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1+sinA. 1- sinA/1+cosA.1-cosA

Answer» 1+sinA×1-sinA/1+cosA×1-cosA=1^2-sin^2/1^2-cosA^2 by ((a+b)(a-b)=a^2-b^2) then cos^2A/sin^2A=cot^2A hence 1+sinA×1-sinA/1+cosA×1-cosA=cot2A
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