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In a mixture of sugar and salt, their amount is in ratio 4 : 5. In some amount of this mixture, 4.5 kg of salt is added so that ratio of sugar and salt becomes 2 : 3. How much salt was present in the mixture taken?1). 20 kg2). 22.5 kg3). 18 kg4). 40.5 kg |
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Answer» Let AMOUNT of mixture TAKEN be T kg. Amount of sugar in T kg of mixture = 4T/9 kg Amount of salt in T kg of mixture = 5T/9 kg Now, 4.5 kg of salt is added so that ratio of sugar and salt becomes 2:3. ⇒ (4T/9)/(4.5 + (5T/9)) = 2/3 ⇒ 12T = 81 + 10T ⇒ 2T = 81 ⇒ T = 40.5 kg ∴ Salt present in the mixture taken = (5 × 40.5)/9 kg = 22.5 kg |
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