InterviewSolution
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1). 7 ∶ 22). 4 ∶ 13). 3 ∶ 14). 5 ∶ 1 |
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Answer» Let the INITIAL quantity of jar B is p litres and amount of milk added in jar A is Q litres; Then initial quantity in jar A = 2p/3 litres (33.33% LESS than jar B) After adding 36 litres water in jar B, mixture X with 50% water is prepared; ∴ 0.2p + 36 = (p + 36) × 0.5 ⇒ 0.3p = 18 ⇒ p = 60 litres ∴ Initial quantity of jar B is 60 litres Now when q litres milk is added to jar A, mixture Y with 52% water (48% milk) is prepared; ∴ 0.35 × 2p/3 + q = (q + 2p/3) × 0.48 ⇒ 0.52q = 0.96p/3 – 0.7p/3 Putting p = 60 litres; ⇒ 0.52q = 5.2 ⇒ q = 10 ∴ Amount of milk added to jar A is 10 litres ∴ Required Ratio = 60 ? 10 = 6 ? 1 |
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