1.

10th term of the AP: 1, 7, 13 ………….. is ………………………..Your answer

Answer» a = 1 d = 4-1 = 3an\xa0= a + (n-1)da10\xa0= 1 + (10-1)3a10\xa0= 1 + (9)3a10= 1 + 27a10= 28


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