InterviewSolution
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1). 61 ∶ 212). 7 ∶ 23). 49 ∶ 154). 51 ∶ 8 |
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Answer» Initially, in the container amount of milk = 64 litres Amount of water = 0 litres First, 8 litres of milk is replaced ∴ Amount of milk = 64 - 8 = 56 litres Amount of water = 8 litres RATIO of milk and water = 56 ? 8 = 7 ? 1 Second, 8 litres of MIXTURE is replaced In this mixture, ratio of milk and water is = 7 ? 1 Thus, amount of milk replaced = $(\frac{7}{8} \times 8 = 7)$ litres Amount of milk REMAINING = 56 - 7 = 49 litres Amount of water = 64 - 49 = 15 litres Now NEW ratio = 49 ? 15 Alternate method : To find amount of milk $({\rm{Original\;amount\;}}{\left( {1 - \;\frac{{Amount\;replaced\;by\;water}}{{Original\;amount}}} \right)^n})$ Where n = number of operations $(64{\left( {1 - \;\frac{8}{{64}}} \right)^2} = 49)$ litres Amount of water = 64 - 49 = 15 litres Now new ratio = 49 ? 15 |
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