√1+sinA/1-sinA = secA +tanA (( root is in whole of 1+sinA/1-sinA. And we have to show LHS =RHS))

√1+sinA/1-sinA = secA +tanA (( root is in whole of 1+sinA/1-sinA. An

1.	√1+sinA/1-sinA = secA +tanA (( root is in whole of 1+sinA/1-sinA. And we have to show LHS =RHS))
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