1.

In an alloy of Copper, Silver and Bronze, the three are present in the ratio 3 ∶ 2 ∶ 3. In another alloy, they are present in ratio 4 ∶ 1 ∶ 5. The two alloys are mixed in the ratio 2 ∶ 3. What will be the amount of Silver in 5 kg of mixture?1). 0.5 kg2). 0.75 kg3). 0.8 kg4). 1 kg

Answer»

LET the weights of two alloys mixed in RATIO 2 : 3 be 2T and 3T, respectively.

Weight of Silver in first alloy = (2/(3 + 2 + 3)) × 2T = 0.5T

Weight of Silver in SECOND alloy = (1/(4 + 1 + 5)) × 3T = 0.3T

Amount of Silver in final mixture = 0.5T + 0.3T = 0.8T

⇒ In 5T KG of mixture, there is 0.8T of Silver.

⇒ In 5 kg of mixture, there is 0.8 kg of Silver.


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