1-sin A ÷1+sinA = (secA+tanA)²

1.	1-sin A ÷1+sinA = (secA+tanA)²
Answer» Very nice explain gaurav seth 1-sinA/1+sinA=(secA-tanA)²L.H.S1-sinA/1+sinARationalising the denominator1-sinA (1-SinA) /1+sinA(1-SinA)(1-SinA)²/ 1² -(Sin²A)(1-SinA)²/ 1 -(Sin²A)(1-SinA)² /Cos² A[ 1 -Sin²A = cos²A](1-SinA/CosA)²(1/CosA-SinA/CosA)²(SecA-tanA)²L.H S = R H.S

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