InterviewSolution
Saved Bookmarks
| 1. |
1). 7 kg2). 10 kg3). 15 kg4). 8 kg |
|
Answer» Amount of first alloy = 24 kg ∴ Amount of A = 5/12 × 24 = 10 kg ⇒ Amount of B = (24 - 10) = 14 kg Amount of second alloy = 7 kg ∴ Amount of A = 4 kg ⇒ Amount of B = 3 kg Let the amount of METAL B mixed be X kg ∴ TOTAL amount of A = 10 + 4 = 14 kg ⇒ Total amount of B = 14 + 3 + x = (17 + x) kg ⇒ Total weight = A + B = 14 + 17 + x = (x + 31) kg Percentage of A in mixture = 40% ∴ [14/(x + 31)] × 100 = 40 ⇒ (14 × 100)/40 = x + 31 ⇒ 35 = x + 31 ⇒ x = 4 kg ∴ Amount of metal B mixed = 4 kg |
|