1+sec A/secA=sinA/1-cosA give the answers

1.	1+sec A/secA=sinA/1-cosA give the answers
Answer» LHS= 1+1/cosA/1/cosA cosA+1/cosA/1/cosA cosA+1RHS=sin2A/1-cosA 1-cos2A/1-cosA (1-cosA)(1+cos)/1-cosA (using identity) 1+cosA LHS=RHS

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