1.The first three terms of an AP are respectively (3y_ 1),(3y+5),and (5y+1),find the value of y

1.The first three terms of an AP are respectively (3y_ 1),(3y+5),and (

1.	1.The first three terms of an AP are respectively (3y_ 1),(3y+5),and (5y+1),find the value of y
Answer» Y = 5 The common difference between a1 and a2Common difference = a2 - a1=(3y + 5) - (3y - 1)=3y + 5 - 3y + 1=6. ――1Now the common difference between a3 and a2Common difference =a3 - a2=(5y + 1) - (3y + 5)=5y + 1 - 3y - 5= 2y - 4 ――2On equating 1 and 2 we get2y - 4 = 62y = 10y = 5So the value of y is 5