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1/a+b+c=1/a+1/b+1/c .....solve for x |
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Answer» No the question is right Take lcm 1/x(a+b+x)=1/abX a+b-x/x(a+b+x)=a+b/abX cut by x-a+b/x(a+b+x)=a+b/abNow-a+b cut by a+b-1/x(a+b+x)=1/abCross multiple-ab=x(a+b+x)-ab=ax+bx + x^2-ab=x(a+b)+x^2Take ab to right sideX^2+(a+b)x+ab=0 By quardic formula-b+/-√b²-4ac/2a(You can see formula from book)Now but values-a-b +/-√(a+b)²+4*1*ab/2Put identity of (a+b)²-a-b+/- √a²+b²+2ab-4ac/2-a-b+/-√a² +b²-2ab/2-a-b +/-√(a-b)²/2 Now take +ve -a-b+a-b/2A cut by a-2b/2X= -bTake -ve-a-b-a+b/2B cut by b-2a/2X= -a So the values for X = -a , -b If ur question is like this then it is ur ans....1/a+b+x=1/a+1/b+1/xNow take 1/x to left sideThen ,1/a+b+x-1/x=1/a+1/bTake lcmon both side Because if you don\'t have x in ur question then how u can solve it for xI think the ques can be like this ....1/a+b+x=1/a+1/b+1/x Hii I think ur question is wrong |
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