1.

1). 94%2). 93%3). 95%4). 92%

Answer»

Let the weight of both ALLOYS be 100 kg

In first alloy,

AMOUNT of iron = 95 kg

Amount of carbon = 3 kg

Amount of chromium = 2 kg

In second alloy,

Let the amount of iron = x kg

⇒ Amount of carbon = (100 - x) kg

Total weight of MIXTURE = 100 + 100 = 200 kg

∴ Amount of chromium = 1% of 200 kg = 2 kg

⇒ Amount of iron = 94% of 200 = 188 kg

Total iron present = iron from first alloy + iron from second alloy

∴ 188 = 95 + x

⇒ x = 93

∴ Percentage of iron in second alloy = 93%



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