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1). Rs. 2002). Rs. 3003). Rs. 4004). Rs. 250 |
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Answer» Suppose TOTAL work = 72 UNITS (LCM of 24, 36 and 3) ⇒ Efficiency of Sumit = 72/3 = 24 ⇒ Efficiency of the 1st SON = 72/24 = 3 ⇒ Efficiency of the 2nd son = 72/36 = 2 Suppose the efficiency of the 3rd son = x Since Sumit can do TWICE the work as much as done by all the 3 sons together ⇒ 24 = 2 × (3 + 2 + x) ⇒ x = 7 ⇒ Ratio in which the amount will be distributed among the 3 sons = 3 ? 2 ? 7 ∴ Share of the 3rd son = 600 × 7/12 = RS. 350 |
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