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100 Liters of mixture contains 15% water and rest milk, the amount of milk that must be added so that the resulting mixture contains 87.5% milk is?1). 20 L2). 15 L3). 25 L4). 10 L |
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Answer» Amount of water in the MIXTURE = 15L ⇒ Milk = 85 L On adding the milk to make the concentration of milk 87.5%, the quantity of the milk remains the same, ⇒ 12.5% Water = 15 L ⇒ 100% = 120 L ⇒ Out of 120 L, concentration of water is 15L ⇒ Quantity of milk = 105 L ∴ Quantity added = 105 – 85 = 20 L |
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