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1). 94%2). 93%3). 95%4). 92% |
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Answer» Let the weight of both ALLOYS be 100 kg In first alloy, AMOUNT of iron = 95 kg Amount of carbon = 3 kg Amount of chromium = 2 kg In second alloy, Let the amount of iron = x kg ⇒ Amount of carbon = (100 - x) kg Total weight of MIXTURE = 100 + 100 = 200 kg ∴ Amount of chromium = 1% of 200 kg = 2 kg ⇒ Amount of iron = 94% of 200 = 188 kg Total iron present = iron from first alloy + iron from second alloy ∴ 188 = 95 + x ⇒ x = 93 ∴ Percentage of iron in second alloy = 93% |
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