1.

1). 80 min2). 75 min3). 50 min4). 100 min

Answer»

Total capacity of Cistern = LCM of 25, 20 and 10 = 100 units

Efficiency of pipe 1 = 100/25 = 4 units/min

Efficiency of pipe 2 = 100/20 = 5 units/min

Efficiency of pipe 3 = - 100/10 = -10 units/min

Efficiency of pipe 1, pipe 2 and pipe 3 together = 4 + 5 - 10 = -1 units/min

TIME taken to empty the cistern = 100/1 = 100 min



Discussion

No Comment Found

Related InterviewSolutions