1.

1). 15 : 172). 15 : 193). 21 : 194). 19 : 15

Answer»

Let the equal QUANTITIES of each alloy which are melted be a

Given,

Alloy A metals are in the ratio 7 : 3

AMOUNT of gold = 7a/10

∴ Amount of copper = 3a/10

Given,

Alloy B metals are in the ratio 7 : 13

∴ Amount of gold = 7a/20

∴ Amount of copper = 13a/20

∴ Ratio of gold and copper in alloy C $(= \;\FRAC{{\frac{{7a}}{{10}}\; + \;\frac{{7a}}{{20}}}}{{\frac{{3a}}{{10}}\; + \;\frac{{13a}}{{20}}}})$ 

⇒ Ratio of gold and copper in alloy C = 21a/19a = 21 : 19



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