1.

1). 7 ∶ 22). 4 ∶ 13). 3 ∶ 14). 5 ∶ 1

Answer»

Let the INITIAL quantity of jar B is p litres and amount of milk added in jar A is Q litres;

Then initial quantity in jar A = 2p/3 litres (33.33% LESS than jar B)

After adding 36 litres water in jar B, mixture X with 50% water is prepared;

∴ 0.2p + 36 = (p + 36) × 0.5

⇒ 0.3p = 18

⇒ p = 60 litres

∴ Initial quantity of jar B is 60 litres

Now when q litres milk is added to jar A, mixture Y with 52% water (48% milk) is prepared;

∴ 0.35 × 2p/3 + q = (q + 2p/3) × 0.48

⇒ 0.52q = 0.96p/3 – 0.7p/3

Putting p = 60 litres;

⇒ 0.52q = 5.2

⇒ q = 10

∴ Amount of milk added to jar A is 10 litres

∴ Required Ratio = 60 ? 10 = 6 ? 1



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