InterviewSolution
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1). 252). 243). 164). 19 |
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Answer» Let, T worked for ‘y’ DAYS. ⇒ R worked for (y - 8) days and S worked for (y - 12) days. R completes the work in 36 days. ⇒ R’s 1 day’s work = 1/36 ⇒ R’s (y - 8) day’s work = (y - 8)/36 S completes the work in 54 days. ⇒ S’s 1 day’s work = 1/54 ⇒ S’s (y - 12) day’s work = (y - 12)/54 T can complete the work in 72 days. ⇒ T’s 1 day’s work = 1/72 ⇒ T’s y day’s work = y/72 According to the QUESTION, ⇒ $(\FRAC{{y - 8}}{{36}} + \frac{{y - 12}}{{54}} + \frac{y}{{72}} = 1 \Rightarrow \frac{{6\left( {y - 8} \right) + 4\left( {y - 12} \right) + 3y}}{{216}} = 1)$ ⇒ 13y - 96 = 216 ⇒ 13y = 312 ⇒ y = 24 days ∴ The number of days for which T worked = 24 days |
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