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10.2question 5 |
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Answer» Diagram should be like this :- a circle, AB ia a tangent , OC is perpendicular to AB and O\' is also a point around O(centre) and join O\'C This can be done by contradiction. Therefore let assume that O\'C is perpendicular to Ab so we can say that angle OC\'b is equal to 90°- © we know that angle ACB = 90°- ® From ©and ® O and O\' are same point therefore angle O\'CB = angleOCB . Which chapter?? Dude |
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