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1). 22). 13). 34). 4

Answer»

QUANTITY of water in 300 ml of MIXTURE = [x/(x + 1)] × 300

When 50 ml of water is mixed in the mixture, ratio of acid and water BECOMES 2 ? 5

⇒ Quantity of water in in the new mixture = 5/7 × (300 + 50)

⇒ (x/x + 1) × 300 + 50 = 5/7 × (300 + 50)

⇒ (x/x + 1) × 300 = 200

⇒ (x/x + 1) = 2/3

∴ x = 2



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