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1/(cosecA--cotA) --1/sinA =1/sinA -- 1/(cosecA+cotA) |
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Answer» For this question you have to change the location of LHS and RHS..... LHS:= 1/(CosecA-CotA) - 1/(cosecA+CotA) =CosecA+CotA+CosecA-CotA/Cosec^2A - Cot^2A=2cosecARHS:=1/sinA + 1/sinA=2/sinA=2CosecAProved!!!! 1 |
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