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| 1. |
1÷a+b+c=1÷a+1÷b+1÷x |
| Answer» Here we have1/a+b+c=1/a+1/b+1/xSo by shifting x terms to one side1/a+b+c-1/x=1/a+1/bBy taking the LCM of both the sidesx-(a+b+x)/x(a+b+x)=a+b/abx-a-b-x/x(a+b+x)=a+b/ab (x-x=0)-a-b/x(a+b+x)=a+b/ab. -(a+b)-(a+b)/x(a+b+x)=a+b/ab. (-(a+b)=(a+b) ( -1=1)-1/x(a+b+x)=1/abCross multiply-ab=x(a+b+x)-ab=xa+xb+x2By shifting -ab to the other side x2+xa+xb+abBy taking commonx(x+a)+b(x+a)(x+a) (x+b)So x=-a or x=-b | |