1.

(1+cotA- cosecA) (1+tanA +secA) =2

Answer» (1+cosA/sinA-1/sinA)(1+sinA/cosA+2/cosA)=1/sinAcosA(sinA+cosA-1)(sinA+cosA+1)=1/sinAcosA{(sinA+cosA)2-1)}=1/sinAcosA(sin\u200b\u200b\u200b\u200b2\u200b\u200b\u200bA+cos\u200b\u200b\u200b\u200b2\xa0A+2sinAcosA-1)=2sinAcosA/sinAcosA=2 proved


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