InterviewSolution
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InterviewSolution
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`|[1,bc,b+c],[1,ca,c+a],[1,ab,a+b]|=|[1,a,a^2],[1,b,b^2],[1,c,c^2]|` |
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Answer» Applying `C_(3) to C_(3) - (a + b +c)C_(1)`, we get `RHS = |[1, bc, -a], [1, ca, -b], [1, ab, -c]| = |[1, c, bc],[1, b, ca],[1, c, ab]|` ` = (1)/(abc) * |[a, a^(2), abc], [b, b^(2), abc], [c, c^(2), abc]| = |[a, a^(2), 1], [b, b^(2), 1], [c, c^(2), 1]| = |[1, a, a^(2)], [1, b, b^(2)], [1, c, c^(2)]| = LHS.` |
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