1.

1). 7 kg2). 10 kg3). 15 kg4). 8 kg

Answer»

Amount of first alloy = 24 kg

∴ Amount of A = 5/12 × 24 = 10 kg

⇒ Amount of B = (24 - 10) = 14 kg

Amount of second alloy = 7 kg

∴ Amount of A = 4 kg

⇒ Amount of B = 3 kg

Let the amount of METAL B mixed be X kg

TOTAL amount of A = 10 + 4 = 14 kg

⇒ Total amount of B = 14 + 3 + x = (17 + x) kg

⇒ Total weight = A + B = 14 + 17 + x = (x + 31) kg

Percentage of A in mixture = 40%

∴ [14/(x + 31)] × 100 = 40

⇒ (14 × 100)/40 = x + 31

35 = x + 31

⇒ x = 4 kg

∴ Amount of metal B mixed = 4 kg


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