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(1-cos A)(1+cos A)(1+cos²A)=1 |
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Answer» And the solution isTaking LHS :Using identity (a-b) (a+b) =(a² - b²) ( 1-Cos²A)( 1 + Cot²A)As we know:[1 - Cos² A = Sin²A 1 + Cot²A = Cosec²A] identity Now, on putting the values, we have( Sin²A ) ( Cosec²A)[Sin²A = 1/ Cosec²A] identity =1=RHSPROVED I think it should be ( 1 - CosA )( 1 + CosA)( 1 + Cot²A)=1 |
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