InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Which of the following species contains three bond pairs and one lone pair around the central atom?A. `BF_(3)`B. `NH H_(2)^(-)`C. `PCl_(3)`D. `H_(2)O` |
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Answer» Correct Answer - C `{:(" Cl Cl"),(" /"),(" "underset(..)(P)),(" /"),(" Cl"):}` |
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| 2. |
Assertion : Between `SiCl_(4)` and `C Cl_(4)` only `SiCl_(4)` reacts with water. Reason : `SiCl_(4)` is ionic and `C Cl_(4)` is covalent.A. Both A and R are true and R is the correct explanation of AB. Both A and R are true but R is falseC. A is true but R is falseD. A is false but R is true |
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Answer» Correct Answer - C Reason : Si can expand its octet to accept a lone pair of electrons from water. This is due to the availibility of vacant d-orbitals in its valence shell. |
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| 3. |
Reaction of `HNO_(3)` with C,P,S and I respectively giveA. `HIO_(3),H_(2)SO_(4),H_(3)PO_(4)` and `CO_(2)`B. `HIO_(3),H_(2)SO_(4),H_(3)PO_(4)` and `CO_(2)`C. `I_(2)O_(5), H_(2)SO_(4),H_(3)PO_(3)` and COD. `I_(2)O_(5),SO_(2),P_(2)O_(5)` and `CO_(2)` |
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Answer» Correct Answer - A `I to HIO_(3) , S to H_(2)SO_(4), P to H_(3)PO_(4)` and `C to CO_(2)`. |
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| 4. |
Assertion : `HNO_(3)` is a stronger acid than `HNO_(2)` Reason: In `HNO_(3)`, there are two nitrogen to oxygen bonds while in `HNO_(2)` there is only one.A. Both A and R are true and R is the correct explanation of AB. Both A and R are true but R is falseC. A is true but R is falseD. A is false but R is true |
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Answer» Correct Answer - A Both assertion and reason are correct. |
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| 5. |
Group 15 of the periodic table consists of the elements N, P, As, Sb and Bi. On passing from N to Bi, the oxides of the elements of general formula `M_2 O_3` becomeA. Stronger reducing agentsB. more ionicC. more basicD. more volatile |
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Answer» Correct Answer - C Basic nature of oxides increases down the group. |
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| 6. |
Which element from group 15 gives most basic compound with hydrogen?A. NitrogenB. BismuthC. AsenicD. Phosphorus |
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Answer» Correct Answer - A Basic character of group 15 hydrides decreases down the group. Thus `NH_(3)` is most basic. |
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| 7. |
Which of the following is least basic?A. `NF_(3)`B. `NCl_(3)`C. `NBr_(3)`D. `NI_(3)` |
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Answer» Correct Answer - A `NF_(3)` is least basic because fluorine is more electronegative than nitrogen and is an electrons withdrawing group. |
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| 8. |
Assertion : Among the hydrides of N-family , `NH_(3)` has highest boiling point . Reason: Extensive H-bonding is present in `NH_(3)` , while other elements of the group can not form H-bonding.A. Both A and R are true and R is the correct explanation of AB. Both A and R are true but R is falseC. A is true but R is falseD. A is false but R is true |
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Answer» Correct Answer - D Assertion: Boiling point `NH_(3)` is more than `PH_(3)` and `AsH_(3)` but less than `SbH_(3)`. |
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| 9. |
In the compounds of the type `POX_3`, P atoms show multiple bonding of the typeA. `p pi , dpi`B. `d pi, dpi `C. `p pi - dpi `D. no multiple bond is present |
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Answer» Correct Answer - C In `POX_(3)`, the hybridisation state of P is `sp^(3)` phosphorous has vacant d-orbitals which will overlap with the P orbitals of oxygen thereby resulting in formation of `p pi -dpi ` bond. `{:(" O"),(" || " p pi -d pi "bond "),(" P"),(" / | "),(" X X X"):}` |
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| 10. |
The decreasing order of the boiling points of the following hydrides (i) `NH_3` (ii) `PH_3` (iii) `AsH_3` (iv) `SbH_3` (v) `H_2O` isA. VgtIVgtIgtIIIgtIIB. VgtIgtIIgtIIIgtIVC. IgtIVgtIIIgtIIgtVD. IVgtIIIgtIgtIIgtV |
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Answer» Correct Answer - A The b.pt of `SbH_(3)` is higher than that of `NH_(3)`. The reason being that the stronger van der walls forces of attraction more than compensate the rease in b.pt of `NH_(3)` due to H-bonding (A ) is correct. |
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| 11. |
Phosphorus pentoxide finds use asA. An oxidising agentB. A reducing agentC. A bleaching agentD. A dehydrating agent |
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Answer» Correct Answer - D `P_(2)O_(5)` (phosphorus pent-oxide) is powerful dehydrating agent. |
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| 12. |
The number of `P-O-P` bridge in the structure of phosphorous pentoxide and phosphorus trioxide are respectivelyA. 6 , 6B. 5 , 5C. 5 , 6D. 6 , 5 |
| Answer» Correct Answer - A | |
| 13. |
In the reaction `2Ca_(3)[PO_(4)]_(2)+6SiO_(2) overset(Delta)to6CaSiO_(3) +P_(4)O_(10)`A. a weaker acid anhydride replaces a stronger oneB. a stronger acid anhydride replaces a weaker oneC. both acid anhydrides have equal strengthD. none of these |
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Answer» Correct Answer - A In this reaction a weaker acid anhydride replaces a stronger one because `P_(4)O_(10)` is volatile while `SiO_(2)` is not. |
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| 14. |
Phosphine is not obtained by the reaction whenA. White P is heated with NaOHB. Red P is heated with NaOHC. `Ca_(2)P_(2)` reacts with waterD. `PH_(4)I` is boiled with water. |
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Answer» Correct Answer - B Red P is does not react with NaOH (aq) |
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| 15. |
`P_(2)O_(5)` is heated with water to giveA. Hyphosphorus acidB. Phosphorus acidC. Hyphosphoric acidD. Orthophosphoric acid |
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Answer» Correct Answer - D `P_(2)O_(5)+3H_(2)O to 2H_(3)PO_(4)` |
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| 16. |
an aqueous solution of `HNO_2` (nitrous acid), free of salt can be obtained from the reactionA. `Ba(NO_(2))_(2)+H_(2)SO_(4) to `B. `NaNO_(2) +HNO_(4) overset("Cold")to`C. `NH_(4)NO_(2)+H_(2)SO_(4) to`D. `KNO_(3) +H_(2)SO_(4) to ` |
| Answer» Correct Answer - A | |
| 17. |
The number of P-O-H links in orthophosphoric acid molecule isA. 2B. 4C. 3D. 1 |
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Answer» Correct Answer - C Orthophosphoric acid molecules is `{:(" O"),(" ||"),(" P"),(" / | "),(" HO OH OH "):}` P-O-H bond =3 |
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| 18. |
Which of the following oxides is an anhydride of nitrous acid?A. NOB. `N_(2)O_(3)`C. `N_(2)O_(4)`D. `N_(2)O_(5)` |
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Answer» Correct Answer - B `N_(2)O_(3)+H_(2)O to 2HNO_(2)` |
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| 19. |
The anhydride of orthophosphoric acid isA. `P_(2)O_(3)`B. `P_(2)O_(5)`C. `P_(3)O_(5)`D. `P_(4)O_(10)` |
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Answer» Correct Answer - B `P_(2)O_(5)+3H_(2)O to 2H_(3)PO_(4)` |
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| 20. |
The acidic strength of oxides of nitrogen follows the order:A. `N_(2)O lt NO lt N_(2)O_(4) lt N_(2)O_(3) lt N_(2)O_(5)`B. `N_(2)O lt NO lt N_(2)O_(3) lt N_(2)O_(4) lt N_(2)O_(5)`C. `N_(2)O lt N_(2)O_(3) lt N_(2)O_(4) lt N_(2)O_(5) lt NO`D. `NO lt N_(2)O lt N_(2)O_(3) lt N_(2)O_(4) lt N_(2)O_(5)` |
| Answer» Correct Answer - B | |
| 21. |
Which one of the following oxides of nitrogen is called mixed anhydride?A. NOB. `NO_(2)`C. `N_(2)O_(4)`D. `N_(2)O_(5)` |
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Answer» Correct Answer - B `2NO_(2)+H_(2)O to HNO_(3) +HNO_(2)` `NO_(2)` is called mixed anhydride because it gives a mixture of `HNO_(2)` and `HNO_(3)` upon dissolution in water. |
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| 22. |
In nitroprusside ion, the iron and `NO` exist as `Fe(II)` and `NO^(+)` rather than `Fe^(III)` and `NO`. These forms can be differentiated byA. Estmating the concentration of ironB. Measuring the concentration of ironC. Measuring the solid state magentic momentD. Thermally decomposing decomposing the compound |
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Answer» Correct Answer - C Fe(III) has five unpaired electrons (`d^(5)` configuartion ) whereas Fe(II) has four unpaired electrons (`d^(6)` configuration). These forms can be differentiated by measuring the solid state magnetic moment. |
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| 23. |
Liquor ammonia isA. ammouinim hydroxideB. liquified ammonia gasC. concentrated solution of `NH_(3)` in waterD. a solution of `NH_(3)` in alchol |
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Answer» Correct Answer - C Liquor ammonia is concentrated solution of `NH_(3)` in water while liquid ammonia is liquified ammonia gas. |
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| 24. |
Phosphine produced smoky rings when it comes in contact with air becauseA. it reacts with water vapoursB. it reacts with nitrogenC. it burns in airD. it contains impurities of `P_(2)H_(4)` |
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Answer» Correct Answer - D Phosphine forms smoky rings in contact with air due to presence of impurities of `P_(2)H_(4)` which is spontaneously inflammable. |
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| 25. |
One of the following can form a chain of three atoms. It isA. NB. PC. AsD. Sb |
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Answer» Correct Answer - A Nitrogen can form a chain of the three atoms e.g., azide ion `N^(3-)` whereas phsophorus can form a chain of two. As we move, down the group tendecy to show catenation, further decreases. |
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| 26. |
Which one among the following is a metalloid?A. BiB. SbC. ND. P |
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Answer» Correct Answer - A Sb is metalloid. N and P are non metal , Bi is a metal. |
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| 27. |
Nitrogen does not form complexes becauseA. there are no vacant d - orbitals in the valence shellB. the dissociation energy of nitrogen is very highC. electronegativity of nitogen is very highD. it has stable electronic configuration |
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Answer» Correct Answer - B There are no vacant d-orbitals, so it cannot accept lone pair of ligands. |
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| 28. |
Which one of the following does not show allotropy?A. NitrogenB. PhosphorusC. ArsenicD. Antimony |
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Answer» Correct Answer - A Except nitrogen and Bismuth the elements of group 15 show allotropy |
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| 29. |
Which of the following pairs contains elements belonging to group 15 but not exhibiting allotropyA. N , PB. N , ClC. N , BiD. Bi , Po |
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Answer» Correct Answer - C Ni and Br do not exhibit allotropy. |
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| 30. |
Nitrogen forms `N_(2)` but phosphorous when forms `P_(2)` gets readily converted into `P_(4)` becauseA. triple bond is present between phosphorus atomsB. `p pi -d pi ` bonding is weakC. `p pi- p pi` bonding is strongD. multiple bond is formed easily. |
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Answer» Correct Answer - B `P_(2)` is unstable because the `p pi -d pi ` bonding in it is weak. It is due to larger atomic size of P and N. thus `P_(2)` is converted into `P_(4)` in which there is no `p pi -dpi` bonding. |
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| 31. |
Which is not true of phosphorus?A. Phosphorus exists in differenet allotropic formsB. Black phosphorus has layer type structureC. Yellow phosphrus is less reactive than red phosphorusD. Yellow phosphorus exists as teterahedral molecular solid |
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Answer» Correct Answer - C Yellow phosphorus is more reactive than red phosphorous |
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| 32. |
In `N_(2)O_(5)` valence of nitrogen isA. 2B. 3C. 4D. 5 |
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Answer» Correct Answer - B `N_(2)O_(5)`has the structure `{:(" O O"),(" \ /"),(" N - O - N"),(" / \"),(" O O"):}` In `N_(2)O_(5)`,N has a covalency of 3. |
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| 33. |
Which oxidation state is not shown by phosphorus?A. -3B. 3C. 5D. -2 |
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Answer» Correct Answer - D Phosphorus does not show the oxidation state of `-2` |
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| 34. |
Nitrogen has no d-orbital in its valence shell and therefore it cannotA. exhibit the oxidation state +5B. have covalency greater than 3C. exhibital hybridizationD. from oxides with oxidation state greater than +3 |
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Answer» Correct Answer - B Because of the absence of vacant d-orbitals electron excitation is not possible so it cannot have covalency greater than 3. |
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| 35. |
The number of vacant orbitals in the valence shell of phosphorous is ____.A. 5B. 3C. 2D. 0 |
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Answer» Correct Answer - A `P(Z=15) 1s^(2)2s^(2)2p^(6) 3s^(2)3p^(3)` . Thus, five 3d orbitals are lying vacant. |
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| 36. |
Which of the following has no basic properties ?A. `NH_(3)`B. `PH_(3)`C. `H_(2)N-NH_(2)`D. `H_(2)P-PH_(2)` |
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Answer» Correct Answer - D Diphosphene `H_(2)P-PH_(2)` has no basic properties. |
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| 37. |
The compound which has molecular nature in gas phase but ionic in solid state isA. `PCl_(5)`B. `C Cl_(4)`C. `PCl_(3)`D. `POCl_(3)` |
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Answer» Correct Answer - A `PCl_(5)` exists as `[PCl_(4)]^(+)[PCl_(6)]^(-)`is the solid state and as `PCl_(5)` molecules in gas phase. |
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| 38. |
Which blue liquid is obtained on reacting equimolar amounts of two gases at `-30^@C`?A. `N_(2)O`B. `N_(2)O_(3)`C. `N_(2)O_(4)`D. `N_(2)O_(5)` |
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Answer» Correct Answer - B `NO (g) +NO_(2)(g) overset(-36^(@)C)toNO_(2)O_(3)(l)` |
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| 39. |
Assertion : White phosphorus is stored under water. Reason: White phosphorus is highly reactive and get oxidised on coming in contact with air.A. Both A and R are true and R is the correct explanation of AB. Both A and R are true but R is falseC. A is true but R is falseD. A is false but R is true |
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Answer» Correct Answer - A Both assertion and reason are correct. |
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| 40. |
Which out of the following gases is obtained when ammonium dichromate is heated?A. OxygenB. AmmoniaC. NitrogenD. Nitrous oxide |
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Answer» Correct Answer - C `(NH_(4))_(2)Cr_(2)O_(7) overset("heat")toN_(2)+Cr_(2)O_(3)+4H_(2)O` |
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| 41. |
Which of the following structures correctly represent trimetaphosphate?A. B. C. D. |
| Answer» Correct Answer - B | |
| 42. |
Which form of phosphorus exist in highly polymeric layer type structure?A. Red phosphorusB. Black phosphorusC. White phosphorusD. Scarlet phosporus |
| Answer» Correct Answer - B | |
| 43. |
Royal water isA. conc. `HNO_(3)`B. aqua regiaC. conc. `HNO_(3)` +conc. `H_(2)SO_(4)`D. dilute `HNO_(3)` |
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Answer» Correct Answer - B Aqua regia i.e, conc. HCl+conc. `HNO_(3)` in the ration 3:1 is called royal water while conc. `HNO_(3)` + conc. `H_(2)SO_(4)` is called nitrating mixture. |
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| 44. |
The formula of microcosmic salt isA. `KBiO_(3)`B. `NaPO_(3)`C. `KHPO_(4)`D. `NaNH_(4).HPO_(4).H_(2)O` |
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Answer» Correct Answer - D `NaNH_(4).HPO_(4).H_(2)O` is called microcosmic salt. |
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| 45. |
Which is wrongly matched?A. Triethyl phosphate : insecticidesB. Tritolly phosphate : petrol additiveC. Triaryl phosphate : plasticzersD. Tri - n - butyl |
| Answer» Correct Answer - D | |
| 46. |
Nitrogen content of urea isA. 63B. 70C. 28D. 47 |
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Answer» Correct Answer - D Urea is `(NH_(4))_(2)CO` `2N-=` Urea `28 g -=60 g ` `:.` Percentage of nitrogen `28/60 xx100` =46.66 % |
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| 47. |
Tartaremetic containsA. ArenicB. NitrogenC. BismuthD. Antimony |
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Answer» Correct Answer - D It is `{:(CH(OH)CO OK),("|"),(CH(OH)CO O(Osb)):}" ". 1/2H_(2)O` |
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| 48. |
Which is wrongly matched?A. `H_(3)PO_(4)`:Orthophosphoric acidB. `H_(3)PO_(3)`: Phosphorous acidC. `H_(5)P_(3)O_(10)`: Pyrophosphoric acidD. `H_(6)P_(4)O_(13)`: Tetrapolyphosphoric acid |
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Answer» Correct Answer - C Pyrophosphoric acid is `H_(4)P_(2)O_(7)` |
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| 49. |
Sodium tripolyphosphate is used inA. FertilizerB. Softening of waterC. Fruit ripeningD. None of these |
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Answer» Correct Answer - B Softening of water. |
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| 50. |
Yellow colour of `HNO_3` is due to the presence of `NO_2` is removed byA. boling the acidB. passing ammonia through acidC. bubbling air through the warm acidD. adding a little Mg powder |
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Answer» Correct Answer - C The yellow colour of nitric acid can be removed by bubbling air (or `CO_(2)`) through the warm acid when `NO_(2)` gets removed |
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