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Pipe A can fill the tank in 45 min and pipe B can empty the tank in 1 hour 30 min. If pipe B is opened after 30 min of start of pipe A, what is the total time required to fill the tank?1). 1 hour2). 1 hour 10 min3). 1 hour 20 min4). 1 hour 30 min |
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Answer» Time require to fill the tank by pipe A = 45 MIN Time require to empty the tank by pipe B = 1 hour 30 min = 60 + 30 = 90 min Amount of tank FILLED in 30 min by pipe A, ⇒ Amount of tank filled = (1/45) × 30 = 2/3 ⇒ Remaining part of tank = 1 - 2/3 = 1/3 For time require to fill the tank, ⇒ (1/45 - 1/90) × t = 1/3 ⇒ [(2 - 1)/90] × t = 1/3 ⇒ (1/90) × t = 1/3 ⇒ t = (1/3) × (90) ⇒ t = 30 min ∴ Total time taken = 30 min + 30 min = 1 hour |
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