume submerged. Calculate `Delta theta`. It is given that coefficient of volume expansion of the solid and the glass (beaker) are `gamma_(s)` and `gamma_(g)` respectively.
Answer» Correct Answer - `Delta theta=(0.1(V_(0)-V))/((0.9V_(0)+V)gamma_(s)-(V_(0)+0.9V)gamma_(g))`

Discussion

14.	A metal ball is being weighed in liquid whose temperature is raised continuously. Then the apparent weight of the ballA. remain unchangedB. increasesC. decreasesD. change erratically
Answer» Correct Answer - B Apparent weight=weight- `F_(B)` As temperature increases, upthrust decreases, Apparent weight increases

Discussion

15.	The volume of a block of a metal changes by `012%` when it is heated through `20^(@)C` . The coefficient of linear expansion of the metal isA. `2.0xx10^(-5)per^(@)C`B. `4.0xx10^(-5)per^(@)C`C. `6.0xx10^(-5)per^(@)C`D. `8.0xx10^(-5)per^(@)C`
Answer» Correct Answer - A `(DeltaV)/(V)=gammaDeltatheta` `(0.12)/(100)=3alpha(20)` `alpha=(0.12)/(100xx60)=2xx10^(-5)//^(@)C`

Discussion

16.	Assume that the coefficient of linear expansion of the material of a rod remains constant, equal to `alpha^(@)C^(-1)` for a fairly large range of temperature. Length of the rod is `L_0` at temperature `theta_(0)`. (a) Find the length of the rod at a high temperature `theta`. (b) Approximate the answer obtained in (a) to show that the length of the rod for small changes in temperature is given by `L = L_0 [1 + alpha (delta- delta_(0))]`
Answer» Correct Answer - `L=L_(0)e^(alpha(theta-theta_(0)))`

Discussion

17.	A solid whose volume does not change with temperature floats in a liquid. For two different temperatures `t_1` and `t_2` of the liqiud, fraction `f_1` and `f_2` of the volume of the solid remain submerged in the liquid. The coefficient of volume expansion of the liquid is equal toA. `(f_(1)-f_(2))/(f_(2)t_(1)-f_(2)t_(1))`B. `(f_(1)-f_(2))/(f_(2)t_(1)-f_(2)t_(1))`C. `(f_(1)+f_(2))/(f_(2)t_(1)+f_(2)t_(1))`D. `(f_(1)+f_(2))/(f_(2)t_(1)+f_(2)t_(1))`
Answer» Correct Answer - A `W+p_(t_1)f_(1)Vg=rho_(t_(2))f_(2)vg` `rho_(t_(1))f_(1)=rho_(t_(2))f_(2)` `(rho_(0)/(1+gammat_(2)))f_(1) =(rho_(0)/(1+gammat_(0)))f_(2)` `(1+gammat_(2))f_(1)=(1+gammat_(1))f_(2)` `f_(1)-f_(2)=(f_(2)t_(1)-f_(1)t_(2))` `gamma=(f_(1)-f_(2))/(f_(2)t_(1)-f_(1)t_(2))`

Discussion

18.	A thin uniform rod of mass M and length l is rotating about a frictionless axis passing through one of its ends and perpendicular to the rod. The rod is heated uniformly to increases its temperature by `Deltatheta`. Calculate the percentage change in rotational kinetic energy of the rod. Explain why the answer is not zero. Take coefficient of linear expansion of the material of the rod to be `alpha`.
Answer» Correct Answer - `-200 alpha Delta theta %`

Discussion

19.	When water is heated from `0^(@)C` to `10^(@)C` , its volumeA. increaseB. decreaseC. remain unchangedD. first decreases and then increases
Answer» Correct Answer - D From `0^(@)C` to `4^(@)C` , volume of water decrreases and `4^(@)C` to `10^(@)C` , volume increases.

Discussion

20.	A liquid with coefficient of volume expansion `gamma` is filled in a container of a material having coefficient of linear expansion `alpha` . If the liquid overflows on heating, thenA. `gamma=3alpha`B. `gammagt3alpha`C. `gammalt3alpha`D. `gamma=alpha^(3)`
Answer» Correct Answer - B `(DeltaV)_(1)gt(DeltaV)_(g)` `VgammaDeltathetagtV(3alpha)Deltatheta` `gammagt3alpha`

Discussion

21.	The coefficient of apparent expansion of a liquid is `C` when heated in a copper vessel and is `S` when heated in a silver vessel. If `A` is the coefficient of linear expansion of copper, than that of silver isA. `(C+S-3A)/(3)`B. `(C+3A-S)/(3)`C. `(S+3C-A)/(3)`D. `(C+S-3A)/(3)`
Answer» Correct Answer - B `C=gamma-3A` `S=gamma-3alpha_(Ag)` `C+3A=S+3alpha_(Ag)` `alpha_(Ag)=(C-S+3A)/(3)`

Discussion

22.	A horizontal tube, open at both ends, contains a column of liquid. The length of this liquid column does not change with temperature. Let `gamma` : coefficient of volume expansion of the liquid and `alpha` : coefficient of linear expansion of the material of the tubeA. `gamma=alpha`B. `gamma=2alpha`C. `gamma=3alpha`D. `gamma=0`
Answer» Correct Answer - B Let `A_(0)` : area of `X`-section at `0^(@)C` `A_(theta)` : area of `X`-section at `theta^(@)C` `V_(0)` : volume of liquid at `0^(@)C` `V_(theta)` : volume of liquid at `theta^(@)C` `l` : length of liquid column (constant) `V_(0)=lA_(0)` , `V_(theta)=lA_(theta)` , `A_(theta)=A_(0)(1+2alphatheta)` `V_(theta)=V_(0)(1+gammatheta)` `lA_(theta)=lA_(0)(1+gammatheta)` `A_(theta)(1+2alphatheta)=A_(0)(1+gammatheta)` `gamma=2alpha`

Discussion

23.	Two metal plates A and B made of same material are placed on a table as shown in the figure. If the plates are heated uniformly, will the gap indicated by x and y in the figure increase or decrease?
Answer» Correct Answer - x increases, y decreases

Discussion

24.	A one litre flask contains some mercury. It is found that at different temperatures the volume of air inside the flask remains the same. The volume of mercury in the flask is `(alpha_(glass)=9xx10^(-6)//^(@)C,gamma_(Hg)=180xx10^(-6)//^(@)C)`A. `150cm^(3)`B. `225cm^(3)`C. `300cm^(3)`D. `450cm^(3)`
Answer» Correct Answer - A `(DeltaV)_(g)=Vgamma_(g)Deltatheta=V.3alpha_(g)Deltatheta` `(DeltaV)_(m)=V_(m)gamma_(m)Deltatheta` `(DeltaV)_(g)=(DeltaV)_(m) implies 3alpha_(g)V=gamma_(m)V_(m)` `3xx9xx10^(-6)xx1=180xx10^(6)V_(m)` `V_(m)=0.15` litre `=0.15xx1000=150cm^(3)`

Discussion

25.	Containers A and B contain a liquid up to same height. They are connected by a tube (see figure). (a) If the liquid in container A is heated, in which direction will the liquid flow through the tube. (b) If the liquid in the container B is heated in which direction will the liquid flow through the tube? Assume that the containers do not expand on heating.
Answer» Correct Answer - In both cases the liquid flows from B and A.

Discussion

26.	Height of mercury in a barometer is `h_0 = 76. 0` cm at a temperature of `theta_1 = 20^(@)C`. If the actual atmospheric pressure does not change, but the temperature of the air, and hence the temperature of the mercury and the tube rises to `theta_(2)= 35^(@)C`, what will be the height of mercury column in the barometer now? Coefficient of volume expansion of mercury and coefficient of linear expansion of glass are `gamma_(Hg) =1.8xx10^(-4).^(@)C^(-1), alpha_(g)=0.09xx10^(-4).^(@)C^(-1)`
Answer» Correct Answer - `h=h_(0)[1+gamma_(Hg)Delta theta]=76.205 cm `

Discussion

27.	A steel sheet at `20^(@)C` has the same surface area as a brass sheet at `10^(@)C` . If the coefficient of linear expansion of steel is `11xx10^(-6)//K` and that of bross is `19xx10^(-6)//K` , the common temperature at which both the sheets would have the same surface area isA. `3.75^(@)C`B. `-3.75^(@)C`C. `7.5^(@)C`D. `-7.5^(@)C`
Answer» Correct Answer - B For area `Atheta=Atheta_(0)[1+beta(theta-theta_(0))=Atheta_(0)[1+2alpha(theta-theta_(0))]` `(A_(s))_(theta)=(A_(s))_(20)[1+2alpha_(s)(theta-20)]` `(A_(b))_(theta)=(A_(b))_(10)[1+2alpha_(b)(theta-10)]` Given `(A_(s))_(theta)=(A_(b))_(theta)` and `(A_(s))_(20)=(A_(b))_(10)` `alpha_(s)(theta-20)=alpha_(b)(theta-10)` `11theta-220=19theta-190` `8theta=-30 implies theta=-3.75^(@)C` .

Discussion

28.	A centigrade and a Fehrenheit thermometer are dipped in boiling water. The water temperature is lowered until the Fehrenheit thermometer registers `140^(@)C` . What is the fall in temperature as register by the centigrade thermometerA. `30^(@)`B. `40^(@)`C. `60^(@)`D. `80^(@)`
Answer» Correct Answer - B `(C)/(5)=(F-32)/(9)` `C=((140-32)/(9))xx5=60` Boiling water temperature `=100^(@)C` Fall in temperature on centigrade thermometer `=100-60=40^(@)`

Discussion

29.	On a new scale of temperature (which is linear) and called the `W` scale. The freezing and boiling points of water are `39^(@)W` and `239^(@)W` respectively. What will be the temperature on the new scale, corresponding to a temperature of `39^(@)C` on the Celsius scale?A. `200^(@)W`B. `139^(@)W`C. `78^(@)W`D. `117^(@)W`
Answer» Correct Answer - D `(C)/(100)=(W-39)/(239-39)` `(39)/(100)=(W-39)/(200)` `W=117`

Discussion

30.	(a) A pendulum clock consists of an iron rod connected to a small, heavy bob. If it is designed to keep correct time at `20^(@)C` , how fast or slow will it go in 24 hours at `50^(@)C` ? `alpha_(iron)=1.2xx10^(-5)//^(@)C` . (b) A pendulum clock having copper rod keeps correct time at `20^(@)C` . It gains 15 seconds per day if cooled to `0^(@)C` . Find the coefficient the of linear expansion of copper.
Answer» (a) `If theta gt theta_(0)` , loss of time `theta lt theta_(0)` , gain of time `theta_(0)` : temperature at which clock gives correct time `theta_(0)20^(@)C` , `theta=50^(@)C` Loss of time per day `=(1)/(2)alpha_(i)(theta-theta_(0))xx86400` `=(1)/(2)xx1.2xx10^(-5)(50-20)xx86400` `=15.6s` (b) Gain of time per day `(1)/(2)alpha(theta_(0)-theta)xx86400=15` `(1)/(2)alpha(20-0)xx86400=15` `alpha=(15)/86400=1.7xx10^(-5)//^(@)C` .

Discussion

31.	A metal cylinder of radius R is placed on a wooden plank BD. The plank is kept horizontal suspended with the help of two identical string AB and CD each of length L. The temperature coefficient of linear expansion of the cylinder and the strings are `a_1` and `a_2` respectively. Angle q shown in the figure is `30^(@)`. It was found that with change in temperature the centre of the cylinder did not move. Find the ratio `(alpha_(1))/(alpha_(2))` , if it is know that L = 4R. Assume that change in value of `theta` is negligible for small temperature changes
Answer» Correct Answer - `(alpha_(1))/(alpha_(2)) =8/1`

Discussion

32.	An iron tyre is to be fitted onto a wooden wheel 1.0 m in diameter. The diameter of the tyre is 6 mm smaller than that of wheel the tyre should be heated so that its temperature increases by a minimum of (coefficient of volume expansion of iron is `3.6xx10^-5//^@C`)A. `167^(@)C`B. `334^(@)C`C. `500^(@)C`D. `-1000^(@)C`
Answer» Correct Answer - C `d theta=d theta_(0)(1+alpha Delta theta)` `1000=(1000-6)(1+(gamma)/(3)Delta theta)` `(gamma)/(3)Delta theta=(1000)/(994)-1=(6)/(994)` `(3.6xx10^(-5))Delta theta=(6xx3)/(994)` `Delta theta=503^(@)C=500^(@)C`

Discussion

33.	A long mercury glass tube with a uniform capillary bore has in it a thread of mercury which is `1m` long at `0^(@)C` . What will be its length at `100^(@)C` if the real coefficient of expansion of mercury is `0.000182` and coefficient of cubical expansion of glass equal to `0.000025` ?
Answer» `V_(0)` , volume of mercury thread at `0^(@)C` `V_(theta)` : volume of mercury thread at `theta^(@)C` `A_(0)` : cross-sectional area of tube at `0^(@)C` `A_(theta)` : cross-sectional area of tube `theta^(@)C` The length of thread at `theta^(@)C` `l_(theta)=V_(theta)/(A_(theta))=(V_(0)(1+gamma_(m)theta))/(A_(0)(1+betatheta)` `=l_(0)(1+gamma_(m)theta)(1+betatheta)^(-1)` `=l_(0)(1+gamma_(m)theta)(1+betatheta)` `=l_(0)[1+(gamma_(m)-beta)theta]["Neglectting small terms"]` `=l_(0)[1+(gamma_(m)-(2gamma_(g))/(3))theta]` `=100[1+(0.000182-(2)/(3)xx0.000025)xx100]` `=101.654cm`

Discussion

34.	a glass tube of length `133cm` and of uniform cross-section is to be filled with mercury so that the volume of the unoccupied by mercury remains the same at all temperatures. If cubical coefficient for glass and mercury are respectively `0.000026//^(@)C` and `0.000182//^(@)C` , calculate the length of mercury column.
Answer» `(DeltaV)_(g)=(DeltaV)_(m)` `(DeltaV)_(g)gamma_(g)Deltatheta=(V_(0))_(m)gamma_(m)Deltatheta` `(V_(0))_(g)gamma_(g)=(V_(0))_(m)gamma_(m)` Let `x` : length of mercury column `l_(0)` : length of glass tube `Al_(0)gamma_(g)=Axgamma_(m)` `x=(gamma_(g)l_(0))/(gamma_(m))=(0.000026xx133)/(0.000182)` `=19cm`

Discussion

Explore topic-wise InterviewSolutions in .

Which of the curves in figure represents the telation between Celsius and Fahrenheit temperatures? ` `A. `a`B. `a`C. `a`D. `a`

There are two sphers of same radius and material at the same temperature but one being solid while the other hollow. Which sphere will expand more if they are given the same amount of heat ?A. sameB. hollow sphereC. solid sphereD. no conclusion

A metal ball is being weighed in liquid whose temperature is raised continuously. Then the apparent weight of the ballA. remain unchangedB. increasesC. decreasesD. change erratically

The volume of a block of a metal changes by `012%` when it is heated through `20^(@)C` . The coefficient of linear expansion of the metal isA. `2.0xx10^(-5)per^(@)C`B. `4.0xx10^(-5)per^(@)C`C. `6.0xx10^(-5)per^(@)C`D. `8.0xx10^(-5)per^(@)C`

When water is heated from `0^(@)C` to `10^(@)C` , its volumeA. increaseB. decreaseC. remain unchangedD. first decreases and then increases

A liquid with coefficient of volume expansion `gamma` is filled in a container of a material having coefficient of linear expansion `alpha` . If the liquid overflows on heating, thenA. `gamma=3alpha`B. `gammagt3alpha`C. `gammalt3alpha`D. `gamma=alpha^(3)`

The coefficient of apparent expansion of a liquid is `C` when heated in a copper vessel and is `S` when heated in a silver vessel. If `A` is the coefficient of linear expansion of copper, than that of silver isA. `(C+S-3A)/(3)`B. `(C+3A-S)/(3)`C. `(S+3C-A)/(3)`D. `(C+S-3A)/(3)`

Two metal plates A and B made of same material are placed on a table as shown in the figure. If the plates are heated uniformly, will the gap indicated by x and y in the figure increase or decrease?

A one litre flask contains some mercury. It is found that at different temperatures the volume of air inside the flask remains the same. The volume of mercury in the flask is `(alpha_(glass)=9xx10^(-6)//^(@)C,gamma_(Hg)=180xx10^(-6)//^(@)C)`A. `150cm^(3)`B. `225cm^(3)`C. `300cm^(3)`D. `450cm^(3)`

A centigrade and a Fehrenheit thermometer are dipped in boiling water. The water temperature is lowered until the Fehrenheit thermometer registers `140^(@)C` . What is the fall in temperature as register by the centigrade thermometerA. `30^(@)`B. `40^(@)`C. `60^(@)`D. `80^(@)`

A long mercury glass tube with a uniform capillary bore has in it a thread of mercury which is `1m` long at `0^(@)C` . What will be its length at `100^(@)C` if the real coefficient of expansion of mercury is `0.000182` and coefficient of cubical expansion of glass equal to `0.000025` ?