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1). 15 : 172). 15 : 193). 21 : 194). 19 : 15 |
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Answer» Let the equal QUANTITIES of each alloy which are melted be a Given, Alloy A metals are in the ratio 7 : 3 ∴ Amount of copper = 3a/10 Given, Alloy B metals are in the ratio 7 : 13 ∴ Amount of gold = 7a/20 ∴ Amount of copper = 13a/20 ∴ Ratio of gold and copper in alloy C $(= \;\FRAC{{\frac{{7a}}{{10}}\; + \;\frac{{7a}}{{20}}}}{{\frac{{3a}}{{10}}\; + \;\frac{{13a}}{{20}}}})$ ⇒ Ratio of gold and copper in alloy C = 21a/19a = 21 : 19 |
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