1/a+b+c = 1/a + 1/b + 1/ c

1.	1/a+b+c = 1/a + 1/b + 1/ c
Answer» 1/a+b+c=1/a+1/b+1/c=>1/a+b+c -1/c=1/a+1/b=>[c-(a+b+c)] /c(a+b+c) =(b+a) /ab=>Cross multiplying (since a, b, c=0 and a+b+c=0) =>c(a+b+c) (b+a) = -ab(a+b) =>(a+b) (ca+cb+cc+ab) =0=>(a+b) (ca+cc+cb+ab) =0=>(a+b) (b+c) (c+a) = 0?

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