InterviewSolution
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1). 22). 13). 34). 4 |
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Answer» QUANTITY of water in 300 ml of MIXTURE = [x/(x + 1)] × 300 When 50 ml of water is mixed in the mixture, ratio of acid and water BECOMES 2 ? 5 ⇒ Quantity of water in in the new mixture = 5/7 × (300 + 50) ⇒ (x/x + 1) × 300 + 50 = 5/7 × (300 + 50) ⇒ (x/x + 1) × 300 = 200 ⇒ (x/x + 1) = 2/3 ∴ x = 2 |
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