Saved Bookmarks
| 1. |
11term of the AP -3,-1/2, 2 ........is\xa0 |
| Answer» The given AP is\xa0{tex} - 3,\\frac{1}{2},2,......{/tex}Here, a = -3{tex}d = - \\frac{1}{2} - ( - 3) = - \\frac{1}{2} + 3 = \\frac{5}{2}{/tex}and n = 11a11 = ?We have, an = a + (n - 1)dSo,\xa0{tex}{a_{11}} = - 3 + (11 - 1)\\left( {\\frac{5}{2}} \\right){/tex}{tex} \\Rightarrow {a_{11}} = - 3 + 25{/tex}{tex} \\Rightarrow {a_{11}} = 22{/tex} | |